Search found 78 matches
- Wed Dec 09, 2020 11:19 am
- Forum: Sigma & Pi Bonds
- Topic: textbook #2.45
- Replies: 2
- Views: 39
Re: textbook #2.45
Another thing to remember is that single bonds are sigma bonds, double bonds consist of 1 sigma and 1 pi bond, and triple bonds consist of 2 pi bonds and 1 sigma bond. To determine the hybridization, you would consider both the number of lone pairs and the number of bonded atoms.
- Wed Dec 09, 2020 11:16 am
- Forum: Bronsted Acids & Bases
- Topic: why is HCl a strong acid?
- Replies: 2
- Views: 23
why is HCl a strong acid?
Hello, Could someone please explain why HCl is a strong acid? I understand that by definition, it's strong because it readily gives off a proton to form H+ and Cl-, but why does it do this? Since Cl have 7 valence electrons and H has 1 valence electrons, aren't they more stable in the combined/depro...
- Wed Dec 09, 2020 10:31 am
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Textbook 6C.19
- Replies: 3
- Views: 36
Re: Textbook 6C.19
Hello! As explained by the Lowry-Bronsted concept, a strong acid has a weak conjugate base and a weak acid has a strong (more stable) conjugate base. The weaker conjugate base will be less inclined to take up a proton, so the molecule will remain deprotonated and will make the solution more acidic (...
- Wed Dec 09, 2020 9:06 am
- Forum: Lewis Acids & Bases
- Topic: Lewis Acid and Base in Reaction
- Replies: 4
- Views: 36
Re: Lewis Acid and Base in Reaction
A Lewis acid can accept a pair of nonbonding electrons and a Lewis base can donate a pair of nonbonding electrons. In the example, you can see that NH3 has a lone pair of electrons. The BF3 can react with it to form the stable compound NH3BF3 The NH3 acts as a Lewis acid and the BF3 acts as a Lewis ...
- Wed Dec 09, 2020 8:57 am
- Forum: Identifying Acidic & Basic Salts
- Topic: Neutralization Reactions
- Replies: 2
- Views: 26
Re: Neutralization Reactions
In a neutralization reaction, H+ and OH- ions combine to generate water. Salts are formed from neutralization reactions with acids and bases that are in equal concentrations. If a strong acid combines with a weak acid, the pH will be 7. Strong acid + weak base --> pH less than 7 and weak acid + stro...
- Wed Dec 09, 2020 8:52 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: pH to pOH
- Replies: 8
- Views: 88
Re: pH to pOH
Yes, this is correct. This is because the concentration of pH times the concentration of POH must equal to to the equilibrium constant for the ionization of water, which is 1.0 x 10^-14. If you take the log of both sides and simplify, you would get pH + pOH =14. We use pH and pOH because representin...
- Tue Dec 08, 2020 11:03 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: classifying weak/strong acids and bases
- Replies: 2
- Views: 10
classifying weak/strong acids and bases
Could someone please explain why this is incorrect?
- Thu Dec 03, 2020 10:19 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Difference between electron geometry and molecular geometry
- Replies: 5
- Views: 31
Re: Difference between electron geometry and molecular geometry
It's also important to note that the placement of both atoms and lone electrons helps determine the molecular geometric shape. This is because the location of the lone electron pairs can change the bond angles between atoms (the electrons have a greater repulsion than bonded atoms).
- Thu Dec 03, 2020 10:14 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Textbook question 2E. 1
- Replies: 3
- Views: 27
Re: Textbook question 2E. 1
The molecular structure can be linear if there are only electron pairs (no atoms) in the equatorial plane and only the axial atoms remain. In this case, the atoms would be at the max distance apart possible (the bond angle between then would be 180 degrees). Also, the electron repulsion would be min...
- Thu Dec 03, 2020 10:09 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: VSEPR and Resonance
- Replies: 1
- Views: 18
Re: VSEPR and Resonance
Hi! Here is a really helpful pic Your structure is correct. The structure with 2 double bonds minimizes the differences in formal charges because in the all-single bond structure, the I has a +2 charge and the Os all have -1 charges. In the double bond structure, 2 Os has 0 charge, one O has -1 char...
- Thu Dec 03, 2020 9:56 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Shape--VSEPR > Hybridization?
