## Search found 38 matches

- Thu Feb 18, 2021 5:30 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: textbook 4D.9
- Replies:
**4** - Views:
**28**

### Re: textbook 4D.9

Using the link that the question provided, you need to calculate the Enthalpies of formation for each product and then add all of these values up. Example: If the enthalpy of formation for H2O is -241.82 then remember to multiply it by 10 for this particular reaction. The sum of enthalpies for the ...

- Wed Feb 17, 2021 3:02 pm
- Forum: Calculating Work of Expansion
- Topic: Textbook 4B.5
- Replies:
**3** - Views:
**28**

### Re: Textbook 4B.5

Because we were given the pressure in torr, we need to multiply by 1atm/760torr. We can then use this value to calculate work which would be the change in volume multiplied by the pressure in atm. The units come out to be L.atm. The units for work must be in joules, so you must multiply by (8.314mJ...

- Wed Feb 17, 2021 1:32 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Textbook 4C.13, 4C.11
- Replies:
**1** - Views:
**17**

### Textbook 4C.13, 4C.11

4C.13 An ice cube of mass 50.0 g at 0.0°C is added to a glass containing 400.0 g of water at 45.0°C. What is the final temperature of the system (see Tables 4A.2 and 4C.1)? Assume that no heat is lost to the surroundings. For this question, I know the heat lost by the ice cube = - heat gained by wat...

- Wed Feb 17, 2021 11:23 am
- Forum: Calculating Work of Expansion
- Topic: Textbook 4B.5
- Replies:
**3** - Views:
**28**

### Textbook 4B.5

4B.5 An ideal gas in a cylinder was placed in a heater and gained 5.50 kJ of energy as heat. If the cylinder increased in volume from 345 mL to 1846 mL against an atmospheric pressure of 750. Torr during this process, what is the change in internal energy of the gas in the cylinder? For this questio...

- Wed Feb 17, 2021 11:17 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Textbook 4A.13
- Replies:
**2** - Views:
**26**

### Re: Textbook 4A.13

Yes that makes sense, thank you!

- Wed Feb 17, 2021 7:30 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Textbook 4A.13
- Replies:
**2** - Views:
**26**

### Textbook 4A.13

A constant-volume calorimeter was calibrated by carrying out a reaction known to release 3.50 kJ of heat in 0.200 L of solution in the calorimeter (q=−3.50kJ), resulting in a temperature rise of 7.32°C. In a subsequent experiment, 100.0 mL of 0.200 M HBr(aq) and 100.0 mL of 0.200M KOH(aq)were mixed ...

- Sun Feb 14, 2021 9:07 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Sapling Week 5/6 HW 18
- Replies:
**11** - Views:
**72**

### Re: Sapling Week 5/6 HW 18

Hi. Thanks for all the help. How do I correctly put the scientific notation into Sapling? I keep getting a message that says "we could not recognise your answer, make sure it's in valid form." You should get a prompt when you click into the answer box that gives you the option to input &q...

- Sun Feb 14, 2021 8:51 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Sapling #19
- Replies:
**4** - Views:
**48**

### Re: Sapling #19

I solved it this way:

Q = (PCH4)2/(PC2H4)(PH2)

∆G = ∆Gº + RT ln Q

Q = (0.600)2/(0.500)(0.350) = 2.057

You can then plug this into ΔG = ΔG∘ + RTlnQ!

Q = (PCH4)2/(PC2H4)(PH2)

∆G = ∆Gº + RT ln Q

Q = (0.600)2/(0.500)(0.350) = 2.057

You can then plug this into ΔG = ΔG∘ + RTlnQ!

