CHEMISTRY COMMUNITY

Earl Garrovillo 2L

I personally handwrite everything since it does sort of force me to think about what I'm writing. Also taking the time to maybe pause lecture and rephrase his slides in a way that I understand/shorter than what Lavelle wrote also helps me with learning the material. I also reinforce the lecture note...

Earl Garrovillo 2L

To add onto the post above, if you want to be super meticulous about the order (like Sapling #7 from last week I think?) place the solid metals at the ends and the aqueous ions that interact with salt bridge in the middle (surrounding the double line ||). But I personally don't think it matters that...

Earl Garrovillo 2L

Unless I'm severely misunderstanding what we're learning (which is honestly completely possible), I believe you're right in saying the total rate is equal to the slowest elementary step. The reaction can only proceed as fast as the rate-determining step (slowest step) which is why the rate law uses ...

Earl Garrovillo 2L

I believe that order does matter (at least it does in Sapling #7 from last week). I think that the aqueous ions should be on the inner end:
Pt(s) / Cl2 (g) / Cl- (aq) // K+ (aq)/ K2 (g) / Pt(s)
Sapling specified that the ions that make contact with salt bridge should be placed in the middle.

Earl Garrovillo 2L

We can't make X negligible because X has a significant effect on K when it's greater than 10^-4. We say X is negligible when K is less than 10^-4 because it essentially has no effect on the denominator of the fraction. For instance (X^2)/(3-X). As K becomes smaller, ignoring K on the bottom matters ...

Earl Garrovillo 2L

Remember that K is equal to the [products]/[reactants] of a chemical reaction at a given temperature. When you add two chemical reactions, you have to find K again with the "new" products and reactants. As for why we cant make K negative, K is a ratio of products to reactants. It wouldn't ...

Earl Garrovillo 2L

The salt bridge allows for ion transfer (and subsequently electron transfer). Without the salt bridge, the electrons moving from the anode to the cathode would build up and electron flow would become unfavorable causing the reaction to stop. The salt bridge moves spectator ions between the two solut...

Earl Garrovillo 2L

I was feeling the burnout a second ago. Personally, I need a lot of rest and just separation from school for a few hours, maybe a day. At these times, the most I do is look at emails to make sure I'm not missing some deadline but aside from that school mentally doesn't exist. To get back into school...

Earl Garrovillo 2L

I obviously can't speak for Lavelle but from past answer choices, I think there's usually a clear difference in answer choices. He also usually gives specific values that we should use in order to avoid rounding differences. In the example you gave, he would probably ask something like "report ...

Earl Garrovillo 2L

This might be what you're thinking of? "If you need x more O atoms on one side, you should add 2x OH− ions to that side, then x H2O molecules to the opposite side."

Earl Garrovillo 2L

Just to add to this, Sapling really did not like it when I put OH- in the middle of the Pb(OH)4 equation. Not sure how if the order of other compounds affects it but if anyone else is having trouble (and the issue isn't with the coefficients), try putting OH- at the end.

Earl Garrovillo 2L

It's a bit hard to see the problem without your work but since you said you have extra electrons, I'm assuming that you already balanced the equation for a basic solution? If you haven't, you need to add H2O and OH- to the magnesium oxide half-rxn and balance that. You may also be getting extra elec...

Earl Garrovillo 2L

You're on the right track with having to compare the standard reduction potentials of the given reagents with the answer choices. To oxidize one reaction without oxidizing the other would mean that the standard reduction potential of your answer should be in between the standard reduction potentials...

Earl Garrovillo 2L

It's designed to have 0V as the E naught so that we can calculate cell potentials with varying electrodes and concentrations without having to factor in the E naught of the SHE.

Earl Garrovillo 2L

dana hu 1B wrote:Thank you for your response

I then got this which is also wrong:
2MnO4-(aq0 + 4H2O(l) + 3S+2(aq) -> 2MnO2(s) +3S(s) +8OH-(g)

What did I do wrong here? Are my states wrong?

Yup, OH- should be aqueous, your charge on S should be 2- too

Earl Garrovillo 2L

Spontaneous processes are when ∆G = ∆H-T∆S is negative. In an exothermic process, ∆H is negative but this doesn't always mean ∆G is also negative. If ∆S is negative and the temperature is high enough, ∆G can become positive. I think this is called an entropy-driven reaction or entropy is dominant. I...

