Search found 78 matches
- Sun Mar 07, 2021 10:35 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Sapling #13 and Textbook #7C.9
- Replies: 2
- Views: 16
Re: Sapling #13 and Textbook #7C.9
I think you misunderstood the question. Each of these mechanisms are hypothetical sets of elementary reactions. One of the 3 could be the actual elementary reactions for the overall reaction: NO2(g) + CO(g) -> CO2(g) + NO(g). You are absolutely right that intermediates cannot be included in the over...
- Sun Mar 07, 2021 10:19 pm
- Forum: Balancing Redox Reactions
- Topic: Textbook Problem 6L.5d
- Replies: 1
- Views: 13
Re: Textbook Problem 6L.5d
Actually, balancing the half equations is the easiest part because you don't even need to balance them! First of all, since the question tells you this is a cell reaction, identify the anode and cathode reaction. Next, because the skeletal equation has only one reactant, you know there's one reactan...
- Sun Mar 07, 2021 8:32 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Textbook 7E.1
- Replies: 2
- Views: 10
Re: Textbook 7E.1
I would like a add that the factors that influence the reaction rate constant k are the following: (which I learned from my brilliant high school chemistry teacher) 1. Activity (of the reactants themselves) - for example, in the Alkali metal series, due to electronegativity differences, Fr>Cs>Rb>K>N...
- Sun Mar 07, 2021 7:45 pm
- Forum: General Rate Laws
- Topic: Sapling HW Week 9/10 #13
- Replies: 3
- Views: 25
Re: Sapling HW Week 9/10 #13
I would suggest to use the equilibrium constant to understand better how to find a substitution for the intermediate molecule. However, at equilibrium, the concept that the forward and reverse rate are the same is correct. In this case, the K (equilibrium constant) for the first equation "ClO−(...
- Sun Mar 07, 2021 4:53 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: When forming rate laws do we include solids and liquids?
- Replies: 5
- Views: 3427
Re: When forming rate laws do we include solids and liquids?
If you want a more detailed explanation, here is a great website:
https://chemistry.stackexchange.com/questions/5520/why-do-liquids-and-solids-have-constant-concentrations
https://chemistry.stackexchange.com/questions/5520/why-do-liquids-and-solids-have-constant-concentrations
- Sun Mar 07, 2021 4:36 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Advice from a Medical Student - Part II [ENDORSED]
- Replies: 223
- Views: 16048
Re: Advice from a Medical Student - Part II [ENDORSED]
Hello! I'm Anthony, a first year Neuroscience major. I really appreciate your story and I love people who are trying to help young aspiring people learn and grow.
- Thu Feb 18, 2021 8:18 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Cv(Heat Capacity) of Monoatomic and Diatomic Particles
- Replies: 2
- Views: 22
Cv(Heat Capacity) of Monoatomic and Diatomic Particles
According to the U of monoatomic and diatomic gas, which are 3/2RT and 5/2RT respectively, we know that Cv for them respectively is 3/2R and 5/2R because Cv is the derivative of U. What about Cp? Do we need to know Cp for MIdterm 2?
- Wed Feb 17, 2021 5:23 am
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: 4C.3
- Replies: 5
- Views: 41
Re: 4C.3
I think I know how to explain this. For (b), when the volume is constant ΔU = q because w = 0. This is why the correction puts 765J in place of ΔU. First problem solved. Next, since ΔH = ΔU + PΔV, if V is constant, then according to PV = nRT, pressure must have changed since temperature increased. H...
- Wed Feb 17, 2021 1:01 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 4.15
- Replies: 2
- Views: 18
Re: 4.15
Ok, I can explain this annoying problem. So the reaction releases heat, which can be calculated from the Enthalpy of formation values from Appendix 2 in the textbook. This heat is given off by the reaction(the system) and absorbed by the solution(the surrouding), so although the calculated value for...
- Mon Feb 15, 2021 7:43 pm
- Forum: Calculating Work of Expansion
- Topic: Why do we care about the external pressure only when calculating work of expasion?
- Replies: 2
- Views: 34
Why do we care about the external pressure only when calculating work of expasion?
