Search found 90 matches
- Sun Feb 28, 2021 11:13 pm
- Forum: Balancing Redox Reactions
- Topic: Canceling Out Added Electrons in Half Reactions
- Replies: 6
- Views: 19
Re: Canceling Out Added Electrons in Half Reactions
You would need to have an equal amount of electrons on the products and reactants side of the two half equations in order to have them cancel out when writing the final equation.
- Sun Feb 28, 2021 11:04 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling Week 7/8 #15
- Replies: 6
- Views: 42
Re: Sapling Week 7/8 #15
We do not consider the concentrations of solids when calculating Q and K for a reaction.
- Sun Feb 28, 2021 11:01 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling Week 7 and 8 #7
- Replies: 10
- Views: 35
Re: Sapling Week 7 and 8 #7
The anode should be in the first box, in this case being Pb(s) and the cathode should be in the last box, in this case being Ag(s). The chloride ions should be on the either side of the salt bridge. The phase changes change as you go through the shorthand notation.
- Sun Feb 28, 2021 10:59 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling Week 7/8 #18
- Replies: 3
- Views: 12
Re: Sapling Week 7/8 #18
That looks good to me. Maybe try removing the parenthesis.
- Thu Feb 11, 2021 10:40 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling Week 3/4 Question 18
- Replies: 9
- Views: 75
Re: Sapling Week 3/4 Question 18
Cp-Cv=R and delta U=nCdeltaT are the two equations I used for this problem.
- Thu Feb 11, 2021 10:37 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Can heat capacities be negative?
- Replies: 52
- Views: 161
Re: Can heat capacities be negative?
Heat capacities cannot be negative and if you get a negative value just take the absolute value of it.
- Thu Feb 11, 2021 10:37 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling Week 3 & 4: #12
- Replies: 3
- Views: 20
Re: Sapling Week 3 & 4: #12
For this problem convert the given value of grams to moles and multiply by the heat of combustion. Divide that value by the change in temperature and take the absolute value for part a. For part b, calculate delta T and multiply it by the value you got for part a. Divide that value by the grams of s...
- Thu Feb 11, 2021 10:34 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling #14B W3/4
- Replies: 4
- Views: 35
Re: Sapling #14B W3/4
For part b you would use the equation w=PexdeltaV and then convert to the proper units.
- Thu Feb 11, 2021 10:30 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: sapling 20
- Replies: 3
- Views: 21
Re: sapling 20
I used q=mcdeltaT and I had to multiply the constant R by three.
- Thu Feb 11, 2021 10:28 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling #16 W3/4
- Replies: 3
- Views: 15
Re: Sapling #16 W3/4
First covert from Kcal to KJ and subtract that number by the heat given off to solve for deltaE
- Thu Feb 11, 2021 10:26 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling #20 Week 3/4
- Replies: 2
- Views: 15
Re: Sapling #20 Week 3/4
You should use q=mcdeltaT and choose the correct constant based of the shape of the molecule.
- Thu Feb 11, 2021 10:25 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling 3/4 #10
- Replies: 5
- Views: 23
Re: Sapling 3/4 #10
We first use the equation mcdeltaT to find the final temperature for ice and then we would use that value as the initial temperature value for the second equation in which we set mcdeltaT =-mcdeltaT and then solve for the final temperature.
- Thu Feb 11, 2021 10:22 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sampling 3/4 #12
- Replies: 3
- Views: 18
Re: Sampling 3/4 #12
You would first convert the value of grams to moles and multiply it by the heat of combustion and then divide it by the change in temperature. Take the absolute value of that number for the first part. Second, calculate delta T and multiply the value you found in the first part. Divide that number b...
- Thu Feb 11, 2021 10:19 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Cv and cp
- Replies: 7
- Views: 19
Re: Cv and cp
Cv-Cp = R Cp being the molar heat capacity of a gas at constant pressure and Cv being the molar heat capacity of a gas at constant volume.
