Search found 103 matches
- Tue Mar 02, 2021 7:47 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Book Problems 6K.3 and 6L.5
- Replies: 1
- Views: 6
Re: Book Problems 6K.3 and 6L.5
I think if you determine the oxidation states of the substances, you can compare them before and after the reaction to figure out which one is reduced and oxidized.
- Mon Mar 01, 2021 8:13 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling Weeks 7 & 8 #13
- Replies: 2
- Views: 21
Re: Sapling Weeks 7 & 8 #13
When a reagent oxidizes another substance, it means that the reagent itself is being reduced. That means we have to compare the reduction potentials of each atom, with a higher reduction potential meaning that it is more likely to be reduced. That is why Co2+ (-0.28) is able to oxidize Cr (-0.74), b...
- Sun Feb 28, 2021 11:12 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Sapling #15
- Replies: 3
- Views: 19
Re: Sapling #15
Its the same as finding Kc, we use the concentrations of the products and divide it with the concentrations of the reactants. We are not given the other concentrations because the other substances are both solids
- Sun Feb 28, 2021 11:04 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling Week 7/8 Q5
- Replies: 4
- Views: 13
Re: Sapling Week 7/8 Q5
When I balance half reactions, first I try to balance the other atoms that are not H or O. After that, if I need to add oxygen anywhere I use H2O to balance the O atoms. Finally I use H to balance out the H atoms.
- Sun Feb 28, 2021 11:01 pm
- Forum: Balancing Redox Reactions
- Topic: Canceling Out Added Electrons in Half Reactions
- Replies: 6
- Views: 19
Re: Canceling Out Added Electrons in Half Reactions
When you find the added electrons on each half reaction you find the lowest common factor between the two added reactions so they can cancel out and be balanced. Then you multiply each of the half reactions by the multiple required to reach that lowest common factor so that the added electrons match...
- Sun Feb 28, 2021 10:47 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Clarifying standard reduction potential
- Replies: 3
- Views: 10
Re: Clarifying standard reduction potential
That's correct, and moles are not necessary in reduction potential because reduction potential is an intensive property, meaning it does not change no matter how many times the reaction is run.
- Sun Feb 28, 2021 10:19 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling week 7/8 #3
- Replies: 3
- Views: 23
Re: Sapling week 7/8 #3
In order to convert a balanced redox equation in an acidic solution into a basic solution you simply need to find the number of H+ ions in the equation and add the same number of OH- ions on both sides of the equation. Then, you convert the side with both H+ and OH- into water molecules, and then ca...
- Sun Feb 28, 2021 10:15 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: sapling 12
- Replies: 4
- Views: 23
Re: sapling 12
You don't need to multiply by its coefficients and your answer is in joules instead of kilojoules
- Sun Feb 28, 2021 10:05 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Anodes and Cathodes
- Replies: 22
- Views: 43
Re: Anodes and Cathodes
The cathode will have the higher reduction potential.
- Sun Feb 28, 2021 10:02 pm
- Forum: Balancing Redox Reactions
- Topic: Finding Reagents From Provided Table
- Replies: 9
- Views: 23
Re: Finding Reagents From Provided Table
Yes, you find the reduction potential in the list of ions that is between the reduction potentials of the two reactions in the question. The idea is that the reduction potential that is higher works as the oxidizing agent.
- Sun Feb 28, 2021 9:34 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling 7&8 #5
- Replies: 4
- Views: 58
Re: Sapling 7&8 #5
It looks like the sulfur atoms aren't balanced, which might affect the rest of the equation
Edit: Nevermind, I realize that I misread the post, do you have a picture of your work process?
Edit: Nevermind, I realize that I misread the post, do you have a picture of your work process?
- Sun Feb 28, 2021 9:30 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling #9
- Replies: 4
- Views: 22
Re: Sapling #9
The standard potential for silver ions is +0.80
- Sun Feb 28, 2021 8:46 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling Week 7/8 #15
- Replies: 6
- Views: 42
Sapling Week 7/8 #15
Calculate the cell potential for the reaction as written at 25.00 °C , given that [Mg2+]=0.808 M and [Sn2+]=0.0180 M . Use the standard reduction potentials in this table. Mg(s)+Sn2+(aq)↽−−⇀ Mg2+(aq)+Sn(s) I figured out which formula you need to use, but I'm having trouble solving for Q. How come we...