I found this really good answer on Quora. Please take look. So in thermodynamics, why do we only care about the external pressure when calculating the work done on a system? The key word here is the system ... it includes the piston itself as well. Work done by the system implies a transfer of energ...
- Mon Feb 15, 2021 7:24 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Why is deltaU zero in isothermal expansion?
- Replies: 2
- Views: 295
Re: Why is deltaU zero in isothermal expansion?
such a great explanation!
- Sun Feb 14, 2021 10:44 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: When is the Gibbs Free Energy useful
- Replies: 4
- Views: 11
Re: When is the Gibbs Free Energy useful
It is useful to see whether a reaction is at equilibrium or not if we don't know K for the reaction.
- Sun Feb 14, 2021 10:42 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: different types of entropy
- Replies: 1
- Views: 24
Re: different types of entropy
I don't know for sure but I think both has a measured value, which can be found using the formulas: the Boltzmann equation for positional entropy and S = Cpln(t2/t1) for thermal entropy. IF you can measure them, you can tell which is larger.
- Sun Feb 14, 2021 10:34 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Boltzmann equation: positional entropy or thermal entropy?
- Replies: 4
- Views: 243
Re: Boltzmann equation: positional entropy or thermal entropy?
In Dr. Lavelle's February 3rd lecture, he said that the Boltzmann equation is used to calculate positional entropy and ignores thermal entropy because it is more practical to do so.
- Sun Feb 14, 2021 10:28 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Spaling 5/6 #6
- Replies: 6
- Views: 27
Re: Spaling 5/6 #6
multiple J/(mol*K) by the number of moles, which is 4.63
- Sun Feb 14, 2021 10:25 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Textbook 4G.5
- Replies: 3
- Views: 27
Re: Textbook 4G.5
Basically, these types of questions require you finding out the total number of possible combinations, similar to the probabilities section in math. After all, entropy is a tool to explain the spontaneity of a change due to possibilities. Take this question as an example. We could reframe it as &quo...
- Sat Feb 06, 2021 6:44 pm
- Forum: Calculating Work of Expansion
- Topic: Maximum work from reversible processes [ENDORSED]
- Replies: 2
- Views: 162
Re: Maximum work from reversible processes [ENDORSED]
Thank you so much Dr. Lavelle!
- Fri Feb 05, 2021 5:02 am
- Forum: Calculating Work of Expansion
- Topic: Maximum work from reversible processes [ENDORSED]
- Replies: 2
- Views: 162
Maximum work from reversible processes [ENDORSED]
Why does a reversible process do maximum work? Since a reversible process undergoes when the internal and external pressures are equal, is the work done through slight fluctuations of the pressures? And is this why we use the integral to calculate the equation of work for a reversible process equals...
- Thu Feb 04, 2021 7:31 pm
- Forum: Calculating Work of Expansion
- Topic: Sapling week 3/4 #15
- Replies: 9
- Views: 57
Sapling week 3/4 #15
The question is as follows: Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2NaN3(s)⟶2Na(s)+3N2(g) Calculate the value of work, w, for the system if 24.9 g NaN3 reacts completely at 1.00 atm and 22 ∘ C. How am I supposed t...
- Thu Feb 04, 2021 6:30 am
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Entropy = 0
- Replies: 6
- Views: 43
Re: Entropy = 0
Hi, I believe that entropy is very small because oxygen only has two particles, which means the number of combinations to achieve the state of oxygen is very small. We can tell from the equation with the degeneracy variable, and so all diatomic molecules have very small degeneracy.
- Sun Jan 31, 2021 7:04 pm
- Forum: Phase Changes & Related Calculations
- Topic: Sarah Tang Workshop Question
- Replies: 2
- Views: 48
Re: Sarah Tang Workshop Question
To add on to Asheley's wonderful explanation, the heat of sublimation is equal to the heat of fusion + the heat of vaporization. So you could combine steps 2 and 4 in Ashley's description by calculating m*(heat of sublimation) = q. Then add this to the rest of the calculations, which will yield the ...
