CHEMISTRY COMMUNITY

Gabe_Ek 1G

Chemistry community scores are additive and I believe we have until tomorrow (Tuesday) morning to make up points if we missed any posts throughout the quarter. As long as you have 50 posts for the quarter by then you should get full credit! I was just about to ask when the chemistry community score...

Gabe_Ek 1G

Ismar Zamora wrote:Drake!

Agreed! His music always has a vibe.

Gabe_Ek 1G

I believe the rate constant only affected If there's a change in temperature.

Gabe_Ek 1G

I started watching Peaky Blinders but haven't been able to go through it yet, but 10/10 would recommend.

Gabe_Ek 1G

Yes I believe that when there is no volume chance there is no work done by system as well!

Gabe_Ek 1G

I completely forgot about day light savings time but it at 9:30AM on Sunday. I am still not sure whenever what time the review session starts

Gabe_Ek 1G

Here n is the number of electrons that are being transferred in the reaction.

Gabe_Ek 1G

I believe that when work is done on the system, the work value is positive. But when the system does work then the value is negative.

Gabe_Ek 1G

Since K is usually always at equilibrium, when Q<K the reaction moves towards the products and when Q>K it favors the products.

Gabe_Ek 1G

I believe it's on Sunday morning March 14th

Gabe_Ek 1G

The purpose of salt bridges is not to of move electrons from the electrolyte, but rather maintain the charge balance because the electrons are moving from one half cell to the other.

Gabe_Ek 1G

I'm really craving like a brownie cake right now

Gabe_Ek 1G

At least for this equation, n is used as the number electrons transfered in the balanced equation for the particular reaction.

Gabe_Ek 1G

What is the chemical formula for “coffee”?
CoFe2

Gabe_Ek 1G

Hi! When Q<K, reactants are greater relative to it's proportion at equilibrium, so the reaction will go towards products. It will be the reverse for Q>K.

When Q<K, there are more reactants are and the reaction with shift towards the products. It is the reverse when Q>K.

Gabe_Ek 1G

I believe using Kelvin is the safe option. But I know at time it's okay to use Celsius because both units have the same degree of change.

Gabe_Ek 1G

Kiara Phillips 3L wrote:
305405193 wrote:Does any one have any good practice problems or YouTube videos for this topic to study for the final?

This video breaks it down a bit (https://youtu.be/6bi4_sAi0gE) hope this helps!

This is a very helpful video as well, thank you!

Gabe_Ek 1G

I was thinking to tell a Sodium and Hydrogen pun, but NaH.

Gabe_Ek 1G

Since K is a ratio, the units usually cancel our at the end, that's why they're no units with the final answer.

Gabe_Ek 1G

Yes like most people said there is two different R constants to use. You should either one accordingly based on which values are presented in the problem to get the appropriate answer.

Gabe_Ek 1G

I believe d is used for derivatives and delta is what we will be and have been using for change.

Gabe_Ek 1G

Thank you guys for the explaination, I was also stuck on this and it really helped me out!

Gabe_Ek 1G

Yea I have had similar things happened to me as well, but I believe its something that just goes on off but will eventually be there officially later on.

Gabe_Ek 1G

Thank you for sharing! I feel much better after reading this and knowing I'm not the only person feeling this way!

Gabe_Ek 1G

Yes I also believe that an additional one stated is standard molar entropy which is expressed as Sm⁰

Gabe_Ek 1G

If there is specific heat on both sides of the equation, I believe it is okay to cross them out on each side before proceeding to the next step.

Gabe_Ek 1G

I also feel the same way and I'm not really happy with how it went. I'm also going to focus more on going to UA sessions and workshops and reading the text more as well.

Gabe_Ek 1G

Why do chemist like nitrates so much?
They're cheaper than any day rates!

Gabe_Ek 1G

At least for studying I listen to slow jazz and piano instrumentals which help me focus most times.

Gabe_Ek 1G

I believe K would stand for Kp which is in regards to the equilibrium constant for pressure and Kc for molar concentrations.

