Search found 55 matches
- Sun Mar 13, 2022 11:48 am
- Forum: General Rate Laws
- Topic: Overall order
- Replies: 67
- Views: 2340
Re: Overall order
The overall order of a reaction is found by summing up all the of the orders of each reactant.
- Sun Mar 13, 2022 11:43 am
- Forum: General Rate Laws
- Topic: Achieve Week 9 & 10 #1
- Replies: 10
- Views: 454
Re: Achieve Week 9 & 10 #1
For this one, you would just have to multiply the rate by the stoichiometric coefficients, and change to negative for the rate of the reactants. Hope this helps!
- Sun Mar 13, 2022 11:40 am
- Forum: General Rate Laws
- Topic: Order of a Reaction
- Replies: 11
- Views: 437
Re: Order of a Reaction
Yes, the units of k can be used to easily determine the order of the reaction.
for 0-order, is M/s
for 1st-order its 1/s
for 2nd-order its 1/M*s
and finally, for 3rd-order its 1/M2*s
for 0-order, is M/s
for 1st-order its 1/s
for 2nd-order its 1/M*s
and finally, for 3rd-order its 1/M2*s
- Sun Mar 13, 2022 11:36 am
- Forum: General Rate Laws
- Topic: Sign of rate
- Replies: 41
- Views: 1350
Re: Sign of rate
This is due to the fact that reactants are being used up, hence why the rate of change of reactants is negative. Therefore, the rate of change of products is positive because products are being formed.
- Sun Mar 13, 2022 11:33 am
- Forum: General Rate Laws
- Topic: Achieve #5 Weeks 9-10
- Replies: 7
- Views: 309
Re: Achieve #5 Weeks 9-10
For this problem, you will need to use the rate law you identified which was rate= k[A]a[B]b[C]c. Anything to the power of 0 is 1, so you can ignore any reactant that is zero order.
Plug in the concentrations given along with k(the rate constant)
Then you will obtain your initial rate!
Plug in the concentrations given along with k(the rate constant)
Then you will obtain your initial rate!
- Sun Mar 06, 2022 3:23 pm
- Forum: First Order Reactions
- Topic: half-life
- Replies: 9
- Views: 521
Re: half-life
The half-life equation of a first-order reaction would be t1/2=0.693/k
- Sun Mar 06, 2022 3:19 pm
- Forum: First Order Reactions
- Topic: 0.693 ?
- Replies: 39
- Views: 9219
Re: 0.693 ?
0.693 comes from ln(2)!
- Sun Mar 06, 2022 3:19 pm
- Forum: First Order Reactions
- Topic: graph
- Replies: 23
- Views: 863
Re: graph
Hello,
So in this case, the graph should have a negative linear slope (slope=-k)
So in this case, the graph should have a negative linear slope (slope=-k)
- Sun Mar 06, 2022 3:17 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Checking-In :)
- Replies: 34
- Views: 1620
Re: Checking-In :)
It has been quite difficult in my opinion, but enjoyable!
- Sun Mar 06, 2022 3:14 pm
- Forum: General Rate Laws
- Topic: Instantaneous vs Average Rates
- Replies: 35
- Views: 1583
Re: Instantaneous vs Average Rates
Hello, the difference between the two are:
The average reaction rate: the reaction rate over a period of time
The instantaneous reaction rate: the reaction rate a specific point in time
The average reaction rate: the reaction rate over a period of time
The instantaneous reaction rate: the reaction rate a specific point in time
- Sun Feb 27, 2022 3:25 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Nernst Equation
- Replies: 24
- Views: 982
Re: Nernst Equation
You use the first one when temp ≠ 298K(25°C) or when you are trying to solve for pH, the second one is much simpler and can only be used when temp=298K(25°C)
- Sun Feb 27, 2022 3:20 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: finding the value of n
- Replies: 24
- Views: 839
Re: finding the value of n
Once you balance half of your redox reactions, you then have to ensure that the number of reduced and gained electrons are equal to each other. If not, you add a stoichiometric coefficient to obtain this. You will then know n, the number of mols of electrons transferred.