- Sun Jan 31, 2021 7:01 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Calculus for thermochemistry
- Replies: 5
- Views: 40
Calculus for thermochemistry
Hi,
I just saw in the textbook that there are some questions requiring Calculus, so I'm wondering if there's any class in UCLA that teaches using calculus to approach chemistry.
I just saw in the textbook that there are some questions requiring Calculus, so I'm wondering if there's any class in UCLA that teaches using calculus to approach chemistry.
- Sun Jan 31, 2021 6:45 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Calculating heat of combustion
- Replies: 1
- Views: 23
Re: Calculating heat of combustion
Hi, for your first question, we don't divide c by mass; we divide C by mass. c is the specific heat while C is the heat capacity. They are related by the equation C = c*m. Thus, c = C/m. So, if the question gives you the heat capacity, then divide it by the mass of the substance combusted. For the s...
- Sun Jan 24, 2021 7:28 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: pH of salt/bases
- Replies: 4
- Views: 37
Re: pH of salt/bases
Go check table 6C.1 and 6C.2. lol. It will give you the answer.
- Sun Jan 24, 2021 7:28 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 4E.9 bond enthalpy
- Replies: 2
- Views: 34
Re: 4E.9 bond enthalpy
I believe that the resonance structure has lower energy, and is therefore more stable.
- Sun Jan 24, 2021 7:18 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Polyprotic Acids
- Replies: 5
- Views: 53
Re: Polyprotic Acids
I'll just attach these texts and graphs from the textbook to show that: 1. Ka1 for Sulfuric acid is considered so large that it is basically a 100% deprotonation. 2. Accounting for Ka2 of sulfuric acid (and other rare cases) only shifts the pH slightly 3. when Ka2 is less than Ka1/1000 then it does ...
- Fri Jan 22, 2021 5:12 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Homework Problem 6D.13
- Replies: 6
- Views: 73
Re: Homework Problem 6D.13
You need to calculate [H+] to solve this. First, observe that C6H5NH2 is basic in solution while all others are acidic solutions. Therefore, it has the highest pH. Next, do calculate [H+] for the rest. First, for HCl [H+] is 10^-5, which is the same as the initial concentration. For CH3NH3Cl, use th...
- Sun Jan 17, 2021 7:33 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ice tables
- Replies: 7
- Views: 48
Re: ice tables
I suggest checking a few things before you do the work. 1. which side will the reaction shift towards? (so that the plus and minus signs are placed correctly) 2. the coefficients of each reactant and product (so that the ratio is clear and the power of each item is correct when writing the K) 3. whe...
- Sun Jan 17, 2021 7:11 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Week 2 Problem 10
- Replies: 1
- Views: 46
Re: Sapling Week 2 Problem 10
B(aq)+H2O(l)↽⇀BH+(aq)+OH−(aq) It is hard to understand the relationship of pH and pKa if you don't break it down mathematically. Let me give you the magic equation: pH = pKa + log\frac{[A^{-}]}{[HA]} I highly encourage you to calculate this by your self, which requires some simple logarithmic calcul...
- Sun Jan 17, 2021 6:17 pm
- Forum: General Science Questions
- Topic: Matthew UA WS 2 #5
- Replies: 2
- Views: 70
Re: Matthew UA WS 2 #5
First, watch this video: [youtube]https://www.youtube.com/watch?v=50tT_jdkINw[/youtube] It helps a lot. But I'll still explain. First calculate the volume(mL) of NaOH needed, which is 50.51082959mols from this: 7.416\cdot10^{-3}\cdot\frac{100}{1.4682\cdot10^{-2}} . So you now have the mols of NaOH a...
- Sun Jan 17, 2021 5:49 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook Problem 5I23
- Replies: 3
- Views: 30
Re: Textbook Problem 5I23
It is simple. Contruct the ICE table and you get this: CO | 3H_{2} | CH_{4} | H_{2}O 2-x |3-3x | +x | +x 2-x |3-3x | 0.478 | x Since the change in concentration of CH4 is x, and its equilibrium concentration is 0.478, then x = 0.478. And don't forget to divide these numbers by 10L in the end!