Gabe_Ek 1G

Nicely done! Now one to the next one! :|

Gabe_Ek 1G

I believe it will be important for the rest of the class. To find Ka you would have to raise it to the power of 10 to the negative of exponent where - Ka would be 10^(-pKa)

Gabe_Ek 1G

nayha a 1E wrote:I believe it's negative because the energy is being lost.

Yea I believe it represents an exothermic reaction that has occurred.

Gabe_Ek 1G

I was also quite frustrated by having my calculations all done to then find that none of the answer choices reflected the answer. It was a lot just a bit rushed but arguably doable.

Gabe_Ek 1G

What do you do with a sick chemist?
If you can't Helium and you can't curium, then you're going to have to Barium

Gabe_Ek 1G

Since they are relatively equal around 1atm = 1 bar, both units can be used interchangeably when solving problems!

Gabe_Ek 1G

I also really like listening to lofi music, piano instrumentals, and classical jazz. I find those really help me stay focused and in the zone.

Gabe_Ek 1G

I would say they're quite helping getting a refresher on chemical chemical equilibrium. At times I even find myself going back to it figure out problems as well.

Gabe_Ek 1G

This would really be helpful! I'll be able to keep on track and get a some help with all my confusion!

Gabe_Ek 1G

Lily Anne Garcia 1C wrote:do the textbook problems and attend step ups

I also think this is very useful alongside the specific problems on the outline.

Gabe_Ek 1G

I believe that they're stated in the syllabus

Gabe_Ek 1G

with all problems involving pH, I believe you can use it

Gabe_Ek 1G

Yea i believe sapling gives you different values

Gabe_Ek 1G

The textbook questions really have everything you need for the midterms and finals

Gabe_Ek 1G

I believe it would be critical to determine if the reaction is endothermic or exothermic for this rxn

Gabe_Ek 1G

Is there any case where we won't use atm? Such as having to change the final answer into Pa (Pascal) or kPa?

Gabe_Ek 1G

904571591 wrote:You can search your username or the main words of your post.

This is what I usually do but I think we can use quick links on the top right hand corner of the website. I'm not so sure if this was here during 14A as well...

Gabe_Ek 1G

KTran 1I wrote:Are there a lot of topics in the book that are not covered during lecture that show up on tests?

I had the same question as well because I've heard that there's a lot of information covered that we don't need.

Gabe_Ek 1G

OmarArafat_2K wrote:Only include H2O in the ice table if it is aqueous and gaseous, never a liquid or a solid. Ensure that you know which phase it is in always.

Is aqueous not the same as a liquid or am I getting this wrong?

Gabe_Ek 1G

alebenavides wrote:
Lily Anne Garcia 1H wrote:i would encourage multi term, that way you can use it over several quarters for a more reasonable price

yea this is more reasonable and beneficial bc u can use it on another term.

I believe it is more beneficial because at least for when you enrolled in 14A with Lavelle it carried over into 14B.

Gabe_Ek 1G

Nicole Critzer 2L wrote:Everything on Sapling is automatically graded right? We don't have to turn anything in for this portion of the course?

Yeah, I believe so. We just have the 5 chemistry community posts weekly that we have to "turn in."

Gabe_Ek 1G

You would only use the Latin name when the atom is negatively charged / is an anion.

Gabe_Ek 1G

Ocyacids are compounds that have include both hydrogen, oxygen, and another element to make up an acid. Some examples of this are HBrO3, H2CO3, and HIO3 where the strength of the acid increases per number of oxygen.

Gabe_Ek 1G

Forget Hydrogen, you're my number one element ;)

Gabe_Ek 1G

What is the name of 007's Eskimo cousin?
Polar Bond.

Gabe_Ek 1G

I believe it is possible for a very strong acid to have a negative pH based on the logarithmic pH scale of the concentration of hydronium ions. But I think for this class it is going to be addressed within the 0-14 scale.