- Thu Feb 11, 2021 10:15 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: q equation
- Replies: 21
- Views: 56
Re: q equation
It would based of the units given n being moles and m being mass in grams.
- Thu Feb 11, 2021 10:13 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Difference between constants
- Replies: 4
- Views: 18
Re: Difference between constants
Cp is the molar heat capacity of a gas at constant pressure.
- Thu Feb 11, 2021 10:10 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Thermo Equilibrium like Chemical Equilibrium?
- Replies: 4
- Views: 17
Re: Thermo Equilibrium like Chemical Equilibrium?
I also think that Professor Lavelle meant NET because he also mentioned that heat spontaneously moves from the hotter object to the cooler object.
- Thu Feb 11, 2021 10:07 am
- Forum: Calculating Work of Expansion
- Topic: Work
- Replies: 6
- Views: 40
Work
Can someone please explain the difference between work done along a reversible pathway compared to an irreversible pathway?
- Thu Feb 11, 2021 10:07 am
- Forum: Calculating Work of Expansion
- Topic: Work
- Replies: 6
- Views: 45
Work
Can someone please explain the difference between work done along a reversible pathway compared to an irreversible pathway?
- Tue Feb 02, 2021 9:44 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: sapling #7 week3
- Replies: 3
- Views: 37
Re: sapling #7 week3
It is the sum of the products - the sum of the reactants. The H2g and Cs have values of zero because they are in their standard states.
- Tue Feb 02, 2021 9:37 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #8
- Replies: 5
- Views: 25
Re: Sapling #8
I first set up a chemical equation being NH4+ + H2O yields NH3 + H30+. I then calculate ka using the equation ka x kb=10^-14. I set the initial concentration of NH4 to the given M in the question. I then set up my equilibrium equation and solve for x. Calculate the pH by using -log. That is what I ...
- Tue Feb 02, 2021 9:35 pm
- Forum: Phase Changes & Related Calculations
- Topic: Endothermic vs exothermic
- Replies: 24
- Views: 58
Re: Endothermic vs exothermic
Water cooling on a surface is an exothermic process because in order for the water to have a phase shift from vapor to liquid, it must be cooled and therefore release heat.
- Tue Feb 02, 2021 9:32 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Heat capacity units
- Replies: 3
- Views: 16
Heat capacity units
I was just wondering how it's possible that we can use either use J/K or J/C when finding specific heat capacity.
- Tue Feb 02, 2021 9:23 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling 9 Week 3 and 4
- Replies: 2
- Views: 19
Sapling 9 Week 3 and 4
I was just confused on how to calculate the change in temperature for this problem because I know delta T is equal to final temperature - initial temperature but Im not sure how to find the final temperatures for this problem.
- Mon Jan 25, 2021 12:16 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #3
- Replies: 8
- Views: 29
Re: Sapling #3
Set up an ice chart and use the given molarity of CH3CH(OH)COOH as the initial concentration. Set up an equilibrium equation using the given ka value and solve for x. Use negative log to calculate pH and subtract pH from 14 to find pOH. The x value divided by the initial concentration of lactic acid...
- Mon Jan 25, 2021 12:12 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #8
- Replies: 5
- Views: 25
Re: Sapling #8
I first set up a chemical equation being NH4+ + H2O yields NH3 + H30+. I then calculate ka using the equation ka x kb=10^-14. I set the initial concentration of NH4 to the given M in the question. I then set up my equilibrium equation and solve for x. Calculate the pH by using -log.
- Mon Jan 25, 2021 12:06 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Sapling week 2 #8
- Replies: 8
- Views: 47
Re: Sapling week 2 #8
I first wrote the chemical reaction being NH4+ + H20 yields NH3 + H3O+. From there I make an ice chart and put the given M of NH4Cl for my initial concentration of NH4+. I then find the ka value by using the equation ka x kb = 10^-14. Set up an equation for ka and then use negative log to find the pH.
- Mon Jan 25, 2021 12:00 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Sapling 9
- Replies: 10
- Views: 67
Re: Sapling 9
Alexis Sanft 1E wrote:What does it mean to be a "predominant" species?