- Replies: 2
- Views: 8
Re: Shape--VSEPR > Hybridization?
VSEPR helps determine the molecular shape. It is based on the fact that molecules tend to achieve a geometry that minimizes the repulsion of valence electrons. On the other hand, hybridization refers to atomic orbitals mixing to reach the lowest overall energy states. It explains why atomic orbitals...
- Thu Dec 03, 2020 3:59 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: how is CO3(-2) both mono and bi-dente?
- Replies: 2
- Views: 48
how is CO3(-2) both mono and bi-dente?
Hello,
Could someone explain why CO3 (2-) is both mono- and bi-dente?
Could someone explain why CO3 (2-) is both mono- and bi-dente?
- Wed Dec 02, 2020 3:18 pm
- Forum: Naming
- Topic: Sapling Question 6
- Replies: 4
- Views: 57
Re: Sapling Question 6
Here's an example: in [Co(NH3)5)Cl]Cl2
The Cl- inside the brackets has a negative 1 charge and the Cl2 outside of the brackets has a combined -2 charge. -1 + -2 is -3. The overall coordination complex must be neutral so you know that Co must have a +3 charge to counteract the -3 charge.
The Cl- inside the brackets has a negative 1 charge and the Cl2 outside of the brackets has a combined -2 charge. -1 + -2 is -3. The overall coordination complex must be neutral so you know that Co must have a +3 charge to counteract the -3 charge.
- Wed Dec 02, 2020 2:59 pm
- Forum: Naming
- Topic: what does (en) mean?
- Replies: 23
- Views: 201
what does (en) mean?
Could someone please explain what the (en) means in Cd(en)Br2] ?
- Mon Nov 30, 2020 4:33 pm
- Forum: Hybridization
- Topic: how hybridization matches bond formation
- Replies: 7
- Views: 40
how hybridization matches bond formation
Could someone please explain this statement from the textbook?
The concept of hybridization enables the description of bond formation to be matched to the observed molecular shape.
The concept of hybridization enables the description of bond formation to be matched to the observed molecular shape.
- Tue Nov 24, 2020 12:01 pm
- Forum: Hybridization
- Topic: Hybridization Clarification
- Replies: 9
- Views: 83
Re: Hybridization Clarification
Hybridization refers to the mixing of orbitals to create new hybrid orbitals that have an energy that is in between the 2 starting orbitals. For instance, one s and one p can mix to form 1 sp orbital or 2s and 2p^3 can mix to create four 2sp^3 orbitals. In other words, hybridization happens when the...
- Tue Nov 24, 2020 11:56 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Negative Poles on Molecules
- Replies: 2
- Views: 13
Re: Negative Poles on Molecules
You can determine negative poles by considering differences in electronegativity. In COF2, for instance, the negative pole will be between the two F atoms because F is more electronegative than O. In COHF, it will be between the O and the F (but closer to the F) because those two atoms are much more...
- Tue Nov 24, 2020 10:47 am
- Forum: Hybridization
- Topic: Lecture 23 question
- Replies: 5
- Views: 55
Re: Lecture 23 question
The valence electrons are the ones responsible for molecular shape because they are the ones that actually determine bonding. The n=1 shell is not the valence shell; the n=2 shell is so we only consider the subshells in that shell.
- Tue Nov 24, 2020 10:20 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: regions of electron density
- Replies: 7
- Views: 66
Re: regions of electron density
Another thing to remember is that lone pair electrons contribute to the shape of a molecule, but they are not considered when determining the name of the molecular shape. The lone pairs also have greater repulsion than the bonds. So while both bonds and lone pairs are both considered regions of elec...
- Tue Nov 24, 2020 9:11 am
- Forum: Resonance Structures
- Topic: Atom Connectivities
- Replies: 5
- Views: 56
Re: Atom Connectivities
Connectivity refers to how atoms are connected/arranged. If 2 molecules have the same molecular formula, but different connectivity, they would be called constitutional isomers. Isomers are molecules that have the same formula but different shapes. Here's an example to illustrate the concept: 2-meth...
- Tue Nov 24, 2020 9:03 am
- Forum: Hybridization
- Topic: Lecture example ethene
- Replies: 9
- Views: 111
Re: Lecture example ethene
The 2p and 2sp^2 orbitals a smaller energy gap between them than 2s and 2p because the 2sp^2 hybridized orbital is found in between the 2s and 2p orbitals. Atoms forms hybridized orbitals because it makes the resulting molecule more stable (lower potential energy) because it allows the regions of el...
