CHEMISTRY COMMUNITY

Jaden Ji 2K

We would multiply a unit by Avogadro's number if the weight, energy, etc. of a single atom were given and you wanted to find the weight, energy, etc. in mols. To find the weight, energy of a single atom you would divide the number of mols by Avogadro's number in order to figure out how much each ato...

Jaden Ji 2K

I like to review a bit and try to sleep early, but it's only like thirty minutes before my usual bedtime lol

Jaden Ji 2K

Taber Ball 1F wrote:Hi! Does anyone have a good way to memorize the various wavelengths on the atomic spectrum?

I like to relate the terms to the things that remind me of the term, like nanometer is like nine-o-meter, because it is 10^-9 m. Hope this helps!

Jaden Ji 2K

Hello! For the conjugate acid of HSO4- I put H3O+. Is that not the conjugate acid? When thinking about what it is asking for, the conjugate acid, first think about what that means. A base turns into a conjugate acid because when doing the reverse of the chemical reaction it would go back to being a...

Jaden Ji 2K

Hello! For the conjugate acid of HSO4- I put H3O+. Is that not the conjugate acid?

Jaden Ji 2K

Happy late thanksgiving! We buy pumpkin pie and usually go to a friend's house, but this year we just relaxed at home :)

Jaden Ji 2K

Forgive me if I am wrong, but I cannot think of an example with one lone pair that is not polar. I think that if the lone pairs are opposite each other they will cancel out. If I am wrong I would appreciate it if someone corrected me. Actually that's really interesting! I found this old forum that ...

Jaden Ji 2K

A lone pair does not make a molecule polar, but usually if an atom is asymmetrical then it is polar because the dipole moments cancel each other out. On a nonpolar molecule, the dipole moments cancel each other out, which makes all the molecule neutral overall.

Jaden Ji 2K

It is because the equatorial lone pair has contact with less atoms than the axial lone pair; if the lone pair were placed on the side equatorially, it would have 90° angles with two atoms and 120° with the other two. If it were axial, it would have 90° with three atoms and 180° with the last atom. h...

Jaden Ji 2K

I'd say that frequent repetition and practice with the names is the best way to get them down! Maybe making a quizlet or finding someone else's quizlet could help. Also, I think we do have to know the angles of the shapes, but memorizing how the shape looks should give you a general idea of what the...

Jaden Ji 2K

Polar molecules are often asymmetric and consequently have dipole moments that do not cancel out, while nonpolar molecules are symmetrical which causes the dipole moments to cancel each other out.

Jaden Ji 2K

Oh I see! I was thinking that what makes a bond polar or nonpolar was the two atoms on the very end, not the two atoms involved in a specific bond! Thank you so much for responding!

Jaden Ji 2K

Hello! Is BeCl2 polar or nonpolar as a whole? I know that because there are two CL atoms on each side that it is nonpolar bonding, and that the dipole moments of the chlorine atoms should cancel out, but I can't seem to get it right. I also put that H2O has nonpolar bonds and is polar overall.

Jaden Ji 2K

Like what Sophia said, calculating the formal charge and counting the number of electrons around each atom helps in finding the electrons in the middle. I like to see how many valence electrons are needed to fulfill the electrons in the middle and count the bonded electrons as those needed electrons...

Jaden Ji 2K

Yeah I wasn't happy at all with how I felt taking Midterm 2, but now I know what to study for!! And what others have said, the final is the time to study as hard as possible and bring up that grade!

Jaden Ji 2K

I have an additional question relating to bond angles, For two molecules with the same shape (like an AX_3 for example), will all the bond angles be the same? Or will they change depending on the individual elements? I understand bond angles with be slightly different with lone pairs vs no lone pai...

Jaden Ji 2K

I see! Thank you so much for the explanation.

Jaden Ji 2K

Thank you all!

Jaden Ji 2K

How does iodine complete the octet rule with four single bonds to oxygens? Are the oxygens forming coordinate covalent bonds with the iodine?

Jaden Ji 2K

Ionic character is the probability of two electrons to be ionically bonded. An ionic bond is where electrons are given to one atom rather than shared between the two. For example, if you put fluorine and sodium together, the fluorine is more likely to steal the sodium's electron to become more stabl...

Jaden Ji 2K

Octet exceptions are when an atom of an element does not need 8 valence electrons exactly to reach a stable state. For example, phosphorus can have 10ve-, and sulfur in SO4-2 can have 6 bonds, which results in 12ve-. I hope this helped!

Jaden Ji 2K

I think the bond lengths would be given if we needed to calculate, but like what other people have been saying, to calculate the resonance structure bonds you just need to calculate the average of all the bonds (triple, double, single). The more single bonds, the longer the resonance bonds would be,...

Jaden Ji 2K

The least electronegative atom goes in the center, however oxygen and hydrogen typically surround the element in the center.

Jaden Ji 2K

The larger an anion is, the further away its electrons are from the nucleus so the less pull they will have anchoring them down, leading to an increase in covalent character.

