CHEMISTRY COMMUNITY

John Antowan 1K

Thank you for the incredible collaborative and entertaining class that 14B was! I wish you all the best Dr. Lavelle!

John Antowan 1K

The relationship between E and E naught is the same as the other variables such as G and G naught; E naught is simply E of the reaction at ideal conditions.

John Antowan 1K

The order of the reactant tells us how the reactant affects the reaction rate. This is significant because we can understand if a reactant is contributing to the speed of the reaction or if it is not.

John Antowan 1K

I know that the activation energy of the forward reaction will decrease, but as for the reverse reaction I believe it is the same. I am not 100% sure about this, but I believe that the catalyst will not effect the reverse reaction activation energy unless it is built to do so (as most catalysts work...

John Antowan 1K

Most of the derivations are included on the constants sheet! I think its just a matter of knowing where you can substitute the values. Otherwise I am not aware of any such documents.

John Antowan 1K

I have also seen inconsistencies, I am going to guess that it is not too important but there was one question on the week 8 sapling that was a little picky so I am also not sure.

John Antowan 1K

Hi! I wanted to know if we already have 50 points for Chemistry Community if we still need to post on Chem Community for points. Thank you!

John Antowan 1K

So far I have been pretty active with USAC! I am in the office of the IVP but I am also doing a fellowship with the EVP.

John Antowan 1K

I just finished the Mandalorian recently and it was AMAZING! 10/10 recommend.

John Antowan 1K

Hey Irene! Entropy usually relies on enthalpy for getting a sure value of Gibbs free energy, but we can be sure that if the total entropy of a reaction (entropy of the universe) is greater than 0, then Gibbs free energy is likely negative as both indicate a spontaneous reaction is occurring. To answ...

John Antowan 1K

idella 1D wrote:
John Antowan 1K wrote:Hi! I don't have that class but I know someone who might be willing to switch. Let me know if you still need the spot!

Heyo thanks for replying! I think I might have found someone willing to switch already, but thank you!!

Of course! Let me know if it doesn't work out. :)

John Antowan 1K

Yes, all exergonic reactions are spontaneous.

John Antowan 1K

The potential difference of a circuit is defined as the amount of energy that can be transferred between two electrodes, so I believe that the positive value is just a measurement of that energy potential.

John Antowan 1K

I am pretty sure that it allows the ions to flow across from one cell to the other, but I am still a little fuzzy on this topic myself. Would love another explanation!

John Antowan 1K

I am pretty sure we would use it in a question where we were basically given all of the other variables excluding either K2 or the enthalpy of the reaction value.

John Antowan 1K

Hi! I don't have that class but I know someone who might be willing to switch. Let me know if you still need the spot!

John Antowan 1K

I believe that the post is still valid for receiving credit, but the moderators have limited who can make comments on the post or have limited access altogether.

John Antowan 1K

I believe that the C is the specific heat capacity. I believe the main difference between specific heat and the values for Cp is the units, but I am not completely sure.

John Antowan 1K

Isochoric is a reaction at a constant volume. I have done a little bit of research and apparently isometric is the same as isochoric? I am not 100% sure about that though.

John Antowan 1K

Adiabatic indicates that no heat leaves the system or enters it, and thus the only change in internal energy can be found in the value for work.

John Antowan 1K

I totally feel that. The amount of stress eating I have done today is ungodly. I will say you will do great just make sure to do all the textbook problems! That's what I am hoping will help me the most!

John Antowan 1K

I am taking BL this upcoming quarter because I think it makes more sense as far as how I am approaching the chem series as well as how much of the information I may need to complete the class will stay in my mind.

John Antowan 1K

Hi! Which question were you having confusion about?

John Antowan 1K

I literally watched the Queen's Gambit in ONE SITTING. SO GOOD!

John Antowan 1K

You are completely off track. I'm kidding. You only forgot to add one step, multiplying the enthalpy of fusion by the amount of ice that you have. Make sure to convert the grams of ice to moles (49.4/18.02) which should give you 2.72 moles of ice. So your new values should be the same except 2.72 be...

John Antowan 1K

Hi! I would start out by finding just how much my heat released is. In order to do this, we find the amount of moles of the grams of the molecule we are given (divide 1.157/105.01) and then multiply this number by the value given for heat released per mol (-3740*(1.157/105.01). We can omit the negat...