- Sun Jan 17, 2021 5:42 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Week 1 and 2 #9
- Replies: 5
- Views: 32
Re: Sapling Week 1 and 2 #9
So first calculate K from the equilibrium concentrations, which is indeed 25. Then, calculate x from your equation = 25. Finally, SUBTRACT 2X from 0.8. You did correctly so I think it may be that you did this final step wrong.
- Mon Jan 11, 2021 5:28 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook Problem 5.39
- Replies: 6
- Views: 79
Re: Textbook Problem 5.39
Table 5G.2 in the textbook has an error. For the reaction N2O4 ⇌ 2NO2 at 298 K, the Kc value is 6.1 x 10-3. 5.39 Since the reverse reaction is needed the inverse of 6.1 x 10-3 is 1.6 x 102. Which is the correct value used in the solutions manual for 5.39. The solutions manual is correct. This is the...
- Sat Jan 09, 2021 6:43 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Wk 1 Q2
- Replies: 3
- Views: 88
Re: Sapling Wk 1 Q2
A concentration table would be 0.304-x | +x| +1/2x|
Since 1/2x = 0.13, x = 0.26, so K =
, which is 0.0.14. Hope this helps!
Since 1/2x = 0.13, x = 0.26, so K =
- Sat Jan 09, 2021 6:26 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook Problem 5.39
- Replies: 6
- Views: 79
Re: Textbook Problem 5.39
This is really weird. The answers given are 0.0065M for N2O4 and 0.007M for NO2, but if you calculate K from this: 0.0065/(0.007)^2, then K = 132.653, which does not match Table 5G.2. Table 5G.2 gives 0.15 for the reverse reaction, so K should be 1/0.15 = 6.66666667. I can't explain this. However my...
- Sat Jan 09, 2021 5:20 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Question 4
- Replies: 5
- Views: 53
Re: Sapling Question 4
You've made a good point. A reaction can actually have two K values: a forward one and reverse one, but scientists define Kp of a reaction written as A+B -> C as equal to [C]/[A][B]. So the Kp given by the problem is equal to [PCL5]/[PCl3][Cl2], which has nothing to do with what is going on in the r...
- Sat Jan 09, 2021 5:09 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Question 5I.23
- Replies: 2
- Views: 37
Re: Question 5I.23
I got 3.909 too. I'm pretty sure it's correct. My calculation was
.
- Sat Jan 09, 2021 4:01 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling week 1 #10
- Replies: 1
- Views: 28
Sapling week 1 #10
N2O4c -> 2NO2 is allowed to reach equilibrium in a chloroform solution at 25 ∘C . The equilibrium concentrations are 0.487 mol/L N2O4 and 2.34 mol/L NO2 . Calculate the equilibrium constant, Kc , for this reaction. The correct Kc is 11.24. I was stuck on the last question in this problem: Calculate ...
- Sun Dec 13, 2020 6:01 am
- Forum: Conjugate Acids & Bases
- Topic: Fundamentals J.9
- Replies: 1
- Views: 40
Re: Fundamentals J.9
(a) HOK + CH_{3}COOH \rightarrow K(CH_{3}COO) (b) 3NH_{3} + H_{3}PO_{4} \rightarrow (NH_{4})_{3}PO_{4} (c) CaOH + 2HBrO_{2} \rightarrow Ca(BrO_{2})_{2} (d) 2NaOH + H_{2}S \rightarrow Na_{2}S So I've typed the equations. The general rule here i...
- Sun Dec 06, 2020 7:25 pm
- Forum: Polyprotic Acids & Bases
- Topic: multiple deprotonations and sulfuric acid
- Replies: 2
- Views: 19
Re: multiple deprotonations and sulfuric acid
What the textbook is saying is that Ka1 for sulfuric acid is way larger than other polyprotic acids. In fact, sulfuric acid is classified as a strong acid if you remember the list: HCl, HBr, HI, HNO3, HClO3, HClO4, and H2SO4! Since Ka is a tool to measure the degree of deprotonation of weak acids an...