I'm pretty sure it just means that there is more of it or it is the most basic/acidic in solution.
- Sun Jan 24, 2021 11:44 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Base/Acid Scale
- Replies: 4
- Views: 12
Re: Base/Acid Scale
It is important to differentiate between weak and strong acids and bases because strong acids and bases completely dissociate in solution.
- Sun Jan 24, 2021 11:42 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Number 5
- Replies: 18
- Views: 95
Re: Sapling Number 5
I first calculate concentration of OH and BH using the given pH and inverse log. I set these values as final concentrations for OH and BH on my ice chart and B reactant is x-the final concentration of OH. I then would solve for x after setting up my expression for kb.
- Thu Jan 21, 2021 10:00 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Approx K<10^-4 for Cubic
- Replies: 3
- Views: 17
Re: Approx K<10^-4 for Cubic
You could always check just to be sure by putting the value you get for x divided by the initial molarity given.
- Thu Jan 21, 2021 9:58 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Including (aq) Solvents
- Replies: 4
- Views: 15
Re: Including (aq) Solvents
We do not typically include water in our expressions for k
- Tue Jan 19, 2021 10:59 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: initial molarity situations?
- Replies: 3
- Views: 23
Re: initial molarity situations?
This is because strong acids and strong bases dissociate completely in solution.
- Tue Jan 19, 2021 10:57 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Rounding E Values in ICE charts
- Replies: 17
- Views: 79
Re: Rounding E Values in ICE charts
I think if k is smaller than 10^-5 then we can assume it is 0 when calculating equilibrium.
- Sun Jan 10, 2021 7:23 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: change in K
- Replies: 22
- Views: 106
Re: change in K
Yes, a change in temperature is the only thing that changes K I believe.
- Sun Jan 10, 2021 7:11 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Direction of a non-equilibrium reaction
- Replies: 11
- Views: 93
Re: Direction of a non-equilibrium reaction
When Q is less than K it means that there are more reactants than products and therefore the forward reaction is favored due to the excess of reactants in the chemical reaction.
- Sun Jan 10, 2021 7:03 pm
- Forum: Ideal Gases
- Topic: reversing reactions
- Replies: 83
- Views: 461
Re: reversing reactions
The K of a reverse reaction is the inverse of the K for the forward reaction.
- Sun Jan 10, 2021 6:56 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Concentration
- Replies: 12
- Views: 90
Re: Concentration
The concentration has to be positive because any concentration less than 0 does not exist, 0 concentration means we do not have anything.
- Sun Jan 10, 2021 6:42 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: reaction quotient Q vs. equilibrium constant K
- Replies: 11
- Views: 80
Re: reaction quotient Q vs. equilibrium constant K
Q is calculated at any time during the reaction before it has reached equilibrium and the value of q varies as the reaction approaches equilibrium while the k is when equilibrium is reached.
- Sun Jan 10, 2021 6:38 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Homogeneous and Heterogeneous Equilibrium
- Replies: 13
- Views: 122
Re: Homogeneous and Heterogeneous Equilibrium
You would look at the reaction as a whole and see if there are more than one phase in the reaction. Such as gas and liquid or all gas.
- Tue Dec 08, 2020 11:55 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Sapling #12
- Replies: 7
- Views: 60
Re: Sapling #12
I think the question was just trying to show us that the more oxygen atoms present in the molecule, the higher the strength of the acids because the more oxygen atoms, the weaker the bond to hydrogen is in the molecule.
- Tue Dec 08, 2020 11:50 pm
- Forum: Identifying Acidic & Basic Salts
- Topic: Sapling #8
- Replies: 2
- Views: 24
Re: Sapling #8
At equilibrium, both H and OH have 1x10^-7 so if either H or OH has a higher concentration than 1x10^-7 then the solution is either basic or acidic.