Gabe_Ek 1G

En stands for a natural bidentate ligand ethylenediamine where its full chemical formula is NH2CH2CH2NH2

Gabe_Ek 1G

CH3COOH is a weak acid because within a solution it dissociates partially, not completely, where an H+ ion is formed alongside CH3COO- ions.

Gabe_Ek 1G

Chloride is a halogen with an oxidation state of -1. The overall charge of the compound is also -1. Even if we aren't given the oxidation of Cu we can still solve to find out. It would be X + 2(-1) = -1, where X stands for Cu. When solved we get +1 and that's the oxidation state for the metal atom Cu.

Gabe_Ek 1G

All this time I thought there was a tik or a specific shape on his hat, guess I was completely wrong too.

Gabe_Ek 1G

So far I feel okay because I think I am understanding the materials so far. The upcoming material is what is worrying me a little which is why I am not so confident about the final, but I hope to utilize all these resources well.

Gabe_Ek 1G

I believe the weekly discussion grades come from the Chemistry Community posts every week.

Gabe_Ek 1G

Yes, that's true. Some of the electrons are delocalized which means they form delocalized pi bonds that are perpendicular to the Benzene molecule which can also share these electrons.

Gabe_Ek 1G

I also found this really helpful, thank you!

Gabe_Ek 1G

Yes this is true, London dispersion forces are always present within molecules. These are usually not so strong depending if the molecular mass is relatively large or not.

Gabe_Ek 1G

I still do not trust Green, but just for this round, I will make friends with them to see if they act suspicious.

Gabe_Ek 1G

I believe that every single bond has a sigma bond, and every other bond also consists of a sigma bond. However, a double bond has an additional pi bond, and a triple bond has 2 pi bonds as well.

Gabe_Ek 1G

The outermost electron, or the one that is furthest away from the nucleus on the outermost orbital, is what is referred to as the first ionization energy.

Gabe_Ek 1G

Yes, I believe Lavelle said the Final will be cumulative so it will cover everything.

Gabe_Ek 1G

A unit of mmol or known more as millimole is 10^-3 of a mole or mol.

Gabe_Ek 1G

The main difference between the two ions is that the sulfur on the sulfite ion has a lone pair which changes up the geometry of the shape compared to the carbon on the carbonate ion that has no lone pairs.

Gabe_Ek 1G

I also really struggle with memorizing and visualizing some of the shapes. I've also heard testing yourself on Quizlet along with some useful diagrams can be really helpful.

Gabe_Ek 1G

I think the atomic radius trend Is a trend we should know but I am not sure about the Ionic trend. But for the ionic radius, it decreases across a period and down a group the ionic radius increases.

Gabe_Ek 1G

I would call out green, just incase I as yellow was going to die there....

Gabe_Ek 1G

I am not sure that he went into much detail about them last week. A single bond is a sigma bond. Double bond has one sigma, one pi. Triple has one sigma, 2 pi bonds. A sigma bond is stronger than a pi bond. Sigma bonds are overlapping of electrons on the end of each atom; it is a linear overlapping...

Gabe_Ek 1G

It would be due at Sunday 11:59 before week 7 for the week 5/6 homework.

Gabe_Ek 1G

It will cover all the bullet points for outline 3 - chemical bonds section and the last 8 points of outline 2 - quantum world section.

Gabe_Ek 1G

Yes I believe Van Der Waals and London Dispersion are interchangeable. I was more familiar with VDW forces and was slightly confused but they're both dipole induced dipole interactions.

Gabe_Ek 1G

I would follow green so if I die hopefully they know who is really being suspicious.

Gabe_Ek 1G

Nicole Attiq 3D wrote:The Organic Chemistry Tutor and Khan Academy are both amazing!

These are really good review videos. I also use Bozeman Science, he really helps too.

Gabe_Ek 1G

Not the best, the online system makes everything a bit more draining but maybe that's just me. I'm definitely getting used to it though but saying that I still have a bit of catching up to do.