Earl Garrovillo 2L

Another way to approach this using the same deltaG = deltaH - TdeltaS equation is to only find the deltaS of the formation reaction by using the standard molar entropies of formation. Since a lower deltaG is more stable, we need to see the sign of the deltaS. If deltaS is positive, increasing the te...

Earl Garrovillo 2L

I had a lot of problems with this exercise too. To find the energy released, you're supposed to find the enthalpy of the reaction using the standard enthalpies of formation. This gives us the amount of energy released in the total reaction but since we need energy per mole of TNT, we need to divide ...

Earl Garrovillo 2L

Calibrating a calorimeter means measuring a calorimeter's heat capacity by carrying out a reaction that releases a known quantity of heat and then observing the change in temperature. We can then use this heat capacity in future procedures/calculations that use the same calorimeter.

Earl Garrovillo 2L

Oxygen difluoride is a colorless, very poisonous gas that reacts rapidly and exothermically with water vapor to produce O2 and HF: OF2(g) + H2O(g) → O2(g) + 2HF(g). ΔH=-318 kJ. What is the change in internal energy for the reaction of 1.00 mol of OF2? I understand that we have to use the delta U= de...

Earl Garrovillo 2L

If you really want an in-person lab experience, you're better off waiting. But if you're fine with having simulated labs/just watching labs and having the data given to you, then I'd recommend taking 14BL. I'm taking it with Casey so I can't really speak for any other professors but the class is ver...

Earl Garrovillo 2L

I could be wrong but I thought you only need the variations of R when computing the Cv,m or Cp,m of the gas. Since the equation of delta S for a change in Volume only states R, we don't need to use the 5R/2 because then you would be inputting the Cv,m of Neon into the equation, not the gas constant.

Earl Garrovillo 2L

Hi! I remember Dr. Lavelle stating that some of these are more reliable than the others, and I was wondering which ones are more accurate and why. Thank you! Hess' Law and Standard Enthalpies of Formation are about the same level of reliability and are the more reliable ones. These are specific to ...

Earl Garrovillo 2L

I misread this at first but it's actually because the question is asking for orderliness when the samples are liquids. Larger ΔSvap means that when a liquid became gas, the entropy changed by the ΔSvap. Since C2H5OH has the largest ΔSvap, it's gas form is the most disorderly but it's liquid form is ...

Earl Garrovillo 2L

Standard change in enthalpy and change in enthalpy are both in terms of energy so they would both use Joules. Standard change in enthalpy is commonly reported as kJ/mol and is used under standard conditions (298K and 1atm). Change in enthalpy is usually reported as kJ or J (doesn't really matter) an...

Earl Garrovillo 2L

The textbook definition of entropy is "(1) A measure of the disorder of a system. (2) A change in entropy is equal to the heat supplied reversibly to a system divided by the temperature at which the transfer takes place." It's a bit of a weird concept but it's sort of a measure of how mess...

Earl Garrovillo 2L

When you see a chemical reaction that involves O2 in the reactants and CO2 and H2O in the products, it's a combustion reaction. So it would be the enthalpy of combustion. But if you forgot that, you can also look at the +/- 4×bond energy of C−H and notice that the reaction involves the breaking of O...

Earl Garrovillo 2L

I'm actually not too familiar with most kdrama but I got into watching "Run On" (on Netflix) and I'm surprised no one recommended it yet. It's fairly new and the season finale came out not too long ago. It's a romcom so take that as you will lol.

Earl Garrovillo 2L

I used the PV=nRT equation, substituting the P, T, and V with the initial conditions of the problem

Earl Garrovillo 2L

I don't think there's one that's necessarily preferred over another, like you said, it depends on what information is given in the problem. The context of the problem and what information they provide will ultimately determine which equation to use. The actual equation is -\int_{v1}^{v2}P_e_x dV but...

Earl Garrovillo 2L

They're basically the same thing but deprotonation is used for acids while protonation is used for bases. If you recall, H3O+ is sometimes substituted with H+ (or a proton). Since acids give away protons when dissociated, we use %deprotonation with them. Meanwhile bases accept protons so we use %pro...

Earl Garrovillo 2L

Yup, since solids and liquids basically don't change concentration ever, while concentrations of aqueous things only change when solvent or solute is added, pressure will only affect the gases. Gases fill up the container they're in so if they're compressed, their concentrations change. If there's e...

Earl Garrovillo 2L

I haven't taken either so I'm really just reciting what I've heard from my upperclassman so take it with a grain of salt. It's definitely possible to take C and CL concurrently since they cover the material again in lab but if you feel like you need a more in-depth background with the topics, most p...

