CHEMISTRY COMMUNITY

emma brinton_3B

NH3 can be both an acid or a base so its amphiprotic and will depend on the situation.

emma brinton_3B

final grades will be posted by december 22nd at the latest.

emma brinton_3B

sigma bonds are easily breakable while pi bonds are very hard to break.

emma brinton_3B

i think the code comes with a certain amount of months that you bought it for.

emma brinton_3B

cisplatin works in chemotherapy as it has two Cl- atoms on one side and 2 NH3 molecules on the other side. This causes the bent shape and for cisplatin to be bidentate while transplatin would have one Cl and one NH3 on each side causing it be monodentate. The transplatin would have a harder time sta...

emma brinton_3B

no, i believe Cisplatin is all we should need to know for the final as it is the main example he went over in lecture.

emma brinton_3B

for oxides its:
acidic = nonmetal
basic = metal
amphoteric = metalloids or a mix of nonmetals and metals

emma brinton_3B

hydrogen bonding occurs between molecules and it happens with H and F,N, or O

emma brinton_3B

It varies depending on the atom of lone pairs. To be honest i would recommend memorizing the VSEPR formula and the shape. Linear models are AX2, AX2E3, and AX2E4.

emma brinton_3B

Test 2 will be handed back in discussion sections. The sections on tuesday and wednesday already got test two back. If unsure I would recommend asking your TA to see if you can earlier before the final.

emma brinton_3B

Cis is when the atoms are on the same side causing a bend in the structure while for trans the atoms are on different sides making the structure straight.

emma brinton_3B

yes, the final exam is cumulative of the entire quarter.

emma brinton_3B

he sent out an email that for many TAs the week 9 and week 10 homework would both be due week 10

emma brinton_3B

a ligand is polydentate is one that gives up more than 1 e-; however, i believe he wants us to be more specific and say bi-, tri-, and hexadentate.

emma brinton_3B

a bent molecule is AX2E and AX2E2 while linear is AX2, AX2E4, and AX2E3

emma brinton_3B

i think the final is cumulative of everything we have learned this quarter and the format will be similar to that of the midterm

emma brinton_3B

yes it is too late to change from letter grading to pass/no pass and i dont think there is a way to get around that

emma brinton_3B

i think that even if there are not review lectures, there are definitely going to be lots of offered review sessions.

emma brinton_3B

yes, a single bond is only sigma bonds, a double is a sigma and pi bond, and a triple bond is a sigma and 2 pi bonds.

emma brinton_3B

i think we need to draw the lewis structure, name the sigma and pi bonds, the inter and intramolecular forces, VSEPR structure, and bond angles

emma brinton_3B

dipoles are created when the electronegativity btwn 2 atoms is >0.5. These happen between a partial negative and partial positive.

emma brinton_3B

the resonance structure does not matter since double and single bonds are both considered one electron density.

emma brinton_3B

electron geometry is used in order to understand the electrons interactions in a 3D shape. also the molecular geometry vs shape is used to know angles of the bonds

emma brinton_3B

the quantum number L is for angular momentum

emma brinton_3B

i try to tell chemistry jokes but there is no reaction

emma brinton_3B

does this mean the class is on a curve?

emma brinton_3B

no the resonance structures do not need to have the same formal charge for all the atoms. The only thing that must stay the same is the overall charge. the difference in formal charge is what causes one molecule structure to be more stable or favorable than others.

emma brinton_3B

this is because with the addition of more electrons between the pairs, the pull of the two atoms together is stronger and thus shortens the length of the bond.

emma brinton_3B

he said about a week but it could be a little longer as the test was pretty long and a lot of free response work

emma brinton_3B

i dont think so, I think we only need to say that the actual structure is a mixture of the resonance structures and be able to draw the resonance structures.

emma brinton_3B

this is because the actual structure of the molecule is a hybrid of the resonance structures, meaning the bond lengths would be an average of each other.

emma brinton_3B

the trend for electronegativity is that it increasing going right and up periods

emma brinton_3B

the exceptions to the octet rule are H, He, Li , and Be! also if the electron is in the 3rd period or above they can occupy greater than 8 electrons going beyond the octet rule.

emma brinton_3B

yes you add the total uncertainty since it makes it account for both the positive or negative

emma brinton_3B

Hi! i would just recommend copying this chart whenever you come across a question asking for the electron configuration of an element

emma brinton_3B

yesterday during lecture he said that he was still in the process of setting up chem midterm review dates as he could not get them during the day like usual. Most likely the review dates will be later in the evening so they can be in a bigger lecture hall.

emma brinton_3B

i am unsure :/ i was attempting problems too and was a little confused but i know for electron configurations it should be written in the order seen in this picture https://www.google.com/search?q=electron+configuration&source=lnms&tbm=isch&sa=X&ved=0ahUKEwjJ7bCqnazlAhWH9Z4KHfViBOgQ_...

emma brinton_3B

i think that as long as the content is discussed one day of the week you should be able to do homework on it. Like some people have discussion on tuesday so it does not make sense to limit what homework can be done so i think you should be fine doing quantum problems

emma brinton_3B

I agree with everything Rebekah said! To add onto it, sig figs are important when calculating your final answer. For example, if you were multiplying two numbers - 2.0 (2 sig figs) and 554.0 (4 sig figs) - your answer would have as many sig figs as the value with the lowest number of sig figs. The ...

emma brinton_3B

personally for studying i make sure to do the practice homework problems and review my notes if im still confused. if you really dont understand a problem follow along with the solutions manual and try again later. also there are some good videos on youtube which covers some of the topics in a more ...

emma brinton_3B

at the lecture on friday we discussed more about the Quantum numbers with some examples and also discussed electron configuration in terms of 1s,2s,2p,3s,3p,4s,3d,4p,5s

emma brinton_3B

the quantum number ml species the orientation of an orbital in space

emma brinton_3B

use the equation M1V1=M2V2 in order to solve the amount of volume needed to get the same molarity when diluting.

emma brinton_3B

the size of the particle matters when trying to observe or detect the wavelike properties. all matter has wavelike properties but some things like baseballs and cars are too big in order to detect the wavelike properties. the outcome of the De Broglie equation must be greater than x10^-15 to be dete...

emma brinton_3B

Hi! i haven't taken chemistry since sophomore year of high school and i was wondering if anyone could explain sig figs to me?

emma brinton_3B

In what situations would you use Rydberg's equation vs De Broglie's equation?

emma brinton_3B

you can use this equation when you have 3 of these values and need to find the fourth value. for example if you had M1 and M2 and V1 you could use this equation to find V2.

emma brinton_3B

an angstrom is used in order to express wavelengths and is equal to the value of 10^-10 meter. good luck on your exam!

emma brinton_3B

when would we meet for study groups? also can someone maybe make a groupme for the study group?

emma brinton_3B

I'm interested!! i really need the study help

emma brinton_3B

thanks so much for the help! does anyone by chance understand how to solve part B of this problem?? which is asking how many formula units of the compound are present in 5.15 g of epsom salt?

emma brinton_3B

I was attempting to do this problem and saw in the solutions manual that you have to multiply the MgSO4 by 7 H2O to get the formula mass of 246.48 g x mol^-1. Does anyone understand why this step has to be done in order to get the answer?

emma brinton_3B

Avogadro's number, 6.0221 x 10^23, is used in order to calculate the amount of particles within a certain mass of a substance.

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