Search found 103 matches
- Sat Mar 12, 2022 11:31 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Orientation of reactants
- Replies: 5
- Views: 1800
Re: Orientation of reactants
hello, "A" is a constant that takes into account orientation and number of collisions. It is a frequency factor. Reactants must collide with enough energy to break bonds/overcome the energy barrier, but they also need to collide with the correct orientation (A). When A increases, k will in...
- Sat Mar 12, 2022 11:26 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Understand the difference between activation energy and free energy of activation
- Replies: 8
- Views: 502
Re: Understand the difference between activation energy and free energy of activation
Hello, This can be a bit confusing because of how close the two terms sound! When you see the term "Free energy," you should think of Gibbs Free energy, which is the amount of energy "free"/available to do thermodynamic work. Activation energy is the amount of energy needed for r...
- Sat Mar 12, 2022 11:23 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Slow Reaction
- Replies: 31
- Views: 1240
Re: Slow Reaction
Hello, The slow step is also known as the "rate determining step." The reaction can only go as fast as the slowest step. It doesn't matter how fast the other steps are if one step is slower. This means that when you are writing your rat law, you should write it in terms of the slowest step...
- Sat Mar 12, 2022 11:20 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: HW - #6
- Replies: 2
- Views: 155
Re: HW - #6
Hello, By looking at your axes, it shows that you are plotting concentration vs time. If the reaction was zero order, you would get a straight line, but since the rxn is first or second order, it will be curved because the rate is dependent on concentration. Zero order reactions are independent on c...
- Sun Mar 06, 2022 5:54 pm
- Forum: General Rate Laws
- Topic: Determining the Order of a Reactant
- Replies: 5
- Views: 287
Re: Determining the Order of a Reactant
Hello, In order to determine the order for a reactant, you need to look at the data table given. For reactant A, you need to compare a data set where A changes concentration and the other reactants remain constant. Then, you will compare the change in concentration of A to the possible change in the...
- Sun Mar 06, 2022 5:48 pm
- Forum: General Rate Laws
- Topic: Achieve week 9&10 question 7
- Replies: 4
- Views: 221
Re: Achieve week 9&10 question 7
hello, I had the same issue when I was doing the achieve problem. I guess achieve wants you to put it in the most simple form. Since C is zero order, it can be excluded from the rate because anything raised to the zero power is just 1. Since A is first order, you don't have to include the exponent b...
- Sun Mar 06, 2022 5:41 pm
- Forum: Zero Order Reactions
- Topic: Achieve Week 9 #6
- Replies: 11
- Views: 600
Re: Achieve Week 9 #6
Hello, When a reaction order is zero order, this means that the rate is constant and independent of the concentration of the reactant. Graphically, the linear line is depicting the concept that the rate of decomposition at minute one is the same as the rate of decomposition at minute 2 and so forth....
- Sun Mar 06, 2022 5:32 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Finding Units for k (Week 9 Achieve #4)
- Replies: 8
- Views: 509
Re: Finding Units for k (Week 9 Achieve #4)
Hello, The unit of rate needs to be M/s. Zero order rate = k[A]^0 -------> rate = k(1) - to get rate with the correct units, k must have the units of M/s because there is nothing else it is multiplied with. First order rate = k[A]^1 - [A] has a unit of M - in order to get the proper units of rate, k...
- Sun Mar 06, 2022 5:17 pm
- Forum: General Rate Laws
- Topic: achieve week 9 and 10 question 1
- Replies: 5
- Views: 294
Re: achieve week 9 and 10 question 1
Hello, When solving this problem, you need to use the coefficients of the balanced chemical reaction. The rate given is 0.240 M/s. This problem can be figured out stoichiometrically. The coefficient of A is 1, however, it is a reactant that is being "used up" (decreasing). This means that ...
- Sun Mar 06, 2022 5:05 pm
- Forum: General Rate Laws
- Topic: Question #19 Achieve Week 9&10
- Replies: 3
- Views: 199
Re: Question #19 Achieve Week 9&10
Hello, The purpose of a catalyst is the reduce the activation energy needed to facilitate the reaction. This works both ways, meaning that with the addition of a catalyst, the activation energy of the forward AND backwards reaction is reduced. If less energy is needed to facilitate a reaction and pr...
- Sun Mar 06, 2022 4:58 pm
- Forum: General Rate Laws
- Topic: Achieve week 9 question 3
- Replies: 8
- Views: 353
Re: Achieve week 9 question 3
Hello, The instantaneous rate of change is also known as the slope of the derivative of the function, which is the tangent line. On the graph given, the blue line is the function, and the red line is the tangent line to the curve. You can calculate the slope of the red line by taking (y2 - y1)/(x2 -...
- Sun Mar 06, 2022 4:45 pm
- Forum: Zero Order Reactions
- Topic: Achieve HW week 9 #8
- Replies: 14
- Views: 1195
Re: Achieve HW week 9 #8
Hello, For a zero order reaction, you should use the formula T=([A]0 - [A]t)/k in order to determine the amount of time it would take to decrease in concentration. Another tip I have is to look at the units given. The rate is given in M/s and the concentration given is in Molarity (M). In order to g...