- Sun Feb 14, 2021 7:52 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Sapling Question #16
- Replies:
**8** - Views:
**41**

### Re: Sapling Question #16

Since we know

ΔG°rxn = Σ G°f (products) - Σ ΔG°f (reactants), you can disregard temperature to solve for ΔG°rxn:

ΔG°rxn = [ 2(-65.3 kJ/mol) + 0] - [ 1(+209 kJ/mol + 4(0) ]

= -130.6 – 209

= -339.6

ΔG°rxn = Σ G°f (products) - Σ ΔG°f (reactants), you can disregard temperature to solve for ΔG°rxn:

ΔG°rxn = [ 2(-65.3 kJ/mol) + 0] - [ 1(+209 kJ/mol + 4(0) ]

= -130.6 – 209

= -339.6

- Sun Feb 14, 2021 7:48 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Sapling W5-6 Q15
- Replies:
**6** - Views:
**21**

### Sapling W5-6 Q15

Given the information A+BC⟶2D⟶DΔH∘ΔH∘=−720.7 kJΔS∘=287.0 J/K=546.0 kJΔS∘=−185.0 J/K calculate ΔG∘ at 298 K for the reaction A+B⟶2C For this question, I calculated the overall ΔHº to be -1812kJ and the overall ΔSº to be -0.083kJ, and I subbed this into the equation ΔGº=ΔHº-TΔSº to get -1787kJ, but th...

- Sun Feb 14, 2021 5:57 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Sapling number 8
- Replies:
**7** - Views:
**82**

### Re: Sapling number 8

Hi! So the way I like to think about it is that this reaction has 4 steps. Step 1 is heating the reactants to 100 degrees Celsius,. So first, we have to convert our celsius to Kelvin by using the conversion 298.15K + degrees celsius given. Next, we assume 1.00 mol, and use the equation ∆S = n*Cp*ln...

- Sun Feb 07, 2021 4:17 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Sapling #19 - Week 3/4
- Replies:
**3** - Views:
**30**

### Re: Sapling #19 - Week 3/4

Heat capacity is the amount of energy required to raise the temperature of an object by one degree, in this case the object is the calorimeter. So overall this question asks about the heat capacity of the calorimeter itself instead of the specific/molar heat capacity of certain substances in the rea...

- Sun Feb 07, 2021 4:04 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Sapling 20
- Replies:
**10** - Views:
**48**

### Re: Sapling 20

In general, when would we use the molar heat capacity at constant volume (3/2 R) value given for atoms in the table? Would it be when the gases are monatomic?

- Sun Feb 07, 2021 3:20 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Sapling Week 5 Number 18
- Replies:
**5** - Views:
**55**

### Re: Sapling Week 5 Number 18

After finding q, how do we find ∆u? I know we use the equation ∆u= q+w but I'm not sure how to find work done with the variables given?

- Sun Feb 07, 2021 7:16 am
- Forum: Calculating Work of Expansion
- Topic: Sapling #15n W3+4
- Replies:
**10** - Views:
**51**

### Re: Sapling #15n W3+4

Hello, Regarding sapling 15, I keep getting -1.08, but it is wrong. I used the PV=nRT and w=-Pdelta T equation but am still getting the wrong answer. Any help would be appreciated. Thank you! I also used the w= -∆nRT equation and it worked for me, the way you would solve it using the values given i...

- Sun Feb 07, 2021 6:47 am
- Forum: Calculating Work of Expansion
- Topic: Sapling #14 for Wk 3 and 4
- Replies:
**12** - Views:
**65**

### Re: Sapling #14 for Wk 3 and 4

The first path is a reversible expansion so you would use w = -nRTln(V2/V1). However you first need to find moles so you would use the ideal gas law to find it (n = PV/RT). Then once you solved for moles you input it in -nRTln(V2/V1). For Path B because it is at a constant pressure, irreversible re...

- Sun Jan 31, 2021 11:39 pm
- Forum: Ideal Gases
- Topic: Sampling hw #4
- Replies:
**16** - Views:
**176**

### Re: Sampling hw #4

i just redid this problem after the comments here said to use the inverse Kp, but that kept giving me the wrong answer even though ever other part of my problem was set up similarly to everyone's in the comments. i only got the correct answer once i used 391 instead of 1/391, can anyone explain why...

- Sun Jan 31, 2021 11:29 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Telling Apart Weak Bases vs Weak Acids by their Formula
- Replies:
**10** - Views:
**32**

### Re: Telling Apart Weak Bases vs Weak Acids by their Formula

There's a link Dr. Lavelle shared previously with a table of the strong acids and bases to know:

https://sites.google.com/site/chempendi ... cids-bases

I think for the purposes of this course and as stated on the table, you can assume any other acids/bases not on the table are weak!

https://sites.google.com/site/chempendi ... cids-bases

I think for the purposes of this course and as stated on the table, you can assume any other acids/bases not on the table are weak!

