Search found 86 matches
- Sun Mar 14, 2021 8:07 am
- Forum: Administrative Questions and Class Announcements
- Topic: Saying Thank You to Dr. Lavelle
- Replies: 490
- Views: 698670
Re: Saying Thank You to Dr. Lavelle
Thank you Lavelle for all your hardwork and time you put into the pre-recorded lectures. All your lectures were so thorough and helpful, it really helped me understand the concepts for this class. I wish nothing but the best for you! Thank you!
- Tue Mar 09, 2021 11:26 am
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Sapling week 9-10. #12
- Replies: 5
- Views: 780
Sapling week 9-10. #12
So my problem 12 states: A particular reactant decomposes with a half‑life of 101 s when its initial concentration is 0.338 M. The same reactant decomposes with a half‑life of 241 s when its initial concentration is 0.142 M. Determine the reaction order. a.)1 b.)2 c.)3 I was wondering how you would ...
- Tue Mar 09, 2021 11:22 am
- Forum: General Science Questions
- Topic: How to study for final 14B
- Replies: 13
- Views: 1211
How to study for final 14B
I wanted to get other people's ideas of how they're studying for the final. I know Lavelle mostly uses textbook problems for the tests but I was wondering how you guys will be studying them? I was thinking of just going over the problems for one topic each day.
Thank you!
Thank you!
- Thu Mar 04, 2021 1:07 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: What was your favorite chem topic?
- Replies: 137
- Views: 14907
Re: What was your favorite chem topic?
Lewis structures in 14A and in 14B Chemical Equilibrium and some thermo topics
- Sun Feb 28, 2021 10:53 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Sapling #17
- Replies: 10
- Views: 526
Re: Sapling #17
Rachael Cohen 3G wrote:The equation we're working with is:
2H+(aq) + 2e− -> H2(g)
Q is products over reactants. H2 is a gas, so we use the pressure. H+ is aqueous, so we use the concentration. Hope this helps!
Thank you for this! I kept doing something else for Q and kept getting the wrong answer.
- Thu Feb 25, 2021 1:44 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Sapling Weeks 7 and 8 Question 12
- Replies: 4
- Views: 309
Re: Sapling Weeks 7 and 8 Question 12
Same, I keep getting it wrong but I feel like I'm doing it right. Did you find out what you did wrong? To see what I'm doing wrong lol. Thank you! Nvm I know what we might've done wrong. The answer will be first given in joules, so you have to convert it to kj for deltaG and then you'll get the cor...
- Thu Feb 25, 2021 1:25 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Sapling Weeks 7 and 8 Question 12
- Replies: 4
- Views: 309
Re: Sapling Weeks 7 and 8 Question 12
Same, I keep getting it wrong but I feel like I'm doing it right. Did you find out what you did wrong? To see what I'm doing wrong lol. Thank you!
- Wed Feb 24, 2021 9:57 pm
- Forum: Balancing Redox Reactions
- Topic: Sapling Week 7/8 #7
- Replies: 4
- Views: 345
Re: Sapling Week 7/8 #7
Its being marked incorrect for me as well. Do you know what you did wrong? because I don't know what Im doing wrong with mine
- Tue Feb 23, 2021 8:18 pm
- Forum: Balancing Redox Reactions
- Topic: Question Regarding videos for balancing redox reactions
- Replies: 2
- Views: 174
Re: Question Regarding videos for balancing redox reactions
rachelhchem1I wrote:Professor Lavelle sent an email yesterday with some text resources for balancing redox reaction in basic and acidic solutions! He also included some videos too so look at that email or his website if you haven't yet :)
thank you!
- Tue Feb 23, 2021 6:56 pm
- Forum: Balancing Redox Reactions
- Topic: Question Regarding videos for balancing redox reactions
- Replies: 2
- Views: 174
Question Regarding videos for balancing redox reactions
Does anybody know any youtube videos to balance redox reactions with H2O/OH and H ions, as shown in the textbook and sapling? I kinda understand it but I need little bit more help. Thank you!
- Thu Feb 18, 2021 6:28 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Question regarding outlines and Midterm 2
- Replies: 1
- Views: 141
Question regarding outlines and Midterm 2
Does anybody know up to what points in outline 3 were covered in midterm 1? To avoid them while I study for midterm 2. Thank you!!