- Sun Mar 06, 2022 4:40 pm
- Forum: General Rate Laws
- Topic: Achieve Week 9-10 Question 7
- Replies: 5
- Views: 277
Re: Achieve Week 9-10 Question 7
Hello, In order to determine the order of reactant C, it is helpful to first determine the order of A and B. When A doubled, the rate also doubled. This means that reactant A is first order (2^1). When reactant B doubled, the rate quadrupled (2^2). This means reactant B is second order. It can be a ...
- Fri Mar 04, 2022 2:47 am
- Forum: Balancing Redox Reactions
- Topic: Spontaneous process in battery
- Replies: 3
- Views: 260
Re: Spontaneous process in battery
Hello, To understand this concept, it is helpful to look at the equation deltaG = -nfE If the cell potential is positive, then delta G will be negative If the cell potential is negative, Delta G will be positive A reaction is spontaneous when delta G is negative Delta G = Delta H - T(Delta S) If the...
- Fri Mar 04, 2022 2:34 am
- Forum: First Order Reactions
- Topic: 1st order: slope = -k [ENDORSED]
- Replies: 3
- Views: 1633
Re: 1st order: slope = -k [ENDORSED]
Hello, The equilibrium constant K cannot be a negative number. K is a proportionality constant for concentrations, so it cannot be negative. first order graphs are negative because the concentration of reactants are decreasing over a period of time. Decreasing means that there is a negative slope. l...
- Fri Mar 04, 2022 2:23 am
- Forum: Second Order Reactions
- Topic: Reaction Order
- Replies: 3
- Views: 313
Re: Reaction Order
hello,
The most common reaction orders are zero, first, and second. There are higher orders such as 3rd and 4th, but we are studying the most common ones. There is also mixed order where the rate is fractional.
The most common reaction orders are zero, first, and second. There are higher orders such as 3rd and 4th, but we are studying the most common ones. There is also mixed order where the rate is fractional.
- Fri Mar 04, 2022 2:12 am
- Forum: Second Order Reactions
- Topic: Molecularity
- Replies: 17
- Views: 862
Re: Molecularity
Hello,
The molecularity will match/agree with the rate law. The kinetic order of any elementary reaction or reaction step is equal to its molecularity. Molecularity refers to the number of particles that collide in a specific step.
The molecularity will match/agree with the rate law. The kinetic order of any elementary reaction or reaction step is equal to its molecularity. Molecularity refers to the number of particles that collide in a specific step.
- Fri Mar 04, 2022 2:08 am
- Forum: First Order Reactions
- Topic: First order graph
- Replies: 11
- Views: 1018
Re: First order graph
Hello,
If the reaction is first order, that means the graph will have ln[a] on the Y axis and time on the X axis. If the reaction is first order, when you plot the points using ln, the graph will have a linear, negative slope.
If the reaction is first order, that means the graph will have ln[a] on the Y axis and time on the X axis. If the reaction is first order, when you plot the points using ln, the graph will have a linear, negative slope.
- Fri Mar 04, 2022 2:02 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Entropy of an Isolated System
- Replies: 9
- Views: 1424
Re: Entropy of an Isolated System
Hello, It is important to understand what isolated means. An isolated system cannot exchange matter or energy with its environment. Entropy describes the likelihood/probability that a system will be in a particular state. Entropy increases when disorder increases. The more positions a molecule can b...
- Fri Mar 04, 2022 1:01 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Achieve Week #5 and #6 Question #10
- Replies: 6
- Views: 374
Re: Achieve Week #5 and #6 Question #10
Hello, When looking at Delta H, is is important to know what it means when delta H is positive or negative. When delta H is positive, that means that the reaction is endothermic and heat is consumed. When delta H is negative, that means the reaction is exothermic is released. In the question, water ...
- Fri Mar 04, 2022 12:46 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Isolated vs. Isothermal
- Replies: 14
- Views: 1277
Re: Isolated vs. Isothermal
Hello,
Isothermal means constant temperature. So in an isothermal reversible expansion, temperature is constant while pressure and volume can change.
Isolated means that matter and energy cannot be exchanged between the system and the environment.
Isothermal means constant temperature. So in an isothermal reversible expansion, temperature is constant while pressure and volume can change.
Isolated means that matter and energy cannot be exchanged between the system and the environment.
- Fri Mar 04, 2022 12:40 am
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Delta G = O
- Replies: 22
- Views: 779
Re: Delta G = O
When Delta G = 0, that means that Q=K. No work can be done.
Since Delta G = -nfE, E cell = 0. When E cell = 0, that means the battery is dead. The reactions are happening at the same rate, opposite directions. This results in cancelation, therefore no work is done.
Since Delta G = -nfE, E cell = 0. When E cell = 0, that means the battery is dead. The reactions are happening at the same rate, opposite directions. This results in cancelation, therefore no work is done.