- Tue Nov 24, 2020 8:57 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Determining Molecular Polarity using VSEPR
- Replies: 8
- Views: 72
Re: Determining Molecular Polarity using VSEPR
CO2 has a total of 4+6+6=16 valence electrons. If we draw the Lewis structure, it would look like this: ::O=C=O:: We see that carbon has 2 regions of electron density, which corresponds to a linear shape. It would be nonpolar because the O and the O are directly opposite each other (form a 180 degre...
- Tue Nov 24, 2020 8:50 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sampling Week 7/8 #6
- Replies: 6
- Views: 48
Re: Sampling Week 7/8 #6
It would only be a linear shape if the regions of electron density were confined to a 2D space: a plane. Then, the arrangement would be square planar and the angle between each region of electron density would be about 90 degrees and the angle between the 2 atoms would be 180 degrees (linear). But, ...
- Mon Nov 16, 2020 2:11 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Quantum number ms
- Replies: 3
- Views: 38
Re: Quantum number ms
The convention is to write that electrons fill spin up first. Make sure that you keep the spin consistent until you have filled all the orbitals with one electron (e.g. in the 3 orbitals of the p subshell, fill them up, up, up, down, down, down and not something like up, down, up --> down, up, down)...
- Mon Nov 16, 2020 2:00 pm
- Forum: Dipole Moments
- Topic: london dispersion forces
- Replies: 5
- Views: 46
Re: london dispersion forces
All molecules exhibit London dispersion forces, but nonpolar molecules are the only ones with only London Dispersion Forces because they don't have any permanent dipoles (since the atoms have equal electronegativities). For instance, Cl2 molecules would have LDFs between them. Temporary uneven elect...
- Mon Nov 16, 2020 1:54 pm
- Forum: Trends in The Periodic Table
- Topic: Oxygen Exception Ionization Energy
- Replies: 12
- Views: 92
Re: Oxygen Exception Ionization Energy
Oxygen has the electron configuration 1s^2 2s^2 2p^3, so the p shell is half. Nitrogen, on the other hand, has the electron configuration 1s^2 2s^2 2p^4. In oxygen, each electron in the p shell occupies its own shell while in nitrogen, there are two electrons in one of the orbitals, which results in...
- Mon Nov 16, 2020 11:09 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Effective Nuclear Charge
- Replies: 6
- Views: 53
Re: Effective Nuclear Charge
The electrons in shells between the electron of interest and the nucleus can shield the electron from the nucleus's positive charge. This is called effective nuclear charge (zeff) Here's an example: sodium's (Na) nucleus has a charge of 11. There are 2 electrons in the first shell, 8 in the second, ...
- Mon Nov 16, 2020 10:53 am
- Forum: Administrative Questions and Class Announcements
- Topic: Matthew's Workshop - Week 6
- Replies: 2
- Views: 229
Re: Matthew's Workshop - Week 6
Hi,
Is there an answer key to this worksheet?
Is there an answer key to this worksheet?
- Mon Nov 16, 2020 10:09 am
- Forum: Lewis Structures
- Topic: Lewis Structure w/ 4+ atoms
- Replies: 4
- Views: 59
Re: Lewis Structure w/ 4+ atoms
One other thing that helps me is remembering patterns. For instance, if there is an OH functional group, the oxygen is usually attached to the central atom and the hydrogen is attached to the O. In the COOH functional group, the two Os are attached to the C (one with a double bond and the other with...
- Mon Nov 16, 2020 9:58 am
- Forum: Polarisability of Anions, The Polarizing Power of Cations
- Topic: dipole moments
- Replies: 10
- Views: 60
Re: dipole moments
Follow Dr. Lavelle! The arrow should be pointing towards the negative dipole, because it indicates where electrons are being pulled. What determines the negative dipole again? The more electronegative atom has the negative dipole because it pulls electrons toward itself more! Electronegativity incr...
- Mon Nov 16, 2020 9:44 am
- Forum: Lewis Structures
- Topic: textbook problem 2C.13: ClO2
- Replies: 3
- Views: 11
textbook problem 2C.13: ClO2
Hi! For the Lewis structure of ClO2, how do we determine that the lone electron belongs to the central chlorine atom and not one of the oxygen atoms? There are 7+2(6)=19 valence electrons total, so we know that one atom will have an incomplete octet, but how do we know which one?
