CHEMISTRY COMMUNITY

Nicole Attiq 3D

Will Skinner wrote:If the pKa is equal to the pH, it will be neutral. If the pKa is not equal to the pH, it is charged.

Actually, it's if pKa is greater than pH, the solution is neutral. If the pH is greater, it's charged.

Nicole Attiq 3D

I'm confused about the explanation in the solutions manual for 6.13a), which says that B(OH)3 has no resonance. This I understood, but then it said the reason for this was that, "B(OH)3 is a very weak acid because it does not have a conjugate system to delocalize the electrons on the oxygen to ...

Nicole Attiq 3D

Ka is the measure of the strength of a weak acid. That is, it measures the amount a weak acid will dissociate. The higher your Ka, the stronger your acid and the lower your pH (they're inversely related). pKa is the negative log of Ka just as pH is the negative log of [H3O+]. They too are inversely ...

Nicole Attiq 3D

The book says this: "The greater the electronegativities of the groups attached to the carboxyl group, the stronger the acid."
The two groups attached are H and CH3. So I guess my question was more geared towards understanding why H is more electronegative than CH3 :)

Nicole Attiq 3D

Personally, I'm a visual learner. I absorb conceptual information much more easily by reading it rather than listening to it. So for me, I'll read the book and take notes on it. Then, I usually call my friend who's in this class and I'll "teach" whatever it is to her-- basically I'll go th...

Nicole Attiq 3D

I would also assume that histidine and oxygen are outside of the coordination sphere, which is why it is not considered when determining the coordination number. Someone correct me if I'm wrong though.

Nicole Attiq 3D

I was having trouble with this textbook problem asking which of formic acid (HCOOH) and acetic acid (CH3COOH) is stronger. The answer was formic acid because, according to the book, H is more electronegative than CH3. Can someone explain this please? It would help if it were explained in the context...

Nicole Attiq 3D

Nevermind, turns out the Lewis acid thing was a typo. Lol

Nicole Attiq 3D

Hi, I was doing Matthew's week 9 worksheet which asked about what species is more likely to bond to myoglobin: CO or O2. The answer was CO because CO is a Lewis acid, but I was confused because in the problem, CO ends up donating an electron to Nitrogen. Wouldn't that make it a Lewis base? For refer...

Nicole Attiq 3D

The organic chemistry tutor never fails! Additionally, reading the textbook usually helps me with concepts just because I'm a more visual learner, so if you're like that too the book should help a lot!

Nicole Attiq 3D

I was a bit confused about the textbook problem 2.45 where it asked for the composition of the bonds and the hybridization of each lone pair. If anyone has done that problem, could you explain it? Thank you in advance!

Nicole Attiq 3D

They do not have prefixes because you can already assume the number of chlorides from the 2+ charge on the overall molecule. If you labeled it Cl2 the charge would be inaccurate. Just use prefixes on your ligands and you should be good!

Nicole Attiq 3D

I believe if they have multiple lone pair donors, they can bind at alll of those lone pair sites.

Nicole Attiq 3D

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Nicole Attiq 3D

Sarah_Hoffman_2H wrote:What date is the final on?

Sunday, December 13th. I believe it will be open from around 11:30 to 2:30. Also, if anyone finds out how many questions it will be and whether there will be partial credit, please lmk.

Nicole Attiq 3D

I would 100% start taking notes on the book. For me, it is the best way to comprehend the concepts because I'm a more visual learner. Another thing that's helped me a lot is making a study guide from the outline a couple days before the exam. It's the best way to refresh the info you got from the bo...

Nicole Attiq 3D

So far no, check the outlines for the rest of the material we're covering to see if we will learn it though. In general, if it is not on the outline we won't be tested on it.

Nicole Attiq 3D

When you count the amount of electrons the structure needs, you should put any leftover electrons as lone pairs on the central atom. Also, all elements from row 3 p block and down can have an expanded octet. They actually usually do because they're more stable this way.