- Fri Mar 04, 2022 12:35 am
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: kinetics vs thermodynamics
- Replies: 25
- Views: 896
Re: kinetics vs thermodynamics
Thermodynamic analysis tells us if the forward or reverse process is favored, but it doesn't say how fast or the pathway taken. Kinetic analysis looks at the speed/rate of reaction and uses experimental technique to observe the concentration of products and reactants. For example, in lecture 20, Pro...
- Fri Mar 04, 2022 12:30 am
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Activation Energy
- Replies: 89
- Views: 3657
Re: Activation Energy
Activation energy is the energy needed to facilitate a chemical reaction. The addition of a catalyst lowers the activation energy needed for a reaction to undergo. This works in the forward and reverse direction.
- Thu Mar 03, 2022 11:05 pm
- Forum: Zero Order Reactions
- Topic: What is a Zero Order Reaction?
- Replies: 31
- Views: 1035
Re: What is a Zero Order Reaction?
A zero order reaction means that the rate of reaction is independent of the concentration of reactants. Increasing the concentration of reacts will not change the rate of reaction.
- Thu Mar 03, 2022 10:36 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Reducing Agents
- Replies: 8
- Views: 376
Re: Reducing Agents
Hello, Yes, you can use standard reduction potentials to determine which metals are better reducing agents. It is important to note that standard reduction potentials tell you the likelihood of something being REDUCED, meaning gain electrons. If looking for the best reducing agent, look for the lowe...
- Thu Mar 03, 2022 10:23 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: GFE negative
- Replies: 12
- Views: 567
Re: GFE negative
Hello, In order for a spontaneous process, delta S universe needs to be positive. In any spontaneous reaction, delta s is positive. Delta S universe = Delta S system + Delta S surroundings relating Delta G to spontaneity 1. delta G = delta H - T(delta S) 2. Delta G/(-T) = delta H/(-T) - (T)(delta S)...
- Thu Mar 03, 2022 10:12 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Entropy / Gibbs Free Energy Equations
- Replies: 6
- Views: 225
Re: Entropy / Gibbs Free Energy Equations
All of the equations given will give you the correct answer, however, not all of them will work with the information given. They are all derived from one another, so you can use equations in conjunction with one another to find a certain variable. For example, in some of the textbook problems, befor...
- Thu Mar 03, 2022 7:53 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Finding n
- Replies: 50
- Views: 1799
Re: Finding n
Hello, the n in the equation refers to the moles of electrons in a redox reaction. You are looking for the number of moles transferred in the redox reaction. The number of electrons lost in oxidation is gained by the species that is reduced. This is the n value that is plugged into the equation.
- Thu Mar 03, 2022 7:46 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: oxidizing/reducing agent
- Replies: 7
- Views: 333
Re: oxidizing/reducing agent
This topic can be pretty confusing because it is not very intuitive. In a redox reaction, the oxidizing agent is what is AIDING the reduction of a compound. The oxidizing agent is the species that gets reduced. The reducing agent is what us AIDING in the oxidation of a compound. The reducing agent i...
- Thu Mar 03, 2022 7:43 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Conducting Material
- Replies: 5
- Views: 228
Re: Conducting Material
Zinc and copper are good conductors of electricity. These metals are often the ones used in examples because of how zinc readily loses electrons compared to copper, so it will cause electrons to flow from zinc to copper. Placing zinc and copper metal in solutions of their salts can cause electrons t...
- Thu Mar 03, 2022 7:40 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Cell Diagram and Ecell [ENDORSED]
- Replies: 29
- Views: 115744
Re: Cell Diagram and Ecell [ENDORSED]
anodes are on the left and cathodes are on the right when using this notation
(II) signifies the salt bridge
(I) signifies phases change in contact with one another
(,) signifies same phase in contact with one another
Solids are written on the outside of the reaction
(II) signifies the salt bridge
(I) signifies phases change in contact with one another
(,) signifies same phase in contact with one another
Solids are written on the outside of the reaction
- Mon Feb 07, 2022 3:29 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Textbook Problem 6D.5
- Replies: 6
- Views: 1435
Re: Textbook Problem 6D.5
Hello,
When setting up your Ka ratio, you would have -x in the denominator, but since your Ka Value is so small, you can omit the X in the denominator because it will have very little effect on 0.057. 0.057 - a very small x value will still be about 0.057.
When setting up your Ka ratio, you would have -x in the denominator, but since your Ka Value is so small, you can omit the X in the denominator because it will have very little effect on 0.057. 0.057 - a very small x value will still be about 0.057.
- Mon Jan 31, 2022 5:03 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpies + Endo or Exothermic
- Replies: 2
- Views: 98
Re: Bond Enthalpies + Endo or Exothermic
Hello,
forming bonds is an exothermic process whereas breaking bonds is endothermic. If the bond that is broken is stronger than the fond formed, then it was an endothermic rxn. If the bond that is broken is weaker than the bond formed, it is an exothermic rxn.
forming bonds is an exothermic process whereas breaking bonds is endothermic. If the bond that is broken is stronger than the fond formed, then it was an endothermic rxn. If the bond that is broken is weaker than the bond formed, it is an exothermic rxn.
