Search found 51 matches
- Sun Dec 08, 2019 10:56 pm
- Forum: General Science Questions
- Topic: Aqueous
- Replies: 3
- Views: 504
Re: Aqueous
Aqueous molecules disassociate in water. Also, you should only use the concentrations of aqueous compounds when calculating the Ka or Kb.
- Sun Dec 08, 2019 10:55 pm
- Forum: Amphoteric Compounds
- Topic: As2O3
- Replies: 3
- Views: 443
Re: As2O3
It's a good rule of thumb to know that elements near the metalloids will form amphoteric salts. For example, aluminum oxide will form an amphoteric salt.
- Sun Dec 08, 2019 10:53 pm
- Forum: Biological Examples
- Topic: Biological Function
- Replies: 2
- Views: 287
Re: Biological Function
Cis platinum chelates a nitrogenous base and blocks DNA replication.
- Sun Dec 08, 2019 10:52 pm
- Forum: General Science Questions
- Topic: Final : Question about Neutral or Ionized acid
- Replies: 3
- Views: 504
Re: Final : Question about Neutral or Ionized acid
Another way to think about it is that in the pH of 2, there are a lot of H+ ions. In equilibrium reactions, which is what happens when weak acids disassociate, an equilibrium must be maintained. Since there are a lot of H+ ions, this would cause the reaction to favor the opposite end of the acid dis...
- Sat Dec 07, 2019 2:12 pm
- Forum: Identifying Acidic & Basic Salts
- Topic: 6.21
- Replies: 1
- Views: 213
6.21
In 6.21 c, it asks to mark the amphiprotic areas of Thymine. According to the solutions manual, the Nitrogen atoms are amphiprotic. Why is that? Can someone explain this to me?
- Sun Dec 01, 2019 9:27 pm
- Forum: Octet Exceptions
- Topic: Why can't Aluminum have an expanded octet?
- Replies: 5
- Views: 3362
Re: Why can't Aluminum have an expanded octet?
As everyone else has said, Aluminum can have less than the octet rule. Boron is another important element that can have less than the octet rule.
- Sun Dec 01, 2019 9:25 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: AXE formula
- Replies: 32
- Views: 12263
Re: AXE formula
Yes, the AXE formula is part of VSEPR Theory, which is used to determine a molecule's shape. Just remember that you can't use hybridization to determine a molecule's shape!
- Sun Dec 01, 2019 9:23 pm
- Forum: Hybridization
- Topic: Hybridization of Carbon and Nitrogen
- Replies: 2
- Views: 258
Re: Hybridization of Carbon and Nitrogen
For CH20, carbon will have a sp2 hybridization because it has a single bond for each H atom and a double bond with the O atom. Carbon will only have 3 electron densities, which correlates with sp2.
- Sun Dec 01, 2019 9:21 pm
- Forum: Hybridization
- Topic: 2F. 15 General Pattern?
- Replies: 2
- Views: 248
Re: 2F. 15 General Pattern?
I agree. I believe that s character is referring to the role of the s orbital in the hybridization. An sp2 hybridized orbital would have more s character than an sp3 hybridized orbital. And, as we know from molecular structures, a structure with sp3 hybridized orbitals (like a tetrahedral molecule) ...
- Sun Dec 01, 2019 9:15 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Homework question 9C.7
- Replies: 2
- Views: 333
Re: Homework question 9C.7
The answer would be b. The two NH2 molecules are close to each other, so a metal atom can be drawn between them, forming a bidentate ligand, which would be a chelate. Here is an image address to what I mean: https://ars.els-cdn.com/content/image/3 ... 186880.jpg
- Sun Nov 24, 2019 9:01 pm
- Forum: Hybridization
- Topic: How to Determine Hybridization
- Replies: 2
- Views: 349
Re: How to Determine Hybridization
Molecules have hybridizations to form enough bonds. For example, CH4 has hybridization because normally C only has 2 unpaired electrons. With an sp3 hybrdization, C has 4 unpaired electrons that can bond with 4 H's. On the other hand, hybridization can also ensure the stability of a molecule. For ex...
- Mon Nov 18, 2019 11:57 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: seesaw
- Replies: 5
- Views: 461
Re: seesaw
I asked my TA, and he said that the angles will be less than 120 and 90.
- Mon Nov 18, 2019 11:20 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: polarity
- Replies: 5
- Views: 479
Re: polarity
I was really confused about this too, but I highly recommend that you watch this Youtube video to contextualize the answer: https://www.youtube.com/watch?v=As-hcYY8Yaw Start at the the 5 minute mark. To give you a written answer, CH2Cl2 is polar because of the bond angles. Remember that a tetrahedra...