- Sun Feb 28, 2021 6:00 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Shorthand Notation for Electrolytic Cells
- Replies: 2
- Views: 12
Re: Shorthand Notation for Electrolytic Cells
Shorthand notation is a simpler representation of the reaction in a electrolytic cell. You have your anode on the far left side and the cathode on the far right side. You write the phases of the reaction in the order they are in contact from the anode to cathode, separating them by a single line to ...
- Sun Feb 28, 2021 1:39 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling Week 7/8 #12
- Replies: 3
- Views: 9
Sapling Week 7/8 #12
Calculate the standard free-energy change for the reaction at 25 ∘C. Refer to the list of standard reduction potentials. 2Au3+(aq)+3Cr(s)↽−−⇀2Au(s)+3Cr2+(aq) I know you need to find the number of electrons traded and use the Faraday constant to find standard free-energy change, but I'm not too clear...
- Sun Feb 21, 2021 11:54 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Entropy value
- Replies: 17
- Views: 35
Re: Entropy value
Entropy tells us how many microstates a system can access
- Sun Feb 21, 2021 10:34 pm
- Forum: Calculating Work of Expansion
- Topic: Topic 4A Exercises: 4A. 13
- Replies: 2
- Views: 14
Re: Topic 4A Exercises: 4A. 13
The question wants you to find the change in internal energy for the neutralization reaction, so we need to find the amount of heat and work done in the reaction because deltaU = q + w. Since the calorimeter is at constant volume, and work can be calculated with w= -PdeltaV, that means that no work ...
- Sun Feb 21, 2021 8:10 pm
- Forum: Van't Hoff Equation
- Topic: Deriving the Van't Hoff EQ
- Replies: 3
- Views: 17
Re: Deriving the Van't Hoff EQ
Gibb's free energy equation and deltaG = -RTlnK
- Sun Feb 14, 2021 11:59 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Favorability of a Reaction and ∆U
- Replies: 4
- Views: 12
Re: Favorability of a Reaction and ∆U
I don't think internal energy is related to Gibb's free energy
- Sun Feb 14, 2021 11:49 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Sapling #5, Week 5/6
- Replies: 2
- Views: 26
Re: Sapling #5, Week 5/6
Flipping the numbers simply switches whether its positive/negative, so either you added another sign to cancel it out, or the change was insignificant enough that Sapling just accepted it within the range of answers
- Sun Feb 14, 2021 11:29 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Units for Gibbs Free Energy Calculations
- Replies: 6
- Views: 21
Re: Units for Gibbs Free Energy Calculations
I'm pretty sure that Gibb's free energy and enthalpy are measured in kilojoules, and enthalpy is in joules, but if you're worried about using the correct units on the midterm you can always just check what units the answers use
- Sun Feb 14, 2021 11:24 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Textbook Problem 4A.1
- Replies: 3
- Views: 11
Re: Textbook Problem 4A.1
I'm not too sure about how refrigerators work, but I think the idea is that heat is constantly being transferred out of the system to keep the system cool, but you don't see any of that coolant leaking out of the refrigerator hopefully. This would make it a closed system. On the other hand, gasoline...
- Sun Feb 14, 2021 10:44 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Determining greater molar entropy
- Replies: 5
- Views: 20
Re: Determining greater molar entropy
NH3 has a higher molar entropy than Ne because it's amore complex molecule, and thus has more possible microstates.
- Sun Feb 14, 2021 10:30 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Sapling #7
- Replies: 3
- Views: 23
Re: Sapling #7
The molar entropy of vaporization is calculated by dividing the enthalpy of vaporization by the boiling point of the liquid in kelvin. Since the change in Gibb's free energy is zero during phase transitions, the equation deltaG = deltaH -TdeltaS can be rewritten as deltaS = (deltaH/T)
- Sun Feb 07, 2021 10:31 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling 10 week 4
- Replies: 3
- Views: 24
Re: Sapling 10 week 4
It looks like you forgot to include the Final Temperature variable on the ice cube side. Using 1.54*10^4 + 195.6x for the ice cube side gets you around the 30ish range
- Sun Feb 07, 2021 10:28 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Heat and Enthalpy at Constant Pressure/Constant Volume
- Replies: 1
- Views: 13
Re: Heat and Enthalpy at Constant Pressure/Constant Volume
I agree with this. I found this website that says the same:
https://thefactfactor.com/facts/pure_sc ... e%20system.
https://thefactfactor.com/facts/pure_sc ... e%20system.
