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The coordination number is the number of ligands bonded to the central atom. The oxidation number is the charge on the transition metal in the coordination compound.

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A chelate forms when a plydentate ligands forms multiple coordinate covalent bonds with a central metal atom.

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Since CH2O is trigonal planar, there are three regions of electron density. Hence, there are 3 hybrid orbitals corresponding to sp2 hybridization.

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The coefficent number in front represents the period the atom is in, while the S is refering to the orbital.

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Both methods are correct

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Yes, since lone pairs are a region of electron density it is taken into account for hybridization.

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Electron density refers to regions that have bonding electrons or lone pairs, which gives you the molecular orbital geometry. The VSEPR geometry only refers to the bonded electrons, or atoms.

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Single bonds consist of a sigma bond, double bonds consist of a sigma and a pi bond, and triple bonds consist of a sigma bond and two pi bonds.

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Since hybridized orbitals have less energy than unhybridized orbitals, it results in more stable compounds.

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Generally, the more electronegative atoms have charges and the central atoms dont have charges for it to be most stable.

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Any element in period 3 or below can have expanded octets as they can expand into the d-orbitals.

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Boron is one of the exceptions to the octet rule.

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If you are given bond lengths, the smaller value is the double bond and the higher value is the single bond. If it is a resonance structure, you find the average of the values.

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Since electon repulsion increases as the number of bonds increase, the higher number of bonds will not be as effective at pairing as those with lower number of bonds, thus explaining why lower number of bonds have higher strength and require more energy to break.

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The more elctronegative atom accepts electrons so it is more negatively charged, hence delta negative. The atom that donates the elctrons becomes positively charged, or delta positive.

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Using the equation, Energy of photon = work function + kinetic energy, you can solve for work function given the other variables.

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The atom with the lowest ionization energy is the central atom.

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Yes electronegativy and electron affinity both increase across due to a stronger nuclear attraction and decrease down as the number of shells increase making electrons further away from the nucleus.

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The EM spectrum regions should be known, but it is not neccesary to know each range of values. From highest energy (shortest wavelength) to lowest energy (highest wavelength), the spectrum is as follows: gamma rays, x-rays, ultraviolet light, visible light, infrared rays, microwaves, radio waves.

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The photoelectric effect is the emission of electrons from the radiation of a light that is greater than the threshold energy. It showed that intensity does not affect the ejection of light, but that one photon interacts with one electron.

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Light has properties of waves as displayed in diffraction patterns that are shown when light passes through a crystal and particles as seen in the photoelectric effect.

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No you do not need to calculations of the equation as it is advanced math, but know the conceptual implications of the equation regarding orbitals and wave functions

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When we combine the equations E=hv and c=λv, we get E=hc/λ. Hence, we get the constants, h, Planck's constant (6.626x10^-34Js) multiplied by c, the speed of light (3.00x10^8 m/s).

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Both options are correct and can be used on the exam, but 2.998 x 10^8 will be more precise.

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While the mole coefficients may not be equal, this does not mean the equation is not balanced. Balancing equations deals with the same number of atoms/elements on the reactant and product side.

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The value should be close to a whole number or if not very close so you can round to one.

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In this equation, E is the energy of light (photons) in Joules.

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I tend to find the element that occurs the least and balancing from there as it makes the process way easier.

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Yes, since molarity is expressed in moles/liter, ml should be changed to L to express the answer in the right units

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The empirical formula represents the most basic ratio of atoms in the formula.

CHEMISTRY COMMUNITY

Search found 30 matches

Re: Coordination Number

Re: How to tell if something is a chelate

Re: CH2O hybridization

Re: 2s or s?

Re: Hybridization Notation

Re: lone pairs

Re: Electron Density vs Shape?

Re: double bonds

Re: reason for hybridization

Re: Formal Charge

Re: Expanded Octets

Re: Boron Trifluoride

Re: Bond Lengths

Re: Proportionality of bond strength

Re: delta positive delta negative

Re: Work Function

Re: Lewis Structures

Re: Electronegativity

Re: Electromagnetic Spectrum

Re: Photoelectric Effect

Re: Is light in waves or photons?

Re: Schrodinger's Wave Function

Re: Wavelength Calculations

Re: Calculating the wavelength of light

Re: Mole Coefficients in Chemical Equations

Re: Going from empirical to Molecular formula

Re: E=hv

Re: Balancing reactions tips

Re: molarity conversion

Re: Definition of Empirical Formula