- Tue Dec 08, 2020 11:40 pm
- Forum: Conjugate Acids & Bases
- Topic: Conjugates and Charge
- Replies: 8
- Views: 50
Re: Conjugates and Charge
It depends on the initial charge of the molecule. For example the third question on sapling is asking us what the conjugate base of HSO4- is and the answer would be SO42-.
- Tue Dec 08, 2020 11:32 pm
- Forum: Bronsted Acids & Bases
- Topic: Amphoteric compounds
- Replies: 8
- Views: 71
Re: Amphoteric compounds
An example of an Amphoteric compound is H2O because it can both lose and accept protons. If the molecule can both lose and accept protons it is amphoteric.
- Tue Dec 08, 2020 11:29 pm
- Forum: Lewis Acids & Bases
- Topic: general conceptual question
- Replies: 9
- Views: 101
Re: general conceptual question
We can look at bond length and electronegativity of the central atom of the molecule.
- Mon Dec 07, 2020 11:02 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Sapling Homework W10 Problem#5
- Replies: 4
- Views: 60
Re: Sapling Homework W10 Problem#5
To find the pOH, we would take the negative log of the value we have for out OH concentration.
- Mon Dec 07, 2020 11:00 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Sapling Question 9 (Week 10)
- Replies: 5
- Views: 52
Re: Sapling Question 9 (Week 10)
We know that [OH-]([H+]=1x10^-14. We can use this information to determine pH based off of concentration of either OH or H. We know that at equilibria, we have both H and OH having 1x10^-7 concentrations so if OH has a concentration less than that number, then it is more acidic.
- Mon Dec 07, 2020 10:56 am
- Forum: Bronsted Acids & Bases
- Topic: bronsted vs. lewis acid
- Replies: 10
- Views: 80
Re: bronsted vs. lewis acid
A Bronsted Acid is a proton donor, it donated an H+ while a lewis acid accepts an electron pair. You can think of H+ being a lewis acid because it cannot donate an electron pair and must instead accept an electron pair because it has no electrons to donate.
- Mon Dec 07, 2020 10:51 am
- Forum: Bronsted Acids & Bases
- Topic: pKA and KA
- Replies: 4
- Views: 43
Re: pKA and KA
pKa is the pH value at which there are equal quantities of acid and conjugate base.
- Mon Nov 30, 2020 1:41 am
- Forum: Dipole Moments
- Topic: Dipole arrows
- Replies: 8
- Views: 46
Re: Dipole arrows
Dipole Arrows are simply the vectors we draw on the structure of a molecule from the slightly positive charged element to the slightly negative element. if these arrows are equal in magnitude and opposite in direction, then they cancel out rendering the molecule nonpolar.
- Mon Nov 30, 2020 1:33 am
- Forum: Resonance Structures
- Topic: Stable Resonance Structures
- Replies: 4
- Views: 36
Re: Stable Resonance Structures
I think formal charge is the only way to check which resonance structure is ideal unless the question tells you the determined bond lengths the elements form. You would then need to choose the structure that most accurately has bond lengths similar to the experimentally determined ones.
- Mon Nov 30, 2020 1:30 am
- Forum: Lewis Structures
- Topic: Tips on drawing Lewis structures
- Replies: 20
- Views: 170
Re: Tips on drawing Lewis structures
I write out the number of valence electrons and learn how to recognize the number of bonds elements tend to form. For example carbon tends to form 4 bonds while oxygen tends to form two bonds based off of the electrons in their valence shell.
- Mon Nov 30, 2020 1:27 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Polarity and Dipole Moments
- Replies: 4
- Views: 42
Re: Polarity and Dipole Moments
Dipoles cancel out if the vectors drawn are in opposite directions and equal in magnitude. For example an H2O will have a stronger dipole moment than that of CaS.
- Mon Nov 30, 2020 1:22 am
- Forum: Hybridization
- Topic: Delocalized Pi Bond
- Replies: 10
- Views: 94
Re: Delocalized Pi Bond
A delocalized pi bond is essentially a pi bond of a molecule that has resonance. If the molecule has resonance (as can be determined by the Lewis structure), then it can have a delocalized pi bond.
