CHEMISTRY COMMUNITY

Jose Miguel Conste 3H

So from solving multiple problems, the fault I can see is it is either one answer of x will be negative or one answer will be too large which will result in the concentration total to be negative therefore it would have to be the other.

Jose Miguel Conste 3H

Yes left side will always be reactants and right side will always be products, even if the reaction goes both ways, it is important to know this as this will be the Kc with those molecules as reactants and products. If flipped Kc would be the inverse or 1/Kc.

Jose Miguel Conste 3H

so basically you're trying to find what the new equilibrium concentration would be if you added 1.0 M of NO2. So with the Kc you found from the original, you would then use icebox to solve what the new concentrations would be with 1.0 M added to NO2. Aka the initial would be 3.28 for NO2 and .463 fo...

Jose Miguel Conste 3H

I would usually use ICE box to make sure all the steps I made were correct, it really is the most correct way to solve things even if there's something easier. I would use it to check your answer sometimes if you're unsure.

Jose Miguel Conste 3H

so basically what you would do to solve this is using the ICE box, your initial would now be 2.94 for NO2 and 0.335 for N2O4, then you would solve it like the usual ICE box problem you do using the equilibrium constant you found for the first problem. Afterward, you would use the smallest x you solv...

Jose Miguel Conste 3H

I believe you should always convert to moles, just so you can get the whole picture for the problem and just incase you do need it.

Jose Miguel Conste 3H

You can only find the odd-numbered answers in the back of the book

Jose Miguel Conste 3H

I believe it is with respect to the problem and what units they give, sometimes it can give mmHg or atm or torr, but take it with a grain of salt, you should ask a TA this question

Jose Miguel Conste 3H

always has to be in kelvin

Jose Miguel Conste 3H

because its moles over volume, that is the measurement for molarity, therefore n/V is molarity

Jose Miguel Conste 3H

I wouldn't necessarily base the shape off its hybridization, as hybridization only gives the electron density connections, I would mostly base it off the AXE format, as it allows you to know how many electrons and actual elements its connected to

Jose Miguel Conste 3H

They're the same, just allows you to draw the lewis dot structure easier

Jose Miguel Conste 3H

Because it's bonded with a K+, the necessary Cu charge for it to be a non charged compound is Cu(I)

Jose Miguel Conste 3H

there's a charge in the compound therefore it is cobaltate

Jose Miguel Conste 3H

I believe the lewis theory was based off the bronsted

Jose Miguel Conste 3H

I basically went over my notes over a span of two weeks, went from week 1 to week 10 and did problems here and there, what also helped were the review sessions going over specific topics

Jose Miguel Conste 3H

I recommend going to office hours and going over the past midterms with TA, then doing more textbook problems from the last three weeks

Jose Miguel Conste 3H

it's just a coincidence, not necessarily specific, just know that double is shorter than single and triple is shorter than double

Jose Miguel Conste 3H

Cl- is bigger because of the extra electron, that extra electron allows for more push from protons making the atomic radius larger

Jose Miguel Conste 3H

it means if you get a 50% in the class, you will receive a C-, anything below will be a fail

Jose Miguel Conste 3H

the final was cummulative, it included everything from week 1 to 10 unfortunately

Jose Miguel Conste 3H

there was no curve administered, it was just 10 points added

Jose Miguel Conste 3H

Co is bonded with 1 SO4 and 5 NH3 compounds, therefore the coordination compound is 6, remember that the number of bonds to the central metal ion determines its coordination number, only counts inside brackets also

Jose Miguel Conste 3H

unfortunately you kind of have to memorize the common oxidation numbers in order to find oxidation numbers of others, some I can grab at the top of my head it nitrite (no2-), nitrate (no3-), group elements from group 17 will always be -1, group elements from element 1 will always be +1, and group el...

Jose Miguel Conste 3H

it goes by alphabetical order, and literally by alphabetical order of the ions, so other examples were Co(NH3)3CL3, therefore since ammine is A and chlorine is C, it is first ammine triamminetrichlorocobalt(III)

Jose Miguel Conste 3H

it is short for ethylenediamine

Jose Miguel Conste 3H

naming is based on the literal name of the compounds so because ammine is A and Chloride is C, ammine comes first, then chloride

Jose Miguel Conste 3H

remember that the chlorine is inside the bracket so it is included in the name, it will be triamminetrichlorocobalt(III)

Jose Miguel Conste 3H

Hi, so you have to read the question thoroughly as it asks specifically what is the hybridization of Phosphorus , which then allows you to see then how many bonds and how many lone pairs are connected to the phosphorus, allowing you to then find the hybridization, dont let the picture intimidate you...