- Tue Nov 10, 2020 10:01 pm
- Forum: Electronegativity
- Topic: Sapling #15
- Replies: 9
- Views: 94
Re: Sapling #15
F, N, and O are very electronegative because they only need one electron to achieve an octet. Thus, they have a very high affinity for electrons and tend to have a large partial negative charge that attracts the partial charge of a Hydrogen atom.
- Tue Nov 10, 2020 9:59 pm
- Forum: Bond Lengths & Energies
- Topic: electron affinity
- Replies: 2
- Views: 25
Re: electron affinity
It has lower energy (a bigger negative value) because it takes that much energy to ionize it. As an electron moves away from the nucleus, its energy approaches 0. Electrons closer to the nucleus are harder to remove because their negative charge is attracted to the positive charge of the protons. It...
- Tue Nov 10, 2020 9:52 pm
- Forum: Octet Exceptions
- Topic: electron deficiency
- Replies: 2
- Views: 24
Re: electron deficiency
Electron deficient means (at least for the elements we're focusing on) that the atom doesn't have a full octet of valence electrons. Boron and Aluminum are electron deficient because they only receive 6 electrons when they bond with other atoms to form molecules. For instance, in AlH3, the Al only h...
- Tue Nov 10, 2020 8:17 pm
- Forum: Student Social/Study Group
- Topic: Exercising Our Minds and Bodies
- Replies: 120
- Views: 633
Re: Exercising Our Minds and Bodies
I love going on runs, especially on hiking trails with pretty viewpoints or during sunset. I also stretch.
- Tue Nov 10, 2020 8:16 pm
- Forum: Coordinate Covalent Bonds
- Topic: General Question on Coordinate Covalent Bonds
- Replies: 8
- Views: 82
Re: General Question on Coordinate Covalent Bonds
I think a coordinate covalent bond is when one atom donates both electrons (for instance in the bond between BF3 and NH3, the the two electrons in the bond both come from NH3. On the other hand, in the bond between two oxygen atoms, the oxygen atoms contribute 1 electron each (regular covalent bond).
- Tue Nov 10, 2020 8:12 pm
- Forum: Electronegativity
- Topic: Electronegativity Difference for Covalent and Ionic Bonds
- Replies: 6
- Views: 37
Re: Electronegativity Difference for Covalent and Ionic Bonds
If the value is between 1.5 and 2, we have to examine the bond more closely to determine whether is is more ionic or covalent. But, since the electronegativity for one of the atoms is much greater, the partial charges will be more defined/distinct and the molecule will be more polar.
- Tue Nov 10, 2020 8:07 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: 4s before 3d?
- Replies: 6
- Views: 93
Re: 4s before 3d?
Another thing to remember is that full orbitals are generally more stable than half filled ones, which are generally more stable than partially filled ones. For instance, Zn, which has the electron configuration [Ar] 4s^2 3p^10, will be more likely to lose 2 electrons from 4s^2 than 3p^10. Also, eac...
- Tue Nov 10, 2020 7:49 pm
- Forum: Bond Lengths & Energies
- Topic: reactive
- Replies: 10
- Views: 84
Re: reactive
Here are some additional details: Double and triple bonds are also stronger because they restrict electron mobility around the nucleus, thus increasing stability (because of their pi bonds). This is because pi bonds are created by p orbitals (lobe shaped) Single bonds (sigma bonds) however, permit t...
- Wed Nov 04, 2020 12:12 pm
- Forum: Octet Exceptions
- Topic: Exceptions List
- Replies: 4
- Views: 77
Re: Exceptions List
Here are the common ones we should know: H, He, Li, and Be all want the He noble gas configuration (which only has 2 valence electrons since it only has the n=1 shell). B and Al often only need 6 electrons. compounds with 7 valence electrons (notably, N) can form free radicals with an unpaired elect...
- Wed Nov 04, 2020 12:07 pm
- Forum: Octet Exceptions
- Topic: Covalent Bonding with elements in period 3+
- Replies: 3
- Views: 45
Re: Covalent Bonding with elements in period 3+
The electron configuration for Sulfur is1s^2 2s^2 2p^6 3s^2 3p^4. Sulfur thus has 6 valence electrons because that's how many are in the third shell (when n=3). The electrons in the 1st and the 2nd shell won't participate in bonding. I think you meant to say the fourth period. Let's use scandium as ...