Gabe_Ek 1G

Jonathan Malau 2I wrote:As a basketball fan, I really liked the Michael Jordan documentary that came out recently (now, on Netflix), known as the Last Dance.

Same here, I really enjoyed The Last Dance as well. I also finished up a new show on Netflix called The Queens Gambit which was really good too.

Gabe_Ek 1G

Whatever is at the lower energy level should be listed first. So for this example, it would be 3d^1 4s^2!

Gabe_Ek 1G

I had a similar question as well. It is confusing how Planck's constant may be introduced into this equation as I have seen before yet it is not within the original equation

Gabe_Ek 1G

I also had a similar question to this but specifically, since affinity is associated with the addition of electrons to an atom, wouldn't gaining an atom require energy instead of it being released?

Gabe_Ek 1G

Happy Halloween!! I dressed up as a soccer player and had some cake! Hope everyone stayed safe!

Gabe_Ek 1G

Hi! I think some students had complications with the testing (zoom/respondus issues) so likely due to make-ups it may delay but I also heard that the scores should be out by the end of the week.

Gabe_Ek 1G

I am also confused with this problem, however, I am not too sure how to determine the values of n using a chart of the energy level differences. If it is specifically noted to be within the H-atom does that automatically mean it is within the Balmer series?

Gabe_Ek 1G

The following question is from the Heisenberg module - Use the above uncertainty in velocity to calculate the electron's uncertainty in kinetic energy. Then calculate the uncertainty in kinetic energy per mole of electrons (that is, per mole of hydrogen atoms). I was able to do the first part of the...

Gabe_Ek 1G

I was also very confused about this question. I also thought that we had to multiply the hydrogen radius by 2 before continuing on with the problem. I got a similar answer of 1.1 x 10^8 m/s, which is very close to the correct answer of 10m^8 m/s. So will it practically not matter in most situations?

Gabe_Ek 1G

I enjoy playing video games and watching youtube to keep me entertained. If not, I sometimes like to go on walks listening to music (of any kind really) just so I can clear my head and be in a relaxed state of mind.

Gabe_Ek 1G

I am not so sure too and wondering about the same thing. Does this mean we shouldn't omit some of the practice questions?

Gabe_Ek 1G

This actually sounds very interesting! I wonder if any shift in mass can influence the potential of reach a natural frequency, if it was possible at least!

Gabe_Ek 1G

Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 105 m.s-1. The work function for sodium is 150.6 kJ.mol-1. How much energy is required to remove an electron from one sodium atom? Hi, I was able to get through this problem using the work function but got different...

Gabe_Ek 1G

Teti Omilana 2E wrote:Sorry just to make sure I have this correct so there is no Sapling HW due tonight?

Yes, I believe there is no Sapling HW due tonight. It will be due midnight of week 4.

Gabe_Ek 1G

Can someone please help me work through this problem? I'm really getting mixed up, especially with the calculation.

An excited hydrogen atom emits light with a frequency of 1.14 x 1014 Hz to reach the energy level for which n = 4. In what principle quantum level did the electron begin?

Gabe_Ek 1G

Same here with me. I am quite confused as well. I think it's something relating to "meter" in the first few words of the question but not sure what.

Gabe_Ek 1G

There are 3 significant figures here, in this case, 7 is a significant figure due to it being a non zero number, and the 2 zeros after the decimal points are also significant figures because it is after the decimal point. If it was to be written in standard notation (700), then 7 would be the only s...

Gabe_Ek 1G

Yes, I also agree! This is a concept that is often missed, especially by me, when trying to find the amount of product that has been produced. It can get a little unclear especially when the molar ratio of the moles of the element desired is similar to the given compound and it seems like there's no...

Gabe_Ek 1G

I also believe Professor Lavelle mentioned that the main unit that will be used for temperature will be Kelvin (K). However, most of the time I think it will depend on the units given within the problem unless it mentions otherwise, but it would also be helpful to be familiar with the conversion bet...

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