- Mon Nov 30, 2020 1:20 am
- Forum: Hybridization
- Topic: Hybrid Orbitals
- Replies: 7
- Views: 57
Re: Hybrid Orbitals
An easy way to determine hybrid orbitals is to count the number of electron density regions around the central atom and choose the answer that provides the accurate number of orbitals for the electron density regions.
- Sun Nov 22, 2020 10:54 pm
- Forum: Dipole Moments
- Topic: Determining higher dipole moments
- Replies: 5
- Views: 64
Re: Determining higher dipole moments
You can do this by checking the difference in electronegativities of the elements in the molecule. For example, HO would have a higher dipole moment than a CH bond.
- Sun Nov 22, 2020 10:47 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Determining polar molecules
- Replies: 7
- Views: 66
Re: Determining polar molecules
An easy way to determine if a molecule is polar or nonpolar is by drawing out vectors on the Lewis structure of the molecule. Keep in mind that if the central atom on a molecule has a lone pair but the vectors cancel out, the molecule is still polar.
- Sun Nov 22, 2020 10:44 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: NO2- Bent Molecular Geometry
- Replies: 7
- Views: 75
Re: NO2- Bent Molecular Geometry
Once the central atom has a lone pair, other bonds are pushed down changing the bond angles of the molecule.
- Sun Nov 22, 2020 10:16 pm
- Forum: Lewis Structures
- Topic: Expanded Valence
- Replies: 11
- Views: 65
Re: Expanded Valence
An atom can have an expanded valence if it has space in the d orbital. Elements period 3 and below can have expanded valence shells.
- Sun Nov 22, 2020 10:13 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling #1
- Replies: 6
- Views: 69
Re: Sapling #1
The lone pair on the sulfite pushes all the other bonds down changing the bond angle of the molecule.
- Sun Nov 15, 2020 11:37 pm
- Forum: Lewis Structures
- Topic: Textbook Question 2.C.9
- Replies: 2
- Views: 22
Re: Textbook Question 2.C.9
In this scenario Arsenic can form 6 bonds because the molecule is a cation with a -1 charge.
- Sun Nov 15, 2020 11:25 pm
- Forum: Lewis Structures
- Topic: Hydrogen Bonding
- Replies: 12
- Views: 66
Re: Hydrogen Bonding
This is because Carbon is not as electronegative as Nitrogen, Oxygen, and Fluorine
- Sun Nov 15, 2020 11:23 pm
- Forum: Dipole Moments
- Topic: Sapling #14
- Replies: 2
- Views: 20
Re: Sapling #14
In choice A, the hydrogen is bonded to carbon while in choice C, the hydrogen is bonded to an Oxygen. In order for a Hydrogen bond to form, the hydrogen has to be bonded with a Nitrogen, Oxygen, or Fluorine atom. Therefore choice C is correct because the hydrogen involved in the hydrogen bond is bon...
- Sun Nov 15, 2020 11:09 pm
- Forum: Lewis Structures
- Topic: expanded octets
- Replies: 2
- Views: 26
Re: expanded octets
We would need to count the number of valence electrons and if atoms that are not capable of having expanded octets are full, then we would assign the extra electrons to atoms that can have expanded octets. We can also count the number of bonds we need by counting the valence electrons available and ...
- Sun Nov 15, 2020 10:39 pm
- Forum: Lewis Structures
- Topic: Focus 2 Exercise 11
- Replies: 1
- Views: 12
Re: Focus 2 Exercise 11
The Lewis Structure would have two Oxygen Carbon single bond and if we added two protons (two Hydrogens), they would bond to the two Oxygens because Oxygen wants to form two bonds in order to have a formal charge of 0.
- Sun Nov 08, 2020 1:42 pm
- Forum: Lewis Structures
- Topic: question about BCl3
- Replies: 2
- Views: 27
Re: question about BCl3
Boron and Aluminum (group 13 elements) can also be exceptions to the octet rule. Boron has 3 valence electrons that can bond and therefore Boron can form three bonds. Boron can complete its octet if another atom provides both electrons forming a coordinate covalent bond.