- Wed Nov 04, 2020 11:54 am
- Forum: Resonance Structures
- Topic: Delocalized Electrons
- Replies: 2
- Views: 31
Re: Delocalized Electrons
This means that the electrons aren't strictly associated with a single atom or a single covalent bond. Delocalized electrons are sometimes indicated by a circle (like for benzene). On the other hand, localized electrons tend to stick around a single atom. Delocalized electrons are seen when a molecu...
- Wed Nov 04, 2020 11:50 am
- Forum: Lewis Structures
- Topic: How do we know when an element will have more than 8 electrons?
- Replies: 6
- Views: 29
Re: How do we know when an element will have more than 8 electrons?
One way to know is by examining the formal charge, which is FC= V (L+ s/2). L represents lone pair electrons and s represents shared electrons. The closer the formal charge is to 0, the more stable the element is. Usually, elements with an atomic number less than 20 form an octet (based on their orb...
- Wed Nov 04, 2020 11:39 am
- Forum: Octet Exceptions
- Topic: Radicals
- Replies: 5
- Views: 61
Re: Radicals
Can someone elaborate more on what radicals are? From what I understand, they are just atoms that are electron-deficient, but if I am missing another essential part of its definition, please let me know! To answer your question, radicals are compounds with unpaired electrons. As a guideline, we kno...
- Wed Nov 04, 2020 11:34 am
- Forum: Octet Exceptions
- Topic: Radicals
- Replies: 5
- Views: 61
Re: Radicals
Some causes of free radical formation inside out body are toxic chemicals (like pollutants and pesticides), smoking, alcohol and fried foods. Fats and oils (especially saturated ones) can undergo oxidation when they're exposed to light, air, or heat (for instance, during the frying process). The fat...
- Wed Nov 04, 2020 10:32 am
- Forum: Octet Exceptions
- Topic: Expanded Octet of Phosphorus
- Replies: 4
- Views: 48
Re: Expanded Octet of Phosphorus
Phosphorus is in the third row of the periodic table (where n=3). Going back to last week, we talked about how the third shell can have three possible sublevels (l=0, l=1, and l=2). The l=0 orbital corresponds to 1 orbital, l=2 is 3 orbitals, and l=3 is 5 orbitals). The s-and p- orbitals (correspond...
- Sat Oct 31, 2020 1:33 pm
- Forum: Trends in The Periodic Table
- Topic: Ionization Energy & Electron Affinity Relationship
- Replies: 3
- Views: 33
Re: Ionization Energy & Electron Affinity Relationship
Another thing to remember is that noble gases have 0 electron affinity because they don't want to gain an electron (since they already have a full shell). However, they have the highest ionization energy because it takes the most energy to remove an electron from them. Besides that, noble gases have...
- Fri Oct 30, 2020 11:25 am
- Forum: Trends in The Periodic Table
- Topic: Electron Affinity
- Replies: 9
- Views: 86
Re: Electron Affinity
To add on, electron affinity is reported as a negative value because it represents the energy released when an atom gains an electron. In other words, it represents how favorable it is for an atom to gain an electron (e.g. it is favorable if it helps the atom reach a noble gas electron configuration...
- Fri Oct 30, 2020 11:19 am
- Forum: DeBroglie Equation
- Topic: Sapling Homework Week 2,3,4 No. 25b
- Replies: 2
- Views: 42
Re: Sapling Homework Week 2,3,4 No. 25b
To get the energy of the electron, first use the DeBroglie equation (wavelength= h/(mv)) to calculate the velocity of the electron (convert 2.3 μm into meters first and use 9.109 x 10^31 for the mass of the electron). Then, use the equation E= 0.5m (v^2) to solve for the energy. Good luck! An import...
- Thu Oct 29, 2020 3:20 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Question 1D.25
- Replies: 6
- Views: 51
Re: Question 1D.25
Hi! The first shell (when n=1) has 1 subshell (s) The second shell (when n=2) has 2 subshells (s and l) The third shell (when n=3) has 3 subshells (s, l and d) The fourth shell (when n=4) has 4 subshells (s, l, d and f) As a result, we can't have a 2d subshell because the 2nd shell doesn't have the ...
