CHEMISTRY COMMUNITY

Nick Saeedi 1I

Yes Q is a constant for the reaction at a time not at equilibrium which is compared to k in order to see which direction the reaction is shifting towards.

Nick Saeedi 1I

I make sure to double check the coefficients so I dont mess up the change expressions. I also check to see which way the reaction is shifted towards so I know which concentrations are decreasing and increasing.

Nick Saeedi 1I

I used an ICE table to solve this question. You know the initial concentrations by dividing moles/Liters and you have the coefficients which will give u the change. Then you can set up an expression that you can set equal to Kc which is [HI]^2/[H2][I2]

Nick Saeedi 1I

If inert gases were in the reaction, then the reaction will not shift right or left. it will only shift if the pressure change is due to a change in volume.

Nick Saeedi 1I

A reaction is endothermic if it requires energy to run. Exothermic reactions release energy. delta H is negative in a exothermic reaction and positive in an endothermic reaction.

Nick Saeedi 1I

There needs to be a change in volume to have a change in concentration so adding gases wont shift the reaction.

Nick Saeedi 1I

The Q is the ratio of products to reactants at a point other than equilibrium. This value is compared to K to see if the reaction will favor the reactants or products.

Nick Saeedi 1I

Large is greater than 10^3 and small is less than 10^-3

Nick Saeedi 1I

I usually tend to keep it in Kelvin.

Nick Saeedi 1I

I bought the package last quarter so this quarter I just used my credit from when I bought it. It gave me that option.

Nick Saeedi 1I

Look to see if it donates or accepts hydrogen ions.

Nick Saeedi 1I

I think this is the correct way it works.

Nick Saeedi 1I

We need to know the stoichiometric point.

Nick Saeedi 1I

Yes if both the cation and anion is from a strong acid/base, then the pH will not change.

Nick Saeedi 1I

pH and pOH are just scales that represent the concentration of H+ ions and OH- ions.

Nick Saeedi 1I

The pH formula is -log[H+].

Nick Saeedi 1I

for a molecule to be amphoteric it needs to be able to act as a base or a acid so it needs to be a proton acceptor or a proton donor depending on what it reacts with. water is a good example as it can donate a hydrogen atom to become a hydroxide ion or accept an electron to become a hydronium ion.

Nick Saeedi 1I

Have more oxygens will delocalize the charge more and make it easier to break the bond which results in it being a stronger acid.

Nick Saeedi 1I

BrO- has a negative charge so it is more likely to be a proton acceptor than morphine making it a stronger base.

Nick Saeedi 1I

HBr is a strong acid and HBrO is not on the list of strong acids so HBr is stronger.

Nick Saeedi 1I

We dont have to memorize the actual number but we have to know the trends and what the pKa means for the strength of the acid.

Nick Saeedi 1I

I think we just need to know about cisplatin and how it is used in chemotherapy treatments by disrupting cell replication.

Nick Saeedi 1I

Hemoglobin carries oxygen through the blood while Myoglobin carries oxygen through the muscles.

Nick Saeedi 1I

I memorized them by making flashcards with the ligand names and the prefixes.

Nick Saeedi 1I

I think its just the new IUPAC naming convention. It is still correct to use cyano.

Nick Saeedi 1I

Im pretty sure we cant. We can only use the periodic table and equations sheet.

Nick Saeedi 1I

-ido is the new IUPAC convention but it is not widely recognized yet so Dr. Lavelle said we can just use -o.

Nick Saeedi 1I

I think we should memorize all of them because were not sure which ones are going to be tested on the final.

Nick Saeedi 1I

Hemoglobin carries more oxygen as it has 4 myoglobins and transports o2 in the blood. Myoglobin transports through the tissues.

Nick Saeedi 1I

I think we should memorize them because I think it is important to know for our final as we most likely wont have the name sheet.

Nick Saeedi 1I

In lecture today, Dr. Lavelle explained that chloro is more widely used but I think both are still accurate.

Nick Saeedi 1I

Yes, the coordination number is the amount of bonds.

Nick Saeedi 1I

It is chelating if it has more than one lone pair.

Nick Saeedi 1I

It is related to resonance structures because if the bond is delocalized, the electrons can move.

Nick Saeedi 1I

Thats how I think of it. If the dipoles are in opposite direction and of the same magnitude, they cancel out. If all dipole moments cancel out, then the molecule is non polar.

Nick Saeedi 1I

There are 5 regions of electron density in PBr5 so there are 5 hybridized orbitals.

Nick Saeedi 1I

double bonds dont necessarily mean the molecule is going to be bent. The molecule is bent when there are lone pairs on the central atom of molecule like H2O.

Nick Saeedi 1I

The sulfur has a lone pair which changes the structure.