Earl Garrovillo 2L

Yup, it's common practice for books to forego telling the temperature since it's usually assumed that it's room temperature unless specified otherwise. If there's no way to solve for the temperature with the given information, I'd say to either consider if temperature is even relevant to the problem...

Earl Garrovillo 2L

Look at the units of your temperature, pressure, energy, and moles. The units of your R constant should be the same so that they cancel out when used. You may have to do some dimensional analysis to get the right value of R.

Earl Garrovillo 2L

It's because steam is a gaseous state. If you remember the phase diagram Lavelle showed, there's a significant amount of energy needed to convert water into steam. When steam hits your skin, it condenses back to water and all that energy released from changing from a gas back into a liquid is releas...

Earl Garrovillo 2L

Sorry if this is a vague answer but it's a bit hard to discern what the problem is since your numbers may vary from mine and I can't see your work but I suggest to make sure the values you input are correct, you're using the right units, and to double-check your signs when you did the algebra to wri...

Earl Garrovillo 2L

Like the person above said, since enthalpy is the change in energy between the products and reactants, the one-way arrow is probably used to denote that the given change in enthalpy specifically applies to the forward reaction. I think the reverse reaction's change in enthalpy would just be the nega...

Earl Garrovillo 2L

My interpretation of phase changes are a bit different than work functions for electron ejection. In the photoelectric effect, as long as the minimum energy was met the electron was ejected. Phase changes are similar in that there is a specific amount of energy between phases that have to be overcom...

Earl Garrovillo 2L

Depends on how accurate you want to be but a general rule of thumb is when Ka is less than 10^-4 or 10^-5 (Sapling sometimes says when the acid concentration is 1000 times greater than the Ka). But always make sure to check that the x-value you find is less than 5% of the original concentration othe...

Earl Garrovillo 2L

As others have said K should be less than 10^-3 but to using 10^-4 is safer. If that's hard to remember, Sapling says that if the molarity of the initial concentration is 1000 times greater than the K, you can assume x is negligent.

Earl Garrovillo 2L

According to the lecture from last Friday, only temperature can change the equilibrium constant. So if the temperature remains constant, I don't think starting with a higher pressure will result in a larger K value.

Earl Garrovillo 2L

I think we have to use P before a molecule to denote that we're using the partial pressure of that molecule, otherwise, it may be misconstrued as the concentration.

Earl Garrovillo 2L

I'd say unless you know for sure that you're working with a strong acid/base (i.e. stated in the problem) to just use the ICE box. It'd be a lot more efficient to only use the OH-/H3O+ concentrations when you know you're working with strong acids/bases but if you're unsure, using the ICE box would b...

Earl Garrovillo 2L

I could be wrong but the line after you found the [OH-] concentration, I think you miswrote the exponent on the Kb as -3 instead of -5

Earl Garrovillo 2L

They're inversely related. At constant temperature, increasing one will cause the other to decrease. Vice versa, decreasing one will increase the other. As for why, increasing pressure is the same as compressing a system (which effectively decreases the volume). Or when volume is increased, there is...

Earl Garrovillo 2L

Sections aren't mandatory so missing one is fine. If you're concerned about what you missed, you can email your TA/go to their office hours about what they went over during discussion. You can also attend the UA sessions to catch up on what you missed.

Earl Garrovillo 2L

Temperature is the only condition that can change K since it involves a change in the energy of the system which affects whether the forward or reverse reactions will be favored. However, like the others previously stated, changing pressure is equivalent to changing the volume and thus changes the c...

Earl Garrovillo 2L

Unless the reaction is a well-known precipitation reaction (e.g. NaCl(aq) + AgNO3(aq) ----> AgCl(s) + NaNO3) which is a reaction that always results in an insoluble solid, then we may be expected to know that a substance is a solid. But as far as I know, we haven't been taught that yet so I'm inclin...

Earl Garrovillo 2L

I'm a little confused with your question so I might give unnecessary info but the conditions of equilibrium are usually given to us in the problem (with the context of problems that we've been introduced to so far). Future problems may require us to solve for certain conditions given other condition...

Earl Garrovillo 2L

When we draw the lewis structure of NH3, we get 3 N-H bonds with one lone pair on the N. Which means that N has 4 regions of electron density and since hybridization depends on the # of electron density regions, we also need 4 hybridized orbital which correlates to a sp3 hybridization.

