CHEMISTRY COMMUNITY

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you can look at the rate law given or graph

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I think electronically, probably scan and submit?

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Honestly, I'm still waiting for the email that he said he will send today. I understand that he has been busy, but hopefully itll come soon because im getting anxious

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im thinking textbook, lecture notes, discussion notes

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joules or kilojoules

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I think it would be best to

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determining the oxidation number determines whether it is oxidizing or reducing. when balancing half reactions, it will show how many electrons will be lost or gained

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yes, it is probably the most common

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Concentration does not affect rate in zero order reaction

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they will probably have us download and print the finals

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you can just an app call genius scan for android users to scan

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wait so is the exam three hours or will he just post it tomorrow? I just want to know because other professor have given a twenty-four hours limit

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n is the number of moles of e in the reaction that is being transferred

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no, that is the only topic that will not be tested before the final

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kelvin, just make sure the units for R is the same

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k is unit-less because it is a ration of concentrations of products and reactants

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same kind of cells, just different names

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identify delta g- spontaneous--> will dissolves
not spontaneous--> will not dissolves

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on the left side, oxidation is taking place at the anode- so the rod itself is giving off electrons which then travel to the right side, the cathode to binds with free floating molecules waiting to be reduced.

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yes, just change the sign of the given value

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the salt bridge is needed to maintain the charge balance of the two solutions as the electrons move from the anode to cathode, it leaves the left-side solution positively charged, therefore the ions from the salt bridge enters to to stabilize the charge difference

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delta g is equal to the max non-expansion work (at constant p and t)

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the sign is used more to keep track, so its a good idea to use it as it minimizes your chances of making a mistake

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the equilibrium changes in responds to change in temperature

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you don't include the coefficients in the cell diagrams

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n refers to the moles of electrons that is being transfered

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not sure if this answers your question, but electricity is used in the body so now physicians use EEG to detect abnormalities

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personally, lyndon's reviews are great for me.

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I don't think it is important to memorize that equation. As long as you understand that losing heat is neg and absorbing is pos. and the amount of energy lost/gain by the system is equal to the amount gain/lost by the surrounding.

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Enthalpy is the amount of heat released or absorbed when the rxn is at a constant pressure

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It would depends on the problems, one of the best thing to do is check the units of a given constant in that problem.

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Internal energy is the total energy found in a system which is, as defined by the equation, the sum of heat plus work (a form of energy)

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It can be either one depending on the units of the C that you use

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I don't think we have to memorize them

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It would depends on the chemical equation given

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yes it is included in the calculation as long as it is not in pure liquid form

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Percent Ionization = ([H3O+]/[initial concentration of acid]) x 100

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I believe that it is measured in joules

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I do not believe that enthalpy values will ever be negative

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Following the examples that have already been given- those values will most likely be given to us

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We went over some examples as practice. No new material

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Partial pressure (from what I have seen) is usually given in the problem. But I do not doubt that we might have to solve for Partial Pressure in some cases.

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Test one will be covering Chemical Equilibrium and Acid&Base Equilibria

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When Q < K, that means the reaction is not in equilibrium and the reaction is favoring the product side.

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I do not think that there will be a study guide for test one, but Professor Lavelle said that the extra problems that he put on the outlines are good practice.

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I'm having the same problem. Please help

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Autoprotolysis can happen with other molecules apart from water molecules, such as ammonia and acetic acid.

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When K is between 10^-3 and 10^3, it means that neither the reactants nor the products are favored when the reaction is in equilibrium. You can't necessarily tell which side of the equilibrium has more in concentrations.

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We get the $\sqrt{41}$
because when you write out the expression for K. We notice that the exponents (which are the coefficients in the equilibrium equation) are divided by 2. Therefore, in order to keep the two sides equal, we must take the Square root of 41.

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Although gases are never perfectly "ideal". We assume most of the time that gases are ideal because at higher temperature and lower pressure there are not a significant intermolecular forces between the gas molecules. This assumption allows for calculations of other properties of the gases.

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