- Thu Feb 18, 2021 6:26 pm
- Forum: General Science Questions
- Topic: Question Regarding Midterm 2 and outlines
- Replies: 1
- Views: 398
Question Regarding Midterm 2 and outlines
Does anybody know up to what points in outline 3 were part of midterm 1? To not waste time on revising them while I study for midterm 2. Thank you!
- Thu Feb 11, 2021 10:24 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: 4F.11
- Replies: 3
- Views: 208
Re: 4F.11
I don't think 4F 11 was part of the assigned hw problems, so don't worry about it! x)
- Thu Feb 11, 2021 10:21 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Equations
- Replies: 8
- Views: 386
Re: Equations
Jenny Chau 1I wrote:Will we ever use the integral equations like integral T1 to T2 dq/T and - integral V1 to V2 PdV?
I highly doubt it. Like everyone else said, he used it to just show us how we get the final equation and how everything relates.
- Thu Feb 11, 2021 10:19 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Sapling Week 5/6 #12
- Replies: 4
- Views: 309
Re: Sapling Week 5/6 #12
Hi! Here is a super useful chart for this concept. Screen Shot 2021-02-10 at 2.24.49 PM.png The bottom two rows explore the temperature-dependent scenarios for Gibbs free energy. In these scenarios, a temperature can be above or below (or at, if in equilibrium and delta G is 0) a certain point of m...
- Mon Feb 08, 2021 12:16 am
- Forum: Calculating Work of Expansion
- Topic: Extra practice problems/videos
- Replies: 13
- Views: 822
Re: Extra practice problems/videos
This is such a clutch post. I got so many resources to use. Thank you!
But to answer your question, check out the step up sessions. They really do help.
But to answer your question, check out the step up sessions. They really do help.
- Mon Feb 08, 2021 12:15 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Calorimeter Heat Capacity
- Replies: 4
- Views: 259
Re: Calorimeter Heat Capacity
Is the way you calculate the specific heat capacity of a calorimeter different from how you calculate specific heat capacity in general? Or does it always occurs with a calorimeter? I think it depends on the context you're given. If it asks for the specific heat capacity of a calorimeter than I thi...
- Mon Feb 08, 2021 12:10 am
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Change in internal energy
- Replies: 3
- Views: 231
Re: Change in internal energy
Can someone explain who change in internal energy is different from q? The internal energy, U, of a system can be changed by q, which is energy transferred as heat. Thus, when internal energy of a system is changed by transferring energy in the form of heat (and no other processes of expansion or c...
- Mon Feb 08, 2021 12:03 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Work on a system
- Replies: 27
- Views: 1337
Re: Work on a system
An example can be like the one Lavelle gave in his lecture of a piston compressing a gas, thus resulting into an increase of energy.
- Sat Feb 06, 2021 10:03 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 4C.13 Question
- Replies: 3
- Views: 300
Re: 4C.13 Question
Hi! For these calorimetry problems you should recognize which species is releasing heat and which is absorbing heat. Since ice is lower in temperature, this means that ice is absorbing the heat from the water. Since we assume no heat is lost to the surroundings, that means that the heat absorbed by...
- Thu Jan 28, 2021 7:06 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 4.31 Q (b)
- Replies: 1
- Views: 145
4.31 Q (b)
Can someone explain why the H2O from the product side is disregarded when solving for delta-H using the (sum of all products' standard enthalpies)-(the sum of all reactants standard enthalpies)? Thank you!
- Thu Jan 28, 2021 12:52 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: 4E.5, 4E.7
- Replies: 7
- Views: 648
Re: 4E.5, 4E.7
For 4.E.5, Looking at the lewis structure for C2H2 gives us 1 C-C triple bond, which has an enthalpy of 837, and also 2 C-H bonds which have a combined value of 824. Add these 2 numbers and multiply by the moles, which is 3, and you get the total enthalpy for C2H2, 4983. For benzene, the table of b...
- Wed Jan 27, 2021 11:32 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook problem 4D. 15
- Replies: 7
- Views: 438
Re: Textbook problem 4D. 15
Determine the reaction enthalpy for the hydrogenation of ethyne to ethane, C2H2(g)+2H2(g)→C2H6(g), from the following data: ΔHc°(C2H2, g)=−1300.kJ⋅mol−1, ΔHc°(C2H6, g)=−1560.kJ⋅mol−1, ΔHc°(H2,g)=−286kJ⋅mol−1. Hello, can someone explain how to approach this problem and why do we need to use O2 when ...
