CHEMISTRY COMMUNITY

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he does not curve but he does work out ways to help improve ones grade when stuck between two grades.

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Im pretty sure he is going to do the same thing for this final yes.

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I will try and give an analogy that helps me visualize this. Think about a very wealthy community. Imagine giving each individual $2000. Now think about a much poorer community. Imagine giving each individual $2000. The money will have a much greater impact on the poorer community than the wealthie...

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Mitzy Garcia 1k wrote:use ln(k2/k1) = (Ea/R) (1/T1 - 1/T2) and isolate T2
also convert 32.43 KJ/mol to J/mol by multiplying it to 1000
ln(7.00) = (32430/8.314)*(1/331 - 1/T2)

Thank you so much, this helped me on the problem I was stuck on for a while.

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These responses really helped me a lot thank you !

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Calculators , blank paper, and your two sheets are allowed for the final.

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Im going to review sessions, doing textbook questions from previous sections I struggled with and watching online videos to help me better understand some topics.

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Awesome tips ! I really got into those textbook questions more this week.

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I make sure to have one thing i like to do throughout the day that is sort of a escape. For me is my workout and lifting weights, and i set it at the end of the day so i have something to look forward to and motivation to finish all i gotta finish in order to get to that reward

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This whole sounds like so much fun looking forward to it !

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The Organic Chemistry Tutor, is who I usually watch when doing YouTube review.

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Really draining quarter, looking forward in doing well in all my finals and going into spring break.

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The final is on sunday 3/14 from 9:30AM - 11:00AM let’s all get ready for it we got this !

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What should you do if no one laughs at your chemistry jokes?

Keep telling them until you get a reaction.

Get it?! Like a chemical reaction. Chemistry jokes are funny.

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Hello this is what I got hope it helps:)

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If you get half the points in the class you pass.

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I really need to study more practice problems I feel, safe to say this final is really stressing me out.

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This was really helpful thank you !

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gabbi_r2C wrote:I've tried switching up the order of the elements on either side and get different, unhelpful error messages each time, so if someone did this question right, let me know.

Hello, this is what I was able to get hope it helps.

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Work is negative when work is done on the system.

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We did it! good luck to everyone and we all deserve a little fun afterwards!

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I feel like I did better than midterm 2 and that's how it usually goes so I expect to get a better school, I felt pretty confident throughout.

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I would have to guess in a little less than a week, so perhaps on Wednesday or thursday.

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Post midterm really lifted a lot of stress from me shoulders, I spent the night watching the new wandavison episode and playing some good old Minecraft.

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Criminal Minds and I carly is what im watching at the moment I feel I could watch a whole season of Criminal Minds in one sitting its that good.

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Step up sessions, online videos and rewatching lectures are what help me the most.

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definitely try to attend as many UA sessions as possible as those really helped me last quarter when i was struggling

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Units may be the issue in this case. To solve, I converted all energy terms to Joules and all temperature terms to Kelvin so that they would cancel with R=8.314 J/Kmol. I then calculated Q using the equation (PNH3)^2/(PH2)^3 (PN2). Finally, I converted my final answer back to kJ as prompted by the ...

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1. First you need to convert the the 2 temperature given from Celsius to Kelvin. So 25C and 800C have to be converted. 2. Then use PV = nRT to find moles which you isolate n and get n = PV/RT 3. Multiply "n" (the number of moles you found in step 2) and Cv (which is 20.17). 4. Use the equ...

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I thought I'd make a post to share some tips of what works for me to study for this class for anyone who is struggling since we just got our midterm scores back. I definitely make mistakes too so this isn't to "talk down" to anybody at all. feel free to add some more suggestions below! *u...

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Hello! I just wanted to let you know that w = -(delta)nRT is another option for solving for work, which is what I ended up using. My version of this question had a different amount of grams, but you would do the molar mass conversion of NaN3 to find the number of moles for that number of grams, the...

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Thank you for sharing this, this was really a good time for me to hear something like this.

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Hi! I had been having a hard time with this too. So basically you need to recognize that we are told Cp = 4R The relationship between Cp and Cv is: Cv = Cp-R. So 4R-R = 3R. ∆U = q + w. Then, understand that because we are at constant volume, ∆U = q + 0, since no change in volume means no work. q is...

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Since the problem says that 1g/1mL is the density of water, the sample of water that is 330 mL is 330 g and the one that is 100mL is 100g. Because the two water samples are being combined, the one that has the lower initial temperature is going to absorb heat, and the one with the high initial temp...

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I like to keep my area clean as possible, it really helps me.

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Way to go everyone!!

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I feel good about the midterm, it felt similar to those we had during 14A, no surprises.

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Whenever Ka is less than 10^-4

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For these types of problems with bases, I actually use the generic idea that, B + H2O <-> BH+ + OH- (which is just how I think of bases problems). I put that NaClO was my "B" because it was specified as a base in the problem and the solution is NaClO, which meant I had to convert Ka into ...

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Week 1 to week 3 is what is going to be on the midterm.

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Attend as many step up sessions and do as many book questions as possible. I also find watching videos online on subjects Im struggling in is very helpful.

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Hello, You have to convert the pH to pOH by using the equation 14-pH= pOH. You then need to take the pOH and convert it onto the concentration of OH. Now you have the concentration of OH at equilibrium. The general chemical equation is going to be: Base + H2O(l)= Conjugate acid +OH-. Make an ice ta...

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The value of X you take from your two answers received from the quadratic equation needs to satisfy two conditions. As you know, it needs to be positive. It also has to be less than your initial concentrations. Intuitively, this makes sense because you cannot have a change in X concentration that i...

