CHEMISTRY COMMUNITY

Mahika More 1H

I felt a little rushed at the end, but I think I did all I could have done.

Mahika More 1H

I'm assuming you meant [Co(CN)5(OH2)]2-. For that, the name would be Aquapentacyanocobaltate (III) Aqua comes first alphabetically. Then cyano and we have to add penta- because there are 5. After that, we add the transition metal name and add -ate because the complex is negative. Add the charge of t...

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There are quite a few so I just remember them as the conjugates of strong acids and bases!

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I agree just try to look at electronegativity. The larger the difference the more ionic the character of the bond.

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I'm tired. Very tired :/

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I play lo-fi music or instrumental music because it doesn't have words.

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Thank you so much! I have been looking for some to watch!!

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I'm not sure of any practice exams, however, I do remember Dr.Lavelle mentioning in an email that he would be going through previous years exam Q&A on wednesday. I imagine this would be super helpful!

Mahika More 1H

All of these tips seem really helpful. I will slowly but surely do all the textbook problems that I can and write summaries of the units we have gone through! My main strategy is just practice, practice, practice!!

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Probably just a very limited amount of questions will offer partial credit.

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I'm ok, just tired. Definitely ready for break!

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Lone pairs do not cancel out. Rather they play a larger role in repelling atoms around/near it.

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Will there be an emphasis on the new material though?

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Renny_kim_2G wrote:Does anyone know if we get partial credits for questions on the finals?

I'm guessing that we can just because we were able to on the first one. But it would probably just be for a limited number of questions.

Mahika More 1H

Renny_kim_2G wrote:Does anyone know the minimum points we can lose to maintain an A or A-? Or is he curving the grades later?

I don't think I heard anything about curves, but who knows! As for the grading scale I think it is as mentioned above.

Mahika More 1H

I ended up doing worse on this midterm but I guess I just gotta make up for it on the final :/. I'll take it as a learning curve. We all got this, just got to push through!!!

Mahika More 1H

Inderpal Singh 3B wrote:Would we have to memorize the bond angles as well?

I don't think we would have to memorize bond angles for each one but you should know the general idea about how each shape looks and be able to deduce from there what the values of the angles are around (for example 90 vs less than 90 degrees).

Mahika More 1H

Yes, lone pairs are considered their own regions and they repel other regions strongly too. That is why when looking at the shape of molecules we have to consider lone pairs (because they repel the other bonds).

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I will most likely go through old problems I had trouble with and try to redo them all. This way I get to revisit all the old topics. I have also been making consolidated lists of midterm material throughout the quarter, so I will probably create one for the new material and study the lists collecti...

Mahika More 1H

This was actually pretty helpful! I personally like remembering which trends are the same and why they go that way. From there I deduce the other trends I may need to know.

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Yes you must otherwise you may get a completely different shape then what is right.

Mahika More 1H

I also felt somewhat disappointed after the midterm. Hopefully, this is just a case of me underestimating myself. Thank you for the song by the way. Much needed and appreciated.

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When you have this, I believe you use the radius of the atoms to see which one has a stronger bond. Since F has a smaller radius than Cl it will have a shorter bond and therefore be slightly stronger.

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Instead of spending the time stressing about my grade (which I do my fair share of) and I like to spend that energy on working to improve it. This is a habit I am trying to change for myself. I think that if you spend time to know the material and really understand it, the grade will hopefully come ...

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I like to go biking or on short walks around my neighborhood. It is a great way to get some air and take a break.

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You should use formal charges to check if what you are drawing is the most stable it can be. You want to prioritize formal charges of 0 as that is the most favorable. You also want to make sure that if there is a formal charge for example of -2 total, that it is spread across the structure evenly. F...

Mahika More 1H

I just remember the largest radius as the corner opposite to electronegativity (diagonally across)! That way I don't have to memorize too much.

Mahika More 1H

To add on, most likely your second device will just be your phone which will be pointed towards your desk during the midterm.

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If there are enough people I would follow green. If there are not enough people I would shut off the reactor because if the reactor time runs out the game ends!

Mahika More 1H

A cation pulls in an electron much more and therefore it requires more energy for it to be removed. After the first ionization, the atom loses a negative charge and therefore it becomes positive making the nucleus stronger requiring more energy for the next removal.

Mahika More 1H

It's down for me too! I like to check "downforeveryoneorjustme.com" whenever this happens (i found this to be super helpful). Should be back up now though

Mahika More 1H

One thing I do is definitely keep my phone away from me. It helps me focus and keeps away any distractions. I also like to prepare my workspace before I work there. By this I mean grab water, clean my desk, and etc. I definitely understand the struggle of working at home so I hope this helps!

