CHEMISTRY COMMUNITY

Julianna Laurentano 4G

Yes, but more specifically I would know what parts of their structures give them these characteristics and how you could identify other bidentates, hexadentates, etc.

Julianna Laurentano 4G

Diffraction patterns of light show that light can act like a wave, as well as constructive and destructive interference patterns.

Julianna Laurentano 4G

The heme complex consists of the central Fe atom and four CN groups; when the heme complex binds to a protein it forms hemoglobin, which helps in oxygen delivery throughout the body. Myoglobin is made up of several hemoglobin structures.

Julianna Laurentano 4G

Denticity describes the number of potential atoms that can bond to the central metal atom on the ligand. Polydentates are capable of forming chelating structures.

Julianna Laurentano 4G

It might be, but it's good to include both to demonstrate that there are other potential atoms involved besides H, N, O, F, etc.

Julianna Laurentano 4G

This is because strong acids dissociate completely; HCl, for example, completely dissociates into H+ and Cl-, so a weak conjugate base would have no impact on this.

Julianna Laurentano 4G

I would definitely familiarize yourself with a list of both the common weak and strong acids before the final. However, a good rule to test is that strong acids can completely dissociate in a solution, while weak acids can only partly dissociate. For example, HCl, a strong acid, can fully dissociate...

Julianna Laurentano 4G

An amphoteric compound is one that can both accept and donate electrons when need be, so I would test the compound to see if that is the case. For example, H2O can accept an electron to become H3O+ or it can donate an electron to become OH- depending on the problem. Additionally, amphoteric molecule...

Julianna Laurentano 4G

The tri is referring to the number of ammonia molecules; since there are only three, the name remains triaminetriaquacobalt.

Julianna Laurentano 4G

Definitely refer to the resource source the previous commenter posted!
To summarize it quickly, coordination compounds are those molecules that consist of one or multiple metal center atoms bound to ligands.

Julianna Laurentano 4G

I would assume that we should know the structures of the examples Dr. Lavelle covered in depth in class, since those relate strongly to the key concepts covered.

Julianna Laurentano 4G

The formula relates the energy of a photon is to its frequency; the energy is directly proportional to the frequency. Therefore, as the frequency of a particle increases, so does its energy.

Julianna Laurentano 4G

Out of the bonds, hydrogen is the strongest, and London (or dipole-induced dipole) forces are the weakest. When the hydrogen atom binds to an extremely electronegative atom (N, O, or F), it's only electron is pulled in very close, reducing the atomic radius and therefore forming a very stable bond.

Julianna Laurentano 4G

In an organometallic compound, there is at least one bond between a carbon (that's part of an organic molecule) and a metal.

Julianna Laurentano 4G

Coordination compounds possess a chemical structure in which the central atom, a metal, has nonmetal atoms bonded to it by chemical bonds. These nonmetal atoms donate electrons to the metal. Coordination compounds are produced by Lewis acid-base reactions.

Julianna Laurentano 4G

Yes, the final will be on all material covered from weeks 1-10!

Julianna Laurentano 4G

I don't believe hybridization will be on the test. Dr. Lavelle said on Friday there was one more slide from tomorrow's lecture that will be on the test and I believe that it's related to sigma and pi bonds.

Julianna Laurentano 4G

I would know the corresponding angle measurements for all the examples Dr. Lavelle went over during the past two lectures. I would also know what conditions make the angles slightly less than the usual measure.

Julianna Laurentano 4G

A linear molecule can have no lone pairs or it can have lone pairs. Since the angle remains at 180 degrees, these lone pairs must be oriented in such a way that they cancel out, permitting the bond angle to remain at 180. This often found on central atoms possessing three or four lone pairs of elect...

Julianna Laurentano 4G

The VSEPR model takes the number of electron density regions into consideration, and since single, double, and triple bonds are all considered just one region of electron density, they are treated equally. Because of this, the resonance structure used to determine the VSEPR model does not matter.

Julianna Laurentano 4G

When there is a lone pair on the central atom, the bond angle is slightly less. This is because the lone pair of electrons on the central atom forces the bonding electrons closer together, therefore distorting the angle.

Julianna Laurentano 4G

The fact that the S atom has three bonds and a lone pair slightly affects the bond angles; instead of being exactly 109.5 degrees, we can expect the angles to be slightly less than 109.5 degrees. This is because the lone pair of electrons repels the shared pairs, causing a slight displacement in the...

Julianna Laurentano 4G

Polarizability increases down a column because the atomic radius increases down a column, and large molecules are more polarizable. Polarizability also decreases across a period because there is an increase in the effective nuclear charge across a period, and cations are smaller than neutral atoms. ...

Julianna Laurentano 4G

I believe that if you have discussion on Monday-Wednesday you will still have it, as my TA mentioned during our Thursday discussion that the reason why we met during week zero (in which classes were only on Thursday and Friday) was to make up for not meeting during the week of Thanksgiving. However,...

Julianna Laurentano 4G

Dipoles do not occur between atoms of the same element; dipoles are due to an uneven distribution of electrons, so one atom must possess a different distribution than the other. Dipoles occur between two different nonmetals that are unevenly sharing electrons.

Julianna Laurentano 4G

According to Lewis, acids accept pairs of electrons while bases donate them. Using H2O as an example, Lewis said that the H+ is the atom that actively accepts electrons from OH-, forming H2O.

Julianna Laurentano 4G

In a regular covalent bond, the two nuclei of the two atoms attract one another. In a coordinate covalent bond, one of the atoms donates both electrons, making it a bit weaker than a regular covalent bond.