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alexandralopez 3F wrote:Hey guys! Im having trouble getting the correct answer for this problem. Im going through the steps correctly but I think I'm making a mistake somewhere along the way. Can someone look over it pls? Thanks!

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this was really helpful thank you !

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Hello? When do we know we have to use the inverse of Kc or any K?

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I find helpful going to as many step up sessions as I can, then for additional resources I watch videos online on areas I find myself struggling in. I also find doing a lot of practice problems from the textbook is helpful.

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Make sure you use all the resources Lavelle has for us. Step up sessions, office hours, lectures, the sapling problems, text book homework, and his website all have things that can lead you to be really successful in this class.

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Music and some good food is always the way to go .

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To put it simply, it is based on the energy level of the reactants and products. This is why we measure it with enthalpy (H) which is related to heat energy. The attached drawings of graphs is from my notes on one of the lectures, it might help make sense of the idea. So basically, a reaction is ex...

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Just to stay more consistent in everything I do mostly, school, health, diet etc.

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Also are we supposed to use the same zoom link that we used for our midterms for final or is there another way the final is going to be proctored?

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705383815 wrote:I scream at the top of my lungs and then calmly enter the room

wow you're just like me.

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Im tired and ready for a break.

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I find that remembering how many bonds an atom likes to from (B=3, C=4, 0=2, H=1...etc) really helps me break down a large structure.

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I would expect more questions similar to the textbook as the midterms were filled with them.

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Trevor_Ramsey_2J wrote:Hi I use this for solving pH or pOH problems :) https://www.sciencegeek.net/Chemistry/t ... nit8pH.htm

This graph is super helpful thank you for sharing it!

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Hi, the conjugate base is the one that has accepts protons. To form the conjugate base, we must lose the proton on HSO4- so that it can accept protons. Therefore, the conjugate base would be SO4 2- and the conjugate acid would be H2SO4 as acids tend to be proton acceptors. This helped so much thank...

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Turning off my phone is a must in order to stay focus and I usually just play some background music while studying. It really helps.

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I watch quick review videos online so that I get a grasp of the content then right after that I do some practice problems from the text book.

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I believe oxides are strong bases due to their very small size and high charge.

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Hi, Im pretty sure it's at 5pm still unless something changes.

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I think he might have meant that there will be more questions from the Quantum unit than other units.

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So we should really focus on the bigger units for this final?

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Organic chemistry teacher on YouTube I like a lot, those videos really slow things down for me and I gather a lot from them.

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UA sessions come in clutch, they're the best!

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Does anyone know if we can make up for weeks we didnt get 5?

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Ccle isn't redirecting me to the sapling page to do my weekly homework, does anyone have the link or the name of the website where I can do my homework? I can not seem to find it anywhere else.

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Non polar molecules are symmetric while polar molecules are asymmetric. Polar molecules have a electronegativity difference between the bonded atoms. while Nonpolar molecules electrons are shared equal between atoms.

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I think it has to do with resonance structures, since Pi bonds are found in double and triple bonds, a delocalized pi bond is found in structures where the double or triple bonds can be moved since they have resonance structures.

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What if the electronegativity difference is equal?

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How can we determine the number of pi and sigma bonds a molecule has ?

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Will the final have more new material or will it be a balance of the whole year?

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So the longer the bonds are the less dissociation energy the structure will have?

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How would we determine which element has a stronger bond dissociation energy ?

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Step up sessions are really really useful! After not doing so good on the first midterm, I started attending more and I was able to fully grasp more concepts I was having troubles with.

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I fell good after this Midterm 2 but I can help but think I messed up bad on somme parts lol

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Okay so something with MgS and MgO which would have the most covalent character ? Would the Charges come into play at all?

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Hey y'all on the midterm 2 there was a question asking which element had the most covalent characters and I was just wondering what did that mean.

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How do you determine the Oxidation number of an element in a Lewis Structure ?

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Hi! Based on the homework that was due week 6, it seems like this midterm's content is not as focused on calculations but rather concepts and drawing Lewis structures. I would refer to the outline posted on Lavelle's website to know exactly what we should study, though. Lavelle also has office hour...

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Rajshree 1B wrote:BeCl₂ is a Lewis acid because the central electron can still accept electrons because of its Lewis structure. Be is bonded to Cl on both sides but there are still empty spaces where Be can accept electrons.

Thank you that makes more sense !

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Hello, I was having trouble with identifying the difference between a Lewis base and Lewis acid for sapling problem 6 in weeks 5. How do I figure out what is what when given a formula like BeCl2 for example ?

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Hey y'all, when is midterm 2 again?

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I just had a fun evening of working at my local McDonalds :D

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My favorite T.v. show definitely has to be regular show, and I recently went back to rewatch the show and it seemed like it was better watching it at my age right now. Definitely a good show overall.

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Hi I wanted to post some jokes onto the chemistry community but... but all the good ones argon.

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I once heard Old chemists never die....They just stop reacting!

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When multiplying two numbers in scientific notation, multiply their coefficients and add their exponents. When dividing two numbers in scientific notation, divide their coefficients and subtract their exponents. If you remember from math where we were taught how to multiply and divide with exponent...

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Hello for sapling question 6 for week 5, Im not sure what's the difference between a Lewis acid and Lewis structure, can someone explain what makes them different?

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When working with scientific notations, what are some rules when it comes to multiplying and dividing them? Especially when it comes down to the exponents.

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