- Sun Nov 08, 2020 12:32 pm
- Forum: Ionic & Covalent Bonds
- Topic: Oxidation number
- Replies: 7
- Views: 47
Oxidation number
Is there any way to easily determine the oxidation number of a bonded element?
- Sun Nov 08, 2020 12:13 pm
- Forum: Lewis Structures
- Topic: Sapling #3
- Replies: 10
- Views: 90
Re: Sapling #3
I calculate the formal charge of each element in a bond and try to get the charge to be as close to 0 as possible using the formula Valence electrons-(lone pairs+ shared electrons/2).
- Sun Nov 08, 2020 12:10 pm
- Forum: Ionic & Covalent Bonds
- Topic: Covalent Character
- Replies: 7
- Views: 72
Covalent Character
I don't understand how ionic bonds have covalent character and how covalent bonds have ionic character.
- Sun Nov 08, 2020 12:04 pm
- Forum: Ionic & Covalent Bonds
- Topic: Bond Lengths Favorability
- Replies: 3
- Views: 47
Bond Lengths Favorability
I don't understand on the sapling homework how to determine which Lewis structure is more plausible based off of the experimentally determined bond lengths. Do we just see which bond length is closest in length to the bond length experimentally determined?
- Sun Nov 01, 2020 6:42 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Sapling Question 13
- Replies: 2
- Views: 28
Re: Sapling Question 13
For n=3 you can have 18 electrons because the s subshell can hold 2 electrons, the p subshell can hold 6 electrons, and the d subshell can hold 10 electrons. For n=5,l=0 you can have 2 electrons because l=0 represents the s subshell and the s subshell can hold two electrons. For n=7,l=1,ml=-1 you ca...
- Sun Nov 01, 2020 5:37 pm
- Forum: Trends in The Periodic Table
- Topic: Electron Shielding Question
- Replies: 5
- Views: 42
Re: Electron Shielding Question
I think it means that the inner shell electrons shield the electrons in the outer shell because the nucleus is positively charged and the electrons are negatively charged so they attract. The inner shell electrons repel the outer shell electrons because both are negatively charged. The inner electro...
- Sun Nov 01, 2020 5:26 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Resources for quantum numbers
- Replies: 3
- Views: 68
Re: Resources for quantum numbers
I watched some Khan Academy videos about quantum numbers but he goes very in depth into the subject but they were helpful nonetheless.
- Sun Nov 01, 2020 4:46 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Sapling question 21
- Replies: 11
- Views: 71
Re: Sapling question 21
In the n=2 level we know that there are s and p subshells and we know that the s subshell can hold 2 electrons and the p subshell can hold 6 electrons. So the n=2 level can hold a total of 8 electrons.
- Sun Oct 25, 2020 1:33 am
- Forum: Properties of Light
- Topic: How does an atom continuously emit light?
- Replies: 4
- Views: 87
Re: How does an atom continuously emit light?
I'm pretty sure an electron just emits light when it moves from the excited state back to its ground state.
- Sun Oct 25, 2020 1:17 am
- Forum: Properties of Light
- Topic: Sapling problem
- Replies: 6
- Views: 113
Re: Sapling problem
I used the Rydberg equation but the version that uses the constant 1.097*10^7 for R and instead of frequency the equation is equal to 1/wavelength. This way you don't have to do an extra conversion but I'm sure both methods work.
- Sun Oct 25, 2020 1:08 am
- Forum: Student Social/Study Group
- Topic: How are you studying?
- Replies: 203
- Views: 1402
Re: How are you studying?
I'm just doing as many practice problems as I can and I'm also trying to form a study group where I can explain what I know and learn what I don't from others.
- Sun Oct 25, 2020 1:02 am
- Forum: Properties of Electrons
- Topic: Schrodinger's wave equation
- Replies: 4
- Views: 59
Re: Schrodinger's wave equation
I think the main takeaway from the Schrodinger Equation is that we can find the areas where an electron is most likely located and it gives us the energy of the electron.