- Mon Jan 31, 2022 4:48 pm
- Forum: Phase Changes & Related Calculations
- Topic: Baking a Cake
- Replies: 41
- Views: 3357
Re: Baking a Cake
When thinking about baking a cake, you need to put heat in for the cake to bake. Heat absorbed will be endothermic.
- Mon Jan 31, 2022 4:39 pm
- Forum: Phase Changes & Related Calculations
- Topic: Achieve #9 (Week 5)
- Replies: 7
- Views: 388
Re: Achieve #9 (Week 5)
Hello,
We say q = - q because one side is losing heat, while the other is gaining heat. The heat lost will be proportional to the heat gained.
We say q = - q because one side is losing heat, while the other is gaining heat. The heat lost will be proportional to the heat gained.
- Mon Jan 31, 2022 4:35 pm
- Forum: Phase Changes & Related Calculations
- Topic: Hw week 3/4 question 14
- Replies: 3
- Views: 224
Re: Hw week 3/4 question 14
hello,
when using PV=nRT to solve for moles, it is important to use the correct gas constant R. In this case, you should be using (0.08206 [(L)(atm)]/[(mol)(K)])
I hope this helps!
when using PV=nRT to solve for moles, it is important to use the correct gas constant R. In this case, you should be using (0.08206 [(L)(atm)]/[(mol)(K)])
I hope this helps!
- Mon Jan 31, 2022 1:00 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Achieve #5
- Replies: 2
- Views: 164
Re: Achieve #5
Hello, In order to find the enthalpy of this reaction using supplemental reactions, it is important to look at whether compounds/elements are acting as reactants or products, stoichiometric ratios, and phases (such as solid or aq). In the equation of the rxn you want to derive, you have 2M(s) as a r...
- Mon Jan 31, 2022 12:39 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Achieve Week 3&4 #8
- Replies: 1
- Views: 113
Re: Achieve Week 3&4 #8
Hello, To solve for the second part of question 8, you will first have to convert grams of carbon to moles carbon using molar mass. Next, you will stoichiometrically find the delta H using the information given. Moles Carbon x (ΔH=+358.8 kJ / 4 moles carbon) I hope this helps! I am unsure if the num...
- Mon Jan 31, 2022 12:33 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Achieve HW Q10
- Replies: 3
- Views: 197
Re: Achieve HW Q10
Hello,
The values that should go on the negative side are the values that are losing heat. For example, in this problem, the water will be on the negative side because it is initially at 45 degrees celsius and will lose heat, dropping to a lower temperature once the ice is added.
The values that should go on the negative side are the values that are losing heat. For example, in this problem, the water will be on the negative side because it is initially at 45 degrees celsius and will lose heat, dropping to a lower temperature once the ice is added.
- Mon Jan 31, 2022 12:30 am
- Forum: Phase Changes & Related Calculations
- Topic: Achieve 15
- Replies: 2
- Views: 135
Re: Achieve 15
Hello, To do this problem, you need to first take the grams of NaN3 and convert it to moles Then stoichiometrically convert moles NaN3 to moles N2 gas. This is because NaN3 reacts completely. N2 is the only gas product that will inflate the bag. Once you get moles of N2 gas, use PV=nRT to solve for ...
- Mon Jan 31, 2022 12:21 am
- Forum: Phase Changes & Related Calculations
- Topic: Achieve #11
- Replies: 4
- Views: 283
Re: Achieve #11
Hello,
To solve for this problem you need to set the equations equal to each other with the side that is losing heat being negative to demonstrate the loss of heat
(m)(C)(Tf - Initial T) = - (m)(C)(Tf - Initial T)
To solve for this problem you need to set the equations equal to each other with the side that is losing heat being negative to demonstrate the loss of heat
(m)(C)(Tf - Initial T) = - (m)(C)(Tf - Initial T)
- Mon Jan 31, 2022 12:08 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Achieve # 19
- Replies: 1
- Views: 123
Re: Achieve # 19
hello, First, The problem tells you that it is a constant-volume calorimeter. This means that NO WORK is done. Therefore, the Delta U of the reaction is equal to qrxn. (Delta U = q rxn When looking at a problem like this one, I find it extremely helpful to look at your units. For example, you first ...
- Wed Jan 19, 2022 4:21 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Shifting Left/Right
- Replies: 32
- Views: 1120
Re: Shifting Left/Right
hello, The K value is an equilibrium constant, so the K value would not "shift" a reaction left or right. It is the Q value that would tell you if the reaction needs to shift to reach equilibrium. The Q value is calculated at any point in the reaction to see whether a reaction has reached ...
- Wed Jan 19, 2022 2:24 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Pressure effect on a system
- Replies: 6
- Views: 370
Re: Pressure effect on a system
Hello, When looking at the effect of pressure on an equilibrium reaction, it is important to notice whether or not the pressure is changing the concentration of the reactants and products. For example, if you have your reaction in a 1.00L vessel and you increase pressure by changing the volume to 0....
