CHEMISTRY COMMUNITY

Arpita Padhy 3E

Yes, this is because the pi bond is only present after there is already a sigma bond. For example, in a single bond, it is only a sigma bond, in double bonds, there is one sigma and one double bond, and in triple bonds, there is one sigma bond and two pi bonds.

Arpita Padhy 3E

It would be another pi bond. Single bonds have one sigma bond, double bonds have one sigma and one pi bond, and triple bonds have one sigma and two pi bonds.

Arpita Padhy 3E

I know that the textbook itself provides answers for the odd numbered questions.

Arpita Padhy 3E

This was actually a really helpful tip, thank you so much!

Arpita Padhy 3E

Lewis acids and bases deal with electrons where Lewis acids are electron acceptors while Lewis bases are electron donors. On the other hand, Bronsted acids and bases deal with protons where Bronsted acids are proton donors while Bronsted bases are proton acceptors.

Arpita Padhy 3E

Since ligands are named alphabetically, the chlorido would be named before the oxalato.

Arpita Padhy 3E

I'm almost positive that responding to other people's posts counts, so it does not necessarily have to be an original post.

Arpita Padhy 3E

I would agree that VSEPR is more for bond angles rather than the length of the actual bond.

Arpita Padhy 3E

yes, since chlorine has a higher electronegativity than iodine, it does a better job at being able to withdraw electrons.

Arpita Padhy 3E

I think this is a topic that is more covered in 14B, but he taught it so we had more context and understanding for the possibility of conceptual questions.

Arpita Padhy 3E

Since it accepts electrons, it would be considered a Lewis acid.

Arpita Padhy 3E

Polarizability increases going down a group but decreases going across a period.

Arpita Padhy 3E

Additionally, in double bonds, the first bond would be considered a sigma bond while the other would be considered a pi bond. In a triple bond, there would be one sigma bond and two pi bonds.

Arpita Padhy 3E

Since it has 4 regions of electron density and 2 lone pairs, it would be considered bent/angular :)

Arpita Padhy 3E

I usually try to round at the very end. I keep the other numbers in my calculator, so I get the most accurate number possible.

Arpita Padhy 3E

Hayden Jackson wrote:The proton is given to H2O, making H2O the lewis base because it excepts the proton and becomes H3O+, and then the anion left behind by the loss of the H+ proton is just dissolved in water and won't affect pH. Hope this helps!

This was a really good explanation, thank you!

Arpita Padhy 3E

The biggest tip would be to go somewhere that isn't a place where you normally relax. For example, it's a lot harder for me to study in my dorm since my body automatically wants to go into relaxation mode when I should be focusing.

Arpita Padhy 3E

I've heard people say that you could use either since they essentially are the same thing, so I wouldn't worry too much about it.

Arpita Padhy 3E

Even though drawing out the Lewis structure can be helpful when determining polarity, it's more important to look at the difference in electronegativity.

Arpita Padhy 3E

The easiest way to do this is by counting the amount of valence electrons there are in the atom, and if it is an odd number, it would be considered a radical which are very reactive.

Arpita Padhy 3E

Even though Be is further up than chlorine on the periodic table, chlorine is a lot further to the right which makes it more electronegative.

Arpita Padhy 3E

I definitely think that there would be something similar, and I don't think the extra practice would hurt :)

Arpita Padhy 3E

Hi! Electronegativity increases as you go across the period and increases as you go up a group.

Arpita Padhy 3E

Morgan Micallef 3G wrote:I'm also really nervous about this final, I feel super unprepared because I haven't taken chemistry since sophomore year of high school

I'm literally in the same boat, and I think it's important to just keep a positive mindset and realize that you know more than you think you do.

Arpita Padhy 3E

605721741 wrote:Will Chemistry Community posts also be a part of 14B?

I'm pretty sure chemistry community will be a part of 14B, I think I remember seeing a 14B topic section on the website itself, so I wouldn't be surprised if it was a part of the course.

Arpita Padhy 3E

They're essentially the same thing except they focus on different aspects of an atom. Bronsted acids and bases deal with protons while Lewis acids and bases deal with electrons. Bronsted acids donate protons while bronsted bases accept protons. Lewis acids accept electrons while Lewis bases donate e...