- Sun Oct 25, 2020 12:19 am
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: How to measure uncertainty in an experiment
- Replies: 2
- Views: 52
Re: How to measure uncertainty in an experiment
I think to measure uncertainty in real life we would compare our calculated (theoretical data) with our experimental data. There is also an equation that allows us to find percent error and if I'm not mistaken it was experimental/theoretical *100. Hope this helps!
- Sun Oct 18, 2020 8:25 pm
- Forum: Properties of Light
- Topic: Remembering EM spectrum
- Replies: 6
- Views: 63
Re: Remembering EM spectrum
I don't think we would need to memorize all of them but I'm not too sure.
- Sun Oct 18, 2020 8:04 pm
- Forum: DeBroglie Equation
- Topic: Sapling 2 #10 Temperature
- Replies: 1
- Views: 20
Sapling 2 #10 Temperature
Why are we given the degrees Celsius in the question? Is it because at higher temperatures electrons move faster?
- Sun Oct 18, 2020 5:56 pm
- Forum: Properties of Electrons
- Topic: Sapling 2 Homework #8
- Replies: 2
- Views: 32
Re: Sapling 2 Homework #8
We know that blue light is part of the Balmer Series because it is under visible light and in the Balmer series n1=2. I used the Rydberg formula to solve this problem by manipulating the equation for n2^2. I used the version of the equation that says 1/wavelength is equal to as opposed to the v is e...
- Thu Oct 15, 2020 9:24 pm
- Forum: Properties of Electrons
- Topic: Sapling 2 #6
- Replies: 4
- Views: 48
Re: Sapling 2 #6
I'm not sure if this question made sense so I can clarify if need be.
- Thu Oct 15, 2020 9:23 pm
- Forum: Properties of Electrons
- Topic: Sapling 2 #6
- Replies: 4
- Views: 48
Sapling 2 #6
I was going through the sapling homework and I got the right answer by using the same equation (Rydberg Formula) except instead of using frequency is equal to, I used 1/wavelength instead and the units on the Rydberg constant I used were 1/m. Is this fine or should I stick to the frequency is equal ...
- Wed Oct 14, 2020 2:45 pm
- Forum: Properties of Electrons
- Topic: Energy of Electrons
- Replies: 1
- Views: 66
Energy of Electrons
Are the different lengths between n=1 n=2 and so on measured in nanometers. I don't understand how visible light has larger wavelength but appears to be shorter on the model shown in lecture number 6.
- Sun Oct 11, 2020 12:35 am
- Forum: Empirical & Molecular Formulas
- Topic: Sapling Week 1 #8
- Replies: 23
- Views: 237
Re: Sapling Week 1 #8
I simply counted the number of atoms in the picture and added all their masses
- Sat Oct 10, 2020 7:21 pm
- Forum: Empirical & Molecular Formulas
- Topic: Sapling Hw 1 #10
- Replies: 5
- Views: 47
Re: Sapling Hw 1 #10
Every zig zag has a carbon and hydrogen atoms are used to fill the valence shell of the carbon atoms. The carbon atoms on the far right and left of the image are bonded to three hydrogen atoms.
- Sat Oct 10, 2020 6:43 pm
- Forum: Balancing Chemical Reactions
- Topic: Equilibrium Constants
- Replies: 2
- Views: 35
Re: Equilibrium Constants
This is because solids and liquids have an activity series of 1 so we don't include them in the calculation.
- Sat Oct 10, 2020 6:15 pm
- Forum: Properties of Light
- Topic: Atomic Spectra HELP
- Replies: 3
- Views: 29
Re: Atomic Spectra HELP
Doesn't it have to do with the amount of energy an electron gives off as it moves from a higher to lower state?
- Sat Oct 10, 2020 5:50 pm
- Forum: Properties of Light
- Topic: Electromagnetic properties
- Replies: 2
- Views: 31
Electromagnetic properties
Does anyone know how electron density is measured?