- Wed Jan 19, 2022 2:11 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Endo vs Exo thermic
- Replies: 32
- Views: 1484
Re: Endo vs Exo thermic
Hello,
If the delta H is positive, that means that the reaction is endothermic (requires energy as a reactant)
If the delta H value is negative, that means that the reaction is exothermic (releases energy)
If the delta H is positive, that means that the reaction is endothermic (requires energy as a reactant)
If the delta H value is negative, that means that the reaction is exothermic (releases energy)
- Sun Jan 16, 2022 9:58 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Autoprotolysis
- Replies: 7
- Views: 365
Re: Autoprotolysis
hello,
Autoprotolysis is when there is a proton transfer between the SAME type of molecule. For example, the autoprotolysis of water is equilibrium reaction of water to hydroxide and hydronium ions
2 H20 <------> H3O+ + OH-
Kw = 1 x 10^-14 (at 25 Degrees Celcius)
Autoprotolysis is when there is a proton transfer between the SAME type of molecule. For example, the autoprotolysis of water is equilibrium reaction of water to hydroxide and hydronium ions
2 H20 <------> H3O+ + OH-
Kw = 1 x 10^-14 (at 25 Degrees Celcius)
- Mon Jan 10, 2022 2:24 am
- Forum: Ideal Gases
- Topic: Kp and Kc
- Replies: 47
- Views: 1845
Re: Kp and Kc
Hello,
Yes, they are both solved the same way where you divide the concentration of the products by the reactants all raised to their respective powers. The only difference between the two is that Kp uses partial pressure and Kc uses concentration.
Yes, they are both solved the same way where you divide the concentration of the products by the reactants all raised to their respective powers. The only difference between the two is that Kp uses partial pressure and Kc uses concentration.
- Mon Jan 10, 2022 2:21 am
- Forum: Ideal Gases
- Topic: What is r?
- Replies: 17
- Views: 658
Re: What is r?
Hello, R is known as the gas constant in the ideal gas law PV=nRT. When looking for an unknown value using the gas law, it is important to use the correct gas constant in terms of units. The gas constant differs when using atm, bar, or torr. Make sure to pay attention to units to make sure you are u...
- Sun Jan 09, 2022 8:36 pm
- Forum: Ideal Gases
- Topic: Reverse and Forward Reactions
- Replies: 13
- Views: 538
Re: Reverse and Forward Reactions
Hello, When a reaction reaches equilibrium, then there is no net change in concentration and the reactants and products are forming at the same rate. This would then be used to calculate the equilibrium constant. The value of this constant can tell you which side (reactant or product) is favored. K>...
- Sun Jan 09, 2022 6:45 pm
- Forum: Ideal Gases
- Topic: Partial Pressure vs Concentration
- Replies: 9
- Views: 960
Re: Partial Pressure vs Concentration
Hello, The equilibrium constant K can be derived for either partial pressure or concentration. If the reaction is in an aqueous solution, then concentration will be used as partial pressure is used for gases. The reason we can calculate K using partial pressure for gases is due to its relation to th...
- Sun Jan 09, 2022 6:11 pm
- Forum: Ideal Gases
- Topic: K and Q
- Replies: 57
- Views: 4290
Re: K and Q
Although they are calculated in the same fashion (which is the concentration/partial pressure of products divided by the concentration/partial pressure of the reactants) they are different in what they represent. The K value is an equilibrium constant. When a reaction reaches equilibrium, there is n...
- Wed Dec 01, 2021 4:41 pm
- Forum: Calculating the pH of Salt Solutions
- Topic: Question 7
- Replies: 9
- Views: 599
Re: Question 7
Hello, In order to do this problem, you will need to look at the components of the salt, meaning the cation and the anion. A salt may be defined as the product of a neutralization reaction of an acid and a base. For example, when looking at the salt NH4ClO4, you can see that it is composed of NH4+ a...
- Wed Dec 01, 2021 12:43 am
- Forum: Conjugate Acids & Bases
- Topic: Achieve HW week 10 Question 3 [ENDORSED]
- Replies: 3
- Views: 209
Re: Achieve HW week 10 Question 3 [ENDORSED]
Hello, in general, its useful to know that: The conjugate base is the formula of the acid with one less hydrogen attached to it. Make sure you don't forget the charge of the compound. The conjugate acid is the formula of the base with one more hydrogen attached to it. Again, don't forget to look at ...
- Wed Dec 01, 2021 12:32 am
- Forum: Identifying Acidic & Basic Salts
- Topic: Salts
- Replies: 10
- Views: 463
Re: Salts
Hello, Salts can only be acidic, basic, or neutral. They cannot be both at the same time. I think you might be thinking of amphoteric compounds in which those are compounds that can act as an acid or base depending on the situation/type of solution it is placed in. Amphoteric oxides can form salts. ...
- Wed Dec 01, 2021 12:16 am
- Forum: Identifying Acidic & Basic Salts
- Topic: NaCl and pH
- Replies: 10
- Views: 1155
Re: NaCl and pH
Hello, When we were in lecture, Lavelle discussed how Na+ does not change pH because the +1 charge is not strong enough to break the bond between oxygen and hydrogen and pull off a proton. Furthermore, it is important to remember that group 1 and two cations are weak lewis acids. Lewis acids are ele...