- Sun Feb 07, 2021 2:13 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: HW Question
- Replies: 4
- Views: 24
Re: HW Question
Use the formula q= n x CV,m x deltaT to find heat. The problem gives you all the variables you need to plug in, but you also need to know what type of gas CO2 is in order to find the right constant to multiply the gas constant with.
- Sun Feb 07, 2021 2:03 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Sapling Homework #20
- Replies: 6
- Views: 40
Re: Sapling Homework #20
For the first part, you are given the amount of moles and change in temperature, and you need to figure out what type of gas Xe (g) is. With this, you can use q= n x Cvm x deltaT to find heat.
- Sun Feb 07, 2021 1:48 pm
- Forum: Phase Changes & Related Calculations
- Topic: Textbook 4C.11
- Replies: 3
- Views: 17
Re: Textbook 4C.11
It looks like you understand the steps to solving this problem. First you found the amount of heat required to melt 80g of ice into liquid water. Next, you find the amount of heat required to raise 80g of water by 20 degrees. That is why instead of using the specific heat capacity for ice, you need ...
- Sun Jan 31, 2021 11:16 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: pKa and conjugate base
- Replies: 4
- Views: 21
Re: pKa and conjugate base
The pKa value is -logKa. Ka, the acid disassociation constant, is very high for strong acids, and very weak for weak acids. What this means is, if you have a small Ka, you would have a large pKa. Since weak acids have strong conjugate bases, and larger pKa's are indicative of a weaker acid, the larg...
- Sun Jan 31, 2021 10:48 pm
- Forum: Phase Changes & Related Calculations
- Topic: X2 vs 2X
- Replies: 14
- Views: 76
Re: X2 vs 2X
Energy is required to break bonds, in this case being X2 into 2 Xs, making it endothermic. And since heat is being added, the system will try to lower the amount of heat by running in the direction where heat is being absorbed. I think a good model would look something like this:
heat + X2 ==> 2X
heat + X2 ==> 2X
- Sun Jan 31, 2021 7:20 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling Homework #9
- Replies: 4
- Views: 42
Re: Sapling Homework #9
An important thing to think about is that the amount of heat gained by the colder water should be equal to the amount of heat lost by the hotter water after they mix. This means that we have to find the amount of heat within each body of water based on specific heat capacity, density, and mass, as w...
- Fri Jan 29, 2021 10:12 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpy concept clarification
- Replies: 2
- Views: 18
Re: Bond Enthalpy concept clarification
Yes, that's correct
- Sun Jan 24, 2021 10:39 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Sapling Question 6
- Replies: 2
- Views: 22
Re: Sapling Question 6
The inclusion for "another quantity" makes more sense for the other questions, and it does make it seem misleading. However, I couldn't find anything that claims that the "combustion of CH4" was anything different from the equation above, in burning in the presence of oxygen to p...
- Sun Jan 24, 2021 10:32 pm
- Forum: Phase Changes & Related Calculations
- Topic: Bond Effects During Phase Changes
- Replies: 5
- Views: 24
Re: Bond Effects During Phase Changes
When liquid water is vaporized, the hydrogen bonding that holds water together is not present at all in water vapor. On the other hand, in fusion the hydrogen bonding found in ice can still be seen when it melts in liquid water, but to a lesser degree.
- Sun Jan 24, 2021 10:14 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Sapling #4
- Replies: 3
- Views: 26
Re: Sapling #4
When you you a large amount of energy to break a strong bond, and the result is the formation of a weaker bond that releases fewer energy you have an endothermic reaction. When you use a fewer amount of energy to break a weak bond, and the result is the formation of a stronger bond that releases a g...
- Sun Jan 24, 2021 9:57 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook Problem 4E.7
- Replies: 1
- Views: 26
Re: Textbook Problem 4E.7
The carbon double bond is completely broken and replaced with a single bond. I remember Dr. Lavelle emphasized during the lecture that the double bond isn't losing its pi bond to become a single bond, but that it's actually broken and another single bond forms in its place.
- Sun Jan 24, 2021 9:34 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.35 Textbook Question
- Replies: 1
- Views: 18
Re: 5.35 Textbook Question
I vaguely remember doing something like this in my discussion section. Basically you want to set up an ICE table for the decomposition of A into B+C, and figuring out "n" will give you the correct coefficent. The chart gives you the initial and final partial pressure at equilibrium, so you...