- Wed Jan 27, 2021 11:30 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Topic 4D Question 23
- Replies: 4
- Views: 189
Re: Topic 4D Question 23
Sorry this isn't an answer lol, but how come you get to see the explanation of the answer in the solutions manual? I only see the final answer we need to get.
- Wed Jan 27, 2021 1:27 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook problem 4D. 15
- Replies: 7
- Views: 438
Re: Textbook problem 4D. 15
Determine the reaction enthalpy for the hydrogenation of ethyne to ethane, C2H2(g)+2H2(g)→C2H6(g), from the following data: ΔHc°(C2H2, g)=−1300.kJ⋅mol−1, ΔHc°(C2H6, g)=−1560.kJ⋅mol−1, ΔHc°(H2,g)=−286kJ⋅mol−1. Hello, can someone explain how to approach this problem and why do we need to use O2 when ...
- Wed Jan 27, 2021 1:11 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook 4d.15
- Replies: 6
- Views: 256
Re: Textbook 4d.15
I'm not completely sure what balanced reactions are in the answer key, I only see -312 kJ.mol^-1 as the answer. But, to solve this problem I identified that I needed to make the delta H value for C2H6 negative because it accounted for the bonds formed. I kept the sign the same on H2 and C2H2 as the...
- Wed Jan 27, 2021 1:11 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Textbook 4d.15
- Replies: 6
- Views: 256
Re: Textbook 4d.15
I'm not completely sure what balanced reactions are in the answer key, I only see -312 kJ.mol^-1 as the answer. But, to solve this problem I identified that I needed to make the delta H value for C2H6 negative because it accounted for the bonds formed. I kept the sign the same on H2 and C2H2 as the...
- Tue Jan 26, 2021 11:12 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Question regarding 4D section/Midterm
- Replies: 4
- Views: 318
Question regarding 4D section/Midterm
This may seem like a dumb question lol, but since we haven't really covered all of thermochemistry and thermodynamics yet, should we just focus on the 4D HW problems that Lavelle sent in his email for the Midterm? Or is it possible to do all the chapter 4D questions with the readings he told us to f...
- Tue Jan 26, 2021 7:48 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Sapling #8
- Replies: 7
- Views: 601
Re: Sapling #8
Does anybody know if Lavelle has talked about a problem like this? Cuz I feel like he hasn't yet? Just asking to make sure I didn't miss it.
- Sat Jan 23, 2021 8:34 pm
- Forum: Phase Changes & Related Calculations
- Topic: Constant Temperature
- Replies: 20
- Views: 953
Re: Constant Temperature
The temperature remains constant during phase changes because the heat energy which is supplied to change the state is used in breaking the intermolecular forces and other attractive forces; so, it remains constant as all the heat is used up and no external heat is released or absorbed. To add to J...
- Sat Jan 23, 2021 8:11 pm
- Forum: Phase Changes & Related Calculations
- Topic: Explaining phase changes in the phase diagram and in reactions
- Replies: 7
- Views: 420
Re: Explaining phase changes in the phase diagram and in reactions
It's endothermic because heat is going into the system to break the intermolecular forces of the molecules present to change them into another state. For example, if water was being heated at 100 degrees, and the water needed to go to a vapor phase, the intermolecular phases of water have to be brok...
- Sat Jan 23, 2021 8:03 pm
- Forum: Phase Changes & Related Calculations
- Topic: State Property
- Replies: 71
- Views: 3755
Re: State Property
I don't think you have to worry so much on the proper definition. I think the main point to know is that for a state property, all you need to know is the initial state and the final state to calculate the difference. Also know that delta H is a state property, meaning that enthalpy only depends on ...
- Wed Jan 20, 2021 9:12 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 6D. #15 (b)
- Replies: 3
- Views: 203
Re: 6D. #15 (b)
Hi! I actually answered this for someone else, so I'll just copy and paste it here. So for this, I think it's good to know that Cl won't be included in this whole thing, as it doesn't affect the pH. Al3+ is the (weak) acid, here, as it attracts water molecules enough that said water's hydrogen atom...
- Wed Jan 20, 2021 2:32 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 6D. #15 (b)
- Replies: 3
- Views: 203
6D. #15 (b)
Can someone explain in the chemical formula for AlCl3 in water, if all three Cl molecules will dissociate from Al? or just one? Because if its all 3 wouldn't Cl cancel on both sides and we just have Al on the left side and Al(H20)6^3+ on the right, and when solving for x from the ICE table, wouldn't...