Nicole Attiq 3D

Everyone will take it on 12/13. But does anyone know whether we all take it at the same time? Or how many questions it will be?

Nicole Attiq 3D

I am quite certain Professor Lavelle does not curve this class, although someone in a chat mentioned something about adjusting grades at the end of the quarter and I was confused about it, so if anyone knows anything about that lmk! The point distribution in this class can be pretty tough. Especiall...

Nicole Attiq 3D

I'm a big extrovert, so usually I like to go do something fun with my friends. It's obviously a little different now with covid, so usually I'll go drive to the beach with my sisters or watch a bunch of Netflix!

Nicole Attiq 3D

I'm pretty sure there will be a lecture, but I don't think there will be any discussions. Does anyone know if there are only no discussions on Thursday/friday, or is it all week?

Nicole Attiq 3D

Yes, hydrogen bonds are a type of dipole-dipole interaction. When it comes to intermolecular bonds though, the hydrogen must be bonded by an F, O, or N atom on both sides to be classified as a hydrogen bond, not just one side.

Nicole Attiq 3D

Just to add onto this, a polar molecule will generally pull in the direction of the more electronegative atom.

Nicole Attiq 3D

One thing in particular I think you should definitely know is that when deciding which atom a radical goes on, you have to consider electronegativity. It will always go on the atom that is least electronegative because that one will, of course, attract less electrons. So if you had a bond between C ...

Nicole Attiq 3D

In order to have a hydrogen bond between two molecules, the hydrogen must be bonded by an F, O, or N on both sides. So, if hydrogen is bonded by carbon on one side and fluorine on the other, this is not a hydrogen bond.

Nicole Attiq 3D

Hi! When it comes to determining which atom gets the radical, it is supposed to be the least electronegative. In this case, oxygen has a higher EN than chlorine, so it wouldn't be the one with one less electron. In part b, the book gives you the structure with the oxygens in the middle on purpose. I...

Nicole Attiq 3D

I'm confused about this as well. Maybe the question was asking which had the MOST ionic character?

Nicole Attiq 3D

ml refers to which orbital an electron will be placed in. For example, if ml=0 and you had a p orbital, _ _ _ , the electron would be found in the middle space. So, if a problem gives you ml and asks what can work for those values, the answer will always be 2 since that's the max an orbital can hold...

Nicole Attiq 3D

The Organic Chemistry Tutor and Khan Academy are both amazing!

Nicole Attiq 3D

It's important to note that when it comes to periodic trends, oxygen is an exception. Since oxygen has a half full orbital, and an electron is being added, electron repulsion occurs, resulting in a lower ionization energy than Nitrogen, which comes to the right of oxygen. Since the energy required t...

Nicole Attiq 3D

I'm sure we will cover it if/when we do redox reactions. That might be a part of 14b though, I'm not sure. But for this unit I don't believe we need to know them.

Nicole Attiq 3D

I was wondering if it's a good idea to take bio and chem at the same time next quarter as a pre-med student. Is anyone doing that right now? How's the workload?

Nicole Attiq 3D

It may be because hydrogen bonding is a type of dipole-dipole bond, so just saying dipole-dipole should cover both. I'm not 100% positive though.

Nicole Attiq 3D

A good tip that my TA told me is to always put the bigger number first when using Rydberg's equation since you will always need to get a positive value. For example, if you know n=1 and the electron jumped up some energy levels, you should put (1/1^2) first since you know whatever the value of n fin...

Nicole Attiq 3D

I'm pretty sure that any post that aims to answer a question, help a classmate, or engage in a discussion will get you your points. As long as it's engaging you should be fine.

Nicole Attiq 3D

The v is the greek letter "nu". Like the previous person said, we only use the second equation so as to not confuse velocity with frequency. However, most of the time we use the equation with the nu.

Nicole Attiq 3D

I don't know for sure, but that seems like something we would have to memorize.

Nicole Attiq 3D

My favorite shows are probably Grey's Anatomy, Criminal Minds, and The Vampire Diaries. I know, super basic haha. As a kid I loved Wizards of Waverly Place!