- Sun Jan 24, 2021 8:43 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook 4E 9
- Replies: 2
- Views: 24
Re: Textbook 4E 9
It wants you to calculate and compare the bond enthalpies of benzene with resonance (notice there is a specific carbon-carbon bond in the chart for benzene) and without it (using only single and double bonds). A higher bond enthalpy means more energy required to break the bond, meaning a higher bond...
- Sun Jan 24, 2021 8:22 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Making the Approximating for X: K or % Ionization?
- Replies: 6
- Views: 44
Re: Making the Approximating for X: K or % Ionization?
I thought a small K value like less than 10^-3 was more of helpful indication that x might be negligible, and the 5% ionization was more of a definite indication that it was actually negligible.
- Sun Jan 17, 2021 10:17 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #10
- Replies: 4
- Views: 35
Re: Sapling #10
Looking at how you set the problem up, everything looks correct, assuming that the initial values are 2.21 mol/L NO2 and 0.435 mol/L N2O4. Have you tried finding Kc again with your new values and see if it equals 11.2 again? It might indicate something went wrong with the quadratic equation. You mig...
- Sun Jan 17, 2021 10:06 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: cross multiplying after having a Kc and equillibrium contant
- Replies: 5
- Views: 31
Re: cross multiplying after having a Kc and equillibrium contant
Using cross multiplication is always allowed if you're trying to simplify an equation or figuring out a variable between two ratios. I'm interested to figure out how you used cross multiplication when one was a ratio and the other was a numerical value. Based on your given values, I would multiply {...
- Sun Jan 17, 2021 9:46 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #6 Week 2
- Replies: 1
- Views: 12
Re: Sapling #6 Week 2
For the salts, you have to recognize if their cations are part of strong or weak bases, and if their anions are part of strong or weak acids.
By comparing the relative strengths of these anions and cations, you can figure out if they are more acidic, basic, or neutral.
By comparing the relative strengths of these anions and cations, you can figure out if they are more acidic, basic, or neutral.
- Sun Jan 17, 2021 9:23 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE Box quadratic equation
- Replies: 10
- Views: 68
Re: ICE Box quadratic equation
If you plug in your value for x into any of the terms in the formula and the concentration comes out negative, then you know its extraneous because a negative concentration is physically impossible to occur. If I remember correctly, this means that the lower/negative value for x that you found is us...
- Sun Jan 17, 2021 9:17 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: changing volume by adding more solid reactants.
- Replies: 3
- Views: 23
Re: changing volume by adding more solid reactants.
I don't think solid or liquid reactants apply to Le Chatelier's principle, but I think you bring up an excellent point. I'm inclined to believe that it wouldn't change much because the professor didn't cover such an important detail, but I could be wrong.
- Sun Jan 10, 2021 11:03 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Video Module question 19
- Replies: 3
- Views: 25
Re: Video Module question 19
You need to divide the mols by 3.00L in order to get the concentrations for the gases. Other than that, you're spot on.
- Sun Jan 10, 2021 11:01 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5G.5 part a
- Replies: 2
- Views: 17
Re: 5G.5 part a
Since the amount of diatomic molecules and single atoms doesn't change after the third flask, I think it's safe to say that it means the reaction has reached equilibrium in the third flask.
edit: didn't notice your edit. oh well
edit: didn't notice your edit. oh well
- Sun Jan 10, 2021 10:44 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5G.1 part b
- Replies: 2
- Views: 11
Re: 5G.1 part b
That's correct. The reaction quotient would temporarily be unequal to the equilibrium constant
- Sun Jan 10, 2021 10:43 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling System of Equations
- Replies: 2
- Views: 8
Re: Sapling System of Equations
There should be two reactions that should match the given reactions, although you will have to multiply or reverse them.
- Sun Jan 10, 2021 10:26 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Getting a negative during quadratic
- Replies: 5
- Views: 70
Re: Getting a negative during quadratic
Did you make sure the value for c is negative? In my problem, Kp was 419 and initial pressure of PCl5 was 0.04 bar, which gave me (1) - 4((419) * (-0.04)) inside the square root, which gives me a positive number. It's sounds amazing that you got the right answer with imaginary numbers.