- Fri Jan 15, 2021 12:51 am
- Forum: Administrative Questions and Class Announcements
- Topic: Question on counting of Chem Community Posts
- Replies: 2
- Views: 209
Question on counting of Chem Community Posts
I had a quick question about when the chem community posts start getting counted again for the new week? For example, if I post a question this coming Sunday (of week 2), that post will be counted for Week 3 right? Because I do know that Saturday Midnight is the last day you can post something for i...
- Thu Jan 14, 2021 11:53 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 6A #23 [ENDORSED]
- Replies: 2
- Views: 368
Re: 6A #23 [ENDORSED]
I'm just going to walk through the steps I took to check your answer: First, convert 0.43 g Ba(OH)2 into moles by dividing by the molar mass of Ba(OH)2 (which is 171.344 g/mol). Then divide that value (0.0025mol) by 0.100 L to get 0.025 M as your Ba(OH)2 concentration. I'm not sure where you got 0....
- Thu Jan 14, 2021 11:32 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 6A #23 [ENDORSED]
- Replies: 2
- Views: 368
6A #23 [ENDORSED]
So for this problem I was able to get the initial molar concentration for Ba(OH)2 and I got 5.577x10^-3. To get that I first divided 0.43 grams by the molarity of Ba(OH)2, which I got as 171.327 (0.43g/171.327g.mol), and got 2.509*10^-3. Then I took that result and divided by 0.450L to get the initi...
- Sun Jan 10, 2021 5:53 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.i #15
- Replies: 2
- Views: 77
Re: 5.i #15
Actually, since NH3 and H2S are on the product side of the reaction, you would add 0.200 to x (0.200+x) for NH3 and H2S would correspond to +x. If NH3 and H2S were on the reactant side, then you would subtract x from 0.200 for NH3. Using the quadratic formula, you should get 0.0008 for x. Once you ...
- Sun Jan 10, 2021 1:30 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.i #15
- Replies: 2
- Views: 77
5.i #15
For this problem, I was wondering how NH3=0.2 and how H2S= 8.04x10^-4? doesn't NH3 start with 0.2 mol.L so we subtract 0.2 with our answer that we got from the quadratic formula, and that would equal 8.04x10^-4 for NH3, and since H2S isn't mentioned on how much it's initial molar concentration was, ...
- Sun Jan 10, 2021 12:03 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.i #13 (b)
- Replies: 1
- Views: 67
5.i #13 (b)
For part b, I already have an understanding of what I need to do, but I keep getting an error for the square root part in the quadratic formula. I was wondering if someone can explain or point out if the numbers I got are wrong (which Im pretty sure are wrong, but I've done the problem like 4 times ...
- Thu Jan 07, 2021 10:02 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.i #13
- Replies: 1
- Views: 124
5.i #13
"(a) In an experiment, 2.0 mmol Cl2(g) was sealed into a reaction vessel of volume 2.0 L and heated to 1000. K to study its dissociation into Cl atoms. Use the information in Table 5G.2 to calculate the equilibrium composition of the mixture." Can someone explain how to do this problem? I ...
- Thu Jan 07, 2021 8:45 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 5.i #11
- Replies: 4
- Views: 204
5.i #11
So for the answer for 5.i #11, the textbook states Q=6.9 I was wondering where that number came from because when I do the reaction quotient formula (P / R), the product is (SO3)^2 and the reactants are ([SO2]^2 * [O2]) and after plugging in their respected concentrations ([0.10]^2 / [1.20]^2 * [0.5...
- Thu Jan 07, 2021 5:34 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE tables
- Replies: 11
- Views: 594
Re: ICE tables
HannahRobinson3L wrote:You can also go watch the Audio Visual Focus Topics on Dr. Lavelle's website if you want to hear an explanation directly from the professor! I think it is the Chemical Equilibrium Part 2 where he goes over ICE charts.
I recommend doing what Hannah said. In the module, he goes over it super well!
- Thu Jan 07, 2021 5:31 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Temperature and Kc
- Replies: 4
- Views: 143
Re: Temperature and Kc
Dr. Lavelle mentioned in lecture that temperature affect equilibrium, but how does it factor into the equation for the equilibrium constant? In one of the module's, I remember him stating that later on in Chem 14B, we'll be using temperature that affects the Kc. I don't think it's something to worr...