- Sun Feb 27, 2022 3:15 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: spontaneity
- Replies: 43
- Views: 1941
Re: spontaneity
A negative ΔG and positive Ecell indicate a spontaneous reaction.
- Sun Feb 27, 2022 3:06 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Finding n
- Replies: 50
- Views: 2061
Re: Finding n
Balance your half reactions then multiply them by a stoichiometric coefficient to ensure that the same number of electrons are reduced and gained.
- Sun Feb 27, 2022 3:02 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: F in ∆G = -nFE
- Replies: 86
- Views: 3864
Re: F in ∆G = -nFE
Hello, F is Faraday’s constant 96485!
- Sat Feb 19, 2022 10:33 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: ∆U = 0
- Replies: 84
- Views: 4231
Re: ∆U = 0
ΔU=0 can occur in an isolated system, as w=0 and q=0 because there is no heat transfer or work being done by or on the system.
- Sat Feb 19, 2022 10:28 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Sponetanity
- Replies: 33
- Views: 1568
Re: Sponetanity
Hello,
Yes looking at ΔG can determine spontaneity.
When ΔG is negative, this means the reaction is spontaneous!
Yes looking at ΔG can determine spontaneity.
When ΔG is negative, this means the reaction is spontaneous!
- Sat Feb 19, 2022 10:24 pm
- Forum: Van't Hoff Equation
- Topic: ln vs log
- Replies: 93
- Views: 4993
Re: ln vs log
ln is loge, and while log is usually log10
- Sat Feb 19, 2022 10:20 pm
- Forum: Van't Hoff Equation
- Topic: ln
- Replies: 34
- Views: 2154
Re: ln
It's eto the power of the other side!
- Sat Feb 19, 2022 10:18 pm
- Forum: Van't Hoff Equation
- Topic: Celcius vs Kelvin for T1 and T2
- Replies: 84
- Views: 8990
Re: Celcius vs Kelvin for T1 and T2
I recommend you to use Kelvin only. If the question asks for celsius, then convert it!
- Sun Feb 13, 2022 3:40 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Work (Positive/Negative)?
- Replies: 50
- Views: 2387
Re: Work (Positive/Negative)?
-w = work done by the system
+w = work done on the system
+w = work done on the system
- Sun Feb 13, 2022 3:37 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Sig Figs
- Replies: 18
- Views: 747
Re: Sig Figs
Sig Figs should not be as important given that our tests are multiple-choice.
- Sun Feb 13, 2022 3:35 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Spontaneous
- Replies: 13
- Views: 482
Re: Spontaneous
Yes, a reaction is spontaneous when G is negative. This can be due to a large entropy and or a negative deltaH(exothermic).
- Sun Feb 13, 2022 3:30 pm
- Forum: Balancing Redox Reactions
- Topic: Oxidizing Vs Reducing agent
- Replies: 39
- Views: 2431
Re: Oxidizing Vs Reducing agent
OIL RIG, ---> oxidation is loss of electron and reduction is gain of an electron. A reducing agent losses an electron to give to the other compound/ molecule, while the oxidizing agent gains an electron from a compound/ molecule.
- Sun Feb 13, 2022 3:24 pm
- Forum: Balancing Redox Reactions
- Topic: How to Determine if a Reaction is in Basic or Acidic Solution?
- Replies: 53
- Views: 4604
Re: How to Determine if a Reaction is in Basic or Acidic Solution?
The problem should specify whether the reaction occurs in an acidic or basic solution. This can be given by stating the pH or pKa.
- Sun Feb 06, 2022 12:18 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: open system
- Replies: 65
- Views: 3079
Re: open system
In open systems, the reaction is not covered, for example an open beaker. Here the system can exchange matter and energy with its surroundings.
- Sun Feb 06, 2022 12:16 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Work done by or on the system
- Replies: 30
- Views: 950
Re: Work done by or on the system
When it says work is being done by the system, the internal energy of the system would decrease and w would be negative. When its says work is being done on the system, it means the system's internal energy is raised due to the work done on it, and w here would be positive.