Julianna Laurentano 4G

I believe that if we are given a more uncommon molecular formula like this, Dr. Lavelle will provide us with chemical formula as well. If not, I'm sure you could ask a TA for clarification.

Julianna Laurentano 4G

Homework problems are always related to the material most recently covered in class, so I would assume completing any problems from Chemical Bonds is okay.

Julianna Laurentano 4G

It stands for megaelectronvolt, so I would convert it to eV (1 meV= 1000000ev) and then convert it to Joules.

Julianna Laurentano 4G

The question is asking for the energy emitted by the electron, so I would use the equations c=wavelength * frequency and E=hv to calculate the correct energy. It is not asking for the kinetic energy or the work function, so you do not need to use 1/2mv^2 in order to solve the problem.

Julianna Laurentano 4G

I believe in lecture he said we will be doing review problems for the midterm. If we cover any new material it won't be on the midterm.

Julianna Laurentano 4G

When we compare to the neutral atom, is it easy to determine if there was a loss or gain in electrons due to the positive or negative charge of the given ion. In the neutral state, the number of electrons equals the number of protons, so if there is a change in the net charge of the atom, it becomes...

Julianna Laurentano 4G

Basically the inert pair effect is when electrons in the outer s orbital remain unionized, and this is because there is poor shielding of these orbitals, so they cannot form bonds. As a result, these electrons remain unionized.

Julianna Laurentano 4G

Cations are smaller than their parent atoms because they have less electrons. Cations are positively charged ions, so when they lose their electrons, the remaining electrons move closer to the nucleus, and the size of the cation is reduced.

Julianna Laurentano 4G

The atomic radius is half the diameter of the atom. The ionic radius is half the distance between two atoms that are touching. So, the ionic radius involves two atoms, while the atomic radius is just the radius of the singular atom.

Julianna Laurentano 4G

During my discussions we have been using 3.00x10^8, but as long as your final answer is rounded to the correct number of significant figures I'm sure either is fine to use!

Julianna Laurentano 4G

I would definitely star the topics that are a bit confusing and read about them in the textbook in addition to completing the corresponding homework problems for them! I would also review the problems done for practice in discussion section, as those cover the basic concepts. Additionally, the modul...

Julianna Laurentano 4G

Coulomb's Law refers to the force created between two charged objects (the force that two electrons exert on each other, in this case). According to Coulomb's law, the force that is exerted is inversely proportional to the distance between the object, which is why there is a weaker force for electro...

Julianna Laurentano 4G

I don't think we would be given problems where we have to derive the equations (especially since we are given a formula sheet for exams), but knowing the general basis of the derivation is definitely helpful in understanding the main concepts behind the equation. I would know how each variable relat...

Julianna Laurentano 4G

The Rydberg formula is used to calculate the wavelength of light produced by an electron that is moving between energy levels (between orbitals). So, when a question surrounds the movement of electrons between different orbitals (AKA there is a change in energy), you apply Rydberg's formula, pluggin...

Julianna Laurentano 4G

A nodal plane is a plane where there are no electrons (zero percent chance of finding an electron there). An example is the 2p orbital!

Julianna Laurentano 4G

The intensity of light is determined by the light waves amplitude (vertical extent on a graph).
Therefore, to increase the intensity of light, increase its amplitude.

Julianna Laurentano 4G

Excited atoms give off light of various wavelengths, and these wavelengths respond to different colors, as we saw in class. When this data is observed, the set of colored lines produced is referred to as the atomic spectra. In my class notes, I wrote: "spectroscopic analysis of light given off ...

Julianna Laurentano 4G

Begin by finding the total molar mass of Sr(NO2)2. Then, find the mass of each element and divide that by the total molar mass of Sr(NO2)2 to obtain each percentage. Make sure that your calculations include 1 Sr atom, 2 N atoms, and 4 O atoms.

Julianna Laurentano 4G

You will be given a formula sheet for the test that could potentially list the units (there's a chance it might not, however), so just in case I would definitely familiarize yourself with the units of measurement and what value they have (1 Angstrom= 10^-10 meters).

Julianna Laurentano 4G

My TA told our class during our first meeting that as long as your final answer was rounded to the correct number of significant figures, then you will receive full credit. I don't believe each number in your calculation needs to be correctly rounded as long as you make sure your final answer is.

Julianna Laurentano 4G

I believe that first you would add the two numbers together, and then you would round the final answer to the least number of significant figures present in any part of the problem (so in this case, round to the tenths place). Today in discussion, my TA mentioned that it is most important that our f...

Julianna Laurentano 4G

Essentially, you solve for the limiting reactant twice. Using the first equation, determine the limiting reactant (O2) and how much is produced. Using the amount of P4 in the equation, calculate the moles of P4O6 produced by multiplying by the molar ratio. With this information, the limiting reactan...

Julianna Laurentano 4G

I would definitely take sig figs into account for the entire problem, as it will ensure that you do not forget to round correctly at the end. Today my TA informed my class that it is most important that our final answer is rounded to the correct number of significant figures (and not necessarily eve...

Julianna Laurentano 4G

Empirical formulas are used to display the lowest whole-number ratio of all the atoms involved in the compound; it simply shows the basic ratio that the molecular formula is a certain multiple of.

Julianna Laurentano 4G

As stated above, you cannot add reactants or products to the chemical equation, as the total mass before must equal the total mass after. However, you may use coefficients to make sure each side of the reaction is balanced in respect to the atoms of each element.

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