Nick Saeedi 1I

They are shown in the p orbital because a pi bond is formed when 2 p orbitals overlap vertically.

Nick Saeedi 1I

I dont think you can calculate them. We just know the relative bond angles based on the structure of the molecule.

Nick Saeedi 1I

I made flashcards and used quizlet.

Nick Saeedi 1I

Yes, that is what I do. The shape will have an impact on the bonding but I dont think we have to worry about that for this midterm.

Nick Saeedi 1I

There are LD forces because compounds have some of these forces. The compound is polar so there are dipole dipole forces

Nick Saeedi 1I

They are the same just different names

Nick Saeedi 1I

ionic bonds are stronger and take more energy to break so it would have a higher boiling point.

Nick Saeedi 1I

they are not permanent so it takes a low energy to break them

Nick Saeedi 1I

Boron and Aluminum can be electron deficient and not have a full valence shell. Since both atoms usually have only 6 valence electrons, they can act as an electron accepter.

Nick Saeedi 1I

Yes, the formal charges should add up to the total charge of the molecule.

Nick Saeedi 1I

Double bonds are stronger than single bonds so they pull the atoms closer to each other.

Nick Saeedi 1I

Atoms that have d-orbitals can have an expanded octet.

Nick Saeedi 1I

The number of protons increases as you move across a period so there is a stronger pull on the electrons making the atomic radius smaller.

Nick Saeedi 1I

Yes, an example would be sodium chloride.

Nick Saeedi 1I

non metals want to gain an electron to fill their shell as they have a high ionization energy.

Nick Saeedi 1I

I heard that we were going to get the scores after the last discussion section took the exam but since we have not gotten them yet, I have just been looking for an email from Dr. Lavelle.

Nick Saeedi 1I

The elements down a group have electrons farther away from the nucleus so it is easier to remove and takes less ionization energy.

Nick Saeedi 1I

The UA workshops are helpfully along with doing the textbook problems and reading.

Nick Saeedi 1I

I would study the fundamentals that we learned along with up to 1D.2 in the textbook. This includes the photoelectric effect, the c=lambda(v) and E=hv equations, Bohr frequency condition, Heisenberg Indeterminacy principle, and the Schrodinger wave function.

Nick Saeedi 1I

In the De Broglie equation, you are relating wavelength to momentum so when the question asks you to solve for speed or requires you to solve for speed as one of the steps of the question, you would use De Broglie.

Nick Saeedi 1I

I think the Schrodinger equation gives us a wave function for each orbital basically giving a complex math model for the location of each orbital.

Nick Saeedi 1I

We just need to go up to 1D.2 in the textbook which is the first couple of questions in 1D. The last material that we learned that will be fair game for the midterm is the basics of the Schrodinger wave function.

Nick Saeedi 1I

When there is a maximum number of electrons ejected, the work function is equal to the energy per photon because the kinetic energy is 0. So you divide the total energy you were given divided by the energy for the work function (the energy per photon) resulting in the Joules canceling out leaving yo...

Nick Saeedi 1I

When an electron is ejected, the atom is ionized because an ejecting an electron will change the charge of the atom thus making it ionized since the charge of an electron is negative.

Nick Saeedi 1I

Yes. They were only increasing the amount of photons which is the intensity not the frequency of light.

Nick Saeedi 1I

The unexpected result was that increasing the intensity of the light did not release electrons but were released when the frequency of light was increased.

Nick Saeedi 1I

Hi, I take notes during the lecture and try to stay engaged with the lecture by asking questions in chemistry community. I usually try to read the text before the class and do the text book assignments on the weekends. For the midterm I am planning on reviewing the notes, textbook questions, sapling...

Nick Saeedi 1I

In the question in the lecture where the question is asking to calculate the frequency of light emitted by a hydrogen atom when an electron transitions from the 4th to the second, I am a little confused on why the sign for the energy changed from negative to positive when we plugged it in to the E=h...

Nick Saeedi 1I

I first converted grams of CuNO3 to moles then I used the equation M=n/V and rearranged it for V. Just plug in the values now and you should get the correct answer.

Nick Saeedi 1I

I start with balancing the ones that occur the least and mark my progress with tallies next to the question.

Nick Saeedi 1I

When the problem gives an initial volume and initial moles and then asks you to either find the final volume or final moles, I use the M(initial)V(initial)=M(final)V(final) equation.

Nick Saeedi 1I

Also where can we learn to read such symbols or way of displaying a chemical reaction without the lettering we usually use? For 2-butanone and 3-methyl 3-hexyl, there are Carbon molecules in between each bond represented by the lines in the picture. Each Carbon molecules needs to have 4 bonds so ad...

Nick Saeedi 1I

I was taught not to round until the end of a problem so I just apply sig figs when I am done solving.

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