- Sun Feb 06, 2022 12:11 am
- Forum: Phase Changes & Related Calculations
- Topic: Baking a Cake
- Replies: 41
- Views: 3594
Re: Baking a Cake
It's definitely endothermic as the cake batter absorbs heat (endothermic) inorder to become a solid.
- Sun Feb 06, 2022 12:09 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Q and K
- Replies: 15
- Views: 606
Re: Q and K
Q and K have the same formula, it's just the concentration of products divided by the concentration of reactants. However, you use Q when the system is not at equilibrium as Q is not a constant. K on the other hand is a constant and is equal among all reactions regardless of the amount of moles as l...
- Sun Feb 06, 2022 12:05 am
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Q<K?
- Replies: 87
- Views: 4453
Re: Q<K?
if you remember, Kc or Qc= [products]/[reactants]. If Q<K, this means there are more reactants and the formation of products would be favored in order to reach equilibrium. Hope this helps!
- Fri Jan 28, 2022 10:02 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Achieve Question 9
- Replies: 1
- Views: 99
Re: Achieve Question 9
Hi, So here we say that the heat gained by the cold water = to the heat lost by the hot water q cold water = -q hot water so mC sp ΔT= -(mC sp ΔT) mC sp (T final - T initial )= -(mC sp (T final - T initial )) note that the specific heat (C sp ) of water is 4.184J/g°C Now you have to plug all you kno...
- Fri Jan 28, 2022 8:31 pm
- Forum: Ideal Gases
- Topic: Can R change?
- Replies: 119
- Views: 7723
Re: Can R change?
R is a constant meaning its true value doesn't change, however, it could change if you are using different units
- Fri Jan 28, 2022 8:25 pm
- Forum: Calculating Work of Expansion
- Topic: Work Negative?
- Replies: 20
- Views: 744
Re: Work Negative?
Work is positive when work is done on the system and negative when work is done by the system
- Fri Jan 28, 2022 8:18 pm
- Forum: Phase Changes & Related Calculations
- Topic: Achieve question 5
- Replies: 2
- Views: 344
Re: Achieve question 5
You first have to look for the chemical reactions that have the products and reactants from your reaction of interest. You would probably start by choosing from reaction 1 or 4, though 1 would be the best as 4 has MCl 3 on both sides. As you probably noticed, in 1 you are missing Cl 2 on the reactan...
- Fri Jan 28, 2022 7:58 pm
- Forum: Phase Changes & Related Calculations
- Topic: Endothermic vs Exothermic
- Replies: 15
- Views: 764
Re: Endothermic vs Exothermic
Determining whether heat is added(endothermic) or removed(exothermic) from a system is a much simpler way to tell if its endothermic or exothermic.
- Fri Jan 28, 2022 7:55 pm
- Forum: Phase Changes & Related Calculations
- Topic: Achieve 7 (Week 5)
- Replies: 8
- Views: 391
Re: Achieve 7 (Week 5)
The equation you should use here is ΔHRXN=ΔHf(products)- ΔHf(reactants)
- Mon Jan 24, 2022 10:15 am
- Forum: Administrative Questions and Class Announcements
- Topic: Achieve HW WK 3
- Replies: 6
- Views: 296
Re: Achieve HW WK 3
I believe it has not been assigned.
- Sat Jan 22, 2022 10:42 pm
- Forum: Phase Changes & Related Calculations
- Topic: melting
- Replies: 101
- Views: 4659
Re: melting
Melting(also known as fusion) is an endothermic phase change as energy(heat) is required for a solid to become a liquid!
- Sat Jan 22, 2022 10:40 pm
- Forum: Phase Changes & Related Calculations
- Topic: freezing
- Replies: 70
- Views: 3445
Re: freezing
Freezing is an exothermic phase change as it liquid releases energy to become a solid!
- Sat Jan 22, 2022 10:36 pm
- Forum: Phase Changes & Related Calculations
- Topic: sublimation
- Replies: 22
- Views: 1074
Re: sublimation
Sublimation is an endothermic phase change as it requires heat(energy) to go from a solid to gas. Deposition (gas to solid) would be an example of an exothermic phase change.