Arpita Padhy 3E

I just like to think of the direction in which each atom is pulling to see if they pull in different directions which would cause them to cancel each other out.

Arpita Padhy 3E

I think I remember lavelle saying that they are interchangeable, so you should be able to use either one :)

Arpita Padhy 3E

They're technically the same thing, so if you know either formula, you should be fine :)

Arpita Padhy 3E

I'm pretty sure that it would be classified as a Bronsted base.

Arpita Padhy 3E

Hello, The ground state of an electron configuration is the arrangement of electrons around the nucleus of an atom with lowest to highest energy. This means that ground state is the lowest and also the most stable. An excited state electron configuration means that certain electrons have moved up e...

Arpita Padhy 3E

I used the equations Ek = (1/2)mv^2 , λ=h/p , and p=mv First, I solved for v using by writing λ=h/p as λ=h/(mv) and then v=h/(mλ). You can use the mass of an electron, em=9.109383*10^-31kg , for m. Next, I plugged the value of v into Ek = (1/2)mv^2, and plugged in the constants h and em. Then you j...

Arpita Padhy 3E

It took me forever to understand this, but 4s is supposed to fill up before 3d.

Arpita Padhy 3E

I need to save this thread and use all of these suggestions lol, thanks for the great recommendations guys.

Arpita Padhy 3E

I just like to lay in my bed and listen to music, close my eyes, and try to tune out everything around me. It's super nice to not think about anything for a certain amount of time and just focus on the music.

Arpita Padhy 3E

This is literally perfect, I'm going to start using that.

Arpita Padhy 3E

I know the TAs are going to be going over the testing process as well, so you could ask your TA. The test is only 50 minutes though, and it's just during normal class time.

Arpita Padhy 3E

All of these suggestions are helping me calm down before Friday's midterm, so thank you guys!!

Arpita Padhy 3E

To start find the molecular mass of the chlorine molecule. Remember there's two chlorines and you need to used Avagadro's number as well. Once you have the molecular mass, make sure it is in terms of kg/molecule. If you have done this, just find the wavelength using lamda=h/mv! This was super helpf...

Arpita Padhy 3E

Hi! Yes, there is definitely a link between valence electrons and electron configurations. In the shortcut method of writing electron configurations, we name the nearest noble gas to encapsulate the core electrons in the atom. Then we name all the valence electrons in the atom (the outer shell). Th...

Arpita Padhy 3E

There are a bunch in person and on zoom that have started, but I would definitely try and go for in person because those are always more helpful.

Arpita Padhy 3E

I would stick to using 6.626 X 10^-34 just because it's more accurate. You'll probably get a similar answer with using 6.3, but might as well be more accurate and use 6.626

Arpita Padhy 3E

It'll probably be on the exam sheet, but it wouldn't hurt to know it, so it's easier to implement it into a problem.

Arpita Padhy 3E

I'm definitely going to try to go to as many step up sessions as possible and go through the textbook problems he suggested. I think the best thing to do is just practice problems.

Arpita Padhy 3E

Hi! I would think of doing something like this: 1) Starting off with the Rydberg's equation E = -h (planck's constant) R(rydberg's constant)/n^2 2) Plug in the equation the planck's constant values and rydberg's constant. The n in the equation would be 3-1 because the electron is moving from n=3 to...

Arpita Padhy 3E

I don't think it's mandatory, but discussions are usually a lot of practice problems that will definitely help to get more comfortable with the material.

Arpita Padhy 3E

The only homework is the stuff on achieve and the chemistry community problems; everything else is just practice for when you have time, but I would do them.

Arpita Padhy 3E

I would just worry about the achieve homework and the chemistry community posts. There's so much extra practice that I thought was actual homework, it scared me lol.

Arpita Padhy 3E

For number 9, can someone explain it step by step because I guessed with some random numbers and ended up getting it right, but I am so confused and don't know where to start.

Arpita Padhy 3E

Does anybody know if the audio visual topics for week two are supposed to be done before class or if they are just optional for extra practice

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