- Sun Jan 10, 2021 10:16 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Post Assessment Chemical Equilibrium Part 2 Question 30
- Replies: 2
- Views: 10
Re: Post Assessment Chemical Equilibrium Part 2 Question 30
The equilibrium concentration for hydrogen gas will be your starting point for filling out the ICE table. Since the hydrogen gas concentration at equilibrium is 0.040M, and you know the volume of the system is 50L, you can figure out how many moles of hydrogen gas was made to reach equilibrium. With...
- Sun Jan 10, 2021 9:41 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Le Chatelier's Principle
- Replies: 19
- Views: 135
Re: Le Chatelier's Principle
When an reversible reaction at equilibrium encounters a change in condition, the position of equilibrium moves in order to return the reversible reaction to equilibrium, favoring one side of the reaction over the other. If the concentration of one side increases, the reaction would proceed in the fo...
- Sun Jan 10, 2021 9:17 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: How to choose R
- Replies: 6
- Views: 62
Re: How to choose R
The right gas constant R depends on the units for pressure and volume that the question uses. For example, if the question has the pressures measured in atm and the volume measured in liters, you would need to use 0.082057 L*atm*mol^-1*K^-1 for R.
- Sat Dec 12, 2020 5:42 pm
- Forum: Hybridization
- Topic: 2F. 15 What does it mean for S-character to increase?
- Replies: 5
- Views: 107
Re: 2F. 15 What does it mean for S-character to increase?
Yes, the s-character is quantified just as you explained it. In terms of question 2F.15, it means that bond angle will increase as s-character increases, as an sp2 orbital has 33% s-character, while an sp3 orbital has 25% s-character. Thank you for your help! I don't remember learning about this in...
- Sat Dec 12, 2020 4:32 pm
- Forum: Hybridization
- Topic: 2F. 15 What does it mean for S-character to increase?
- Replies: 5
- Views: 107
Re: 2F. 15 What does it mean for S-character to increase?
Yes, the s-character is quantified just as you explained it. In terms of question 2F.15, it means that bond angle will increase as s-character increases, as an sp2 orbital has 33% s-character, while an sp3 orbital has 25% s-character.
- Sat Dec 12, 2020 11:52 am
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Radial/Angular nodes
- Replies: 3
- Views: 46
Re: Radial/Angular nodes
The total number of nodes is always one less than the principal quantum number, n. The number of angular nodes is equal to the second quantum number, l. With these two numbers, you can find the number of radial nodes it has. As for whether or not it will be on the final, we never covered it in our h...
- Sat Dec 12, 2020 11:36 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Steric #
- Replies: 3
- Views: 49
Re: Steric #
Yes, its the number of atoms bonded to the central atoms plus the number of lone pairs the central atom has
- Fri Dec 11, 2020 7:43 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Why is CH2Cl2 polar
- Replies: 6
- Views: 56
Re: Why is CH2Cl2 polar
As a lewis structure it would be possible. But as a 3d structure it would be impossible to place chlorine atoms opposite to each other in a tetrahedral shape, which makes it polar.
- Fri Dec 11, 2020 7:34 pm
- Forum: Lewis Structures
- Topic: 2E.29
- Replies: 2
- Views: 40
Re: 2E.29
Since the chlorine atoms are closer together in structure 1, they pull electrons in the same direction in a way that's closer compared to structure 2.
- Thu Dec 10, 2020 9:44 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Textbook 6B.1
- Replies: 8
- Views: 76
Re: Textbook 6B.1
You could use any number as long as the molar concentration of your second solution was 12% of your first.
- Thu Dec 10, 2020 9:32 pm
- Forum: Hybridization
- Topic: Textbook 2.57
- Replies: 1
- Views: 47
Re: Textbook 2.57
Hi Chloe, I'm not sure how to totally describe it with words, so I drew a picture instead. I think I labeled everything correctly. Edit: all the bonds with hydrogen and between the two carbon atoms are sigma bonds. The triple bond between carbon and nitrogen has two pi bonds and one sigma bond.
- Tue Dec 08, 2020 10:23 pm
- Forum: Conjugate Acids & Bases
- Topic: conjugate acids and bases
- Replies: 6
- Views: 49
Re: conjugate acids and bases
The conjugate acid is just the original compound with another H atom, while the conjugate base is the original compound but without an H atom. For HSO4-, the conjugate acid would be H2SO4, and the conjugate base would be SO4-2. Remember to keep track of the charges when you add and subtract hydrogen...