- Wed Dec 01, 2021 12:08 am
- Forum: Identifying Acidic & Basic Salts
- Topic: Anion Exceptions
- Replies: 4
- Views: 246
Re: Anion Exceptions
Hello, The anions HSO4- and H2PO4- have a negative charge, but are able to act as an acid. Very few anions are able to act as an acid because it is very difficult for an anion to lose a hydrogen. The two exceptions Professor Lavelle gave us are able to give off a proton. For example, NaH2PO4 (which ...
- Mon Nov 29, 2021 5:59 pm
- Forum: Lewis Acids & Bases
- Topic: Acid and base strength level tricks
- Replies: 1
- Views: 199
Re: Acid and base strength level tricks
Hello, Strong acids and bases are those that completely dissociate in water to their respective ions(aq). Weak acids and bases don't completely dissociate in water It is helpful to memorize some of the strong acids (knowing these 6 is beneficial) 1. If there is a hydrogen in front of these 3 halogen...
- Mon Nov 29, 2021 5:29 pm
- Forum: Lewis Acids & Bases
- Topic: Classifying acids and bases
- Replies: 4
- Views: 216
Re: Classifying acids and bases
To determine whether a compound is an acid or a base, it is helpful to use either the bronsted definition of an acid/base or the lewis definition of an acid or a base. The bronsted definition looks at proton donors and acceptor while the lewis definition looks at electron donors and acceptors. Typic...
- Mon Nov 29, 2021 5:13 pm
- Forum: Lewis Acids & Bases
- Topic: H vs H3O
- Replies: 70
- Views: 4685
Re: H vs H3O
Hello,
These can be used interchangeably. [H+] is just showing the hydrogen on its own and [H3O+] shows that the hydrogen is bonded to a water molecule. Either way, it is showing the hydrogen and its charge.
These can be used interchangeably. [H+] is just showing the hydrogen on its own and [H3O+] shows that the hydrogen is bonded to a water molecule. Either way, it is showing the hydrogen and its charge.
- Mon Nov 29, 2021 5:11 pm
- Forum: Lewis Acids & Bases
- Topic: lewis vs. bronsted [ENDORSED]
- Replies: 30
- Views: 2281
Re: lewis vs. bronsted [ENDORSED]
These terms differ by definition. It is important to know the difference when asked to identify one or the other because it can cause confusion. A Lewis Base is a species that DONATES ELECTRON pair - an example of this is (OH-),(F-),(NH3) - These examples have a lone pair of electrons that can be do...
- Mon Nov 29, 2021 4:54 pm
- Forum: Amphoteric Compounds
- Topic: Amphoteric Compounds
- Replies: 15
- Views: 1551
Re: Amphoteric Compounds
Hello, Amphoteric compounds have basic and acidic character depending on what they interact with (acid or base). The diagonal band of amphoteric oxides on the periodic table closely matches the diagonal band of metalloids. These amphoteric compounds are in aqueous solutions. They include: 1. BeO 2. ...
- Mon Nov 29, 2021 4:49 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: pH equation
- Replies: 24
- Views: 982
Re: pH equation
Hello,
You should know that the equation to calculate pH as:
pH=-logbase 10 [H+]
You should also know how to find [H+] using this equation
[H+]=10^(-pH)
If you are given the pOH, you can use the equation below to figure out pH
14=pH+pOH
You should know that the equation to calculate pH as:
pH=-logbase 10 [H+]
You should also know how to find [H+] using this equation
[H+]=10^(-pH)
If you are given the pOH, you can use the equation below to figure out pH
14=pH+pOH
- Sun Nov 21, 2021 9:10 pm
- Forum: Ionic & Covalent Bonds
- Topic: Delocalized Bonds
- Replies: 11
- Views: 477
Re: Delocalized Bonds
Delocalized bonds can be seen in some molecules with resonance. The electrons can be spread across the molecule. The electrons are not confined to a specific location. Resonance form I contains 2 localized bonds and 1 delocalized bond. A delocalized chemical bond is a bond that is not associated wit...
- Sun Nov 21, 2021 8:44 pm
- Forum: Bond Lengths & Energies
- Topic: Bond length in double vs single [ENDORSED]
- Replies: 57
- Views: 3690
Re: Bond length in double vs single [ENDORSED]
Double bonds have more electrons being shared, meaning that the bond energy is stronger than that of a single bond. With a stronger bond and more electrons being shared, the bond is shorter and therefore becomes harder to break. The electrons are pulled harder and closer.
- Sun Nov 21, 2021 6:16 pm
- Forum: Bond Lengths & Energies
- Topic: polar vs. non-polar
- Replies: 17
- Views: 701
Re: polar vs. non-polar
When looking at the structure of a molecule, you can determine polarity by looking at the dipole moments. if the dipole moment cancel out, it molecule is non-polar. Symmetry in a molecule is non-polar and asymmetry is polar.
- Sun Nov 21, 2021 6:13 pm
- Forum: Bond Lengths & Energies
- Topic: Bond Angles
- Replies: 9
- Views: 1399
Re: Bond Angles
Its better to use the VSEPR model to determine bond angles because you can look at electron density and lone pairs that way. This way, its easier to visualize the atoms in their respective positions and conclude bond angles. It also great to memorize them and how lone pairs affect angles.