Earl Garrovillo 2L

Remember that each double bond is composed of a sigma bond and a pi bond. With that in mind, there are 6 sigma bonds from each of the single C-C bonds and another 6 sigma bonds from each of the C-H bonds. The 3 pi bonds comes from the alternating double C=C bonds in the carbon ring.

Earl Garrovillo 2L

Relative strength of an acid is related to it's ability to lose an H+ ion. So acids where it's very easy to lose a proton are relatively stronger than acids where it is harder to lose an proton. In other words, weaker bonds=stronger acid. With HF and HCl, the bond between HF is very short because of...

Earl Garrovillo 2L

I understand why ions of weak acids and bases can make the solutions more alkaline/acidic when interacting with water but I don't get why ions of strong acids/bases don't? What is the reason these strong acid/base ions don't act like the ions of weak acids/bases?

Earl Garrovillo 2L

The way the book defines weak acid/base is any acid/base classified as strong. https://sites.google.com/site/chempendix/strong-acids-bases . So any acid/base not listed here is considered weak. Since none of the ones you still have left are on the strong acid/base list they are all weak/other NaCl: ...

Earl Garrovillo 2L

I don't know why but this just isn't clicking with me. Is the coordination number just the amount of bonds/ligands to the central cation? And what relationship do dentates have with the CN (if any)?

Earl Garrovillo 2L

The position of lone pairs is dependent on the electron geometry and is determined by what is the most favorable position (usually opposite from each other and equatorial). H2O has tetrahedral geometry and two lone pairs. It's a bit hard to envision but if you look it up, it really doesn't matter wh...

Earl Garrovillo 2L

I think so. Bronsted bases are proton acceptors while Lewis bases are electron donors, so while all Bronsted bases are also Lewis bases, I believe not all Lewis bases are Bronsted bases. For instance BF3 + F- ----> BF4-. F- is considered the Lewis base since it donated its lone pair but in and of it...

Earl Garrovillo 2L

As the person said above, I'd say it depends on whether we're discussing Lewis acids or Bronsted acids. Lewis acids are defined as electron pair acceptors, so compounds like BF3 which accepts a lone pair from F-, is considered an acid but doesn't contain any H. However, Bronsted acids (which the tex...

Earl Garrovillo 2L

Since the number of electron density regions is equivalent to the amount of hybridized orbitals, whatever's left is unhybridized. For instance, in a compound there's 2 e- density regions which means there's 2 hybridized orbitals, or a sp hybridization. Since the p subshell has 3 orbitals but only 1 ...

Earl Garrovillo 2L

This is the way I understand it so anyone is free to correct me if I'm wrong lol. The # of regions of electron density surrounding an atom is equivalent to the # of hybrid orbitals. So if an atom has 3 bonds and 1 lone pair, there should be 4 hybrid orbitals. The type of hybridization is then determ...

Earl Garrovillo 2L

From my understanding, electronegativities do not cancel. They're not like charges where formal charges of atoms within a molecule contribute to the overall charge of the molecule. Electronegativity "stays" with its atom, for lack of a better word. In a molecule where one atom is highly el...

Earl Garrovillo 2L

Yup! You can check by comparing the molar mass of CH4O with the given molar mass of the unknown compound since they should match. CH4O is approximately 32.041 g/mol which is essentially the same as the MM of the unknown compound so you should have the right molecular formula.

Earl Garrovillo 2L

The square planar shape requires an octohedral electron geometry where 2 electron density regions are lone pairs. Since H2O only has 4 regions of electron density, it has tetrahedral geometry and so it's not possible for it to be square planar nor linear. Now given a tetrahedral geometry with two lo...

Earl Garrovillo 2L

So in other words, its basically the exact same molecule/lewis structure except you move the double bond/triple bond to another of the same atom? Yes, to everything but that last part. The atoms are all in the same spot and only the double/triple bonds are "moving". They don't always have...

Earl Garrovillo 2L

The type of bond (single, double, triple) does not affect the shape of the molecule, or at least it doesn't affect the overall shape of the molecule significantly. All bonds and lone pairs (LP) are treated as regions of electron density. You're somewhat on the right track with counting the amount of...

Earl Garrovillo 2L

I think the rule of thumb is that p-block of n=3 and below can accommodate an expanded octet because they have a d-subshell to fit more valence electrons into (although they don't always have an expanded octet). As for a set/maximum number of electrons, (I really don't know so this is really just my...

