Search found 30 matches
- Fri Mar 15, 2019 3:04 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Does a -E and -G mean that the reverse reaction is spontaneous? [ENDORSED]
- Replies: 3
- Views: 670
Re: Does a -E and -G mean that the reverse reaction is spontaneous? [ENDORSED]
Is the reverse also true? Does a +G mean that the forward reaction is nonspontaneous but the reverse reaction is spontaneous?
- Fri Mar 15, 2019 3:02 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 6.57
- Replies: 2
- Views: 186
Re: 6.57
Does this mean that the solution is wrong?
- Thu Mar 14, 2019 6:24 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Does a -E and -G mean that the reverse reaction is spontaneous? [ENDORSED]
- Replies: 3
- Views: 670
- Thu Mar 14, 2019 6:22 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: If delta G is positive does that mean the reverse reaction is spontaneous? [ENDORSED]
- Replies: 1
- Views: 434
- Tue Mar 12, 2019 6:12 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 6.57
- Replies: 2
- Views: 186
6.57
Can someone please explain how to find the cathode and why which equation is the cathode/anode?
The solutions manual says that the reduction of F2 is the cathode even though its reduction potential is lower than that of the supposed anode.
The solutions manual says that the reduction of F2 is the cathode even though its reduction potential is lower than that of the supposed anode.
- Tue Mar 12, 2019 4:34 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Test 2 #5
- Replies: 1
- Views: 257
Test 2 #5
Once you get K2 do you
1. take the square root of it to find [H3O+] and assume that [H3O+] = [OH-] and get the pH from there
2. put 10^-7 as [H3O+] because the pH is 7 and divide K2 by that to get [OH-] and see which one is higher to decide if it's acidic or basic?
1. take the square root of it to find [H3O+] and assume that [H3O+] = [OH-] and get the pH from there
2. put 10^-7 as [H3O+] because the pH is 7 and divide K2 by that to get [OH-] and see which one is higher to decide if it's acidic or basic?
- Tue Mar 12, 2019 4:28 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Test 2: Why is photosynthesis spontaneous?
- Replies: 2
- Views: 662
Test 2: Why is photosynthesis spontaneous?
Here is the exact statement:
The photosynthesis of glucose inside the chloroplast of an old growth Coastal Redwood tree.
I said deltaG > 0 and got it wrong.
The photosynthesis of glucose inside the chloroplast of an old growth Coastal Redwood tree.
I said deltaG > 0 and got it wrong.
- Tue Feb 26, 2019 3:56 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Lyndon's Worksheet #3
- Replies: 1
- Views: 230
Lyndon's Worksheet #3
I'm confused why you can't add the two reactions to make a new reaction and have to convert to G. I thought that was how all redox reactions were solved and I don't understand why this reaction is different.
- Sun Feb 24, 2019 8:57 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 6L.5d
- Replies: 1
- Views: 253
6L.5d
Why is the oxidation equation Au(s) -> Au3+(aq) + 3e- and not Au+(aq) -> Au3+(aq) + 3e-?
- Sun Feb 24, 2019 8:44 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Adding an inert electrode? 6L.5b
- Replies: 1
- Views: 197
Adding an inert electrode? 6L.5b
How do you know when you have to add another element that's not given in the equation into the cell diagram? The solutions manual says that "an inert electrode such as Pt is necessary when both oxidized and reduced species are in the same solution" but I don't understand what that means an...
- Sun Feb 24, 2019 1:37 pm
- Forum: Balancing Redox Reactions
- Topic: 6K.3d
- Replies: 2
- Views: 299
Re: 6K.3d
How do you know that Cl2 goes to Cl- when it's not listed in the equation?
- Sat Feb 23, 2019 8:25 pm
- Forum: Balancing Redox Reactions
- Topic: 6K.3d
- Replies: 2
- Views: 299
6K.3d
How do you find the half reactions?
- Sat Feb 23, 2019 2:29 pm
- Forum: Student Social/Study Group
- Topic: How are you guys going to study for Test 2?
- Replies: 10
- Views: 930
- Sat Feb 23, 2019 2:27 pm
- Forum: Administrative Questions and Class Announcements
- Topic: What topics are going to be on Test 2?
- Replies: 4
- Views: 440
- Sat Feb 09, 2019 3:28 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: When do you use w = -nRTlnV2/v1, q = nRTlnV2/V1, and w = -PdV?
- Replies: 1
- Views: 413
When do you use w = -nRTlnV2/v1, q = nRTlnV2/V1, and w = -PdV?
I'm really confused when to use which equation.
- Sat Feb 09, 2019 3:22 pm
- Forum: Phase Changes & Related Calculations
- Topic: Why does steam cause severe burns?
- Replies: 2
- Views: 335
Why does steam cause severe burns?
Sorry, I realize that Dr. Lavelle has gone over this in class but I didn't really understand his explanation.