- Sun Dec 06, 2020 5:05 pm
- Forum: Naming
- Topic: Anion Naming
- Replies: 7
- Views: 81
Re: Anion Naming
I'm pretty sure that we only use the numerical prefixes (di-, tri-, tetra-) to describe the number of ligands, ie: what's inside the brackets. So what you're saying is correct.
- Sun Dec 06, 2020 4:53 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Sapling #3
- Replies: 7
- Views: 46
Re: Sapling #3
To add on, from what I've read it looks like hexagonal planar structures are basically unknown and can only be found in higher coordination structures like hexagonal bipyramids.
- Sun Dec 06, 2020 4:46 pm
- Forum: Naming
- Topic: Naming on the Final
- Replies: 4
- Views: 39
Re: Naming on the Final
Since the final questions will be from the textbook, and there are only 5 questions assigned for Naming, I assume that there won't be too many questions compared to the others. I still it would be important to remember the names of common ligands and prefixes, as well as the order you arrange them in.
- Sun Dec 06, 2020 4:43 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Sapling #3
- Replies: 7
- Views: 46
Re: Sapling #3
What the questions asks is what geometries are most common for coordination complexes with a coordination number of 6. Even though the other two are possible, they seem to be a lot rarer to find in nature.
- Sun Dec 06, 2020 4:11 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Coordination Number Vs. Oxidation Sates Question
- Replies: 3
- Views: 38
Re: Coordination Number Vs. Oxidation Sates Question
Coordination number is the number of ligands that are attached to the central metal atom, while oxidation state would be the charge of the central metal atom without its ligands and electron pairs
- Sun Dec 06, 2020 3:49 pm
- Forum: Naming
- Topic: Suffixes for Ligands
- Replies: 1
- Views: 45
Re: Suffixes for Ligands
Transition metals like iron have different names depending on its oxidation state. In Fe(CN)6-3, the iron is +3 so it's considered ferric. In Fe(CN)6-4 the iron is +2 and considered ferrous. If I remember correctly this is also the case for other metals like copper (cupric/cuprous) and lead (plumbic...
- Sun Nov 29, 2020 11:58 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Rings and cyclic structures
- Replies: 2
- Views: 31
Re: Rings and cyclic structures
Ring structures are just atoms connected to each other in a way to forms a "ring." Note in my crude drawing of benzene how the carbons are connected in this way.
- Sun Nov 29, 2020 10:30 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling #3
- Replies: 4
- Views: 46
Re: Sapling #3
That would be correct if the molecule had 2 lone pairs. However, since it has three lone pairs, the lone pairs occupy the equatorial positions and forces the "x" atoms into the axial positions. This is what makes them linear.
- Sun Nov 29, 2020 10:17 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling #3
- Replies: 3
- Views: 36
Re: Sapling #3
You are correct in thinking that the smallest bond angle is less than 90 degrees. The question just asks for the approximate smallest bond angle based on VSEPR theory since you would need to figure it out experimentally to get the accurate answer, so 90 degrees suffices.
- Sun Nov 29, 2020 8:56 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Polar
- Replies: 10
- Views: 93
Re: Polar
The type of atoms and its molecular shape help contribute to determining its polarity
- Sun Nov 29, 2020 8:50 pm
- Forum: Hybridization
- Topic: hybridization, but very simple
- Replies: 9
- Views: 54
Re: hybridization, but very simple
Basically. Just count groups of bonds and lone pairs.
- Sun Nov 29, 2020 8:14 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Resonance Structure Definition
- Replies: 9
- Views: 81
Re: Resonance Structure Definition
The overall structures of atoms don't change but their bonds (single/double/triple) can change
- Thu Nov 26, 2020 11:06 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling Question #6 (Week 8)
- Replies: 5
- Views: 56
Re: Sapling Question #6 (Week 8)
From what I understand, lone-pair repulsion is greater than bond-pair repulsion, so in order to stay the farthest away from each other, the lone pairs take up the equatorial plane instead of the axial plane.
- Sun Nov 22, 2020 10:28 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling #1
- Replies: 6
- Views: 69
Re: Sapling #1
Since the carbonate ion has three bonding pairs, they repel each other to form a trigonal plane. However, the sulfite also has a lone pair. In order to accommodate the lone pair in 3D space, the three bonding pairs are repelled downwards to form a trigonal pyramid.