- Sun Dec 06, 2020 6:41 pm
- Forum: Naming
- Topic: Naming [Co(CN)5(OH2)]2-
- Replies: 5
- Views: 49
Re: Naming [Co(CN)5(OH2)]2-
Screen Shot 2020-12-07 at 10.37.14 AM.png Hi, I'm pretty sure aqua is incorrect, as well as your own naming, because according to this chart in this website http://www.chemistry.wustl.edu/~edudev/LabTutorials/naming_coord_comp.html , OH as a ligand is called hydroxo while H2O is called aqua, so the...
- Sun Dec 06, 2020 6:34 pm
- Forum: Hybridization
- Topic: Focus Question 2.45
- Replies: 3
- Views: 35
Re: Focus Question 2.45
This is the lewis structure from the internet https://www.chemistrylearner.com/wp-content/uploads/2011/10/Acrolein-Pictures.jpg Although the lone pairs are not shown, it is obvious that oxygen has two lone pairs and no other atoms has any. Let's work on the bonds first, though. For the bonds, lets g...
- Sun Dec 06, 2020 5:11 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Sapling week 9 question 3
- Replies: 4
- Views: 29
Sapling week 9 question 3
The answer for this problem is that the common shapes for coordination number 4 are tetrahedral and square planar but not seesaw. Why is this? Is this because seesaw is not a ring, which coordination compounds look like?
- Sun Dec 06, 2020 4:59 pm
- Forum: Polyprotic Acids & Bases
- Topic: Box 6E.1
- Replies: 2
- Views: 16
Re: Box 6E.1
I believe that Dr. Lavelle just want us to know about acid rain and its causes, instead of reading the information in 6E.4, which is about composition and pH. However, I think we should be familiar with the major acids involved in acid rain.
- Sun Nov 29, 2020 6:11 am
- Forum: Biological Examples
- Topic: Hemoglobin: a coordination compound?
- Replies: 2
- Views: 33
Hemoglobin: a coordination compound?
In class Dr. Lavelle defined organometallic compounds as transition metal cations with organic ligands, which reminds me of the heme groups in hemoglobin of a RBC. However, the wikipedia says that it is an organometallic compound while another website claims that it's not because the ligands are &qu...
- Sun Nov 29, 2020 6:00 am
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Coordination compound and ions
- Replies: 4
- Views: 43
Re: Coordination compound and ions
NiCl2 is an ionic compound. A coordination compound is defined as being surrounded by multiple ligands (large molecules), forming multiple coordination bonds, as shown in the picture below. Although NiCl2 is surrounded by Cl, Cl is not a molecule and it does not form coordination bonds with Ni. http...
- Sun Nov 29, 2020 5:57 am
- Forum: Sigma & Pi Bonds
- Topic: Rotation on the Internuclear Axis
- Replies: 2
- Views: 25
Re: Rotation on the Internuclear Axis
Hi! The internuclear axis is defined as the straight line connecting the center of the two atoms in a bond. For your first question, the sigma bond does have electron density on both sides of the axis, but the density directly overlaps the axis, as seen in the image below. However, a pi bond is also...
- Sun Nov 29, 2020 5:51 am
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Ligands
- Replies: 4
- Views: 31
Re: Ligands
Sorry but I don't know what you mean by electon rich, but according to Dr. Lavelle, a ligand is any molecule that interacts with a transition metal, which is usually a cation. So, ligands are usually electron pair donors; they form coordination bonds with the transition metal ion.
- Wed Nov 25, 2020 6:48 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling week 7/8 problem 18
- Replies: 2
- Views: 21
Sapling week 7/8 problem 18
This problem is about the pattern of H2C(C)xCH2, which starts with H2CCH2 and continues with H2CCCH2 and so on. The pattern is that for even numbers of x, the H atoms are in the same plane, meaning that H2CCCH2, H2CCCCCH2, H2CCCCCCH2 have H atoms on the same plane. Why is this? Is this due to the pi...
- Mon Nov 23, 2020 4:58 am
- Forum: Sigma & Pi Bonds
- Topic: Sigma Bonds in Double Bonds
- Replies: 2
- Views: 58
Re: Sigma Bonds in Double Bonds
I don't know what you mean by get closer because is inherently the connection of two atoms so of course they are close. But there is a repelling force between the nuclei of the two atoms, so although the bonding decreases the potential energy of the two atoms involved, allowing them to be stabler, t...