- Thu Oct 29, 2020 8:57 am
- Forum: DeBroglie Equation
- Topic: Week 2,3,3 Sampling #25
- Replies: 2
- Views: 47
Re: Week 2,3,3 Sampling #25
I also wanted to add that you can use c=vλ and E=hv when calculating whether an electron can be ejected because electrons absorb the energy of a photon that strikes them. For instance, an energy of light (hv) that equals the work threshold of a metal could eject the electrons (= the energy the elect...
- Thu Oct 29, 2020 7:46 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: 3d and 4s orbitals
- Replies: 9
- Views: 100
Re: 3d and 4s orbitals
Hi! 4s is written first in the filling order because it gets filled before 3d (you can tell because the 4s section is before the 3d section on the periodic table). However, 4s would be written first in the proper order. Electrons would be lost from the proper order. Here's an example: [Ar] 3d^10 4s^...
- Sun Oct 25, 2020 2:32 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: 1E.5 electrons penetrating the nucleus
- Replies: 1
- Views: 18
1E.5 electrons penetrating the nucleus
For question 1E.5 in the textbook, it says that electrons in an s-orbital are more effective than those in other orbitals at shielding other electrons from the nuclear charge because an electron in an s-orbital can penetrate to the nucleus of the atom. Can someone please explain how an electron can ...
- Fri Oct 23, 2020 12:11 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: wavefunction squared = probability density
- Replies: 2
- Views: 50
wavefunction squared = probability density
Hello, Could someone please clarify why exactly the wavefunction squared is equal to the probability density of electrons? I understand what wave function squared means "the probability of finding a particle described by a specific wave function at a given point and time", but I'm not sure...
- Wed Oct 21, 2020 11:31 am
- Forum: *Particle in a Box
- Topic: zero-point energy textbook question
- Replies: 1
- Views: 54
zero-point energy textbook question
The textbook says "a particle in a container cannot have zero energy. Because the lowest allowed value of n is 1 (corresponding to a wave of one-half wavelength fitting into the box), the lowest energy is E 1 = h^2 / 8mL^2. This lowest possible energy is called the zero-point energy. The existe...
- Tue Oct 20, 2020 8:33 pm
- Forum: General Science Questions
- Topic: Rydberg Formula
- Replies: 6
- Views: 63
Re: Rydberg Formula
When using the equation 1/λ = RZ^2(1/n1^2 - 1/n2^2) , you would plug in R=1.097 x 10^7/m. When using the equation v=R[1/n12-1/n22, you would plug in R= 3.29 x 10^15 Hz. I think there are different variations because the units are different. I found that this question was also asked on Chem Community...
- Tue Oct 20, 2020 8:22 pm
- Forum: Photoelectric Effect
- Topic: Sapling Hw #5
- Replies: 3
- Views: 181
Re: Sapling Hw #5
4.86x10^-20 is not the energy per photon; it is the combined energy of all the photons in the light. So, it is equal to hv times the number of photons. E=h x frequency (for one electron), but E (total for all electrons) = hv times the number of photons. 15.77 J = 4.86x10^-20/x Solving for x would gi...
- Tue Oct 20, 2020 8:13 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Sapling Q8
- Replies: 1
- Views: 14
Re: Sapling Q8
The emission of visible light corresponds to a photon dropping from an excited state to the 2nd orbital (the Balmer series). Thus, you know that the final/lower n value would be n=2. Now you need to find the initial/higher n value. To find this, you can use the equation frequency= R(1/(n1)^2 -(1/(n2...
- Tue Oct 20, 2020 9:13 am
- Forum: Photoelectric Effect
- Topic: Applications of the photoelectric effect
- Replies: 2
- Views: 27
Re: Applications of the photoelectric effect
The photoelectric effect helped revolutionize our understanding about the behavior/structure of light and subatomic particles. It helped lead to technologies such as: -imaging technology, like television camera tubes or image intensifiers -photocopiers -light meters -photocells, photoconductive devi...