- Sun Nov 22, 2020 10:03 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: memorizing VSEPR models
- Replies: 13
- Views: 83
Re: memorizing VSEPR models
I don't think there is any better way to memorize the VSEPR models beyond simply memorizing the shapes of the models, but I think it might be helpful to think about how each name describes the structure of the bonding pairs and how the lone pairs contributes to each model's shape.
- Sun Nov 22, 2020 8:39 pm
- Forum: Hybridization
- Topic: Hybridization and Covalent Bonds
- Replies: 2
- Views: 25
Re: Hybridization and Covalent Bonds
That's right, ionic bonds doesn't require hybridizations
- Sun Nov 22, 2020 8:36 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling #13
- Replies: 3
- Views: 33
Re: Sapling #13
We're supposed to look at the geometry of the individual carbon atoms. If you move the structure around you can see that it is bonded to two hydrogen atoms and two other carbon atoms. Since it does not have any lone pairs attached to it, its geometry is tetrahedral.
- Sun Nov 22, 2020 8:29 pm
- Forum: Hybridization
- Topic: Sapling#11
- Replies: 6
- Views: 32
Re: Sapling#11
It has 3 bonded atoms and one lone pair, so 4 hybrid orbitals are needed.
- Sun Nov 22, 2020 8:13 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Ring structures (Sapling Q17)
- Replies: 3
- Views: 17
Re: Ring structures (Sapling Q17)
You make a ring with the three carbons bonded together, with a double bond between two of them. Then attach the hydrogens wherever needed.
- Sun Nov 15, 2020 11:40 pm
- Forum: Ionic & Covalent Bonds
- Topic: Workshop Hydrogen Bonding Question
- Replies: 4
- Views: 34
Re: Workshop Hydrogen Bonding Question
Hydrogens bonded with carbon don't participate in hydrogen bonding because their electronegative difference isn't significant enough to form a dipole.
- Sun Nov 15, 2020 11:24 pm
- Forum: Lewis Structures
- Topic: Hydrogen Bonding
- Replies: 12
- Views: 66
Re: Hydrogen Bonding
The electronegativity difference between carbon and hydrogen isn't significant enough to create a dipole compared to something like oxygen and hydrogen.
- Sun Nov 15, 2020 11:15 pm
- Forum: Dipole Moments
- Topic: London Dispersion Forces
- Replies: 4
- Views: 16
Re: London Dispersion Forces
London dispersion forces are present in all molecules because the electrons are always moving around a nucleus, sometimes creating temporary dipoles when they group up on one side of the nucleus. This means that even nonpolar molecules still experience intermolecular attraction through London disper...
- Sun Nov 15, 2020 11:05 pm
- Forum: Dipole Moments
- Topic: Homework Problem 3F.13
- Replies: 1
- Views: 12
Re: Homework Problem 3F.13
For starters, since Cl is a lot more electronegative compared to C, it creates a dipole where electrons tend to favor the Cl side of its covalent bond with carbon. This makes Cl more negatively charged, and carbon positively charged. Therefore, the strongest intermolecular attractions would be prese...
- Sun Nov 15, 2020 10:33 pm
- Forum: Bond Lengths & Energies
- Topic: Bond Character
- Replies: 3
- Views: 37
Re: Bond Character
I think this post helps describe it best: viewtopic.php?f=31&t=67475
Essentially, ample bond character seems to imply that it is somewhat similar to what is observed, while overwhelming bond character would be extremely similar.
Essentially, ample bond character seems to imply that it is somewhat similar to what is observed, while overwhelming bond character would be extremely similar.
- Sun Nov 15, 2020 11:20 am
- Forum: Formal Charge and Oxidation Numbers
- Topic: Sapling Week 5/6 #9
- Replies: 2
- Views: 51
Re: Sapling Week 5/6 #9
Since oxygen has a oxidation number of -2 when bonded to chlorine, and the sum of oxidation numbers must equal the total charge, we find that chlorine has an oxidation number of +7, which is its formal charge. SInce there isn't a diagram with a Cl+7 ion, we just look for the next best thing, which w...
- Sun Nov 08, 2020 11:12 pm
- Forum: Lewis Structures
- Topic: Bond Character
- Replies: 6
- Views: 83
Re: Bond Character
Are ample/overwhelming actually scientific terms used to describe bond character or was it only used in that problem in order to differentiate between being slightly close and extremely close to the bond lengths?