Jose Miguel Conste 3H

If they can form a resonance structure, they can form delocalized pi bonds

Jose Miguel Conste 3H

I think you should know the shapes of the molecules which will allow you to figure out the angles

Jose Miguel Conste 3H

Hi, yes please take a look at table 2F.1 in the book, and it'll help you figure out the hybridization, based off the name of the shape as well as the orbitals

Jose Miguel Conste 3H

Because there is a total of 4 bonds for C, and 2 bonds with O and 2 lone pairs on O, the hybridization is found out to be SP3

Jose Miguel Conste 3H

I've stated this earlier, memorize all the strong acids using flashcards, and memorize that all strong bases are OH- molecules .

Jose Miguel Conste 3H

It is recommended to memorize all the strong acids, as if you have seen all strong bases are basically OH- chemicals, it'll shorten the time for you when doing the math.

Jose Miguel Conste 3H

No not at all, one is based on a chemical reaction while the other is based on an intermolecular force, do not get both mixed.

Jose Miguel Conste 3H

From what I remember in High school chem, if this isn't correct please feel free to correct me, the Lewis acid-base was a furthermore specific explanation based on the Bronsted-Lowry explanation on acids and bases, that is why bronsted rules apply to lewis acid/bases but not vice versa.

Jose Miguel Conste 3H

The table can be found in the textbook, cheers

Jose Miguel Conste 3H

Its because NF3 has a lone pair that contributes to its shape, unlike BF3 where B does not have a lone pair that contributes, therefore making it trigonal planar

Jose Miguel Conste 3H

H is not bonded to anything highly electronegative aka N, O, or F.

Jose Miguel Conste 3H

because p is farther away from the nucleus (therefore farther away from protons), you need more energy to keep the electrons from leaving the atom, that's how I think of it

Jose Miguel Conste 3H

think of orbitals as an electron cloud where you can spot an electron at a specific place at a specific time, not really much to it

Jose Miguel Conste 3H

When 1 mole of atoms is being asked, then you multiply by Avogadro's number, but since only 1 atom is being asked you did not need to multiply

Jose Miguel Conste 3H

v= h/(m*lambda)

Jose Miguel Conste 3H

both find similar answers, it just depends on what is given

Jose Miguel Conste 3H

It has to be hydrogen paired with (of course itself), or F, O, or N

Jose Miguel Conste 3H

Double bonds are shorter because there are two bonds pulling on two particles rather than just one, making the bond (combined) stronger than a single

Jose Miguel Conste 3H

when the wavelength is continuous from when you add the picture again to both sides, it is compatible, but if the wavelength is not continuous when you add the photo of the wave from either side, then it is not compatible

Jose Miguel Conste 3H

First find the frequency using the c=lambda times frequency equation, then find the energy when the frequency is found using the E=hv equation, then with the number of grams of ice, multiply it times the enthalpy of fusion; then with the energy found divide the answer multiplied with grams of ice an...

Jose Miguel Conste 3H

from wavelength find the frequency, then once frequency is found, find energy, using E=hv, then multiply grams of ice by the enthalpy of fusion (per gram), then divide that by the energy you got from E=hv and you should get the answer

Jose Miguel Conste 3H

divide the mass of flourine by Avagadro's constant then multiply times 2 because it is diatomic and the rest should be smooth sailing

Jose Miguel Conste 3H

it depends on the problem given, it can act as a base and an acid

Jose Miguel Conste 3H

I would write down what is given and what the question is asking you to find, then I would go on the equation handout and find the equation to use to solve the problem, I would say that is the easiest way.

Jose Miguel Conste 3H

To be honest, I believe everything you need to know about the midterm are the questions that is given on the syllabus, I would work through all those questions in order to understand the topic as a whole.

Jose Miguel Conste 3H

All equations needed I believe are in a handout that will be given before midterm and such, no equations will be needed to be memorized I believe.

Jose Miguel Conste 3H

writing it does not matter, but usually as I know, it is preferred to use 10^x instead to reduce any confusions and such, though I do know phone calculators use e

Jose Miguel Conste 3H

the 10^x does not count, the first part does as 10^x basically means the number of 0s that come afterward

Jose Miguel Conste 3H

How I keep on track is basically I write the amount of moles of the certain element on top of it, for example CO2 I put 1 on top of C and 2 on top of O, after labeling all the elements, I check both sides if both sides of the equation have the same amount moles of elements. Then if there are any cha...

Jose Miguel Conste 3H

I would start off first with the amount of grams you would get from the combustion formula for both Carbon and Hydrogen. First use the grams of CO2 and work backwords towards C to find the grams of C. Then use the grams of H2O and work backwords to find the grams of H. To get grams of O, take the to...

Jose Miguel Conste 3H

First you would like to find out how many moles the total grams have, then conver that to Liters using the molarity given, afterwards then convert Liters to militers and you should be able to get the answer.

Jose Miguel Conste 3H

Hi, most likely your molar mass is wrong as the molar mass is 125.55 g

Jose Miguel Conste 3H

Hi there! For number seven you approach it basically as (if 36% is given by mass) 36 g of CaCl2 /100 g of solution!

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