- Tue Oct 20, 2020 8:56 am
- Forum: Photoelectric Effect
- Topic: Fun with Kinetic Energy
- Replies: 2
- Views: 28
Re: Fun with Kinetic Energy
Hello! 1. Consider the equation E (kinetic) = E (photon) - work function. E (photon) is h x frequency. You know that the kinetic energy of the electrons would be 1.25 eV. Convert that to Joules by using the relationship 1eV=1.62 x 10^-19 Joules. You can also find the energy of the photon since you k...
- Tue Oct 20, 2020 8:47 am
- Forum: Properties of Electrons
- Topic: Electron model as a circular standing wave
- Replies: 2
- Views: 28
Electron model as a circular standing wave
During the lecture, Professor Lavelle described that an electron can be modeled as a circular standing wave. Could someone please clarify how this model was derived? I understand that the circular model fits the prediction that waves must be in phase if only certain quantized energy levels are allow...
- Thu Oct 15, 2020 8:32 am
- Forum: Photoelectric Effect
- Topic: Frequency vs. Intensity
- Replies: 16
- Views: 133
Re: Frequency vs. Intensity
Intensity corresponds to the amplitude of the wave (how high it is). It is defined as the distance from the crest or trough of a wave to the baseline (center line). For a classical wave, an increase in amplitude would correspond to an increase in energy. Frequency, on the other hand, is the number o...
- Thu Oct 15, 2020 8:23 am
- Forum: Properties of Light
- Topic: Problem 1A.15
- Replies: 3
- Views: 71
Re: Problem 1A.15
The UV spectrum of the hydrogen atom corresponds to the Lyman series, which represents a jump to the principle quantum energy level n=1. first, you would find the frequency of the 102.6 nm wave using the equation: frequency= c/lambda. Then, you can solve for the initial energy level (from which the ...
- Tue Oct 13, 2020 4:13 pm
- Forum: Properties of Electrons
- Topic: Homework Question 4
- Replies: 2
- Views: 23
Re: Homework Question 4
You would divide the total energy of the photons by the work function. The equation Ek= hv - phi gives us the kinetic energy that one ejected electron will have. The energy to eject one of this electrons from the metal, however, is simply phi. It takes 7.23×10−7 J to eject an unknown number of elect...
- Tue Oct 13, 2020 4:09 pm
- Forum: Properties of Light
- Topic: Sapling Week 2/3 Homework
- Replies: 3
- Views: 24
Re: Sapling Week 2/3 Homework
When you increase the number of photons, you are increasing the intensity (amplitude of the light). However, you aren't actually changing the wavelength or the frequency. As a result, those values will stay the same. The energy of a photon is E= planck's constant times the frequency. Since there are...
- Tue Oct 13, 2020 2:06 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: different values for Rydberg constant
- Replies: 2
- Views: 29
different values for Rydberg constant
From the atomic spectra focus module on Professor Lavelle's website, I wrote down that the Rydberg constant is equal to 3.29 x 10^15/sec when used in the equation En=(-hR/n^2). However, in other resources like https://ch301.cm.utexas.edu/section2.php?target=atomic/H-atom/rydberg.html it says that R ...
- Mon Oct 12, 2020 6:14 pm
- Forum: Empirical & Molecular Formulas
- Topic: Sapling Week 1 Question 10
- Replies: 5
- Views: 52
Re: Sapling Week 1 Question 10
The number in front of the name refers to what carbon in the organic molecule chain an additional molecule/group is bonded to. For instance, the organic molecule pentene would be a straight chain of 5 carbons with hydrogens bonded to them. However, 2-methylpentane would be a pentene molecule with a ...
- Mon Oct 12, 2020 3:46 pm
- Forum: Balancing Chemical Reactions
- Topic: Textbook Problem L35.
- Replies: 8
- Views: 100
Re: Textbook Problem L35.
Thomas Vu: I also got 461.66 kg but the textbook says that the answer is 509 kg.
Did anyone else also get 461.66 for the answer?
Did anyone else also get 461.66 for the answer?
- Mon Oct 12, 2020 1:31 pm
- Forum: Properties of Light
- Topic: Focus 1B.5
- Replies: 3
- Views: 33
Re: Focus 1B.5
One eV (electrovolt) is equal to 1.602×10−19 Joules. Good luck!
