CHEMISTRY COMMUNITY

Jillian C 4C

Coordination number is the number of ligands bonded to the central atom. The coordination number of Ba[FeBr4]2 is 4 since there are 4 ligands bonded to the Fe atom.

Jillian C 4C

A chelate is a complex with at least one ligand that forms a ring of atoms with the central metal atom in it.

Jillian C 4C

Coordination compound and complex can be used interchangeably. A coordination compound has a central atom or ion with ions or molecules attached by coordinate covalent bonds.

Jillian C 4C

EDTA binds to metals and removes them from the bloodstream before it can bind to our DNA.

Jillian C 4C

The terms "bent" and "angular" are interchangeable.

Jillian C 4C

All transition metals in the d-block form coordination compounds, but he speaks more about the first row in his lectures.

Jillian C 4C

A chelate complex contains at least one ligand that forms a ring of atoms that includes the central atom.

Jillian C 4C

NH3 can replace the H2O in the coordination compounds. There are a few that can replace the H2Os.

Jillian C 4C

Since Pt attaches to the two Cl atoms then twice to the two (en), this makes six bonds to Pt.

Jillian C 4C

A ligand is a Lewis Base attached to the central atom or central ion in a d-metal complex.

Jillian C 4C

The VSEPR notation for CH2Cl2 is correct because there are four regions of electron density and the VSEPR notation for PCl3 is also correct because there are three atoms bonded with one lone electron pair.

Jillian C 4C

By knowing the central atom as well as how many lone pairs and bonded atoms there are, it can be deduced which shape the molecule is.

Jillian C 4C

A bond angle gets smaller due to lone pairs being stronger in repulsions than bonded atoms. Because the lone electron pairs repel more, there is less space between atoms, causing smaller bond angles.

Jillian C 4C

It is AX3 because there are three oxygen atoms attached to the central atom of nitrogen.

Jillian C 4C

An axial lone pair is at the axis of the molecule while an equatorial lone pair lies at the equator. The lone pair at the equator is more favorable as it has lower energy and is more stable.

Jillian C 4C

The variable a1 represents the charge of the first ion (cation) while a2 is the charge of the second ion (anion).

Jillian C 4C

Both the ionic and atomic radius trends decrease across a period and increase down a group due to the additions of energy levels. Across a period, the energy level stays the same and protons are being added, increasing the nuclear charge.

Jillian C 4C

Wavelength properties cannot be detected if it is less than 10^-15 m. This usually applies to the wavelengths of larger objects.

Jillian C 4C

When a polar molecule and non-polar molecule interact, the electrons are rearranged so as to create partial negative and partial positive charges that cause the induced dipole.

Jillian C 4C

Since covalent bonds only have partial charges, ionic bonds are stronger due to larger differences in electronegativity.

Jillian C 4C

In general, the arrow points to the negative dipole while the other end of the arrow has another line drawn perpendicular so as to make a + sign, indicating the positive dipole.

Jillian C 4C

Ionic compounds usually have charges and include metals with nonmetals, while covalent compounds are mostly nonmetals.

Jillian C 4C

I think you should only solve formal charge when the question asks or if there's resonance and you want to find the most stable structure.

Jillian C 4C

Since the outermost shell of Cu only has one electron in 4s1, then there is only 1 valence electron.

Jillian C 4C

A resonance structure shows a compound with different electron arrangements.

Jillian C 4C

Lewis structures are drawn for both covalent and ionic bonds. Ionic structures would have the electrons and brackets of each ion with its charge. Covalent structures can be drawn with lines connecting each other as they share their electrons.

Jillian C 4C

Boron is more stable with 6 electrons and does not follow the octet rule.

Jillian C 4C

Compounds with resonance involve delocalized electrons, leading to fewer repulsions and more stability.

Jillian C 4C

There is less shielding and more protons after the first electron is removed. Therefore, more nuclear charge makes it more difficult for the next electron to be removed and will thus make the ionization energy higher.

Jillian C 4C

The brackets indicate the closest noble gas's electronic configuration so that the configuration of the given atom does not have to start from 1s.

Jillian C 4C

With a common variable, you can use substitution to make a new equation.

Jillian C 4C

With a common variable, you can use substitution to make a new equation.

Jillian C 4C

The h is Planck's constant, which is 6.626x10^-34 J*s.

Jillian C 4C

If a photon does not have enough energy to eject an electron, the electron stays in the same energy level.

Jillian C 4C

As seen in the equation speed of light=(frequency)(wavelength), frequency and wavelength have an inverse relationship. Thus, when the frequency decreases, the wavelength increases.

Jillian C 4C

When writing electronic configurations, the order goes from lowest energy to highest energy, and the 3d orbital has lower energy than 4s, so the 3d goes before the 4th level.

Jillian C 4C

The equation requires an object that has mass, but light does not have that. Thus, light cannot be used in this equation.

Jillian C 4C

Diffraction causes radiation to bend as it goes through an edge.

Jillian C 4C

The Rydberg equation is 1/λ = RZ2(1/n1^2 - 1/n2^2), with R=Rydberg constant and Z=atomic number of the atom. This is used to find the light's wavelength of an electron moving through different energy levels.

Jillian C 4C

Planck's constant can be used to find the energy emitted or absorbed at different levels with En = -hR / n^2. This has n= energy level, h=Planck's constant, R=constant value, and E=energy.

Jillian C 4C

The photoelectric has to do with the emission of electrons in reference to the absorption of photons, while the atomic spectra indicate the wavelength to which atoms emit light.

Jillian C 4C

Yes, c and M can be used interchangeably because c refers to concentration and M refers to molarity.

Jillian C 4C

In finding the molarity, you would have to convert the volume to Liters in order to solve, because that is the unit of the volume in the formula of molarity.

Jillian C 4C

To find the concentration of chloride ions in the solution, you would have to find the moles of 0.50g NaCl and 0.30g KCl then find the sum of those moles. From there, you would divide this sum by 0.100 L to find the concentration of the chloride ions.

Jillian C 4C

Typically, the theoretical yield is based on grams unless asked otherwise. It is a rare case for the theoretical yield to be in moles or any other unit.

Jillian C 4C

There was an email sent out that said homework for Week 2 can cover both review topics and the quantum world. I would prefer to focus more on the review topics as there is a test coming up during discussions.

Jillian C 4C

For this question, you would have to subtract the mass of (OH)2 from 74.10 g/mol to find the mass of M and see which element has the closest mass to that of M. After figuring out what element M is, add the molar mass of M and S to get the answer.

Jillian C 4C

In answering these types of problems, I write down the values that are given to me and think about the formula I can use, which is usually M1xV1=M2xV2. I figure out the desired molarity and volume as well as the initial molarity and volume, then plug those values into the formula.

Jillian C 4C

You would have to find the mass of the entire molecule as well as the masses of each element. Divide each element's mass by the entire molecule's mass and multiply each by 100% to get the mass percent composition.

Jillian C 4C

Would it also be necessary to write out the formula being used in answering a question?

Jillian C 4C

Evamae Bayudan 1B wrote:Will we be penalized for putting extra significant figures?

I think we will be penalized since adding extra significant figures or removing them will result in an inaccurate response in the context of the question.

Search found 51 matches