- Sat Feb 09, 2019 3:16 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Textbook glitch
- Replies: 2
- Views: 316
Textbook glitch
Is anyone else's online textbook missing a lot of numbers from the problems? I try to deduce the numbers from the solutions manual but it can get really frustrating having to do it every time... is there any way I can fix this?
- Tue Jan 29, 2019 6:58 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 4D.23
- Replies: 1
- Views: 154
Re: 4D.23
Also,
-169.2 kJ = deltaH (N2O5) - 2(+90.25 kJ)
Why doesn't -169.2 kJ equal delta H(N2O5)? Why do you have to add 2(+90.25 kJ)?
-169.2 kJ = deltaH (N2O5) - 2(+90.25 kJ)
Why doesn't -169.2 kJ equal delta H(N2O5)? Why do you have to add 2(+90.25 kJ)?
- Tue Jan 29, 2019 6:50 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 4D.23
- Replies: 1
- Views: 154
4D.23
How do you come up with the reaction equation N2 (g) + 5/2 O2 (g) -> N2O5 (g) ?
- Tue Jan 29, 2019 6:37 pm
- Forum: Phase Changes & Related Calculations
- Topic: 4B.13b
- Replies: 1
- Views: 180
4B.13b
Why do you have to take the natural log of V2/V1?
- Tue Jan 29, 2019 6:27 pm
- Forum: Phase Changes & Related Calculations
- Topic: 4B.13a
- Replies: 1
- Views: 208
4B.13a
The solutions manual states that the equation for the irreversible work of expansion against a constant opposing pressure is given by w= -P delta V. Why do you have to multiple the result by 101.325 J.L^-1.atm^-1?
- Sun Jan 27, 2019 11:15 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE BOX and coefficients
- Replies: 4
- Views: 764
Re: ICE BOX and coefficients
When there are coefficients in front of the molecules you multiply it by x (the change).
- Tue Jan 22, 2019 9:27 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Does [H3O+][OH-] always equal 10^-14?
- Replies: 9
- Views: 1162
Does [H3O+][OH-] always equal 10^-14?
Under what conditions does it not equal 10^-14? For 6B.9 [H3O+][OH-] does not equal 10^-14...
- Mon Jan 21, 2019 12:43 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: pKa and pKb
- Replies: 3
- Views: 791
pKa and pKb
The textbook says that the weaker the acid, the smaller the value of Ka and the greater the value of pKa. If I'm interpreting this correctly, it makes sense that a weak acid would have a greater number on the pH scale because the lower the number the more acidic and the greater the number the more b...
- Thu Jan 17, 2019 8:48 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: [H3O+] =[OH-]
- Replies: 2
- Views: 286
Re: [H3O+] =[OH-]
[H3O+][OH-] = 10^-14
If [H3O+] =[OH-], then they both equal 10^-7. pH = -log [H3O+] = -log[10^-7] = 7 so the solution is neutral.
If [H3O+] =[OH-], then they both equal 10^-7. pH = -log [H3O+] = -log[10^-7] = 7 so the solution is neutral.
- Thu Jan 17, 2019 12:15 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Why do stronger bases have conjugate acids with larger pKa values?
- Replies: 4
- Views: 2848
Why do stronger bases have conjugate acids with larger pKa values?
Professor Lavelle said in class that strong bases have weak conjugate acids and weak bases have strong conjugate bases. I don't understand why and I also don't understand why stronger bases have conjugate acids with larger pKa values.
- Wed Jan 16, 2019 11:46 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 6B.11
- Replies: 2
- Views: 211
6B.11
For part ii of a, how do you figure out the concentration of OH- from the original solution? The solutions manual says to multiple the concentration of OH- in the diluted solution by 500.0 mL/5.00 mL but I don't understand why.
- Thu Jan 10, 2019 10:41 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: 5.33
- Replies: 2
- Views: 173
Re: 5.33
Also, why does decreasing the volume favor the formation of X2? I understand that decreasing the volume increases the pressure but I do not understand why this would lead to an increase in reactants.
- Thu Jan 10, 2019 10:32 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: 5.33
- Replies: 2
- Views: 173
5.33
According to the solutions manual, the answer is a because the reaction is endothermic. The solutions manual says that the value of the equilibrium constant is larger in Flask 2 than in Flask 1, which is consistent with an increase in temperature of an endothermic reaction. I do not understand why a...
- Wed Jan 09, 2019 5:24 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5G.9c, d, e
- Replies: 2
- Views: 235
5G.9c, d, e
A 0.10-mol sample of pure ozone, O3, is placed in a sealed 1.0-L container and the reaction 2O3 (g) -> 3O2(g) is allowed to reach equilibrium. A 0.50-mol sample of pure ozone is placed in a second 1.0-L container at the same temperature and allowed to reach equilibrium. Without doing any calculation...