- Mon Nov 18, 2019 11:11 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 2E29
- Replies: 1
- Views: 163
Re: 2E29
For the first part of the question, think about symmetry. If the two chlorine bonds are right across from each other, their dipole moments will cancel each other out. Therefore, Form 3 is nonpolar. Form 1 and Form 2 don't have the chlorine atoms straight across each other, so their dipole moments do...
- Sun Nov 17, 2019 9:34 pm
- Forum: Hybridization
- Topic: 2F.5
- Replies: 1
- Views: 163
Re: 2F.5
I'm not sure why the answer is like that. But there is no way that Boron could have a lone pair. The hybridization should just be sp3.
- Sun Nov 17, 2019 9:29 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sigma vs pi bonds
- Replies: 2
- Views: 216
Re: Sigma vs pi bonds
I don't think sigma and pi bonds really affect VSEPR. VSEPR involves where regions where there are valence electrons. If there are only 2 areas where valence electrons can be found, the molecule is linear. If there are only 3 areas where valence electrons can be found, the molecule is trigonal plana...
- Sun Nov 17, 2019 9:26 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Dispersion Forces
- Replies: 3
- Views: 221
Re: Dispersion Forces
Dispersion forces are stronger for bigger molecules. Therefore, a molecule with atoms of bigger atomic radii will have stronger dispersion forces.
- Sun Nov 17, 2019 9:25 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Stronger molecular force?
- Replies: 2
- Views: 224
Re: Stronger molecular force?
I think you are right. Ion-dipole has a larger difference in charges than H bonding.
- Sun Nov 17, 2019 9:20 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: 2E. 27
- Replies: 3
- Views: 254
Re: 2E. 27
If the molecule is asymmetrical, it will be polar. Therefore, for example, CHCl3 would be polar because the H makes it asymmetrical.
- Sun Nov 10, 2019 11:17 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Lattice Energy
- Replies: 2
- Views: 200
Re: Lattice Energy
If the solid has strong intermolecular forces, the lattice energy will increase. The lattice energy is basically the amount of energy requires to break those connections between molecules. As a result, strong intermolecular forces increase lattice energy.
- Sun Nov 10, 2019 11:12 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: dipole dipole of H2SeO4
- Replies: 1
- Views: 189
Re: dipole dipole of H2SeO4
Se is in the middle of two OH groups and two double bonded O atoms. Each bond has dipole moment since there is a substantial difference in electronegativity between Se and each O it is bonded to. If you are wondering why H2SeO4 might be a polar molecule, I saw a post that has a similar topic to that...
- Sun Nov 10, 2019 11:06 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Hydrocarbons at room temperature
- Replies: 2
- Views: 228
Re: Hydrocarbons at room temperature
The bigger a hydrocarbon, the stronger the intermolecular bonds are. In dispersion forces, more electrons means larger dispersion forces. That explains why bigger molecules have stronger dispersion forces.
- Sun Nov 10, 2019 11:02 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: 3F. 3
- Replies: 2
- Views: 251
Re: 3F. 3
Dipole-dipole interactions occur between polar molecules. For the answer, choose the molecules that have an overall polarity. The asymmetrical molecules will be polar.
- Sun Nov 10, 2019 10:59 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: forces and boiling points
- Replies: 6
- Views: 351
Re: forces and boiling points
When there are more electrons, London (Dipole-dipole/Dispersion) Forces are stronger. CCl4 has more electrons than CH4, so it has stronger intermolecular forces.
- Sun Nov 03, 2019 6:54 pm
- Forum: Octet Exceptions
- Topic: 2C.5
- Replies: 2
- Views: 131
Re: 2C.5
To simplify radicals, just look at the total valence electrons of the molecule. If the total is even, the molecule is not radical. If the total is odd, the molecule is radical.
- Sun Nov 03, 2019 6:52 pm
- Forum: Lewis Structures
- Topic: Central Atom
- Replies: 3
- Views: 200
Re: Central Atom
The central atom is usually the atom with the least ionization energy. Of course if the molecule has hydrogen, hydrogen can't be the central atom. For the Lewis Structure, it is important for the central atom to have 0 formal charge.
- Sun Nov 03, 2019 6:51 pm
- Forum: Lewis Structures
- Topic: Radicals
- Replies: 5
- Views: 217
Re: Radicals
For most molecules, the atom that gets the extra electron is the one that that already has other lone pairs. Of course, for problem 5a from Focus 2C, there is a molecule that is ClO. The extra electron is put onto Cl. I think it is likely because Cl is more electronegative. But also, it makes Cl's f...
- Sun Nov 03, 2019 6:43 pm
- Forum: Lewis Structures
- Topic: lone pairs versus double bonds
- Replies: 2
- Views: 320
Re: lone pairs versus double bonds
Usually lone pairs are used to satisfy the total amount of valence electrons in the molecule. Otherwise, if you are dealing with a molecule with an atom from period 3 (or beyond) as the central atom (atoms that are exceptions to the octet rule), having lone pairs might bring their formal charges to ...