- Tue Jan 05, 2021 6:18 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook Question 5H3)
- Replies: 4
- Views: 116
Re: Textbook Question 5H3)
Hi! I believe you have to start by looking at the K values given in the table. These values are for the individual reactions that make up this broad reaction. What you have to do is combine the two reactions to create the overall reaction. When you combine the reaction though you must multiply the ...
- Tue Jan 05, 2021 6:04 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook Question 5H1)
- Replies: 5
- Views: 423
Re: Textbook Question 5H1)
a) they switched the placements of the reactants/products so you would just take the inverse of K, so K in this problem would be 1/41 b) the given equation is the given equation in the problem but the coefficients are just divided by 2 so you would take the square root of 41 as your answer (~6.4). ...
- Fri Dec 11, 2020 1:03 pm
- Forum: Polyprotic Acids & Bases
- Topic: Textbook 6C.19
- Replies: 7
- Views: 542
Re: Textbook 6C.19
HCl is stronger because it has a longer bond than HF, due to trends in the periodic table. Lavelle also mentioned that the longer the A-H bond, the stronger the acid because a property of a strong acid is it gives off protons easily. So if a bond is long, the proton isn't easily held to the nucleus ...
- Fri Dec 11, 2020 1:01 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Bookwork 6B #3
- Replies: 6
- Views: 212
Re: Bookwork 6B #3
Also, how do you know V1=.200L ? and V2=.250L ?
Is it because we initially "think" we used .200 L at first?
Is it because we initially "think" we used .200 L at first?
- Fri Dec 11, 2020 12:45 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Bookwork 6B #3
- Replies: 6
- Views: 212
Re: Bookwork 6B #3
For the pH of the desired solution, you just use the concentration of HCl, which is desired to be 0.025M. 0.025 M of HCl is 0.025 M of H+ since HCl is a strong acid and completely dissociates into H+ and Cl-. pH= -log[H+], therefore, the pH of the desired solution is -log(0.025). For the second par...
- Fri Dec 11, 2020 12:23 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: 6B1
- Replies: 3
- Views: 189
Re: 6B1
Hi! Here's how I solved this problem: 1. the molarity of H+ ions is equal to the molarity of HCl because HCl is a strong acid so its ions will completely dissociate 2. pH of initial HCl solution = -log([HCl]) and pH of diluted HCl solution = -log(0.12 x [HCl]) 3. I divided the pH of the diluted HCl...
- Fri Dec 11, 2020 12:19 am
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Textbook 6B.1
- Replies: 8
- Views: 410
Re: Textbook 6B.1
Jordi M 2F wrote:Is that all the information the question gives?
Yes, it only gives that.
- Thu Dec 10, 2020 12:03 am
- Forum: Bronsted Acids & Bases
- Topic: Determining if an ion is basic or acidic
- Replies: 1
- Views: 151
Determining if an ion is basic or acidic
This may seem like a simple question but how do you determine an ion is acidic or basic?
Thank you!
Thank you!
- Tue Dec 01, 2020 7:50 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Focus Exercise 2.27
- Replies: 4
- Views: 301
Re: Focus Exercise 2.27
I had question about the radical part. So they are not radicals because they at least have paired electrons? So they're only radicals if the central atom has 1 unpaired electron?
- Tue Dec 01, 2020 6:58 pm
- Forum: Hybridization
- Topic: Textbook Q 2F #7
- Replies: 4
- Views: 349
Textbook Q 2F #7
The question states:
" Identify the hybrid orbitals used by the atom in boldface red type in each of the following species: b) AsF3"
the back of the book says the answer is sp^3. Can someone explain how they got the answer? Please! Thank you!
" Identify the hybrid orbitals used by the atom in boldface red type in each of the following species: b) AsF3"
the back of the book says the answer is sp^3. Can someone explain how they got the answer? Please! Thank you!
- Sat Nov 28, 2020 11:55 pm
- Forum: Hybridization
- Topic: dsp^3 vs sp^3d
- Replies: 2
- Views: 115
Re: dsp^3 vs sp^3d
I think Lavelle mentioned something about this in his lecture stating that some textbooks write it either way and that it's the same thing but that he prefers writing it the "sp^3d" way because it's the order of the energy states.
If I'm wrong someone correct me please.
If I'm wrong someone correct me please.