- Sun Nov 22, 2020 4:54 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: lone pair position placing
- Replies: 4
- Views: 29
lone pair position placing
In molecules with a steric number of 5 and 6, why are the lone pair electrons placed with different patterns? For example, AX4E1 is a seesaw shape. AX3E2 is a t-shaped. The lone pair electrons are placed first in the center triangle. However for molecules of steric number 6, the lone pairs are place...
- Sun Nov 22, 2020 4:25 am
- Forum: Dipole Moments
- Topic: Pressures and Points
- Replies: 4
- Views: 57
Re: Pressures and Points
To further clarify Melody Haratian's points, I want to point out that vapor pressure is a definition for convenience of calculation and comparison. You could tell which substance has higher boiling point by its vapor pressure. The correct definition of vapor pressure is the pressure (N/m^2 = pascal(...
- Sun Nov 22, 2020 1:08 am
- Forum: Bond Lengths & Energies
- Topic: IMF vs. Intramolecular Forces
- Replies: 7
- Views: 68
Re: IMF vs. Intramolecular Forces
I think if it asks about the bond strengths then it is intramolecular forces. By the way, the ranking of intramolecular strengths is metallic bond > ionic bond > polar covalent bond > nonpolar covalent bond. Also, for ionic bonds, there are also stronger ionic bonds, which are less polarized. If the...
- Sun Nov 15, 2020 11:37 pm
- Forum: Resonance Structures
- Topic: Defenition of making a major contribution
- Replies: 3
- Views: 14
Re: Defenition of making a major contribution
Thank you Edward! I love how you explained this. since we do not even know exactly where the electron is in even a single atom. Like mixing paint, mixing black and white will yield a color that is much darker than white but slightly brighter than black. So we would say black is a major contribution....
- Sun Nov 15, 2020 11:26 pm
- Forum: Resonance Structures
- Topic: Resonance of Hydrogen phosphate
- Replies: 2
- Views: 16
Resonance of Hydrogen phosphate
In textbook problem 2C.3, when trying to draw the Lewis structure of hydrogen phosphate ion, I can't help but notice that it also has several possible forms, but with the H attached to different oxygens. I googled and found an article with this picture bellow. It didn't explain much besides that &qu...
- Sun Nov 15, 2020 7:47 pm
- Forum: Resonance Structures
- Topic: Defenition of making a major contribution
- Replies: 3
- Views: 14
Defenition of making a major contribution
In some Sapling problems, we are asked to identify which resonance structure makes the most contribution to the actual structure. What does this really mean? Suppose a structure with more double bonds make the contribution, does this mean that empirical bond data would find a bond length closer to t...
- Sun Nov 15, 2020 7:27 pm
- Forum: Octet Exceptions
- Topic: Identifying Radicals
- Replies: 24
- Views: 202
Re: Identifying Radicals
Hello! To add on to previous points, molecules with one unpaired electron are called radicals and those with two unpaired electrons are called biradicals. A picture here for examples: https://upload.wikimedia.org/wikipedia/commons/thumb/d/de/Non-Kekule-Structures.svg/510px-Non-Kekule-Structures.svg....
- Sun Nov 15, 2020 7:22 pm
- Forum: Octet Exceptions
- Topic: Textbook 2C.3 question
- Replies: 3
- Views: 44
Re: Textbook 2C.3 question
To summarize and simplify, phosphate has one double bond and 3 single bonds and chlorate has two double bonds and 1 single bond. The difference is probably because chlorine is more electronegative than phosphorous. The hydrogen phosphate ion and chloric acid are just phosphate and chlorate with an e...
- Sun Nov 15, 2020 7:05 pm
- Forum: Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)
- Topic: Identifying intermolecular forces
- Replies: 2
- Views: 21
Re: Identifying intermolecular forces
Hi~ For question c, if you look at the electronegativity chart, you'll see that the electronegativity of I is very close to C, but that of F is way larger than C. Thus CHF3 is a much more polar molecule and it would experience stronger dipole-dipole forces. So it has a higher melting point.