- Sat Jan 22, 2022 10:32 pm
- Forum: Phase Changes & Related Calculations
- Topic: condensation
- Replies: 35
- Views: 1355
Re: condensation
Condensation is an exothermic phase change as it releases energy to go from a gas to a liquid!
- Sat Jan 22, 2022 10:30 pm
- Forum: Phase Changes & Related Calculations
- Topic: exothermic phase changes
- Replies: 25
- Views: 2037
Re: exothermic phase changes
Freezing, deposition, and condensation are examples of exothermic phase changes!
- Sat Jan 22, 2022 10:27 pm
- Forum: Phase Changes & Related Calculations
- Topic: Temperature of interest
- Replies: 8
- Views: 458
Re: Temperature of interest
The temperature of interest refers to the temperature at which the reaction is occurring. I lectures, Professor Lavelle has stated that if temperature is not sated, you can assume temp = 25°C
- Sat Jan 22, 2022 10:23 pm
- Forum: Phase Changes & Related Calculations
- Topic: Work?
- Replies: 9
- Views: 536
Re: Work?
Work is the transfer of energy from one system to another!
- Fri Jan 21, 2022 3:26 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Week Start/End
- Replies: 12
- Views: 617
Re: Week Start/End
Monday -Sunday 11:59pm
- Tue Jan 18, 2022 10:05 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Ka, Kb, and Kc
- Replies: 13
- Views: 2016
Re: Ka, Kb, and Kc
They are all equilibrium constants,
ka is for acids, kb is for bases, and kc is for concentrations
ka is for acids, kb is for bases, and kc is for concentrations
- Tue Jan 18, 2022 10:03 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Endothermic Reaction
- Replies: 16
- Views: 723
Re: Endothermic Reaction
Since enthalpy(H) is a negative value, this means it's exothermic, meaning the reverse reaction would be favored so reactants are favored.
- Tue Jan 18, 2022 9:59 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Ka vs pKa
- Replies: 16
- Views: 753
Re: Ka vs pKa
Ka is the equilibrium canstant, its Kb for the base, and pKa is the -log of pKa, and pKb is the negative log of Kb
- Tue Jan 18, 2022 9:54 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Q meaning
- Replies: 35
- Views: 1616
Re: Q meaning
Q is the ratio of products/reactants when it's not in equilibrium, if its in equilibrium we use K
- Fri Jan 14, 2022 2:33 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Shifting vs favoring
- Replies: 8
- Views: 794
Re: Shifting vs favoring
Both are used to describe the same thing, lies/shifts/sits to the right means the products are favored, and lies/shifts/sits to the left means the reactants are favored
- Fri Jan 14, 2022 2:29 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: ICE BOX
- Replies: 25
- Views: 873
Re: ICE BOX
You can know the sign of x given the information provided. Say if it says there were more products added, then it would be -x on the products side as the reverse reaction is favored in reaching equilibrium. This means there will be a +x on the reactants for this case.
- Fri Jan 14, 2022 2:22 pm
- Forum: Ideal Gases
- Topic: P = conc(rT) Usage
- Replies: 7
- Views: 292
Re: P = conc(rT) Usage
You can use it to convert molar concentration (n/v) to partial pressure or convert partial pressure to molar concentration.
- Fri Jan 14, 2022 2:19 pm
- Forum: Ideal Gases
- Topic: Ideal Gases and Equilibrium
- Replies: 9
- Views: 562
Re: Ideal Gases and Equilibrium
You can use it to convert molar concentration (n/v) to partial pressure or convert partial pressure to molar concentration.
- Tue Jan 04, 2022 9:14 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: What is R
- Replies: 10
- Views: 512
Re: What is R
R is a gas constant, Dr. Lavelle used it in the Audio-Visual Focus modules.
- Tue Jan 04, 2022 9:10 am
- Forum: Ideal Gases
- Topic: Using Kc vs Kp
- Replies: 19
- Views: 738
Re: Using Kc vs Kp
Like everyone said it depends on the information given. For molar concentrations it's Kc and for partial pressure, it's Kp.