- Sat Nov 28, 2020 11:52 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Sapling HW #18
- Replies: 7
- Views: 444
Sapling HW #18
One of the questions on my sapling problem asked about the relative positions of the atoms in the lewis structure.
What do they mean by the positions of the atom in the lewis structure? and how do you figure it out?
the answer mentioned something about being in the same plane.
What do they mean by the positions of the atom in the lewis structure? and how do you figure it out?
the answer mentioned something about being in the same plane.
- Wed Nov 25, 2020 11:43 pm
- Forum: Hybridization
- Topic: Sapling Week 7 & 8 HW Question 11
- Replies: 14
- Views: 924
Re: Sapling Week 7 & 8 HW Question 11
Lavelle in his lecture from Monday (week 8) he gave a little key on how to find the hybridization of a molecule. He said that the # of regions of electron density around the central atom (or the least ionized element), equals the # of hybrid orbitals. So for example, if there are 2 regions of electr...
- Wed Nov 25, 2020 11:24 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: What does delocalized π bond mean?
- Replies: 18
- Views: 763
Re: What does delocalized π bond mean?
A lewis structure has delocalized Pi bonds when the lewis structure has resonance. Meaning there are delocalized electrons (aka shared electrons) throughout the whole molecule.
- Tue Nov 24, 2020 10:53 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Textbook 2E #17
- Replies: 3
- Views: 170
Textbook 2E #17
the question states: 2E.17 Predict the bond angles at the central atom of the following molecules and ions: (a) ozone, O3 I drew the Lewis structure for "a" and I thought it would have an angular shape due to the loan pairs on the Oxygen atom in the middle. So with the 4 regions of electro...
- Fri Nov 13, 2020 11:53 pm
- Forum: Electronegativity
- Topic: Textbook 2D problem #7
- Replies: 3
- Views: 138
Textbook 2D problem #7
the problem states: Compounds having bonds with a high covalent character tend to be less soluble in water than similar compounds that have low covalent character. Use electronegativities to predict which of the following compounds is the more soluble in water: (b) MgO or BaO. In the back of the boo...
- Thu Nov 12, 2020 10:54 pm
- Forum: Octet Exceptions
- Topic: Texbook Questions 2C1
- Replies: 6
- Views: 228
Re: Texbook Questions 2C1
I don't know exactly why they put A as an answer as well. But I was reading some posts on chem community how O is a special exception to the radical rule because it always has two lone pairs. To back it up, i found this in the reading of the book: "One of the most important examples is the oxy...
- Thu Nov 12, 2020 10:50 pm
- Forum: Octet Exceptions
- Topic: Texbook Questions 2C1
- Replies: 6
- Views: 228
Re: Texbook Questions 2C1
I don't know exactly why they put A as an answer as well. But I was reading some posts on chem community how O is a special exception to the radical rule because it always has two lone pairs. To back it up, i found this in the reading of the book: "One of the most important examples is the oxyg...
- Thu Nov 12, 2020 10:37 pm
- Forum: Octet Exceptions
- Topic: Elements that can have Expanded Octet
- Replies: 5
- Views: 519
Re: Elements that can have Expanded Octet
Only elements from the 3rd period and down can have an expanded octet. Because they all have "n" states bigger than 2, which means their "l" states can be s, p, d, or f orbitals, depending on the particular element you're focusing on and what their "n" state is.
- Wed Nov 11, 2020 9:36 pm
- Forum: Lewis Structures
- Topic: Textbook q 2B #15
- Replies: 2
- Views: 215
Textbook q 2B #15
The question states: Draw the Lewis structures that contribute to the resonance hybrid of nitryl chloride, ClNO2 (N is the central atom). I know how to draw the lewis structure. But i've been confused on why N is in the middle. I know ionization energy decreases down a group and increases across a p...
- Wed Nov 11, 2020 8:09 pm
- Forum: Lewis Structures
- Topic: homework 2B.3
- Replies: 5
- Views: 290
Re: homework 2B.3
Sinc Br is in the 4th period of the periodic table, it has the ability to have an expanded octet. This means n=4, so l=3 (because l is solved by n-1). So since l=3, Br has the s,p, d, and f orbitals. Meaning it has extra orbitals to gain extra electrons, apart of only 8 from the octet rule. just as ...
