Search found 14 matches

by Gwen Casillan Dis 1I
Sat Dec 07, 2019 11:38 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Linear VSEPR model
Replies: 21
Views: 294

Re: Linear VSEPR model

So if the central atom has lone pairs in addition to the bods, then the molecular shape will be bent due to the additional repulsion that the lone pairs have on the other atoms/bonded pair electrons.
by Gwen Casillan Dis 1I
Sat Dec 07, 2019 11:34 pm
Forum: Naming
Topic: charges on a compound
Replies: 2
Views: 31

Re: charges on a compound

So you’d find the charge on the cation by calculating the charge of the anion and figuring out what the charge should be on the cation to get the total charge of the ligand. In this case the total charge is 2-, and CN has a -1 charge (and there are 5 CN- anions, adding up to a -5 charge). Therefore,...
by Gwen Casillan Dis 1I
Sat Dec 07, 2019 11:24 pm
Forum: Naming
Topic: bis,tris,tetrakis
Replies: 6
Views: 108

Re: bis,tris,tetrakis

They are prefixes used for naming ligand when the name for a ligand already includes di- (for example, one wouldn’t say di-di-ethylene, but rather bis-diethylene), tri-, or tetra-, and also when a ligand is polydentate (like en/ethylenediamine).
by Gwen Casillan Dis 1I
Sat Dec 07, 2019 11:20 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: bond angles
Replies: 5
Views: 116

Re: bond angles

Bond angles were covered in lecture and can also be found in the textbook. Bond angles are affected by repulsion between electrons, with stronger repulsions between lone pair and lone pair electrons and weaker repulsions between bonded pair and bonded pair electrons.
by Gwen Casillan Dis 1I
Fri Nov 15, 2019 12:25 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Lone Pair Repulsion?
Replies: 5
Views: 42

Re: Lone Pair Repulsion?

Lone pair electrons are further from the positively-charged nucleus of an atom compared to bonding pairs of electrons and are therefore bound with less electrostatic force, causing them to have stronger repulsive forces than bonding pairs of electrons. Lone pairs have a larger range of negativity co...
by Gwen Casillan Dis 1I
Fri Nov 15, 2019 12:00 pm
Forum: Dipole Moments
Topic: 3 Hydrocarbon Example?
Replies: 1
Views: 34

Re: 3 Hydrocarbon Example?

The 3 hydrocarbons at room temperature show that the greater amount of atoms there are, the stronger dispersion forces are, increasing the attractive forces between them, explaining why octadecane (C 18 H 38 ) is closer to a waxy solid than pentane (C 5 H 12 ), which is a mobile fluid, even though t...
by Gwen Casillan Dis 1I
Fri Nov 15, 2019 11:51 am
Forum: Determining Molecular Shape (VSEPR)
Topic: Lewis structure for 2E23 (a)
Replies: 1
Views: 27

Re: Lewis structure for 2E23 (a)

Yes, I believe there should be a double bond, but as VSEPR primarily looks at electron densities and the position of atoms, the lewis structure depicting the single bond between Sb and O allows one to predict the shape by primarily looking at bonded pairs of electrons and lone pairs of electrons.
by Gwen Casillan Dis 1I
Fri Nov 15, 2019 11:33 am
Forum: Determining Molecular Shape (VSEPR)
Topic: Inter-molecular Electron Repulsion
Replies: 6
Views: 45

Re: Inter-molecular Electron Repulsion

The repulsion forces in order of least to most strong are:
bonding-bonding pr < lone-bonding pr < lone-lone pr
by Gwen Casillan Dis 1I
Fri Oct 04, 2019 12:36 pm
Forum: Significant Figures
Topic: Significant Figures
Replies: 6
Views: 93

Re: Significant Figures

It's best to apply significant figures at the end in order to retain as much accuracy as possible. Rounding early on or in the middle of calculations may initially seem convenient and more practical, but the dropping of a few decimal places/numbers can be severely detrimental to the final result, as...
by Gwen Casillan Dis 1I
Fri Oct 04, 2019 12:26 pm
Forum: Limiting Reactant Calculations
Topic: General Limiting Reactant Question
Replies: 4
Views: 53

Re: General Limiting Reactant Question

There was only one reactant for M.3 and therefore, you did not need to find a limiting reactant/there was none. If there is more than one reactant, you would use the given moles/masses and molar masses to determine the limiting reactant and use that information to calculate the theoretical yield.
by Gwen Casillan Dis 1I
Fri Oct 04, 2019 12:18 pm
Forum: Limiting Reactant Calculations
Topic: M5
Replies: 2
Views: 60

Re: M5

Just use the stoichiometric steps you used to calculate the the 12 mols of the ClO2F product to determine the moles of the other product (Br2).
by Gwen Casillan Dis 1I
Fri Oct 04, 2019 11:56 am
Forum: Empirical & Molecular Formulas
Topic: E.11
Replies: 1
Views: 46

Re: E.11

Yes, you would need to consider the different masses of the isotopes because they have different percentages of abundance, both of which you would then use to calculate the mass of the average lithium atom by adding them together: (7.42/100)(9.988 * 10^-24 g) + (92.58/100)(1.165 * 10^-24 g) = the av...
by Gwen Casillan Dis 1I
Fri Oct 04, 2019 11:38 am
Forum: Molarity, Solutions, Dilutions
Topic: Dilution Calculation
Replies: 5
Views: 65

Re: Dilution Calculation

Yes, you could technically leave the volume in mL since the molarity would cancel, but remember to keep in mind that otherwise, it would be wiser to leave it in liters.

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