CHEMISTRY COMMUNITY

claribel charway 1I

No, you need at least 3 atoms to have resonance because the double bond must be switched with one that has a single bond.

claribel charway 1I

I am a bit confused by the grading but it sounds like the whole class is rounding comparative to everyone else's total score out of 500.

claribel charway 1I

With a double bond and one lone pair on each atom, you do not form a full octet because there's only 6 electrons on carbon and oxygen. In order to get full octets and an overall neutral charge you must use the triple bond and a lone pair on each.

claribel charway 1I

How many coordination compound shapes do we need to know?

claribel charway 1I

I am not sure exactly how much naming will be on the final but definitely memorize the worksheet he gave us.

claribel charway 1I

I think all you need to know is hemoglobin, myoglobin and cisplatin.

claribel charway 1I

the most important thing is knowing where sigma and pi bonds are located and their orientation; sigma bonds are end to end while pi bonds are side by side

claribel charway 1I

Personally, I like videos. I would also focus on the major concepts in addition to just doing problems.

claribel charway 1I

He doesn't have anything up yet on the website about review sessions but I'm sure he'll mention it on Monday. There's also the workshops and step up sessions for review.

claribel charway 1I

pH is a measure of acidity, specifically it measures the H+ ions. pOH is a measure of basicity, specifically the OH ions. Their respective values are inverse of each other. For example, ph of 0 is a pOH of 14.

claribel charway 1I

The same thing happened to me as well. I think the best thing to do is to do textbook problems but also attend as many review sessions as possible. From what I heard, the final might be more conceptually focused so understanding certain principles is imperative.

claribel charway 1I

I get test anxiety as well. I recommend not studying at all the day of the final. As terrifying as it sounds it will help you heeled when it comes time for the test. Your brain won’t be overloaded with chem info and it personally helps me feel confident. I try to listen to the same music that I stud...

claribel charway 1I

the only lone pairs that matter are the ones on the central atom, for example it makes the difference between linear and bent

claribel charway 1I

Writing just E is fine.

claribel charway 1I

It depends where the two atoms are placed. If they same atoms aren’t opposite of each other their dipole moments won’t cancel out thereby making it polar.

claribel charway 1I

For part A in question 13 of 2E, I3- has a bond angle of 180 degrees even though it has 3 lone pairs on it. Why isn't its bond angle less than 180 degrees?

claribel charway 1I

Double and Triple bonds are accounted for as single bonds. So regardless of the number of bonds, it only counts as one region of electron density.

claribel charway 1I

I would love to join! I really need to study before this test.

claribel charway 1I

Lone pairs have the greatest repulsion because they are closer together. Lone bonding is the next strongest because it is the next closest. Bonding-bonding pairs are the weakest because the electrons are more spread apart since each atom takes an electron within its cloud.

claribel charway 1I

What is the difference or what distinguishes a coordinate covalent bond from a regular bond? In a coordinate covalent bond both electrons come from the same atom while in a regular bond each atom provides an electron. Oh, got it! The only way you would know the type of bond (coordinate covalent vs ...

claribel charway 1I

Yes, the more electronegative fluorine atom pulls more of the electron cloud decreasing the repulsion between the C-H bond. But I think it increases the F-C-H bond angle because the fluorine is pulled out "further" so the H-C-H bond angle will decrease as a result of the pull. For the test...

claribel charway 1I

Dipole-dipole moments will exist for b,c, and d. CH4 and CCl4 are completely uniform since the atoms around the central atom are the same. Because of this there is not dipole pull because there’s an even amount of electronegativity around carbon. In the case of CH3Cl, CH2Cl2, and CHCl3 there’s diffe...

claribel charway 1I

I believe so.

claribel charway 1I

Everything from 2D on so chemical forces/bonds and structures (Lewis and vsepr)so basically from the midterm to the lecture today

claribel charway 1I

Ruby Richter 4G wrote:What is the difference or what distinguishes a coordinate covalent bond from a regular bond?

