CHEMISTRY COMMUNITY

SahajDole_1C

They mean the same thing.

SahajDole_1C

The question will usually state to find a certain K value, whether it is the concentration or the partial pressure.

SahajDole_1C

It is considered as a weak acid and base.

SahajDole_1C

If he K value is less than 10^-3, then it would be too small to have an effect in the reaction.

SahajDole_1C

I would like to get better at time management and better scheduling.

SahajDole_1C

Yes M is mol * L^-1

SahajDole_1C

If the K value is a huge number, then it is towards products but if it is a small number then it's towards reactants.

SahajDole_1C

Usually the question should mention what to find but it would depend on the values given.

SahajDole_1C

A pure substance is something that does not change concentration in the reaction in either the forward o reverse process and therefore it is not included in the k constant.

SahajDole_1C

Our sapling homework is not due until the end of week 2 and you should be able to get a free 14 day trial with sapling.

SahajDole_1C

The density of the compound is usually given in the problem.

SahajDole_1C

I plan on going home and spending time with family.

SahajDole_1C

The larger the kb value the stronger the base is

SahajDole_1C

We most likely will have to join our TA links to the zoom

SahajDole_1C

I believe they would have to same energy since they fall in the same subshell.

SahajDole_1C

See saw is very uncommon of a shape to make and thus square planar and tetrahedral were mentioned.

SahajDole_1C

The oxidation state is the charge of the element.

SahajDole_1C

Best way is to memorize the strong bases and acids.

SahajDole_1C

I am pretty sure the final will cover all topics discussed throughout the quarter

SahajDole_1C

Pi bonds cannot rotate because the p orbitals overlap and cause a double bond which is more stronger and thus it cannot rotate

SahajDole_1C

What Professor Lavelle means by that is that the the bonds are all considered one region of density in the VSEPR model because the bonds tend to just combine into a larger area of electron density.

SahajDole_1C

We will probably have to know it later on in the next week, but as of right now we have not gone over it yet.

SahajDole_1C

Yes I believe you do count the double bond as 2 bonds

SahajDole_1C

The shape will always be T shaped

SahajDole_1C

It would be considered as a single region of electron density and thus it will be sp2

SahajDole_1C

In most books, if the polarity difference is about 0.5 or more then it is said to be polar.

SahajDole_1C

Partial charges tend to be dipoles and formal charges are the charges on an atom

SahajDole_1C

Click on the Respondus app and then click on the globe and check for updates

SahajDole_1C

Your second device is the one that should have zoom enabled and camera facing the desk.

SahajDole_1C

We are going to be tested on the last 8 bullet notes and the new material in Outline 3

SahajDole_1C

Best way to memorize is to consider the atom as the periods go across and how they get bigger and when they go down a group. Usually bigger atoms tend to have the smaller ionization energies

SahajDole_1C

I would follow green

SahajDole_1C

Sigma and pi bonds are the bonds on the atom . Sigma is one and pi is a double bond. We have not covered this topic yet.

SahajDole_1C

When it's for a single atom, you just place the electrons in the four cardinal directions.

SahajDole_1C

When it's for a single atom, you just place the electrons in the four cardinal directions.

SahajDole_1C

School has been going pretty good. Nothing too difficult and the class work is pretty sustainable.

SahajDole_1C

Nonmetals tend to bond with covalent bonding since they do not have ionic charges.

SahajDole_1C

The octet rule should be prioritized first and then the formal charges.

SahajDole_1C

You should have about 5 posts per week with a total of 50 posts by the end of the quarter

SahajDole_1C

The 4s shell has a lower energy level than 3d, which is why the 4s shell fills first

SahajDole_1C

It incluudes everything left over in the Second Module and everything we learned from now on

SahajDole_1C

I believe Lavelle will post the midterm grades by next week.

SahajDole_1C

I believe we would be required to know basic molecular compounds.

SahajDole_1C

It will cover everything in the Outline 1 on Fundamentals and Outline 2 up to Focus D

SahajDole_1C

E=pc is used when the mass or velocity of the electron is given in the problem, while the E=hv is used when frequency or wavelength is given.

SahajDole_1C

A high electron affinity means that the energy released will be high when an electron is accepted and is usually high for cations

SahajDole_1C

You are allowed to write both, but the 2px1 and 2py1 is to tell you which axis they fall on

SahajDole_1C

Schrodinger may be referenced, but I do not think it'll be on the exam too much.

SahajDole_1C

Contact your TA as he or she may know most likely.

SahajDole_1C

Theoretical yield should usually be given in terms of grams.

SahajDole_1C

Theoretical yield should usually be given in terms of grams.

SahajDole_1C

They are still in the order that Professor Lavelle is lecturing. He stated that in the email.

SahajDole_1C

It is most likely to just be based on our current technology and how far we are able to measure the wavelength.

SahajDole_1C

Questions tend to not tell you the number of sig figs to use, but will give you some number in the problem which is what you should base your sig fig off of.

SahajDole_1C

Balmer is in the visible light region, while Lymann series is in the UV light region.

SahajDole_1C

Try not to round off your numbers until you get the final answer.

SahajDole_1C

I think you should have an understanding of the levels of the light, but I do not think we will be required to memorize the order of it.

SahajDole_1C

There shouldn't be a unit to use unless stated in the problem/

SahajDole_1C

I do not think there is a specific unit to use unless it is stated in the question. As long as the conversion from m to nm is correct, you should be fine. :)

SahajDole_1C

You should use the molar mass of O2 because it is the molecule listed in grams, not O because the molar masses are different.

SahajDole_1C

I believe you have to post 5 times a week, but you have 5 days to do so. I am not sure though .

SahajDole_1C

The use of (___ mol rxn) is to show how much product is created as a result of an experiment. In the example you had written, the goal was to find out what is the mol of product produced and you use the mole to mole ratio in the equation to solve for that, which is why you wrote (1 mole Rxn/ 3 mol O...

SahajDole_1C

Mole and mol are indeed the same exact thing. mol is just the way most people write the word out during chemical equations and problems.

Search found 63 matches