- Sun Nov 15, 2020 6:35 pm
- Forum: Ionic & Covalent Bonds
- Topic: ε0 [ENDORSED]
- Replies: 1
- Views: 35
ε0 [ENDORSED]
Can someone explain the vacuum permittivity in plain English? I've been confused by it since high school when we learned about the Coulomb force between charges.
- Sun Nov 15, 2020 5:51 pm
- Forum: Ionic & Covalent Bonds
- Topic: Textbook Questions
- Replies: 1
- Views: 19
Re: Textbook Questions
This problem is testing your knowledge on intermolecular forces since the stronger this force, the higher the melting point of a molecule. A) The difference in electronegativity is larger for NaCl, meaning a stronger ionic bond, so NaCl has a higher melting point. B) Butanol (an alchohol) has hydrog...
- Sat Nov 14, 2020 6:17 am
- Forum: Resonance Structures
- Topic: Resonance of HCNO
- Replies: 1
- Views: 33
Resonance of HCNO
In the Sapling Homework week 5&6 quesiton 5, the problem lists three resonance structures of HCNO. However, the bond angles of some bonds in each structure are different, according to VSEPR theory. For example, the carbon in one has no lone pair electrons, another has 1, and another has 2. So in...
- Mon Nov 09, 2020 6:37 am
- Forum: Formal Charge and Oxidation Numbers
- Topic: formal charge vs oxidation number
- Replies: 3
- Views: 30
Re: formal charge vs oxidation number
Adding on to Claire_Latendresse_3J, both the formal charge and oxidation number are rules that are not accurate to describe the real property of bonds. They are simply convenient tools for chemists to calculate. The exact property of atoms or ions bonding with others are not whole numbers like +1 or...
- Mon Nov 02, 2020 6:52 am
- Forum: Ionic & Covalent Bonds
- Topic: Ionic vs Covalent
- Replies: 32
- Views: 18224
Re: Ionic vs Covalent
Alex is completely correct. Adding on to his point, I want to say that for crystalline solids, Network solids have stronger bonds than Ionic solids, but normal covalent bonds are weaker than ionic bonds. What I'm talking about here is intramolecular forces , the forces acting inside a molecule, not ...
- Mon Nov 02, 2020 6:30 am
- Forum: Ionic & Covalent Bonds
- Topic: Differences in structures between ionic and covalent bonds
- Replies: 7
- Views: 75
Re: Differences in structures between ionic and covalent bonds
The ionic bond is stronger than the covalent bond because electric forces are strong, making ions harder to separate than the atoms sharing electrons in a covalent bond.
- Sun Oct 25, 2020 8:14 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Quantum number ml
- Replies: 3
- Views: 71
Re: Quantum number ml
To clarify, the range only indicates the "possible values" of ml (orbitals) , which is based on the value of l. L indicates the subshells s, p, d, f etc., with l = 0 representing s, 1 representing p, and so on. It would be better to visualize this concept by looking at the periodic table. ...
- Fri Oct 23, 2020 4:49 am
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Sapling Weeks 2-4 #13
- Replies: 2
- Views: 44
Re: Sapling Weeks 2-4 #13
1. n= 4 ℓ=2
This is in the 4d sub-shell, so there are 5 orbitals. Each orbital can only have 2 electrons. So that's a total of 5*2 = 10 electrons.
2. n= 6 ℓ=1 mℓ= -1
This is in the 6p orbtial. There are 3 orbitals and the ml means one of the two electrons in a orbital. So thats 3*1 = 3electrons.
This is in the 4d sub-shell, so there are 5 orbitals. Each orbital can only have 2 electrons. So that's a total of 5*2 = 10 electrons.
2. n= 6 ℓ=1 mℓ= -1
This is in the 6p orbtial. There are 3 orbitals and the ml means one of the two electrons in a orbital. So thats 3*1 = 3electrons.
- Fri Oct 23, 2020 4:36 am
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Indeterminacy for Electrons in Bohr's Model of Atoms?