Earl Garrovillo 2L

Remember that atomic orbitals exist in 4 different shapes, or wave functions (s, p, d, f). We don't really know the exact position of an electron at any given point in time but by finding the square of the wave function, we can find the probability of finding an electron in a given orbital. It's har...

Earl Garrovillo 2L

When atoms are isoelectronic (here they all have the same # of electrons as Argon), the size of the ion essentially boils down to which ion has the most protons. The more protons there are, the more positive charges there are to attract all the electrons (as someone said before this is called the ef...

Earl Garrovillo 2L

It'd first be helpful to remember the "bounds" of the quantum number and that the numbers are ordered by {n, l, ml, ms}. l can be 0 to (n-1), ml can be -l to +l (including 0), and ms can only be +1/2 or -1/2. Given these bounds, we can say that (a) is valid set of quantum numbers since non...

Earl Garrovillo 2L

The difference in electronegativity between C and Cl would result in three of the bonds in CHCl3 to be polar. The C-H bond is also slightly polar but it's neither as strong as C-Cl or as numerous. Because of the shape of CHCl3 (tetrahedral if I'm not mistaken), then the electron density of the molec...

Earl Garrovillo 2L

Boiling point is the temperature where a compound changes from liquid to gas whereas the melting point is where a molecule/element changes from solid to liquid. A simple example of boiling is when water becomes water vapor, and melting is when ice becomes water. In context of what we're learning rig...

Earl Garrovillo 2L

Yeah so the resonance structures would be the double bond of the carbon switching between the two oxygens since both theoretically work. But as the person above said, the answer the book gave is more favorable since there are no charged atoms in the compound.

Earl Garrovillo 2L

I think you have it backward, orbitals are parts of a subshell, not the other way around. The order goes shell>subshell>orbital. Within a given subshell (s,p,d,f), there is a certain number of orbitals that can each contain 2 electrons.

Earl Garrovillo 2L

Atomic/Ionic radius: Trend: Increases down a group and increases as you go left across a period (or you could remember it as decreases as it goes right). Increases as you approach bottom left corner Reason: bigger atoms have larger radii and larger atoms in the same period have more nuclear charge s...

Earl Garrovillo 2L

I think the trend would still apply. Remember that ionic character and covalent character aren't mutually exclusive. Even in Groups 1/2, the size of the atoms increases which makes it easier for electrons to be shared since they're farther away from the nucleus and which then increases covalent char...

Earl Garrovillo 2L

Since Lewis acids are electron acceptors and Lewis bases are electron donors, it's best to draw the Lewis dot structure of a compound to see their valence electrons. Compounds that are electron-deficient and need electrons for an octet such as BF3 are bases, while compounds that have lone-pair elect...

Earl Garrovillo 2L

I'm not sure what your question is really saying since you said similar number of electrons. Since this could technically refer to isoelectronic atoms (different elements that have the same amount of electrons) and elements that are close together on the periodic table (close number of electrons at ...

Earl Garrovillo 2L

Theoretically, there would be a g, h, etc. subshells but due to the Aufbau principle, an atom would need A LOT of electrons to fill all the way to the g-subshell and beyond (no ground state element has enough, as far as I know). So for practical purposes, the s, p, d, f-subshells are the only ones w...

Earl Garrovillo 2L

Isoelectronic atoms have the same number of electrons. Their charges would differ depending on how many electrons were added/removed to result in the atoms to be comparatively isoelectronic. Electronegativity and ionization energies are also different despite the same amount of electrons since these...

Earl Garrovillo 2L

Resonance structures are the individual structures of a particular molecule. In a sense, it's each possible drawing where the bond(s) is/are shifting. The resonance hybrid is the mix of all these resonance structures. Like in the case of benzene, the resonance structures are the two possible hexagon...

Earl Garrovillo 2L

Firstly, since Fluorine already has 7 valence electrons, it really "wants" another valence electron to fulfill the octet rule. This is the case for all the other halogens as well. Now why it's more electronegative compared to the other halogens, as the others have said, is due to Fluorine'...

Earl Garrovillo 2L

From highest to lowest I believe the bond strength (in general) is as follows: multiple covalent bonds > single covalent bonds > ionic bonds > hydrogen bonds > van der Waals force.

Earl Garrovillo 2L

When the quantum number n=5, l can theoretically equal 4 but is not necessarily (or realistically 4). When n=5, l can be 0,1,2,3,4 since the values of l range from 0 to n-1. l=4 would also result in subshell g but as far as I know, no ground state elements have electrons in the g subshell.

