Search found 37 matches
edta 4-
If the coordination compound has the ligand ethylenediaminetetraacetato is this written simply as (edta) or (edta 4-) when naming the compound because technically they're two different things?
- Fri Dec 07, 2018 11:52 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: H20 as ligand
- Replies: 1
- Views: 225
H20 as ligand
Why is H20 not a bidentate even though it has 2 lone pairs?
- Fri Dec 07, 2018 11:31 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Ligand
- Replies: 1
- Views: 227
Ligand
Do have to memorize all of these ligands?
- Sun Dec 02, 2018 7:35 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Question 4.91 Part B (Sixth Edition)
- Replies: 1
- Views: 398
Re: Question 4.91 Part B (Sixth Edition)
The two carbons that don't have an H attached to them have an sp hybridization, so they would want to have the linear arrangement. But because the atoms are arranged to form a ring, the two carbons have a strained structure (meaning they won't form 180 degree angles). This is why it is reactive.
- Sun Dec 02, 2018 7:22 pm
- Forum: Student Social/Study Group
- Topic: Fall 2018 Final
- Replies: 1
- Views: 522
Re: Fall 2018 Final
I don't think so, but I would check with your T.A.
- Wed Nov 28, 2018 6:36 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Tetrahedral
- Replies: 2
- Views: 277
Tetrahedral
Does a tetrahedral like CH4 have 5 109.5 degree bond angles?
- Sat Nov 24, 2018 1:08 pm
- Forum: Bond Lengths & Energies
- Topic: Determining Higher Boiling Points
- Replies: 2
- Views: 392
Re: Determining Higher Boiling Points
It is true that the H-Br bond length is shorter than the H-I bond length. However, what you need to consider is also the size of the atoms. I is a larger atom than Br, so it has more electrons that increase the strength of the dispersion forces and the attractive interactions. Due to the greater att...
- Sat Nov 24, 2018 12:55 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: VESPR Geometric Shapes
- Replies: 1
- Views: 302
Re: VESPR Geometric Shapes
Trigonal Bipyramidal: AX5
Seesaw: AX4E
Square Pyramidal: AX5E
A represents the central atom
X bonded atom
E lone pair
Notice how they are not exactly the same because of the lone pairs.
Seesaw: AX4E
Square Pyramidal: AX5E
A represents the central atom
X bonded atom
E lone pair
Notice how they are not exactly the same because of the lone pairs.
- Sat Nov 24, 2018 12:46 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Seesaw bond angles
- Replies: 3
- Views: 419
Re: Seesaw bond angles
There are two 90 degree lone-pair-bonding-pair repulsions, but I am not sure about the number of 120 degree bond angles.
- Sat Nov 17, 2018 7:10 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: End-to-end vs. Side-to-side
- Replies: 2
- Views: 2078
Re: End-to-end vs. Side-to-side
Professor Lavelle drew the p-p orbitals on the board which helped me visualize this. Note that a p-orbital has 2 lobes. For the "end-to-end," if p-orbital 1 and p-orbital 2 are in the horizontal direction next to each other, the "end" of the right lobe of p-orbital 1 will "o...
- Sat Nov 17, 2018 6:52 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond Angles
- Replies: 16
- Views: 1233
Re: Bond Angles
I believe that Professor Lavelle said we don't need to know the exact bond angles for specific molecules, but we should know it for the general shape. So if you identify a molecule to have the trigonal pyramidal shape (3 bonding pairs and 1 lone pair), you can say that the bond angles for that molec...
- Fri Nov 16, 2018 1:49 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Repulsion Strength
- Replies: 2
- Views: 276
Repulsion Strength
Why is lone-lone pair repulsion stronger than lone-bonding pair and bonding-bonding pair?
- Sat Nov 10, 2018 7:35 pm
- Forum: Bond Lengths & Energies
- Topic: Energy of Intermolecular forces
- Replies: 2
- Views: 330
Energy of Intermolecular forces
In our lecture notes, the energy is negative i.e. for ion-ion it is -250 kJ/mol, but in the book all the values are positive. Why is this?
- Sat Nov 10, 2018 5:29 pm
- Forum: Ionic & Covalent Bonds
- Topic: Covalent Character
- Replies: 1
- Views: 256
Re: Covalent Character
Something like NaCl is known to be a salt with an ionic bond between Na+ and Cl-. You have to keep in mind though that all ionic bonds have covalent character, meaning electrons are going to be "shared" between the Na+ and Cl-. The Na+ which is the cation has polarizing power and can exert...
- Sat Nov 10, 2018 5:18 pm
- Forum: Resonance Structures
- Topic: Expanded Octet and Resonance
- Replies: 2
- Views: 402
Re: Expanded Octet and Resonance
I don't think it can because if it has more than 4 single bonds, then that means the central atom has more than 8 valence electrons, already suggesting an expanded octet. The resonance structures also have to reflect this. If an atom does not have a d-orbital or f-orbital for more electrons, it can'...
