CHEMISTRY COMMUNITY

Ipsita Srinivas 1K

No, activation energies are not constant. Catalysts are a good example of this, as they increase reaction efficiency by lowering activation energy (sometimes), requiring less energy for the reaction to take place. They do so by stabilising the transition state between reactant and product. However, ...

Ipsita Srinivas 1K

ln(A.e^-E_a/RT) = ln (A)+ln(e^-E_a/RT.
This is because ln(x.y)=ln(x)+ln(y).

Ipsita Srinivas 1K

The sum of stoichiometric coefficients for the reactants in the slow step is equal to the order of the overall reaction. For elementary reactions, there is only a single step leading from reaction to product, hence one can directly sum the coefficients of the reactants for that reaction, without wor...

Ipsita Srinivas 1K

The energy absorbed includes the activation energy needed for the reaction to take place for both endothermic and exothermic reactions. In the case of exothermic reactions, energy related on product formation is more than energy absorbed for overcoming energy barrier, and hence there is a net loss o...

Ipsita Srinivas 1K

The equation is bimolecular, but a first order reaction. The notation doesn't determine the order of the reaction For example, in example 7B.1, the equation is first-order in N 2 O 5 , despite there being two molecules. The notation is important when determining the rate of a multi-step reaction, bu...

Ipsita Srinivas 1K

In either case though, you should be able to take the temperature difference either way you wanted.

Ipsita Srinivas 1K

Do you mean the van't Hoff equation?

Ipsita Srinivas 1K

I think lecture 15 was when he first introduced e.m.f. The electromotive force of the cell is the potential difference between the electrodes of a galvanic cell, in the scenario where there is very little, or no current flow. It is the maximum p.d between the cell electrodes and is symbolised as the...

Ipsita Srinivas 1K

Ipsita Srinivas 1K

The equilibrium constant for a reaction, can be expressed as the ratio of rate constants i.e for a reaction with forward rate constant = k and backward reaction rate constant = k', K= k/k'. In such a scenario, a large K value implies k>>k' i.e the forward reaction is taking place at a faster rate th...

Ipsita Srinivas 1K

The Arrhenius equation relates the rate constant k, to the activation energy needed for the specified reaction to proceed, the pre-exponential factor, as well as the temperature at which the reaction is taking place.

Ipsita Srinivas 1K

Polar head group, n. Inuit psychiatrists.

Ipsita Srinivas 1K

Organic, adj. Church musician.

Ipsita Srinivas 1K

Flame Test, n. Trial by fire.

Ipsita Srinivas 1K

Diglyceride, n. What you scream when you're trying to kill a glyceride.

Ipsita Srinivas 1K

Activation Energy, n. The useful quantity of energy available in one cup of coffee.

Ipsita Srinivas 1K

Every dipole has its moment.

Ipsita Srinivas 1K

Wanted by the Law: Schrodinger's Cat, Dead And/Or Alive

Ipsita Srinivas 1K

The noble gases walk into a bar. No one reacts.

Ipsita Srinivas 1K

Random Person: Why do you react violently when we put you in H20?
Chemistry Cat: Because my race contains iron, lithium and neon = FeLiNe origins.

Ipsita Srinivas 1K

Q: How did oxygen's date with potassium go?
A: OK

Ipsita Srinivas 1K

Post Midterm Trauma

Ipsita Srinivas 1K

Electrical energy, or here, current flow is caused by the motion of electrons. The potential is determined by the electron difference.

Ipsita Srinivas 1K

The half redox reactions are related to the cell voltage in terms of the net loss and gain of electrons at the ends of the cell - in an electrochemical cell, the electrodes have the 'potential' to gain electrons (reduction potential); the difference in this potential determines which one will be an ...

Ipsita Srinivas 1K

I believe the table they're actually referring to is table 5G.2 which has the equilibrium constant for the reaction at 298K.

Ipsita Srinivas 1K

What do you do with a dead chemist? Barium.

Ipsita Srinivas 1K

What did the thermometer say to the graduated cylinder?
"You may have graduated but I've got many degrees."

Ipsita Srinivas 1K

What do you call a tooth in a glass of water? A one molar solution.

Ipsita Srinivas 1K

If Iron Man and Silver Surfer teamed up, they'd be alloys.

Ipsita Srinivas 1K

Old chemists never die, they just stop reacting.