- Sun Jan 31, 2021 11:24 pm
- Forum: Ideal Gases
- Topic: How can we identify when to use the ideal gas law?
- Replies:
**11** - Views:
**39**

### Re: How can we identify when to use the ideal gas law?

Just to add on to the other answers, sometimes you won't directly get given all the variables e.g. you may be given mass instead of mols, but as long as there is sufficient information provided you should be able to calculate the necessary values to complete the expression (in this case you would di...

- Sun Jan 31, 2021 11:20 pm
- Forum: Ideal Gases
- Topic: Gas Constant Value
- Replies:
**42** - Views:
**129**

### Re: Gas Constant Value

Does anyone know if Lavelle is also strict on significant figures? I just want to make sure that I do not loose easy points on the midterm, so if anyone who has taken him previously could say, I would appreciate it! Also, the midterms are multiple choice so usually you should be able to select the ...

- Sun Jan 31, 2021 11:15 pm
- Forum: Phase Changes & Related Calculations
- Topic: What really is "heat"
- Replies:
**6** - Views:
**27**

### Re: What really is "heat"

Just as an add-on to that, there are 4 different methods of heat transfer that we commonly see - Conduction: transfer of heat through a solid (any heat inside an object is transferred to its surface), Convection: transfer of heat from a surface by a fluid (such as air creating 'convection currents' ...

- Thu Jan 28, 2021 6:18 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Textbook 5I.13 [ENDORSED]
- Replies:
**2** - Views:
**38**

### Textbook 5I.13 [ENDORSED]

For question 5I.13, part c, I'm not sure how to tell Cl2 is more thermodynamically stable than Fl2 based on the size of Kc - I just thought a larger Kc value means products are favored than reactants, but I'm not sure how it relates to this problem? Screen Shot 2021-01-28 at 10.16.09 PM.png Screen S...

- Sun Jan 24, 2021 11:59 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Qudratic Formula
- Replies:
**19** - Views:
**106**

### Re: Qudratic Formula

I would be mindful of negative signs in particular when plugging in values into the quadratic formula, because sometimes if your value is already negative it can be easy to forget there is another negative sign in front of it that will cancel it out. When you say error do you mean two negative roots...

- Sun Jan 24, 2021 11:54 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Weak acids/ Weak Bases
- Replies:
**3** - Views:
**36**

### Re: Weak acids/ Weak Bases

Just to add on, for groups 1 and 2 metal hydroxides, the metal hydroxide will fully dissociate into ions as soon as the solid dissolves, but the group 2 hydroxides are only slightly water–soluble, so group 1 hydroxides are strong bases, but calcium hydroxide or magnesium hydroxide is rarely referred...

- Sun Jan 24, 2021 11:49 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: sapling 2 week 2
- Replies:
**7** - Views:
**61**

### Re: sapling 2 week 2

Since Ka=[H+]{A-]/[HA], you can plug in the values given so 0.00459=x^2/0.14-x , after you multiply it out you get x^2+0.00459x-6.426*10^-4, by plugging it into the quadratic equation you get roots x=0.02315823211... or x= -0.02774823211... so you eliminate the negative x value, and use the remainin...

- Sun Jan 24, 2021 11:32 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Sapling Question 5
- Replies:
**7** - Views:
**37**

### Re: Sapling Question 5

You can use the pH to calculate [OH-] (which is equal to [BH+]), by first finding pOH through 14-pH and then doing 10^-pOH, so in this case it would be 10^-4.751. Then you can sub this into the Kb expression: 7.055*10-5=[10^-4.751]^2/(x-10^-4.751) and solve for x, after which you can sub in 10^-4.75...