- Tue Nov 06, 2018 10:42 pm
- Forum: Administrative Questions and Class Announcements
- Topic: HW for this week
- Replies: 2
- Views: 351
HW for this week
Which HW problems can we turn in this week? 3.73 and onward, or are all chapter 3 problems acceptable?
- Sun Nov 04, 2018 5:17 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Formal Charge SO42-
- Replies: 3
- Views: 11602
Re: Formal Charge SO42-
Thank you that makes sense!
- Sun Nov 04, 2018 4:07 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Formal Charge SO42-
- Replies: 3
- Views: 11602
Formal Charge SO42-
The more stable structure of SO42- has 2 double bonds and 2 single bonds with O, but the single bonds have a formal charge of -1. Why can't those single bonds also become double bonds so that the formal charge becomes 0. Since S can accommodate more than 8 valence electrons, wouldn't this work?
- Sun Nov 04, 2018 12:39 am
- Forum: Trends in The Periodic Table
- Topic: Isoelectronic elements
- Replies: 1
- Views: 439
Isoelectronic elements
So In is [Kr] 4d10 5s2 5p1. So for In3+, I looked at the periodic table and moved 3 to the left, arriving at Palladium. Hence, I thought the electron configuration of palladium/In 3+ will be [Kr] 4d8 5s2, but palladium is an exception like chromium and copper so its electron configuration is [Kr] 4d...
- Sat Nov 03, 2018 11:25 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Valence Electrons
- Replies: 2
- Views: 274
Valence Electrons
Do we need to know the # of valence electrons for the 3d elements?
- Sat Nov 03, 2018 10:16 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Subshells
- Replies: 2
- Views: 535
Subshells
For example, the electron configuration for Selenium (Se) is [Ar] 3d10 4s2 4p4.
If I am looking at n=4, then l can be the 0 (s) ,1 (p), 2 (d) and 3 (f) subshells. Since Selenium goes up to 4p4, does that mean it has empty l=2 and l=3 subshells, or does it not have those subshells at all?
If I am looking at n=4, then l can be the 0 (s) ,1 (p), 2 (d) and 3 (f) subshells. Since Selenium goes up to 4p4, does that mean it has empty l=2 and l=3 subshells, or does it not have those subshells at all?
- Wed Oct 31, 2018 10:21 pm
- Forum: Formal Charge and Oxidation Numbers
- Topic: Oxidation Numbers
- Replies: 3
- Views: 517
Re: Oxidation Numbers
Step 1. Atoms in their elemental state have an oxidation number of 0. Step 2. Atoms in monatomic (i.e. single atom) ions have an oxidation number equal to their charge. Step 3. In compounds: fluorine is assigned a −1 oxidation number; oxygen is usually assigned a −2 oxidation number (except in perox...
- Thu Oct 25, 2018 12:18 am
- Forum: DeBroglie Equation
- Topic: De Broglie module #35
- Replies: 3
- Views: 420
De Broglie module #35
35. Calculate the wavelength of a 275 kg single-seat electric car traveling at a speed of 125 km.hr-1. Do electric cars have wavelike properties? A. λ = 6.94 x 10-38 m , Yes B. λ = 6.94 x 10-38 m , No C. λ = 1.93 x 10-38 m , Yes D. λ = 1.93 x 10-38 m , No I got the wavelength correct, but I chose A ...
- Wed Oct 24, 2018 8:03 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic Spectra Module #37
- Replies: 2
- Views: 494
Atomic Spectra Module #37
37. Write the equation that allows one to calculate the electronic energy levels for the hydrogen atom. Do the calculated energies compare favorably with empirical observation (spectroscopic results)? C. E = -hR/(n2), No D. E = -hR/(n2), Yes Is the 2nd question asking whether the calculated version ...
- Tue Oct 23, 2018 10:46 pm
- Forum: Photoelectric Effect
- Topic: Module: Photoelectric Effect #25
- Replies: 1
- Views: 292
Module: Photoelectric Effect #25
25. Photoelectric experiments gave rise to a new equation relating the energy of light to its frequency. Select the right equation. A. λv = c B. Ek = mv2/2 C. mv2/2 = hv - φ D. E = hv E. None of the above Is E=hv the correct answer since it is the one that clearly relates energy to the frequency? I ...
- Wed Oct 17, 2018 11:54 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Absorption/atomic spectra
- Replies: 3
- Views: 298
Absorption/atomic spectra
If the electron went from a lower energy state (i.e. n to higher energy state that would indicate absorption, so the difference in energy would be positive instead of negative. Would the photon energy still be positive in this case since it is no longer an emission?