Mahika More 1H

To add on, after you remember the stair-like pattern you don't have to memorize much more. So I suggest just knowing that (and hydrogen as an exception!).

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I would suggest first pass unless your other classes are even more competitive to get into. It also depends on what classes you need versus just want.

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I decorated a bunch of cupcakes for Halloween and took a well-deserved break after midterms!

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It is used to describe the number of molecules or atoms per mole. If you have some amount of moles you can use Avogadro's number to convert.

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When you have more protons, the nucleus pulls on the electrons making it smaller despite possibly a larger amount of electrons. So the ion with the least protons will have the largest radius.

Mahika More 1H

I definitely recommend the show Money Heist. I love crime/drama shows and this had the best of both worlds. I also recommend Hunter Hunter or Haikyuu if you want to watch anime!

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The process suggested seems correct. I just wanted to add that you should pay attention to your units to make sure you get the right value. So make sure to covert nm to m and make sure your mass is in kg!

Mahika More 1H

I have started to learn to crochet and I usually do that while watching Netflix! I also love biking to relax.

Mahika More 1H

The basic shapes of the orbitals and schrodingers (which are covered in Wednesday's lecture) should be on the midterm, but no more than that. I would go with what he wrote in the email and just know the shapes of the orbitals/schrodingers. I don't think you need to worry at all about today's lecture.

Mahika More 1H

Since they are in different units, you can just check your units to see which one to use. Most commonly the value in Hz is used.

Mahika More 1H

Don't worry, you are right! The uncertainty is the range (so you need to take into consideration that it can be from 0 to 10 m/s). I do not think "minimum" uncertainty means anything new for future references.

Mahika More 1H

For me, definitely staying organized is super important! It can be super overwhelming with several assignments especially if you don't know when they are due and how much time you need for it. I use my planner to help block out times during the day where I will focus on specific topics or assignment...

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I would print it out because then you don't have to spend time scrambling to find your PT during the midterm. Ensures that you have super easy access. I think Lavelle might provide a PT with equations that he may want us to print out later.

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Adding to the previous answers, once the molecule comes together it then has it's own unique wavelengths that it accepts. The different ratios of atoms in each molecule will accept different wavelengths even if the elements are the same. Hope this helps.

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I think the Balmer series is in the visible region whereas the Lyman series is in the ultraviolet region. So one of the main differences is just where they are on the electromagnetic spectrum.

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Light acts as both a wave and individual particle at the same time! That's why there are many approaches when it comes to solving problems with light. They travel in waves, so collectively light can be understood as waves. That wave is made up of particles and that is why we can apply both conceptua...

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I believe that the metal absorbs the light and the electrons become excited as if they are about to be emitted. It still takes in that energy it just doesn't end up being enough energy to break the free the electron.

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It does mean that it is focusing on the individual molecules and that is the difference between classical and quantum mechanics. With the water example, you can look at it through two viewpoints: a continuous flow falling out or individual molecules. When we say quantized we are looking at the secon...

Mahika More 1H

Make sure to convert your units! The best way to check is to cancel out the units that you can and make sure to include them in your work (instead of just manipulating the numbers). This way you will know what values you may need to convert and you can find any mistakes more easily.

Mahika More 1H

Hey! When I read through the textbook I added to my notes from the modules we watched previous to school starting. I found the textbook to be a good compliment to what I learned in the modules since they often discussed the same topics. For me, taking notes helps me retain information and I think it...

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Volume is an extensive property because it depends on how much you have and not what you have. Whether you have water or any other kind of solution the volume is something you need to measure out. With density, you can have varying volumes of a solution but still have the same density because it dep...

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It should be taking place in vacuum otherwise the constant c would not be true/correct.

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You would just continue using the same equation by replacing the old M and V values with the new diluted ones. So to clarify your M2 and V2 in the first dilution calculation (of a serial dilution) would be the M1 and V1 of the second dilution calculation. The amount of moles "n" should rem...

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If you don't have it in its simplest form it definitely makes your work more difficult because you will have to multiply or divide by much larger numbers. This may leave more room for error when doing your calculations so you should always simplify.

Mahika More 1H

Hi! Thank you for this super helpful advice. I think even if I plan to go to vet school as apposed to med school, all of this information is so important. Thank you for taking the time to post this!

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