- Sun Nov 08, 2020 9:49 pm
- Forum: Lewis Structures
- Topic: nitrate lewis structure
- Replies: 7
- Views: 65
Re: nitrate lewis structure
The nitrogen would have 5 bonds, which violates the octet rule. Second period elements always have to follow it without exceptions.
- Sun Nov 08, 2020 9:45 pm
- Forum: Ionic & Covalent Bonds
- Topic: Electron Affinity
- Replies: 8
- Views: 73
Re: Electron Affinity
Electron affinity is a measurement of energy released in attaching an electron to a neutral gas atom/molecule. This helps us determine whether or not an atom/molecule is an electron acceptor or donor
- Sun Nov 08, 2020 9:26 pm
- Forum: Ionic & Covalent Bonds
- Topic: formal charge
- Replies: 8
- Views: 40
Re: formal charge
It helps us determine what is the most representative Lewis structure based on how close the overall formal charge of the structure is to zero
- Sun Nov 08, 2020 8:33 pm
- Forum: Lewis Structures
- Topic: structure of (CO3)2-
- Replies: 4
- Views: 25
Re: structure of (CO3)2-
Since carbon has 4 valence electrons, it will usually share all of them with the oxygen atoms in order to fill its outer shell and avoid any formal charges. Sharing 4 electrons between the three oxygen atoms means that one of them will form a double bond with carbon with 2 of its shared electrons, a...
- Sun Nov 08, 2020 8:13 pm
- Forum: Bond Lengths & Energies
- Topic: Bond length
- Replies: 11
- Views: 41
Re: Bond length
The order goes: triple>double>single.
Since there are more electrons being shared in double bonds, there is a greater attraction between the nuclei of the bonding atoms than we would see in a single bond.
Since there are more electrons being shared in double bonds, there is a greater attraction between the nuclei of the bonding atoms than we would see in a single bond.
- Sun Nov 01, 2020 10:21 pm
- Forum: DeBroglie Equation
- Topic: When to use de Broglie and what numbers to use
- Replies: 8
- Views: 57
Re: When to use de Broglie and what numbers to use
They are two constants to find different things. 3.29 x 10^15 is used in Hz in order to find the frequency of a given line, while 1.0974*10^-7 m^-1 is used to find 1/wavelength
- Sun Nov 01, 2020 10:12 pm
- Forum: Properties of Light
- Topic: Wavelenght
- Replies: 17
- Views: 116
Re: Wavelenght
Gamma rays have the highest amount of energy out of any of the EM waves because of its incredibly high frequency. Because of this, it has the shortest wavelength.
- Sun Nov 01, 2020 10:04 pm
- Forum: Accuracy, Precision, Mole, Other Definitions
- Topic: Avogadro constant
- Replies: 16
- Views: 187
Re: Avogadro constant
You can also find the mass of a single atom by dividing its molar mass with Avogadro's constant
- Sun Nov 01, 2020 10:01 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Sapling 26
- Replies: 8
- Views: 86
Re: Sapling 26
I kept getting this problem wrong as well until I realized my unit conversions were incorrect. It's important to make sure that mass is in kg and position in meters.
- Sun Nov 01, 2020 9:55 pm
- Forum: Properties of Light
- Topic: How to remember what v is in equations
- Replies: 46
- Views: 277
Re: How to remember what v is in equations
velocity is a lowercase v, while frequency is curved. I think it helps that in most of the equations so far, v (for velocity) deals with the movement of electrons, and v (for frequency) deals with light
- Sun Oct 11, 2020 10:16 pm
- Forum: Significant Figures
- Topic: What is the purpose of significant figures?
- Replies: 11
- Views: 120
Re: What is the purpose of significant figures?
I think it helps you describe how precise your answer or measurement is. For example if you obtained measurements with a lot of sig figs (precise) and measurements with very few (imprecise) in an experiment, it would be safer to opt for the less precise sig figs in order to highlight the imprecision...
- Sun Oct 11, 2020 10:05 pm
- Forum: SI Units, Unit Conversions
- Topic: Avogadro's Constant
- Replies: 12
- Views: 128
Re: Avogadro's Constant
Since atomic units are incredibly small and hard to measure, we use Avogadro's constant to convert them to moles, which are easier to physically measure