Nicole Attiq 3D

If the wave begins above the line and ends beneath it, it is compatible. This is because this is the only form in which the wave will be able to form a smooth circle where the ends meet up perfectly.

Nicole Attiq 3D

What I'm personally doing that definitely helps: doing as many workshops and worksheets as possible, mastering the book and sapling questions, making a study guide out of the outline (I would definitely take book notes on every topic mentioned in the outline), watching the lectures of course, and th...

Nicole Attiq 3D

As for what kind of concept questions there will be, off the top off my head I'd say definitely know the wave model, diffraction, the photoelectric effect, the particle model, Bohr frequency condition, atomic and molecular spectra, conservation of mass, and conservation of energy. The study guide an...

Nicole Attiq 3D

The last reply covered most of it, I just wanted to add one thing. If Ephoton> threshold energy, the left over energy (that is, the energy from the photons that isn't used to remove the electrons) will be your kinetic energy. If Ephoton= threshold energy, then kinetic energy is zero. And of course, ...

Nicole Attiq 3D

I'm pretty sure there's no difference between the two, only that when it asks for either of these you don't double the uncertainty.

Nicole Attiq 3D

Does anyone know/ think there will be any graphs on the midterm? There was one in the book relating work function and frequency, and there was also one in a workshop. Brooke's week 2 workshop also had one I believe.

Nicole Attiq 3D

I believe we will get an equations sheet for our exams. Most likely we will be able to see them beforehand, so you can double check whether certain equations will be on it. All the ones you mentioned should be given, but I'm not 100% certain.

Nicole Attiq 3D

This is what Dr. Lavelle posted on his website regarding the midterm: "Midterm 1 covers all material up to the end of Week 3. This is up to Q21 in Sapling (quantum) homework. In Outline 2 below, all topics except the last three listed. MT 1 is up to quantum numbers (up to end of 1D in textbook)...

Nicole Attiq 3D

Use the equation Ek= hv-Φ.
Plug in -4*10^-19 = (6.63*10^-34)(1.34*10^15) - Φ
Then solve for the work function. You should get 4.88 *10^-19. Hope that helped!

Nicole Attiq 3D

I believe you can run it in "kiosk mode". I found this article that may be able to help. https://support.respondus.com/support/i ... wn-browser

Nicole Attiq 3D

Also, I believe that as long as your TA can see your whole workspace and you then you're fine, but I would still double check with them at your next discussion. As for Respondus, it should be linked on CCLE. Have it downloaded by this week because we're going to take a practice quiz to see how well ...

Nicole Attiq 3D

Hi! In order to do this problem you first have to find the molar mass of X and A. You can do this by taking the total molar mass of H2A (168g) and subtracting the molar mass of hydrogen from it (1.008). You should get 166.992, which is the molar mass of 2A. Divide this by two and you get 83.496 as t...

Nicole Attiq 3D

Hi! You always arrange compounds in this order: Carbon first, then Hydrogen, then in alphabetical order from there. So you should have C10H16O. With organic compounds it will always be CHO. Hope this helped!

Nicole Attiq 3D

Hi! The previous answer pretty much covered all of it, but if you are looking to convert something to formula units such as atom/molecules, it is important to note that the 6.022 * 10^23 number is per mole. So, if you are trying to say convert 5 moles of water into atoms, you would multiply by Avoga...

Nicole Attiq 3D

Hi! For part C, I believe all you have to do is convert 5.15 grams of Epson salt to moles of water. I did this by dividing 5.15 g by the molar mass of the salt, 246.52, and I ended up with 0.021 moles of salt. From there, I used the molar ratio of H2O molecules to salt molecules, 7:1, in order to fi...

Nicole Attiq 3D

In order to find the net amount of gas produced in this reaction, you have to look at the stoichiometric coefficients of the reactants and products that are gases. There are 30 moles of gas on the reactant side of the equation, and 36 on the product side. Therefore, the net amount of gas molecules p...

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