John Antowan 1K

I like the test tube examples provided in lecture:
Open: Test tube with no stopper
Closed: Test tube sealed with stopper
Isolated: Test tube sealed with stopper and insulated.

John Antowan 1K

From what I can recall from lecture, the way a pathway is considered irreversible is if the change in pressure is 0 and a pathway is reversible if the pressure is slowly changing.

John Antowan 1K

I am actually in the exact same position (and it doesn't help that we are doing thermodynamics for this next test). I think that my main focus this time is going to be practicing with a clock to time myself doing the questions, because I think the root of most of my test anxiety came from having so ...

John Antowan 1K

If you look at the constants sheet, there is a list of the coefficients of R depending on the situation. I think you managed to get the right answer despite the values being slightly off because the difference between the coefficient of R for constant pressure (5/2) and the coefficient of R for cons...

John Antowan 1K

Hey there! I believe that CO2 should be classified as a linear molecule, and we can usually use various models in order to know whether or not a molecule is linear. Knowing that there are no lone pairs helps us determine that the CO2 molecule is linear.

John Antowan 1K

I didn't get an A, but I can say with confidence that the best place to start is textbook problems. All relevant questions are listed in the syllabus, so that is usually what I use to know what questions to do.

John Antowan 1K

I have been working through a few textbook problems and haven't seen it come up yet... not 100% sure though.

John Antowan 1K

From some quick research I gathered that pKa is a measurement of the strength of the acid because it measures how tightly the acid is holding on to its proton. If the pKa is smaller, then the proton is more likely to be released from the acid and thus the acid will disassociate more and vice versa. ...

John Antowan 1K

I believe that the increase in pressure leads to more collisions between molecules and thus results in a reaction that occurs more frequently. If I am in a room with 10 people and we are moving around randomly, I will be more likely to collide (interact) with them if the room is smaller.

John Antowan 1K

Jordan Tatang 3L wrote:A mneumonic that one of the UA mentioned was
SO I Brought NO Clean ClOthes which corresponds to the strong acids
H2SO4, HI, HBr, HNO3, HCl, HClO3 and HClO4

This is literally the most creative mnemonic I have ever heard for chemistry.

John Antowan 1K

Nope, but based on the trend from the previous quarter, it should come out by the end of the week 5, beginning of week 6 at most, even with possible errors, since the first midterm grade came out Thursday after testing week with an error on some tests! :) Do you know where the grade will be posted?...

John Antowan 1K

Since pka usually deals with small decimals, adding the values will not get to the desired value of 1x10^-14. The only way to achieve this with decimals is by multiplying.

John Antowan 1K

An isolated system is insulated so that energy cannot flow in between it and the surroundings of the system. A closed system still permits energy to enter or leave the system.

John Antowan 1K

I'm in the not well category with you ;( I felt like I was so prepared and knew everything and then just slipped up bc it went rough. Highly recommend some good food though, it helps! Food heals all wounds. I will say that I can relate a lot to the having everything slip portion, I literally forgot...

John Antowan 1K

The K in a reverse reaction is the reciprocal of K, or 1/K.

John Antowan 1K

We know that in order to break bonds, energy must be put into the system and since we see the bond between X and X being broken to form two lone X's which would mean that the reaction is endothermic.

John Antowan 1K

I usually use the given equlibrium constant as a bit of a guess. If it is below 1x10^-4, I usually would estimate x is insignificant just to be safe, but I believe Professor Lavelle has mentioned that 1x10^-3 is okay too, just as long as it doesn't change the value next to it (which in your example ...

John Antowan 1K

Angel More wrote:Last time we were sent links prior to our exams. I think that is how it is going to be this time as well!

Do you remember where this was posted on CCLE? Or was it his website? Or possibly by email? Haha I have never taken a midterm with Professor Lavelle before and I'm a bit nervous...

John Antowan 1K

The symbol q is intended to express heat and H is to represent enthalpy is a state function while heat is not.

John Antowan 1K

I try to go to at least 3 or 4 UA sessions per week, and then sapling and textbook homework... So 10 -12 hours I would say? I also have other classes and I'm working so i understand the struggle. Going to UA sessions as study time, is very efficient and helpful cause they reinforce stuff we are sup...