- Wed Nov 11, 2020 8:00 pm
- Forum: Lewis Structures
- Topic: Textbook HW #7
- Replies: 3
- Views: 120
Textbook HW #7
The following Lewis structure was drawn for a Period 3 element. Identify the element.
the back of the book says Phosphorus. How does it get to that answer? can someone explain how they solved it? please! Thank you!
the back of the book says Phosphorus. How does it get to that answer? can someone explain how they solved it? please! Thank you!
- Thu Nov 05, 2020 7:53 pm
- Forum: Ionic & Covalent Bonds
- Topic: textbook problem from 2A #17
- Replies: 2
- Views: 109
textbook problem from 2A #17
2A.17 Predict the number of valence electrons present for each of the following ions: a.) Mn^4+ I need help understanding why the answer is 3 valence electrons in the answer section. Because I saw a youtube video saying we count all the electrons of the highest "n" value in the electron co...
- Wed Nov 04, 2020 5:36 pm
- Forum: Lewis Structures
- Topic: Expanded Octet
- Replies: 6
- Views: 278
Re: Expanded Octet
He said in lecture today that the elements from the 3rd period and down have the expanded octet. But then again, he said we'll generally only be focusing on the first three periods of the periodic table for the class because they're more widely used. So I wouldn't really worry about further periods.
- Wed Nov 04, 2020 5:30 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Chem community posts
- Replies: 4
- Views: 180
Re: Chem community posts
I remember him sending an email or reading it somewhere that the points don't carry over for the next week. Each week your points reset, if that makes sense. So each week we have to get those 5 points.
Which, I'm trying to do right now x)
Which, I'm trying to do right now x)
- Wed Nov 04, 2020 5:24 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Lavelle's Office Hours (5-6 p.m.)
- Replies: 1
- Views: 88
Lavelle's Office Hours (5-6 p.m.)
Anybody attending Lavelle's office hours right now, from 5-6 p.m., and still waiting to be accepted into the meeting? or is he taking students one by one?
- Thu Oct 29, 2020 7:22 pm
- Forum: DeBroglie Equation
- Topic: Sapling HW #14
- Replies: 7
- Views: 436
Re: Sapling HW #14
Anh Trinh 1B wrote:Make sure to convert grams to kilograms before solving!
Yes thank you! I totally forgot about converting to kg x)
- Thu Oct 29, 2020 6:33 pm
- Forum: DeBroglie Equation
- Topic: Sapling HW #14
- Replies: 7
- Views: 436
Sapling HW #14
The question states: What would the speed of each particle be if it had the same wavelength as a photon of orange light ( "lambda" =625.0 nm)? proton (mass=1.673×10−24 g) speed: (blank) m/s neutron (mass=1.675×10−24 g) speed: (blank) m/s electron (mass=9.109×10−28 g) speed: (blank) m/s I k...
- Thu Oct 29, 2020 12:19 am
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Sapling HW #11
- Replies: 2
- Views: 127
Sapling HW #11
the question states: A violet line is observed at 434.0 nm in the spectrum of atomic hydrogen. Determine the values of "n" for the beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line. n2= ? n1=? I know n1 is 2 but I'm having tro...
- Thu Oct 29, 2020 12:06 am
- Forum: Photoelectric Effect
- Topic: Sapling HW #11
- Replies: 5
- Views: 199
Sapling HW #11
the question states: A violet line is observed at 434.0 nm in the spectrum of atomic hydrogen. Determine the values of "n" for the beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line. n2= ? n1=? I know n1 is 2 but I'm having tro...
- Wed Oct 28, 2020 10:53 pm
- Forum: Photoelectric Effect
- Topic: Rydberg Equation question
- Replies: 3
- Views: 317
Rydberg Equation question
Is the Rydberg Equation given in the textbook (equation 2: v = R {1/n1 - 1/n2} ) the same as the equation given to us in lecture: ( En = -hR/n^2 )? I know they don't look the same lol, but it's because in one of the Sapling homework problems I had to use the the first equation, given in the book, wh...
- Wed Oct 28, 2020 10:02 pm
- Forum: Einstein Equation
- Topic: Sapling HW #7
- Replies: 7
- Views: 580
Sapling HW #7
the problem states: "As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over the cause of the sparking, with one stating that the microwaves "herd" electrons into "pointy" areas of the metal object, from w...
- Mon Oct 26, 2020 10:44 pm
- Forum: Einstein Equation
- Topic: Sapling HW #4
- Replies: 2
- Views: 284
Sapling HW #4
I need help solving this problem:
A liquid is exposed to infrared radiation with a wavelength of 4.84×10−4 cm. Assume that all the radiation is absorbed and converted to heat. How many photons are required for the liquid to absorb 25.34 J of heat?