Ipsita Srinivas 1K

A proton and a neutron were walking down the street. The proton says, "Stop, I dropped an electron. Help me look for it." The neutron asks, "Are you sure?" The proton replies, "Yes, I'm positive."

Ipsita Srinivas 1K

My logic is that because both the backward and forward reactions are occurring at the same rate, there isn't really a direction or preference for the system. For irreversible reactions, there is a clear energy flow and even a small imbalance in pressure or temperature conditions isn't going to affec...

Ipsita Srinivas 1K

Okay, the temperature bit super weird because the actual textbook (not the solutions manual) has all the odd-numbered answers and it's only given a temperature change for part b = 373 K. I think the 5.025 g is the moles of Kr given converted to grams, over the molar mass of Kr, which is approximatel...

Ipsita Srinivas 1K

You can use either? Assuming that no heat is lost to the surroundings, the q value should be same whether you calculate heat gained by the calorimeter or heat lost by the system; it really depends on whichever is more convenient for you, and the data given. But you cannot use the heat capacities int...

Ipsita Srinivas 1K

Yeah, but even if q is zero for an adiabatic process, delta U will still be = q + w. If you want an equation which states that delta U = (only) q, it is irrelevant what the q value actually is; the w value has to be zero for the statement to be true. Here, because we know it is an adiabatic process,...

Ipsita Srinivas 1K

A reversible process is a process where even a small change can cause either work to be done on the system, or by it. In the examples we've learnt, the reversible process is the expansion of a gas under constant temperature, but changing pressure. The external pressure applied on the system is alway...

Ipsita Srinivas 1K

Because we all need radioactive decay in our lives

Ipsita Srinivas 1K

A good ol' cartoon

Ipsita Srinivas 1K

I know this isn't a satisfactory answer, but the textbook might just be wrong? It seems weird to me that the work done is approximately 10 times more than the internal energy change! (982 J vs 9000 J)

Ipsita Srinivas 1K

Does anyone know if we'll be given a periodic table or are we supposed to know some common mass values?? I'm assuming we will be expected to know molar conversions and stuff like that

Ipsita Srinivas 1K

But what about the homework questions from 6E (1 and 3)?? Those dealt with polyprotic acids. If someone could explain them to me, that'd be really helpful!

Ipsita Srinivas 1K

I'm not sure but I'm guessing that's true? I am assuming that the solute is causing dissociation of H₂O and I'm thinking since there is a reduction in solute moles for a given volume of solution, there will also be less dissociation of water into [H₃O⁺] and [OH^-].

Ipsita Srinivas 1K

Which section of chapter 6 are you referring to (assuming you are talking about a chapter 6 question)? There are three/four sections ( eg. 6A, 6D)!

Ipsita Srinivas 1K

Adding an inert gas to a system in equilibrium at constant volume doesn't effect the equilibrium. However, when adding an inert gas to a system in equilibrium at constant pressure the the total volume will increase. I'm kinda confused here; won't the rate of the reaction change if there is an inert...

Ipsita Srinivas 1K

1.Assume volume of all reactants and products are 0.1 M. (you can take any value!) Then, K c = [H 2 O] 6 [NO] 4 /[O 2 ] 5 [NH 3 ] 4 K c = (0.1) 6 (0.1) 4 /(0.1) 5 (0.1) 4 = 0.1. 2. As pressure is increased by compression i.e volume decreases, we can say that the local concentrations of all the react...

Ipsita Srinivas 1K

Ipsita Srinivas 1K

Elf 1: Why does Santa sound like -
Santa: He He He *squeaky voice af*
Elf 2: Oh, he's ingested some helium

Ipsita Srinivas 1K

Idk if my explanation above makes sense because it's so long, but basically the difference in Gibbs energy (the reaction Gibbs energy) has a standard value at equilibrium (which is zero). If the actual value during reaction is not zero, sorta like Le Chateliers' principle, the reaction will proceed ...

Ipsita Srinivas 1K

I believe the textbook talks about the “reaction Gibbs energy,” which is the difference between the molar free energies of the products and reactants at any stage of the reaction (to quote the txtbk). Here the Gibbs free energy isn't zero, but the change in Gibbs free energy (which is labelled as re...

Ipsita Srinivas 1K

Ok, just to clarify, K_c and K_p are just types of K_eq, and you label the equilibrium constant depending on whether K_eq is calculated using partial pressure or molar conc. ?

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