Search found 36 matches
Search found 36 matches • Page 1 of 1
- Sat Nov 09, 2019 1:06 pm
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: Polar Covalent VS Ionic
- Replies: 11
- Views: 43
Both the ionic and atomic radius trends decrease across a period and increase down a group due to the additions of energy levels. Across a period, the energy level stays the same and protons are being added, increasing the nuclear charge.
- Sat Oct 26, 2019 5:55 pm
- Forum: Ionic & Covalent Bonds
- Topic: lewis structures for diff bonds
- Replies: 5
- Views: 63
Lewis structures are drawn for both covalent and ionic bonds. Ionic structures would have the electrons and brackets of each ion with its charge. Covalent structures can be drawn with lines connecting each other as they share their electrons.
There is less shielding and more protons after the first electron is removed. Therefore, more nuclear charge makes it more difficult for the next electron to be removed and will thus make the ionization energy higher.
As seen in the equation speed of light=(frequency)(wavelength), frequency and wavelength have an inverse relationship. Thus, when the frequency decreases, the wavelength increases.
- Sun Oct 20, 2019 10:33 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Order or orbitals
- Replies: 5
- Views: 35
When writing electronic configurations, the order goes from lowest energy to highest energy, and the 3d orbital has lower energy than 4s, so the 3d goes before the 4th level.
- Mon Oct 14, 2019 2:06 am
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Rydberg equation [ENDORSED]
- Replies: 67
- Views: 846
The Rydberg equation is 1/λ = RZ2(1/n1^2 - 1/n2^2), with R=Rydberg constant and Z=atomic number of the atom. This is used to find the light's wavelength of an electron moving through different energy levels.
- Mon Oct 14, 2019 1:58 am
- Forum: Properties of Light
- Topic: When to use the Planck's Constant?
- Replies: 6
- Views: 30
Planck's constant can be used to find the energy emitted or absorbed at different levels with En = -hR / n^2. This has n= energy level, h=Planck's constant, R=constant value, and E=energy.
- Sun Oct 13, 2019 10:42 pm
- Forum: Photoelectric Effect
- Topic: Photoelectric Effect
- Replies: 3
- Views: 46
The photoelectric has to do with the emission of electrons in reference to the absorption of photons, while the atomic spectra indicate the wavelength to which atoms emit light.
To find the concentration of chloride ions in the solution, you would have to find the moles of 0.50g NaCl and 0.30g KCl then find the sum of those moles. From there, you would divide this sum by 0.100 L to find the concentration of the chloride ions.
- Mon Oct 07, 2019 5:13 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Week 2 Homework Problems [ENDORSED]
- Replies: 67
- Views: 959
There was an email sent out that said homework for Week 2 can cover both review topics and the quantum world. I would prefer to focus more on the review topics as there is a test coming up during discussions.
- Wed Oct 02, 2019 11:42 am
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Homework Problem E.15
- Replies: 4
- Views: 66
For this question, you would have to subtract the mass of (OH)2 from 74.10 g/mol to find the mass of M and see which element has the closest mass to that of M. After figuring out what element M is, add the molar mass of M and S to get the answer.
- Wed Oct 02, 2019 11:39 am
- Forum: Molarity, Solutions, Dilutions
- Topic: Dilution and Molarity Questions
- Replies: 8
- Views: 44
In answering these types of problems, I write down the values that are given to me and think about the formula I can use, which is usually M1xV1=M2xV2. I figure out the desired molarity and volume as well as the initial molarity and volume, then plug those values into the formula.
- Wed Oct 02, 2019 11:36 am
- Forum: Empirical & Molecular Formulas
- Topic: Mass % Composition
- Replies: 7
- Views: 62
You would have to find the mass of the entire molecule as well as the masses of each element. Divide each element's mass by the entire molecule's mass and multiply each by 100% to get the mass percent composition.
- Wed Oct 02, 2019 11:25 am
- Forum: Significant Figures
- Topic: All students read this sig fig post [ENDORSED]
- Replies: 115
- Views: 10258
Evamae Bayudan 1B wrote:Will we be penalized for putting extra significant figures?
I think we will be penalized since adding extra significant figures or removing them will result in an inaccurate response in the context of the question.