John Antowan 1K

ICE boxes are usually used to find any unknown concentration and is vital for calculating numbers like pOH and pH depending on the nature of the question.

John Antowan 1K

Lol I usually spend about 10 hrs as long as I am doing good studying. I think that it is best (especially if taking 5 classes) to prioritize your classes based on what you best understand. If you feel that you are struggling with chem concepts more, spend more time on it and allocate your time in ot...

John Antowan 1K

I am pretty confident that this is material that will be covered next week, but it is done using this equation: m1c(Tfinal-tinitial1)= -m2c(Tfinal-tinital2) where m1 is the mass of the first specimen, c is the specific heat of water, and t initial1 is the given temperature of the first specimen, wit...

John Antowan 1K

I think that he was referring to the standard states because if something is not in its standard state, then the enthalpy of the phase change has to be taken into account during calculations. For instance, if water is in a gas phase in the chemical reaction, then the enthalpy of water vaporization m...

John Antowan 1K

I don't neccessarily think there is a way around it, but I think the best way to check that you are on a 14B post is by checking the top part of the page that displays the directions to get to the post. For instance, this post has Board index<Chem 14B<Chemical Equilibrium<Equilibrium Constants &...

John Antowan 1K

Awesome asset! I personally like referring to my upperclassmen peers, but I also really like this one group that I'm in called PUPPIES that is for pre-med students that gives insight into different courses that most pre-med students take. It's amazing and very supportive!

John Antowan 1K

Essentially you are determining the efficacy of the reaction. I believe it can also be used as a measure of the strength of an acid/base depending on what is given as it will show just how much product is produced.

John Antowan 1K

In order to solve this problem, you must first solve for the Kc of the reaction. This can be done by using the equation for Kc. Then, use this equilibrium constant and set up an ICE table with the new amount of NO as your initial and .2 as the initial for the other two species in the reaction. Then ...

John Antowan 1K

To calculate Kc for this reaction, simply use an ICE table with the given values in the question.

John Antowan 1K

The first thing that you should do is focus on what you know and work from there. Since you have the equilibrium constant for the acid, use that and an ice table to find the value for x. If you need to, write out an equation to visualize this, but as you most likely know, acids produce hydronium and...

John Antowan 1K

My favorite comfort movies are the Star Wars movies. Every single intro when I hear the amazing orchestra playing right after seeing the words "A long time ago, in a galaxy far, far away..." gives me one of my favorite feelings. It reminds me of my dad and I watching the movies together. J...

John Antowan 1K

Hi Shreya! Have you tried using an ICE table? That is your best bet. :)

John Antowan 1K

Does anyone know if we have excess posts from one week (let's say you post 8 times Week 1) if they can carry over to another week (such as if you only posted 2 times Week 2)? Does this count for full credit or is it a week by week situation? Also does this vary based on who your TA is?

John Antowan 1K

jasmineculilap_3F wrote:In an email, Professor Lavelle said 5 posts per week = 5 pts per week. I think the deadline is on sundays, but different TAs might have a different rules.

So it is actually the TA that monitors the amount of posts we have done in a week?

John Antowan 1K

Hi Naomi! My assumption is that any important conditions would be given, but they would probably not apply as the most important thing would be just the concentrations of the given species.

John Antowan 1K

I would assume based on previous examples it would be in your best interest to convert to moles since that is what the square brackets indicate when referring to the concentration of a chemical species in the reaction.

John Antowan 1K

Hi Cristian! I believe the chemical equation will include the phases (s, l, aq, or g) of all the chemical species in the reaction. I don't think we would have to figure out their phase. I think Jillian is correct. In all the questions we have been given so far, I haven't seen anything about having ...

John Antowan 1K

Since K is a constant, it cannot be affected by pressure. From what I understand, pressure affects the concentration of the involved reactants and products, but since K is a constant, it would not change. The concentration changing, however, would result in a lack of equilibrium, and thus Q would be...

John Antowan 1K

John Antowan 1K wrote:Hi Lucy! I am in your discussion and think it would be cool if we could maybe make a discussion chat too. Would you like to do that?

Just to specify, I can make the chat. :)

John Antowan 1K

Hi Lucy! I am in your discussion and think it would be cool if we could maybe make a discussion chat too. Would you like to do that?

John Antowan 1K

I have heard Dr. Lavelle say we will use either bars or atm since they do not vary significantly in their value.

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