- Wed Oct 17, 2018 11:10 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic Spectra
- Replies: 1
- Views: 105
Atomic Spectra
In the image, why is the photon of particular energy given as v? I understand that v=change in Energy/h, but isn't v the Bohr frequency condition and not "the particular energy"?
- Wed Oct 17, 2018 10:49 pm
- Forum: Photoelectric Effect
- Topic: Intensity
- Replies: 2
- Views: 235
Intensity
In the photoelectric effect, higher intensity does not necessarily mean greater amplitude right? Do we stop treating light like a wave once we consider it a photon?
- Wed Oct 17, 2018 9:46 pm
- Forum: Properties of Light
- Topic: Friday 10/5 Lecture
- Replies: 7
- Views: 676
Friday 10/5 Lecture
Properties of Light: Friday 10/5 Lecture: When Professor Lavelle wrote v=m*s^-1 on the board was he referring to velocity? In my notebook, I wrote v as frequency, but I don't think that makes sense.
- Wed Oct 10, 2018 11:16 pm
- Forum: Significant Figures
- Topic: Module: Molarity #15
- Replies: 6
- Views: 1273
Module: Molarity #15
15. Calculate the concentration (molarity) of a glucose solution containing 0.1 moles of glucose in 0.4 liters of water. A. 0.25 mol.L-1 B. 4.0 mol.L-1 C. 2.5 mol.L-1 D. 2 mol.L-1 .1mol/.4L=.25 mol. L-1. So I got this for the answer but I was confused why the answer is exact and not 1 sig fig (.2)
- Wed Oct 10, 2018 7:49 pm
- Forum: Limiting Reactant Calculations
- Topic: Module Question #18 Help
- Replies: 1
- Views: 246
Module Question #18 Help
18. For the following equation, determine the limiting reagent if 21.4 g NH3 is reacted with 42.5 g of O2. 4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g) A. NH3 B. O2 C. Both D. Neither I did this incorrectly the first time, so now I am not sure about my work. Can someone please confirm my work? Based on my...
- Sun Oct 07, 2018 6:43 pm
- Forum: Significant Figures
- Topic: Sig Fig in Relation to Zero
- Replies: 3
- Views: 576
Re: Sig Fig in Relation to Zero
0.0490 has 3 sig figs I read this in another post: "If the decimal point is present, start counting digits from the Pacific (left) side, starting with the first non-zero digit. If the decimal point is absent, start counting digits from the Atlantic (right) side, starting with the first non-zero...
- Sun Oct 07, 2018 6:29 pm
- Forum: Significant Figures
- Topic: Empirical and Molecular Formula's Video #19
- Replies: 3
- Views: 537
Re: Empirical and Molecular Formula's Video #19
The number of significant figures that the answer should have is determined by what is given in the question and not what has been calculated. Therefore, since the molar mass of 84 is the only number that is given, then the answer should have 2 significant figures because 84 has 2 sig figs. If ther...
- Sat Oct 06, 2018 5:04 pm
- Forum: Significant Figures
- Topic: Empirical and Molecular Formula's Video #19
- Replies: 3
- Views: 537
Empirical and Molecular Formula's Video #19
19. The molar mass of cyclohexane is 84 g.mol–1 and its empirical formula is CH2 What is its molecular formula? So I did 1x12.011g.mol^-1+2x1.008g.mol^-1= 14.027g.mol^-1 When I do 84 g.mol–1/14.027g.mol^-1, how many sig figs will the answer have? Is 84 just considered an integer which means that I l...
- Thu Oct 04, 2018 11:04 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Moles and Molar Mass
- Replies: 10
- Views: 609
Re: Moles and Molar Mass
So you are given 1.00 mol of Ag, but what you are supposed to find is the number of Ag atoms from this given info. because only then can you use the radius given (144pm) to figure out how long the fiber is. Step 1: you would convert the mol of Ag to number of Ag atoms 1.00 mol Ag x (6.0221x10^23)/mo...
- Thu Oct 04, 2018 10:49 pm
- Forum: Significant Figures
- Topic: Sig Figs
- Replies: 3
- Views: 702
Sig Figs
If my empirical formula is CH2, for example, and then I need to use the molar mass to find the molecular formula, I do 1(12.011 g.mol^-1)+2(1.008 g. mol^-1). Will my answer have 3 places after the decimal because I am supposed to focus on the addition rule or will it be 4 significant digits because ...
- Wed Oct 03, 2018 2:19 am
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Clarification on Units (Moles)
- Replies: 1
- Views: 123
Re: Clarification on Units (Moles)
I think the book defines N as "# of objects" because a "mole" is the amount of substance and that substance is Cu in your video. The objects that make up a substance can be atoms, molecules, ions, etc. In most examples, the "objects" are the atoms, so N is the # of atom...