In a coordinate covalent bond both electrons come from the same atom while in a regular bond each atom provides an electron.

claribel charway 1I

Water is an example of a coordinate covalent bond, oxygen provides both electrons to the hydrogens.

claribel charway 1I

If the electronegativity difference is greater than 2 then it is polar. It could be either ionic polar or covalent polar.

claribel charway 1I

Dipole moments are calculated by multiplying the charge by the distance between the atoms.

claribel charway 1I

It bonds to highly electronegative elements while being not as negative. As a result, there is an attraction between a very weak element and a very strong one that tremendously pulls on hydrogen’s electron. Hydrogen can be considered the weakest element because it only had one electron to exert forc...

claribel charway 1I

Resonance structures are the different variations of the double bond. A resonance hybrid is the blend of all three resonance structures. It is how the molecules are represented in real life because it evenly distributes the double bond. This is known as the delocalization of electrons.

claribel charway 1I

There is still an electronegative difference between Be and Br but it isn't as great as the one between Ba and Br. I believe that's why you would regard BaBr2 as primarily ionic

claribel charway 1I

Yes, Sb's 4d orbital was full and would then not be considered as valence electrons

claribel charway 1I

It has to be from period 3 onward

claribel charway 1I

Br has an expanded octet

claribel charway 1I

Particles use de Broglie's equation (lambda=h/mv) because they have mass. Light uses E=hc/lambda because the equation features the speed of light and does not include mass since light does not have measurable mass.

claribel charway 1I

I believe it will have everything up to chemical bonds on there.

claribel charway 1I

technically E=hf=hc/lambda calculates total energy of a photon

claribel charway 1I

A substance has resonance when the molecule requires a double bond that can be shifted to another single bond. As long as there's at least three elements and a required double bond, a resonance structure can be made.

claribel charway 1I

Although 4s is filled first, you write 3D first because it still occupies a slighter lower energy level.

claribel charway 1I

the 5s1 goes last

claribel charway 1I

The tutoring offered on the website are all group sessions. Maybe you could contact your TA for one-on-one sessions but I would say that showing up to their office hours works best because you can ask them all the questions you have.

claribel charway 1I

As far as I know it is just something you memorize.

claribel charway 1I

The uncertainty is the range that the velocity would fall into. So in this case, it would fall between 0 and 10 m/s.

claribel charway 1I

The midterm is November 6.

claribel charway 1I

Photons are essentially packets of energy. The photoelectric effect basically states that a certain amount of energy is required to emit an electron from a metal (work function). If the photon's energy equals or exceeds the work function then the photon will transfer it's energy to the electron so t...

claribel charway 1I

He hasn't said how he wants them expressed. I would go with scientific notation with the base units (g, mole, L). Just always make sure your sig figs are correct.

claribel charway 1I

I believe so. I usually do the same thing but on the test I'm going to show all my unrounded answers just in case. The most important thing is that you're not rounding before the final answer.

claribel charway 1I

Yes millimol means 10^-3 moles. When converting from moles to grams you multiply the moles by the molar mass.
Moles * grams/mole = grams

claribel charway 1I

I believe it's just extra information that isn't necessary to finding the solution to the problem.

claribel charway 1I

When you compare the moles of the reactants check to see which compound is in excess. For example is A:B is 1:2 in the balanced equation. If the moles calculated for A is 1 and the moles calculated for B is 3 then B is in excess meaning that A is the limiting reactant. A doesn't have enough of itsel...

claribel charway 1I

The 1.0 comes form the hydrogen in HA and the 17.0 comes from the OH (16 g + 1 g) in XOH.

claribel charway 1I

I'm not 100% sure but believe it would be the first discussion of next week since Week 2 homework needs to be turned in during week 2.

claribel charway 1I

First you need to subtract the mass of (OH)x2 from the molar mass of the metal. When subtracting you find out the unknown metal is calcium. 74.10 - 34.02 = 40.08 Next, add the mass of Sulfur to the remaining amount. This is adding the masses of Calcium and Sulfur to create calcium sulfide. 40.08 + 3...

claribel charway 1I

Phosphorus has 5 valence electrons. The numbers in parenthesis refer to the oxidation states. Phosphorus V is when the element is in the +5 oxidation state meaning that it has removed all its valence electrons. Phosphorus iii means 2 electrons have been removed leaving a +3 charge.

claribel charway 1I

Knowing the molarity can also help you find the moles of a compound given that you know the volume and vice versa.

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