- Sun Nov 03, 2019 6:39 pm
- Forum: Ionic & Covalent Bonds
- Topic: Ionic vs Covalent
- Replies: 14
- Views: 895
Re: Ionic vs Covalent
The difference is their electronegativity. If the electronegativity between the two atoms is more than 2.5, the bond is ionic. If the electronegativity between the two atoms is less than 1.5, the bond is covalent. Between 1.5 and 2.5, the bond has ionic and covalent components.
- Sun Oct 27, 2019 1:49 pm
- Forum: Octet Exceptions
- Topic: Reasoning behind the exceptions
- Replies: 3
- Views: 160
Re: Reasoning behind the exceptions
Actually, Aluminum usually donates its valence electrons to have an octet (Al+3).
- Sun Oct 27, 2019 1:47 pm
- Forum: Resonance Structures
- Topic: formal charge
- Replies: 3
- Views: 368
Re: formal charge
Having a 0 formal charge is the most stable, so the Sulfur has a 0 formal charge. Of course, this causes two of the oxygen atoms bonded to sulfur to each have a formal charge of -1. This is fine because oxygen is already more electronegative than sulfur, so it attracts the electrons more. Even thoug...
- Sun Oct 27, 2019 1:44 pm
- Forum: Resonance Structures
- Topic: Exceptions For Drawing Structures
- Replies: 1
- Views: 104
Re: Exceptions For Drawing Structures
Some exceptions to remember:
1. H, He, Li, and Be are exceptions to the Octet rule. That means they don't need 8 valence electrons.
2. P, S, and Cl can have more than 8 valence electrons. For example, in phosphorous pentachloride, phosphorous has 10 electrons.
1. H, He, Li, and Be are exceptions to the Octet rule. That means they don't need 8 valence electrons.
2. P, S, and Cl can have more than 8 valence electrons. For example, in phosphorous pentachloride, phosphorous has 10 electrons.
- Sun Oct 27, 2019 1:38 pm
- Forum: Lewis Structures
- Topic: bond lengths
- Replies: 2
- Views: 80
Re: bond lengths
Also, double bonds are stronger than single bonds, so they require more energy to break.
- Sun Oct 27, 2019 1:38 pm
- Forum: Lewis Structures
- Topic: Bond Lengths
- Replies: 2
- Views: 105
Re: Bond Lengths
This rule applies to all bonds between all atoms. Generally, single bonds are longer than double bonds.
- Sun Oct 20, 2019 4:52 pm
- Forum: Student Social/Study Group
- Topic: Study Group Fall 2019
- Replies: 32
- Views: 2842
Re: Study Group Fall 2019
Hi everybody, I made a groupme if anyone is interested! I'll probably post it on facebook, too.
https://app.groupme.com/join_group/55046813/XcQgQkkM
https://app.groupme.com/join_group/55046813/XcQgQkkM
- Sun Oct 20, 2019 4:48 pm
- Forum: Properties of Electrons
- Topic: Hund's Rule
- Replies: 5
- Views: 230
Re: Hund's Rule
I like to think Hund's Rule as a school bus. When you enter a bus, you would rather take the empty seat than sit next to someone else. This can apply to electrons in each subshell of an orbital. The subshells need to each have 1 electron before there can be two electron in each subshell.
- Sun Oct 20, 2019 4:44 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Uncertainty value
- Replies: 4
- Views: 125
Re: Uncertainty value
Actually, I saw on a recent post that if it is + - n, the uncertainty is 2n. Therefore, the uncertainty of this should be 10 mm, I think.
- Sun Oct 20, 2019 4:41 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Purpose of the Equation
- Replies: 9
- Views: 383
Re: Purpose of the Equation
Yes! The uncertainty of momentum and the uncertainty of position are indirectly proportional. If you change the equation, you will see that:
p >= h/(4pi *x)
You can see that p is proportional to 1/x. So if p goes up, then x needs to go down and vice versa.
p >= h/(4pi *x)
You can see that p is proportional to 1/x. So if p goes up, then x needs to go down and vice versa.
- Sun Oct 20, 2019 4:37 pm
- Forum: *Shrodinger Equation
- Topic: Hamiltonian
- Replies: 6
- Views: 365
Re: Hamiltonian
The Hamiltonian is the double derivative or the wave function (psi). The double derivative of the wave function is the same as the energy of the electron.
- Sun Oct 20, 2019 4:35 pm
- Forum: *Shrodinger Equation
- Topic: Shrodinger Equation
- Replies: 3
- Views: 175
Re: Shrodinger Equation
Schrodinger's equation is used to describes the probable positions of an electron in an atom. The equation involved sin and cos, so the graph is in waves. This connects to how electrons have wavelike properties.