Earl Garrovillo 2L

H, He, Li, and Be don't apply to the octet rule since they essentially only have access to the 1s subshell which will be stable with (and can only contain) two electrons. But other exceptions exist such as boron and aluminum that often don't follow the octet rule but Lavelle hasn't covered those yet...

Earl Garrovillo 2L

It's a bit of a difficult concept and I'm not too sure if I have a complete understanding as well but I think the gist of it is that filling the electrons using the Aufbau principle does not always result in the most stable atom. In the case of copper, the config is [Ar]4s^2 3d^9 . I believe the sta...

Earl Garrovillo 2L

It really doesn't matter where the electrons are located or how they are filled. Though many use the start at the top and fill in a clockwise way to fill Lewis structures, at the end of the day, I think the dot orders are just a visual interpretation designed to easily see the valence e- of atoms/co...

Earl Garrovillo 2L

The quantum number ℓ would specify the orbital shape aka the subshell (s, p, d, f). In this case, it would mean the p-subshell and each subshell has a specific amount of electrons (s=2 max e-, p=6 max e-, etc.)

Earl Garrovillo 2L

E.15 The molar mass of the metal hydroxide M(OH)2 is 74.10g⋅mol−1. What is the molar mass of the sulfide of this metal? The notation kind of confused me but is it basically saying that "M" is an arbitrary element? And to solve you would just subtract the molar mass of the (OH)2 and add the...

Earl Garrovillo 2L

This is pertaining to #16 on sapling which asks to order ions according to atomic radius. All the ions have the same amount of electrons so I'm thinking the radius has to be determined by how electronegative the element is when it's not ionized?

Earl Garrovillo 2L

Right, for this specific part of the problem, the work function doesn't have any use. If I remember correctly, the work function was used in a different problem with the same context. But since you asked what else we can derive from the work function (aka threshold energy or energy to remove electro...

Earl Garrovillo 2L

Unless specified otherwise, both units would be acceptable since m is the SI unit for length and nm is the common unit for wavelength. But if you want to be safe, you could also just write both units since it's a fairly quick and easy conversion.

Earl Garrovillo 2L

I agree with everyone's studying methods above but honestly what works for other people isn't always gonna work for you. So definitely try out everyone's suggestions but also figure out what helps you learn best. For me, I'm also not particularly good at staying on top of work if I don't designate s...

Earl Garrovillo 2L

Hi! You're right that m would be the mass of the electron but keep the units as kilograms (9.109 × 10^-31 kg). Not only are kilograms the SI unit for mass but since energy in Joules is equivalent to $\frac{kg*m^2}{s^2}$ , keeping the mass in kilograms is necessary to get the correct answer.

Earl Garrovillo 2L

I believe the speed of light and it's related equations should remain constant in a vacuum but does change when travelling through a medium (like air, water, etc.). For our class, I believe we'll only work with the assumption that light is travelling in a vacuum and in any non-vacuum cases, he will ...

Earl Garrovillo 2L

I'm essentially reiterating everyone's answers but yes they are the same. When referring to intensity of a light, we're talking about the amount of photons that are being emitted by a particular light source. Each individual photon has the same amplitude but since there's so much of them, they add u...

Earl Garrovillo 2L

Could someone explain how to find the number of spectral lines when an electron drops from a specific energy level? I'm not sure how to approach this problem. "The electron in a hydrogen atom is excited to energy level n=6 and emits electromagnetic radiation when returning to lower energy level...

Earl Garrovillo 2L

Hi!

Yeah, you do have to convert km/s to m/s since all the units need to be in SI units.

You would also need to use the de Broglie equation $\lambda =\frac{h}{mv}$ where m is the mass of the electron (9.1 x 10^-31 kg).

Earl Garrovillo 2L

Like everyone else said, it's typically best to use the listed molar mass on the periodic table. Second best option would probably be to round to at least 3 decimals. It's always best to get the most accurate answer we can (but if you are in a timecrunch, rounding elements like hydrogen, carbon, and...

Earl Garrovillo 2L

Hi! To start off, since the question is asking for kinetic energy were gonna have to use the equation Ek = \frac{1}{2}mv^{2} where m and v are the mass and velocity of the electron (in this part of the question, the work function doesn't have any purpose). Inputting the mass of an electron (approx 9...

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