- Sun Nov 21, 2021 5:48 pm
- Forum: Bond Lengths & Energies
- Topic: length comparison
- Replies: 44
- Views: 3021
Re: length comparison
A double bond is shorter than a single bond because the electrons are closer together and therefore stronger. Nucleus-nucleus repulsion is overcome by electrostatic attraction between the positively charged nuclei and the electron cloud.
- Sun Nov 14, 2021 8:30 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Pi bonds
- Replies: 20
- Views: 1688
Re: Pi bonds
yes, that is correct. Pi bonds have two lobes that overlap with two lobes of an orbital of the other atom. It's a lateral overlap, so this prevents pi bonds from rotating because it would break.
- Sun Nov 14, 2021 5:30 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Sigma and Pi Bonds
- Replies: 33
- Views: 1823
Re: Sigma and Pi Bonds
a triple bond has one sigma bond and two pi bonds.
- Sun Nov 14, 2021 4:02 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Sigma and Pi bond rotation
- Replies: 5
- Views: 1209
Re: Sigma and Pi bond rotation
hello, sigma bonds have head-to-head overlap in which the electron density is directly along the bonding axis. Because of this, sigma bonds allow for rotation. The bond strength remains constant even when rotating. For pi bonds, however, have electron overlap above and below the plane of atoms. Ther...
- Sun Nov 14, 2021 1:39 am
- Forum: Sigma & Pi Bonds
- Topic: Rotation of Sigma vs. Pi Bonds
- Replies: 4
- Views: 250
Re: Rotation of Sigma vs. Pi Bonds
Sigma bonds have head-to-head overlap. The shared electron density is directly along the bond axis. Pi bonds have an orbital overlap with two lobes of an orbital of another atom. The electron density in pi bonds is above and below the bond axis. because of this, there cannot be rotation or the pi bo...
- Sun Nov 14, 2021 1:01 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Xe
- Replies: 41
- Views: 2129
Re: Xe
hello, Xe can form an expanded octet because it can utilize the unoccupied d-orbital. Just make sure to check the formal charge when doing your lewis structure. It should be zero. When drawing out lewis structures with Xe as the central atom, it is important to count the total number of valence elec...
- Sun Nov 07, 2021 8:03 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: SO2^3-
- Replies: 5
- Views: 495
Re: SO2^3-
The sulfite ion (SO3^2-) is trigonal pyramidal because there are four regions of electron density, but one of those regions are a lone pair. Remember that lone pair influence molecular shape, but only atom positions are used to determine the shape. There are 3 bonding pairs and 1 lone pair arranged ...
- Sun Nov 07, 2021 5:54 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Oxidation State
- Replies: 7
- Views: 285
Re: Oxidation State
Oxidation numbers tell you if an atom has gained or lost an electron. It can be a negative number, positive number, or zero. If the number is negative, that means that the atom has gained electrons. If the number is positive, that means the atom has lost electrons. An oxidation number of zero is neu...
- Sun Nov 07, 2021 5:16 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: When is the bond order 0?
- Replies: 13
- Views: 2541
Re: When is the bond order 0?
(Number of bonding electrons - number of anti bonding electron)/2 is the equation to figure out bond order. If this equation equaled zero, that means that there is no bond formed because there would be the same number of bonding electrons and anti-bonding electrons. This would be highly unstable and...
- Sun Nov 07, 2021 5:13 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: dipole-dipole molecule
- Replies: 3
- Views: 336
Re: dipole-dipole molecule
Dipole-dipole molecules involves electrostatic interactions. The slightly positive side of the molecule interacts with the slightly negative side of the other molecule. For example two HF molecules will have a dipole-dipole interaction between the slightly positive side (hydrogen) and the slightly n...
- Sun Nov 07, 2021 4:34 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Bond Order
- Replies: 14
- Views: 1148
Re: Bond Order
a molecule with a bond order of zero cannot form because it would be too unstable. Bond order can be calculated by taking the (Number of bonding electrons - number of anti bonding electron)/2. If that equaled zero, then no bonds would even be formed.
- Sun Oct 31, 2021 5:40 pm
- Forum: Electronegativity
- Topic: Electronegativity
- Replies: 8
- Views: 448
Re: Electronegativity
Electronegativity is the electron pulling power of atom represented by the Greek letter chi. The reason elements differ in electronegativity is due to differences in atomic number/the positive charge of the nucleus and the distance of the valence electrons from the positively nucleus of the atom. El...
- Sun Oct 31, 2021 4:48 pm
- Forum: Lewis Structures
- Topic: Deciding Order of Elements in Lewis Dot
- Replies: 5
- Views: 259
Re: Deciding Order of Elements in Lewis Dot
We put the element with the lowest electronegativity in the center. This can be determined by the periodic table. Electronegativity increases as you move across and decreases as you move down the periodic table. Hydrogen is an exception to this rule. For example, H2O. Oxygen is more electronegative ...