- Sun Jan 24, 2021 11:24 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Week 2 Sapling Hw #2
- Replies:
**8** - Views:
**89**

### Re: Week 2 Sapling Hw #2

Since Ka=[H+]{A-]/[HA], you can plug in the values given so 0.00214=x^2/0.121-x , then you can solve for x using the quadratic equation and once you've solved for x, you can then divide it by the original concentration 0.121M and multiply it by 100 to get the percent ionization

- Sun Jan 17, 2021 10:06 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Sapling HW
- Replies:
**7** - Views:
**63**

### Re: Sapling HW

I have the same issue with CCLE saying I got 80% on the assignment when I got 100% on Sapling. I'm just worried because I don't know which questions it has counted as 'incorrect' as Sapling isn't giving me any indication - I was wondering if you were able to resolve this issue, and if you know why i...

- Sun Jan 17, 2021 9:58 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling Week 1 #6
- Replies:
**10** - Views:
**57**

### Re: Sapling Week 1 #6

You would calculate Q by just subbing in the values they gave for each of the compounds to the expression, similar to how you would calculate Kc so in this case [3.42]^2/[5.52]^3[1.14], and then compare it to the Kc value for the next part of the question

- Sun Jan 17, 2021 9:44 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE table troubles
- Replies:
**16** - Views:
**78**

### Re: ICE table troubles

I also sometimes get confused about which side of the equation to -x and +x if the reaction is reversible, is there any way to determine it from the way the question is phrased?

- Sun Jan 17, 2021 9:42 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sampling Week 1 #2
- Replies:
**12** - Views:
**122**

### Re: Sampling Week 1 #2

I would first start with making an ICE chart and solving for the initial molarity of 2SO3 by dividing the given moles by the given volume. Then you can start filling out your ice chart. The question gives you the final moles and by dividing that by the 3 L, you get the change in molarity/x. With th...

- Sun Jan 17, 2021 9:35 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #10, WK 1
- Replies:
**8** - Views:
**67**

### Re: Sapling #10, WK 1

I'm also confused about the last part of this question, and I'm especially having a lot of trouble solving for x using the quadratic equation. My numbers are a bit different, so at equilibrium [N2O4] = 0.32 + x, and [NO2] = 2.89 - 2x. My K value is 11.16. So what I have so far: K = [2.89-2x]^2/0.32...

- Sun Jan 17, 2021 9:26 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Sapling #10, WK 1
- Replies:
**8** - Views:
**67**

### Re: Sapling #10, WK 1

Hey! I actually had a similar question to you, for me my x values were 0.235 and 5.78, I subbed in x=0.235 and got the right answer but I'm not sure how to know which value to eliminate. I guessed x=0.235 because it's a smaller value, but if anyone knows how in general to determine the right value I...

- Sun Jan 10, 2021 8:26 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: K vs P
- Replies:
**6** - Views:
**51**

### Re: K vs P

Also, can someone explain how the relationship Q>P means products are favored (I understand it's because the numerator is higher) but I am confused on how this tells us the direction of the reaction and what it really means regarding the stability of the reaction. If someone could explain the corre...

- Sun Jan 10, 2021 8:15 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Solids and Liquids in Equilibrium
- Replies:
**4** - Views:
**16**

### Re: Solids and Liquids in Equilibrium

The way I understand it, pure solids/liquids are not included in the equilibrium expression because their concentrations remain the same through the reaction - this is calculated by their density/molar mass. For a pure solid, it has no concentration because it isn't dissolved in any solvent, so incr...

- Sun Jan 10, 2021 8:05 pm
- Forum: General Science Questions
- Topic: midterm/final
- Replies:
**12** - Views:
**62**

### Re: midterm/final

Sorry if this has already been addressed somewhere, but are the midterms/finals only during lecture times, or can they be taken at alternate times if you are in a different timezone? I took 14A over summer so I'm not sure how it works. Thank you!

- Sun Jan 10, 2021 7:52 pm
- Forum: Administrative Questions and Class Announcements
- Topic: How to find my posts
- Replies:
**97** - Views:
**49789**

### Re: How to find my posts

Massimo_Capozza_1G wrote:Does anyone else have a problem when logging into Chemistry Community where you have to re-register each time you sign-in?

I haven't had that issue so far, maybe you could click the "Remember me" option when you log in?

- Sun Jan 10, 2021 7:47 pm
- Forum: General Science Questions
- Topic: step up sessions
- Replies:
**16** - Views:
**178**

### Re: step up sessions

Are any of the step up sessions recorded?