Jaden Ji 2K

I just did Sapling #9 and I was wondering if all oxidation numbers are ionic? As in, when oxygen is in an equation, the oxidation numbers assume the bonds are more ionic than covalent because the non-oxygen atom has a positive charge to balance out the oxygen's negative charge?

Jaden Ji 2K

The Politician is really good! Also if you're into some fantasy and ok with some gore the Witcher was fun to watch too!

Jaden Ji 2K

Like what everyone else is saying, the 4s orbital would be filled first so potassium (K,19) would be written as [Ar]4s^1, whereas germanium (Ge,32) would be [Ar]3d^104s^24p^2.

Jaden Ji 2K

Adding on, delocalized electrons are what make the bond lengths equal. Like how Dr. Lavelle said in his lecture, sometimes bond lengths can be in between a length of a single bond and double bond. This is because the electrons are delocalized.

Jaden Ji 2K

In the lecture of 10/26 Dr. Lavelle says that you can figure it out based on the periodic table and by calculating the numbers using Pauli's Exclusion Principle and Hund's rule. I think it should be fine if you just remember that the 4s goes before the 3d.

Jaden Ji 2K

I think Group 13 doesn't require an octet because they require too many electrons to reach the octet.

Jaden Ji 2K

I think it is because the oxygens tend to bind to the nitrogen rather than each other like Jonathan said before me.

Jaden Ji 2K

It doesn't allow us to see our answers for now, but I know someone was asking for one on one sessions to go over the answers.

Jaden Ji 2K

I have some test anxiety! I usually just like to do the easier problems first, and if I get to stressed from the harder ones I take a minute to sit back and calm down again before going back to working on the problem. I hope this helps!

Jaden Ji 2K

I heard that most of the focus will be on practical problems and only a few will be conceptual from my TA.

Jaden Ji 2K

They're recommended, I think if you have a camera that can clearly display your work then it should be fine to just use your phone.

Jaden Ji 2K

Like what everyone has been saying, I think that looking for the element that appears once on either side is the most efficient way. When it gets hard or if it's not working, I tend to start balancing off of another element as a sort of second perspective to see if it works. I hope this helped!

Jaden Ji 2K

Hi! I had a question related to the Rydberg constant. I kept seeing "Rydberg constant for hydrogen" when I was looking up the value of the constant. Does the constant change depending on which element is involved? I just searched a little about it, and I found that while there are differe...

Jaden Ji 2K

I see! Thank you!

Jaden Ji 2K

In the lecture on Friday, Professor said that when l = 2, ml = 2,1,0,-1,-2 for nitrogen. So do we have to count the number of spaces an element is from the start of a row in order to know how many possibilities of ml are in the electron?

Jaden Ji 2K

No, I think it has something to do with both the electron configuration of electrons and that the excited state is too unstable to remain in for long.

Jaden Ji 2K

He didn't cover how to find them yet. From my understanding, they are detected when a bunch of different frequencies of light are shined on an element. The lines only show up if they match a certain very specific energy level. So the numbers appear to be empirically derived from experimental observ...

Jaden Ji 2K

I've been sticking to the schedule given to me by UCLA for all my asycnhronous classes just to have a frame, so I don't push them off. I also have been taking notes during the lectures and boxing important things, as well as going through my classes and making note of what is due during the week at ...

Jaden Ji 2K

Increasing the number of photons is the increase of amplitude, because in math equations the amplitude is just the coefficient in front of the main equation, such as 3(x-k), where x-k is the main equation and 3 is the amplitude. It increases the amount, but doesn't change the wavelength or sort of m...

Jaden Ji 2K

Yeah I think that the two energy states is referring to the different electron rungs around a molecule, and how electrons can sometimes jump to a higher level than the one they usually are on when they're excited. So the different rings must have specific energies needed to excite the electron into ...

Jaden Ji 2K

Jada1J wrote:I was wondering if the compound for combustion will also need to be memorized or will it provided.

I think it'll be provided, but I'd memorize it just to be sure. The products are typically CO2 and H2O with something else

Jaden Ji 2K

Thank you both! I'll review the simple compounds then!

Jaden Ji 2K

Are we expected to name compounds on quizzes if the name isn't given, or determine how many of each element is in the compound by looking at the name? For example, knowing like Na3AlF6 is sodium hexafluoroaluminate or getting Na3AlF6 from the name?

Jaden Ji 2K

Here's the link to the textbook's periodic table!
https://www.saplinglearning.com/ibiscms ... d=13094939
I've been using this one and I've gotten answers right using all the decimal places and correct sig figs with this.

Jaden Ji 2K

What type of fish is made out of two atoms? 2Na!

Jaden Ji 2K

Typically, finding the mass percent makes it easier to solve for the amount of moles. For instance, instead of having to use small decimals such as 0.35g to divide atomic masses into, by multiplying the percent by 100g it makes a larger number and in turn makes the products of division by atomic mas...

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