A liquid is exposed to infrared radiation with a wavelength of 4.84×10−4 cm. Assume that all the radiation is absorbed and converted to heat. How many photons are required for the liquid to absorb 25.34 J of heat?
- Thu Oct 22, 2020 12:06 am
- Forum: Einstein Equation
- Topic: Textbook Question 1B.7
- Replies: 4
- Views: 349
Re: Textbook Question 1B.7
Assuming that you have already calculated the answer to part a), you would already know that the energy an excited sodium emits is around E= 3.37 x 10^-19 J Now, the next step is that we covert the 5mg of sodium atoms first to moles of sodium atoms and then from moles to total number of atoms by us...
- Sat Oct 17, 2020 11:59 pm
- Forum: Student Social/Study Group
- Topic: How are you studying?
- Replies: 204
- Views: 30036
Re: How are you studying?
I quickly skim my notes after every lecture. Then, every other day that we dont have lecture, I review my notes again and if I have time I just quickly skim the pre-recorded lecture to review the most important concepts. Then on weekends I just review all of my notes of that week. It helps retain th...
- Fri Oct 16, 2020 1:56 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: E=h*V explanation in atomic spectra
- Replies: 3
- Views: 251
E=h*V explanation in atomic spectra
Why does professor Lavelle compare E (energy of photon) to (delta)E ? I'm having a hard time understanding why. Can someone give their explanation why? Please !!
- Mon Oct 12, 2020 2:20 pm
- Forum: Properties of Light
- Topic: Clarification on intensity and amplitude [ENDORSED]
- Replies: 6
- Views: 214
Re: Clarification on c = (lambda) * V [ENDORSED]
Hi! So yes you are correct that the amplitude of the wave is the intensity of the wave, but increasing amplitude doesn't effect the frequency. As seen in the equation you were talking about C= wavelength*frequency, wavelength and frequency effect each other but not the amplitude. Also, if you graph...
- Mon Oct 12, 2020 2:11 pm
- Forum: Properties of Light
- Topic: Clarification on intensity and amplitude [ENDORSED]
- Replies: 6
- Views: 214
Clarification on intensity and amplitude [ENDORSED]
Is it safe to say amplitude can be characterized as intensity of the wave?
if so, would it also be safe to say increasing amplitude (aka intensity) increases frequency?
if I'm wrong in any of this or mixed up any definitions please feel free to correct me! I'm trying to understand this x).
if so, would it also be safe to say increasing amplitude (aka intensity) increases frequency?
if I'm wrong in any of this or mixed up any definitions please feel free to correct me! I'm trying to understand this x).
- Sun Oct 11, 2020 12:47 am
- Forum: Molarity, Solutions, Dilutions
- Topic: sapling hw #7
- Replies: 17
- Views: 800
Re: sapling hw #7
After reading some of the replies, I'm afraid I have a silly question. People are saying to "multiply 0.325 with 590.1g" but my question is what they did to get 0.325 and why. Thank you! Don't be afraid! Because I too was wondering the same thing. Thank you for asking before I did! We're ...
- Sat Oct 10, 2020 6:34 pm
- Forum: Molarity, Solutions, Dilutions
- Topic: Self Test G.3
- Replies: 1
- Views: 69
Self Test G.3
I know this wasn't part of the assigned problems on the syllabus but I just wanted to know how this problem is figured out [Part of Fundamentals G]: What volume of 1.25 x 10^-3 M C6H1206 contains 1.44 um (micromol) of glucose molecules? the answer was given: [Answer: 1.15mL] I know we have to use th...
- Wed Oct 07, 2020 11:02 pm
- Forum: SI Units, Unit Conversions
- Topic: SI Units
- Replies: 13
- Views: 372
Re: SI Units
I'm pretty sure it's always going to have the units you need to use in the question.
- Tue Oct 06, 2020 12:04 am
- Forum: Balancing Chemical Reactions
- Topic: Stoichemetric Coeffiecients
- Replies: 12
- Views: 533
Re: Stoichemetric Coeffiecients
With stoichiometric coefficients you're always supposed to have the lowest whole number. So if you find that one of your coefficients is like 3.5 or 8.5, etc, you would multiply both sides of the reaction (reactants and products) by 2. That will give you the lowest whole number coefficients and kee...