- Replies: 3
- Views: 78
Re: Indeterminacy for Electrons in Bohr's Model of Atoms?
I don't think the Uncertainty Principle can explain where the electrons are in different outer shells, when the electrons move up or down energy levels, when electrons are ionized, or when electrons are affected by the shielding effect. You could take a look at page 31 in the text where it explains ...
- Fri Oct 23, 2020 3:54 am
- Forum: *Shrodinger Equation
- Topic: Clarrification of EΨ
- Replies: 5
- Views: 111
Clarrification of EΨ
In the Schrodinger equation, I understand the left part (Hamiltonian), but I'm confused about what EΨ actually means. Is it just "one" symbol, so that EΨ means the total energy of an electron, or is it that E means the energy and Ψ just represents the wave function itself, so that EΨ equal...
- Fri Oct 23, 2020 3:33 am
- Forum: Quantum Numbers and The H-Atom
- Topic: Rydberg Constant
- Replies: 13
- Views: 125
Rydberg Constant
In the Equation that Schrodinger found:
, the Rydberg constant according to the text book is 3.29 X 10^15 Hz. However, in the hint section for a question on Sapling, it says R = 10 973 731.6
. Which one should I use??
- Mon Oct 19, 2020 8:48 am
- Forum: Properties of Light
- Topic: Sapling HW Week 2, 3, 4 Question #7
- Replies: 10
- Views: 120
Re: Sapling HW Week 2, 3, 4 Question #7
I had problems with this one too! So first you need to open the link to a table with the energy of fusion of solid H2O, which is in units of J/g. So multiply this value by 411grams and you get the total energy(J) needed. Then calculate the energy of one photon, which is h*\frac{3*10^8}{899*10^{-9}} ...
- Mon Oct 19, 2020 8:38 am
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: How to calculate ΔP and ∆x
- Replies: 3
- Views: 36
How to calculate ΔP and ∆x
I'm confused about the units and the exact value of ∆P and ∆x. Since they are uncertainties i'm assuming the values of these two should be probabilities? In the textbook examples it doesn't really explain how to calculate clearly. Can someone explain?
- Mon Oct 19, 2020 8:00 am
- Forum: Photoelectric Effect
- Topic: Atomic Specta Post-Module Assessment
- Replies: 3
- Views: 38
Re: Atomic Specta Post-Module Assessment
Since in this case the equations E = hv and E = KE + Φ come from quantum physics, they concern only values of one electron, not a mole.
- Sun Oct 18, 2020 6:13 am
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: question 1D23
- Replies: 3
- Views: 179
Re: question 1D23
The number of orbitals in a subshell is determined by the orbital angular momentum quantum number l. The magnetic quantum number m, represents the number of orbitals, and m ranges from -l to +l. So in this case, l = 1, so m = -1, 0, or 1. Therefore there are three orbitals, and each orbital contains...
- Sun Oct 18, 2020 6:00 am
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Sapling Week2 Question 26
- Replies: 2
- Views: 38
Sapling Week2 Question 26
I understand the uncertainty equation but fail to know how to apply it for calculations. This is the question What is the minimum uncertainty in an electron's velocity (Δvmin) if the position is known within 15 Å. I know the unit means 10^-10 meters, but couldn't understand what the phrase "kno...
- Mon Oct 12, 2020 4:41 am
- Forum: Administrative Questions and Class Announcements
- Topic: Students in different time zones [ENDORSED]
- Replies: 27
- Views: 1406
- Mon Oct 12, 2020 1:20 am
- Forum: Properties of Electrons
- Topic: Calculating Kinetic Energy
- Replies: 1
- Views: 76
Re: Calculating Kinetic Energy
Hello Isabel, Ok. So first it gives you the wavelength, 194 nanometers, of the light. Therefore, the frequency of this light is \frac{3*10^8m/s}{194nm} , according to this equation: c = λν And according to a website: For the relationship to hold mathematically, if the speed of light is used in m/s, ...
- Sat Oct 10, 2020 4:36 am
- Forum: Administrative Questions and Class Announcements
- Topic: Petition to Bring Music Back To Lectures [ENDORSED]
- Replies: 34
- Views: 558