CHEMISTRY COMMUNITY

Andrewwiner4D

Both essentially the same thing but when working in an aqueous solution, it is easier the refer as H30+ because water is the proton acceptor.

Andrewwiner4D

I know these are not the same acids but this is a good explanation Lavelle gave in 2014: HOCl vs HOI --> To analyze the acidity of this pair you [censored] the polarizing power of the conjugate base (eg. -OCl and -OI). The more electronegative species (-OCl) will polarize ( pull charge towards it) t...

Andrewwiner4D

We do need to be able to do both. In all the homework problems (or most) you had to find both. But they are pretty easy and depending on which compounds we are working with it is a useful skill.

Andrewwiner4D

A stronger acid will disassociate more and because KA is the ratio of product concentrations over reactant concentrations, the more products, will increase KA. Then since pKA is the negative log of KA the values will decrease and be more acidic.

Andrewwiner4D

Check this out; it is a good explanation:
viewtopic.php?f=55&t=610

Andrewwiner4D

The square planar has six areas of electron density surrounding the central atom: four of these are other bonded atoms and two are lone pairs. Tetrahedral will have angles of 109.5 where the square planar will have angles of 90.

Andrewwiner4D

Dr. Lavelle said there are such things as super acids and bases. The super bases can have pH values greater than 14 and super acids can have pH values below 0.

Andrewwiner4D

YES OF COURSE

Andrewwiner4D

There are three areas of electron concentration. Total valence electrons for CH2 is 6. Each hydrogen has one bond and there is one lone pair. The bent shape will give you an SP2 hybridization.

Andrewwiner4D

If your pi bond refers to the p-p orbitals overlapping, then pi bond is weaker than sigma bond. Double bond is stronger than single bond because double bond consists of a pi bond and a sigma bond. Whereas sigma bond results from s-orbital overlap which has greater area of interaction and overlapping.

Andrewwiner4D

Yes you will need to be able to draw and name the VSEPR models and shapes.

Andrewwiner4D

There are four bonded atoms and one lone pair. The angles of the bonded atoms are 90, 90>angle>180, and 180. Mostly the four bonded atoms are tetrahedral, but the lone pair pushes down the atoms.

Andrewwiner4D

Covalent bonds are stronger than hydrogen bonds, but the induced dipole interactions are weaker than the hydrogen bond.

Andrewwiner4D

When it is telling you to draw the VSEPR structure, which I feel we will only be doing from now on, you must specify the bond length.

Andrewwiner4D

First elements do not have a resonance, molecules do. Second, in nature molecules will go to the lowest energy state which involves (for our proposes) looking at formal charge.

Andrewwiner4D

No^ because in nature the molecule can literally just turn and the elements would switch whether they are on the right or the left.

Andrewwiner4D

The trend is based on the fact that the ratio of protons to electrons in the shell becomes greater. There are more protons than electrons, so the shell will not be able to expand as far with the greater pull.

Andrewwiner4D

I think they are possible (in a lab can be generated) but there are none naturally occurring, and like these people said^^definitely not for this class.

Andrewwiner4D

I visualize ionization energy is having a struggle with an atom to pull one of its electron away from it, where electronegativity is an atom pulling my own electrons away when we are linking up (if the other atom has a higher electronegativity).

Andrewwiner4D

For connection purposes: think of ionization energy as having a similar trend to electronegativity. The elements that pull electrons more towards themselves when bonding are the same atoms that it is difficult to remove an electron from.

Andrewwiner4D

Starting the electron configuration at a noble gas is a shorthand, but in my own experience you become comfortable and memorize the structure. The noble gases are all P^6 so you can just count the rows down on the periodic table to determine. It's pretty simple, but there are some weird moments elec...

Andrewwiner4D

n=principle quantum number
l=angular momentum quantum number
ml=magnetic quantum number
ms=spin magnetic quantum number

Andrewwiner4D

You just need to know where light is visible. I do not believe that you will need to memorize every value, that'd be a little absurd.

Andrewwiner4D

The question is about different aspects of sodium, but in the solutions guide it seems to have the energy per atom of sodium as a given. Will we be provided with such information on tests?

Andrewwiner4D

That reply is by Andrew Winer (4D).^^^

Andrewwiner4D

You will be provided a periodic table but will have to calculate molar masses on molecules.

Andrewwiner4D

Because the electron is losing energy as it moves down energy levels. Photons will be emitted (Light will be visible).
-Andrew Winer 4D

Andrewwiner4D

That reply is by Andrew Winer^^

Andrewwiner4D

It has to do with the effective nuclear charge. Shielding also plays a factor. The shielding effect describes the balance between the pull of the protons on valence electrons and the repulsion forces from inner electrons. The effective nuclear charge is the net positive charge experienced by valence...

Andrewwiner4D

I would wait to round till you get to the final answer. Use the extended version for calculations but then correct at the end for sig figs.

Andrewwiner4D

You turn the homework into your TA during discussion. I believe they return it the following week and definitely before any exam. Also the homework is graded for accuracy so make sure to check your answers in the solutions guide.

Andrewwiner4D

This definition was just an example for one element. The atomic weights given on the periodic table are grams per one mole, so if you wanted to look at another element, let's use hydrogen, one mole would equal 1.001 grams of hydrogen.

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