CHEMISTRY COMMUNITY

Pratika Nagpal

What are some examples of questions we could get asked about degeneracy.

Pratika Nagpal

The R you need to use is dependent on the units.

Pratika Nagpal

Thanks for the help!

Pratika Nagpal

even though there is no measurable change and in volume and no source of pressure isn't the act of expansion, means work is done BY THE SYSTEM

Pratika Nagpal

Malakai Espinosa 3E wrote:Also a difference to note, catalysts can be included in your rate law if they are in the slow step, but intermediates cannot!

why is the rate law governed by the slow step

Pratika Nagpal

For a visual example: A + B --> C + D D + E --> B + F B would be the catalyst C would be the intermediate is B the catalyst in both? I think that this is showing the two elementary steps of the overall reaction A + E (+B) --> C + F (+B). In this case, B is a catalyst in the overall reaction because...

Pratika Nagpal

every time I feel myself getting stressed, it helps to take a beat, close your eyes for a few seconds and breathe deeply.

Pratika Nagpal

Activation energy is the energy that needs to be provided to the system for the reaction to occur.

Free energy of activation refers to Gibbs Free energy.

Pratika Nagpal

This is really interesting, I was under the impression that reactions had fixed orders, instead of thinking of them a dependent on a set of conditions.

Pratika Nagpal

Are heterogenous catalysts formed again at the end of the reaction. for example, will a solid catalyst be able to be recovered at the end of a reaction ?

Pratika Nagpal

is there any mathematical way of understanding why half like of a first order reaction is independent of the concentration - other than considering the ln2/k formula

Pratika Nagpal

what is the difference between pka and ka and pkb and kb

Pratika Nagpal

does it matter how much less than or more than K, Q is.

like is there a particular threshold after which we can determine whether products or reactants will be favoured ?

Pratika Nagpal

Thank you for all the resources you provided Dr.Lavelle, all the support you provided us with in the form of UA and multiple review sessions made me wish I had taken 14A with you as well.

Pratika Nagpal

Is there any case where breaking bonds is not endothermic process, ie, the sign of the enthalpy change is not positive and therefore negative.

Pratika Nagpal

How are we supposed to know whether work done on a system is positive or negative If the work you calculate is positive then work is being done ON the system. If the work is negative, then work is being done by the system. If you think about it conceptually, when work is positive then work is being...

Pratika Nagpal

I thought I should also tell all my fellow international students to be wary of this - especially because we have to account for daylight savings and time difference now.
Good Luck !

Pratika Nagpal

What are the steps for determining oxidation number ?

Pratika Nagpal

Can someone explain the steps for solving this question

Pratika Nagpal

The order for each reactant/product is typically obtained through experiments. Looking at a table which contains the initial concentrations of the reactants/products, and the initial rates, you are able to determine the order of the reactants/products. Remember the general rate law equation, which ...

Pratika Nagpal

Hi! For problems like this, I like to substitute the "new" concentrations into the equation. For example, for [A] halved and [B] tripled, the new rate equation would be rate = k[1/2A][3B]^2, then I move the constants to the front so rate = 9/2 k[A][B]^2. Since k[A][B]^2 is equal to the or...

Pratika Nagpal

Hi! I used the point (80, .2) with the given value .35 for 40 from the table. (.2-.35)/(80-40) gave me the correct answer! I formatted it as .00375. Lemme know if you need anything. Thats so odd, because the feedback that I got for the question if what told me to use the point 0,0.48. Thanks for le...

Pratika Nagpal

How are we supposed to determine the order of a reaction. In the textbook, it has been stated that decomposition of N205 has a=1 and N02 has a=2. How is this obtained. I remember seeing somewhere that an order of a reaction if influenced by the order of the reactants and products. if this is true, h...

Pratika Nagpal

For this question, I followed the steps correctly, even tried to do the sum twice, but my answer seems to be wrong. I calculated the slope of the tangent at t=40 s and used the points (0,0.48) and ( 40, 0.35)

Pratika Nagpal

yes, of someone could share a sample study schedule that would be very helpful

Pratika Nagpal

I'm a sophomore, so I had a few months to experience campus before I had to leave. One of the things I miss the most is being in the LA timezone. I feel so disconnected from everything I can't even believe that my second year of college is almost over. I miss the Study at 2 am, and walking to class ...

Pratika Nagpal

Last quarter, I found that the most helpful for me was probably the outlines and the older sapling assignments. The outlines for me help because it breaks it up into the sections we learned it and when I review it in the order we learned it it helps me. Also I think the older sapling assignments ar...

Pratika Nagpal

Can you explain how you found the order of the reactant

Pratika Nagpal

Samir 3I wrote:
Pratika Nagpal wrote:I'm having a similar problem, but with this question. Could someone help please ?

The balanced equation would be 2MnO4- +3S2- +4H2O ---> 3S +2MnO2 +8OH-

Great, Thanks so much, would you be able to explain the steps to me, so I can understand the process of getting this balancing better.

Pratika Nagpal

I followed all these steps, but I wasn't able to get the correct answer, does anyone have any idea what I might be doing wrong

Pratika Nagpal

I can't seem to figure this out. I know I need to balance it using OH- since it is in basic solution, but I cant figure out to balance the hydrogens out after that

Pratika Nagpal

I'm having a similar problem, but with this question. Could someone help please ?

Pratika Nagpal

The answer you should get for this is :
[Pb(OH)4]2−(aq)+ClO−(aq)⟶PbO2(s)+Cl−(aq)+H2O(l)+2OH−(aq)

Pratika Nagpal

All of these responses are super helpful. Thank you !

Pratika Nagpal

Can someone help me with the steps to solve this.

Pratika Nagpal

removing the parenthesises worked. Thanks a lot

Pratika Nagpal

This helped, Thank you .

Pratika Nagpal

I didn't get it right when I flipped them either.

Pratika Nagpal

Could someone please help me understand what Is wrong about my balanced equation - I can't find any error but Sapling won't accept the answer. I tried it with the phases too, it was still marked incorrect.

See attachment.

Pratika Nagpal

Can someone help me out with this. I keep trying, but I can't seem to figure it out.

Pratika Nagpal

Can someone help me out with this. I keep trying, but I can't seem to figure it out.

Pratika Nagpal

Is there any way to know which is at the cathode/anode or which is being reduced/oxidized just from looking at the values of the standard reduction potentials ?

Pratika Nagpal

I don't exactly know how to relate this to neutralization of a reaction, but a neutralisation reaction is basically the reaction between an acid and a base to form a soluble salt and water. Neturalisation reactions are usually exothermic due to the formation of the bond between hydrogen and oxygen t...

Pratika Nagpal

There are 2 ways to think about this, either conceptually or mathematically - the formula for work is PdeltaV and no change in volume delta v =0 , and therefore w=0. Another way to think about it since there is no expansion, there is no work done by the system. and therefore work is 0

Pratika Nagpal

How are we supposed to know whether work done on a system is positive or negative

Pratika Nagpal

You will need to multiply the Cvm by the number of moles to get the Cv, which you can then plug into your equation. It is important to note whether the value being given is the molar heat capacity or the heat capacity

Pratika Nagpal

Why is this statement false
(c) If one starts with a higher pressure of reactant, the equilibrium constant will be larger.

Pratika Nagpal

When we purchase Sapling, do we get an access code, online or do we have to get the physical access card shipped to us.
Is there anyway to get the code online, for International Students - since shipping it would be an expense almost the price of the code itself

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