- Mon Oct 12, 2020 12:49 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Infinite number of energy levels in the H atom
- Replies: 2
- Views: 62
Infinite number of energy levels in the H atom
How can the Hydrogen atom have an infinite number of energy levels available (as seen by the equation En= -R (1/n)^2 where n=1,2,3... and En is the energy of an individual quantum level)? I understand that the atom has a finite energy range because it takes 13.6 eV to fully discharge an electron, so...
- Thu Oct 08, 2020 3:49 pm
- Forum: Limiting Reactant Calculations
- Topic: L35
- Replies: 3
- Views: 41
Re: L35
I was really confused about this one as well because I wasn't able to balance the last chemical equation. But, I checked Professor Lavelle's website and there's actually an error in the textbook. Here's what the solution manual correction PDF says: L.35 in the textbook question: In the third reactio...
- Wed Oct 07, 2020 12:09 am
- Forum: Administrative Questions and Class Announcements
- Topic: Textbook
- Replies: 1
- Views: 38
Re: Textbook
Here is info from an email sent a few hours ago: Due to the bookstore delays in shipping your Ebook/Sapling access card (with the access code) I have organized that you have Ebook/Sapling access via a free trial period (for details see https://docs.google.com/document/d/1t0ExeH8Rruxp0GKgB-KdSmsNDk0f...
- Tue Oct 06, 2020 11:42 pm
- Forum: Empirical & Molecular Formulas
- Topic: M19: oxygen
- Replies: 4
- Views: 50
Re: M19: oxygen
Hi Annabel, I'm noticing 2 mistakes: 1) H20 has only one mole of oxygen, not two. 2) In the 0.06056 g of oxygen calculation, you accounted for the fact that some of the mass of the oxygen in the products didn't come from caffeine. When you converted to moles first, you forgot to do that. Hope this h...
- Tue Oct 06, 2020 11:18 pm
- Forum: DeBroglie Equation
- Topic: Wave Properties of Electrons Module #34
- Replies: 1
- Views: 25
Re: Wave Properties of Electrons Module #34
This is true. For instance, J.J Thomsons's experiment determined the charge to mass ratio of an electron by sending electrons into a positively charged plate. Millikan's oil drop experiment helped determine the mass of an electron. Furthermore, Wilson's cloud chamber can be used to study an electron...
- Tue Oct 06, 2020 10:52 pm
- Forum: Properties of Light
- Topic: Converting wavelength to Angstrom
- Replies: 5
- Views: 59
Re: Converting wavelength to Angstrom
1 angstrom is equal to 10−10 meters = 0.1 nm
visible light ranges from about 380nm-700nm.
1 nanometer = 10^-9 m
so 380nm x (1 angstrom/0.1 nm) = 3800 angstroms
and 700 nm x (1 angstrom/0.1 nm) = 7000 angstroms
visible light ranges from about 380nm-700nm.
1 nanometer = 10^-9 m
so 380nm x (1 angstrom/0.1 nm) = 3800 angstroms
and 700 nm x (1 angstrom/0.1 nm) = 7000 angstroms
- Tue Oct 06, 2020 10:42 pm
- Forum: Administrative Questions and Class Announcements
- Topic: 2nd set of modules
- Replies: 3
- Views: 60
Re: 2nd set of modules
Here is the information from the email he sent tonight: "the Fundamental section should be finished by the end of week 1 (as we will finish it week 1). The quantum section we will finish by the end of week 3. Therefore, readings and questions from the textbook should be finished by the end of w...
- Tue Oct 06, 2020 11:06 am
- Forum: Photoelectric Effect
- Topic: Difference Between Ejection and Excitation
- Replies: 2
- Views: 26
Re: Difference Between Ejection and Excitation
Energy levels are different for different atoms because they depend on the number of protons and neutrons in the nucleus. Thus, there isn't a universal value that will cause excitation vs emission in every single atoms. In hydrogen, for instance, electrons in the first energy level have a value of -...
- Sun Oct 04, 2020 8:28 pm
- Forum: Properties of Electrons
- Topic: Understanding why an electron's energy is quantized - good resource [ENDORSED]
- Replies: 1
- Views: 272
Understanding why an electron's energy is quantized - good resource [ENDORSED]
Hello, While trying to understand why an electron's energy is quantized, I stumbled on an article published by the University of Nebraska-Lincoln that clarified some points for me. https://astro.unl.edu/naap/hydrogen/transitions.html#:~:text=The%20formula%20defining%20the%20energy,the%20electron%20f...