- Sat Oct 12, 2019 8:44 pm
- Forum: DeBroglie Equation
- Topic: Resonance
- Replies: 2
- Views: 102
Re: Resonance
I'm not exactly sure what resonance of momentum is. However, (fun fact) there is this process called surface plasmon resonance for metal. Basically, when light hits a metal, like gold, the atoms' electron clouds absorb the light and begin moving around. Then, these electron clouds reflect leftover l...
- Sat Oct 12, 2019 8:36 pm
- Forum: DeBroglie Equation
- Topic: Circular standing waves
- Replies: 4
- Views: 185
Re: Circular standing waves
The circular standing wave model shows possible wave movements of an electron around the nucleus. The model shows multiple waves to show that electrons oscillate and have wavelike properties.
- Sat Oct 12, 2019 8:33 pm
- Forum: DeBroglie Equation
- Topic: Knowing Which Equation to Use
- Replies: 4
- Views: 256
Re: Knowing Which Equation to Use
At the moment, I'm distinguishing them based off of electromagnetic radiation and the quantum mechanics of electrons. For example, De Brogile's equation can only be applied to electrons, NOT light.
- Sat Oct 12, 2019 8:30 pm
- Forum: Properties of Electrons
- Topic: wavelike properties of an electron
- Replies: 4
- Views: 141
Re: wavelike properties of an electron
When waves hit something, they bend. This process if called diffraction. For example, if light is shone through a small slit, the waves bend as they interact with each other through that tiny opening. When electrons pass through a crystal, their movement patterns are similar to the patterns of diffr...
- Sat Oct 12, 2019 8:26 pm
- Forum: Properties of Light
- Topic: Equations We’ve Learned So Far
- Replies: 11
- Views: 699
Re: Equations We’ve Learned So Far
It's important to distinguish between equations that are relevant to light (EM radiation) and quantum movement of electrons. For light specifically, you should pay attention to: These two equations are applied to light in the theory that light is a wave: c = λv = 3*10^8 (speed of light = wavelength ...
- Sat Oct 12, 2019 8:25 pm
- Forum: Properties of Light
- Topic: Equations We’ve Learned So Far
- Replies: 11
- Views: 699
Re: Equations We’ve Learned So Far
It's important to distinguish between equations that are relevant to light (EM radiation) and quantum movement of electrons. For light specifically, you should pay attention to: These two equations are applied to light in the theory that light is a wave: c = λv = 3*10^8 (speed of light = wavelength ...
- Tue Oct 01, 2019 11:42 pm
- Forum: Empirical & Molecular Formulas
- Topic: Empirical and Molecular Formulas [ENDORSED]
- Replies: 5
- Views: 404
Re: Empirical and Molecular Formulas [ENDORSED]
Also, a really handy trick with empirical and molecular formulas, is that if you're looking for the molecular formula of a compound, and you know the compound's molar mass (along with the empirical formula's molar mass), you can divide the compound's molar mass by the empirical formula's molar mass....
- Tue Oct 01, 2019 11:33 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Post- Assessment Problem 16
- Replies: 2
- Views: 178
Re: Post- Assessment Problem 16
To find molarity, you have to divide the mols of solute by the volume of the solution. Convert KCL to mols. Then, convert the 125 mL to L. Finally, divide the mols of KCL by the volume in L to get the answer.
- Tue Oct 01, 2019 11:30 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Solving for Volume G.5 a)
- Replies: 8
- Views: 588
Re: Solving for Volume G.5 a)
Sodium Carbonate has two sodium ions, so the ratio needs to be taken into account. When the problem asks you to find the volume for 2.15 mM of Na+, you need to convert 2.15 mM of Na+ into the amount of moles for sodium carbonate. To do that, you would need to show how 1 mol of sodium carbonate has 2...
- Tue Oct 01, 2019 11:03 pm
- Forum: Student Social/Study Group
- Topic: Study Group Fall 2019
- Replies: 32
- Views: 2842
Study Group Fall 2019
I don't know if anyone has done this yet, but I would really like to start a study group! We can reserve study rooms in some of the halls on the hill. Reply if you're interested!
- Tue Oct 01, 2019 10:56 pm
- Forum: General Science Questions
- Topic: Order of Elements When Writing Out a Compound
- Replies: 8
- Views: 560
Re: Order of Elements When Writing Out a Compound
I actually asked my TA, and he said that for now, we don't need to know how to write chemical formulas correctly. We also don't need to know how to write out chemical formulas from just the compound's name for our first test! Apparently, we'll be learning the basics of chemical formulas and nomencla...