- Sun Oct 31, 2021 4:29 pm
- Forum: Lewis Structures
- Topic: Radicals [ENDORSED]
- Replies: 4
- Views: 200
Re: Radicals [ENDORSED]
hello, Radicals are compounds with unpaired electrons. An example of a radical is CH3 with an unpaired electron. This compound is created in the burning of hydrocarbons. Radicals are highly reactive, so they usually exist for a short amount of time. Radicals can damage DNA by reacting and modifying ...
- Sun Oct 31, 2021 4:19 pm
- Forum: Lewis Structures
- Topic: Carbon
- Replies: 16
- Views: 543
Re: Carbon
yes, carbon is usually going to be the central element in a structure. Carbon needs 4 bonds, so it is a generally a good rule of thumb to have it be the central atom.
- Sun Oct 31, 2021 4:17 pm
- Forum: Resonance Structures
- Topic: bond length
- Replies: 14
- Views: 448
Re: bond length
There is a correlation between bond length and type of bond. Single bonds have a longer bond length than double bonds. Double bonds have a longer bond length than triple bonds. Also, the shorter the bond, the stronger the bond. The bond energy is stronger when bond length is shorter.
- Sun Oct 24, 2021 11:32 pm
- Forum: DeBroglie Equation
- Topic: Excited vs Ground State
- Replies: 23
- Views: 2437
Re: Excited vs Ground State
The ground state configuration is the most stable and in the lowest energy level. When the electron configuration is in the excited state, electrons will move/skip to a higher energy state/orbital.
- Sun Oct 24, 2021 10:14 pm
- Forum: Einstein Equation
- Topic: Planck's constant equation
- Replies: 32
- Views: 1279
Re: Planck's constant equation
The constant will be on the equation sheet, but once you use it enough, it will eventually get memorized.
- Sun Oct 24, 2021 9:54 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: finding delta x
- Replies: 12
- Views: 2064
Re: finding delta x
Yes, if you were given the uncertainty of velocity, you would be able to find delta X by substituting momentum with mass and velocity. Momentum= mass(velocity).
- Sun Oct 24, 2021 8:12 pm
- Forum: Heisenberg Indeterminacy (Uncertainty) Equation
- Topic: Using Radius vs Diameter
- Replies: 21
- Views: 14677
Re: Using Radius vs Diameter
Hello,
You need to use the diameter when using the uncertainty equation. Delta X refers to all positions of the atom. The radius only accounts for half of the atoms position.
You need to use the diameter when using the uncertainty equation. Delta X refers to all positions of the atom. The radius only accounts for half of the atoms position.
- Sun Oct 24, 2021 7:57 pm
- Forum: *Shrodinger Equation
- Topic: Hamiltonian
- Replies: 5
- Views: 487
Re: Hamiltonian
Hello, The double derivative is also known as the second derivative. This is when you take the derivative of the first derivative. Also known as the instantaneous rate of change. The two components of the Hamiltonian are momentum and potential energy. When looking at the Time Independent Schrodinger...
- Sun Oct 17, 2021 9:10 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Specifying the orbitals within subshells
- Replies: 4
- Views: 186
Re: Specifying the orbitals within subshells
Hello, When it comes to the p orbital, Lavelle explained that there are 2 orbital lobes on either side of the nucleus and one nodal plane at the nucleus. They are perpendicular to each other and lie on the axis px, py, pz (x, y, z axis). When he says that they are arbitrary, I interpreted it as ther...
- Sun Oct 17, 2021 8:12 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: electron spin
- Replies: 4
- Views: 242
Re: electron spin
Hello, When looking at electron spin, it is important to understand it in context of Hund's rule. This is the electron configuration rule that says that orbitals will be singly occupied before becoming doubling occupied. All of the electrons will fill in the orbitals with the same spin before fillin...
- Sun Oct 17, 2021 7:23 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Aufbau Principle
- Replies: 13
- Views: 475
Re: Aufbau Principle
Hello,
The Aufbau Principle says that can electron cannot occupy a higher energy state until the lower energy states have been filled up first. Electrons fill the sub-shell from lowest to highest energy state. For example, electrons need to fill the 1s sub-shell before occupying the 2s sub-shell.
The Aufbau Principle says that can electron cannot occupy a higher energy state until the lower energy states have been filled up first. Electrons fill the sub-shell from lowest to highest energy state. For example, electrons need to fill the 1s sub-shell before occupying the 2s sub-shell.
- Sun Oct 17, 2021 7:16 pm
- Forum: Wave Functions and s-, p-, d-, f- Orbitals
- Topic: Nodal Planes
- Replies: 15
- Views: 734
Re: Nodal Planes
Hello, Nodal planes are where the electron density is equal to zero. This means that nodal planes are the regions around the nucleus, in which the likelihood of finding an electron is zero. S orbitals have no nodal plane, P orbitals have one nodal plane, and D orbitals have two nodal planes. When lo...
- Sun Oct 10, 2021 4:28 pm
- Forum: DeBroglie Equation
- Topic: Unit Cancellation
- Replies: 6
- Views: 527
Re: Unit Cancellation
Hi, its the easiest to figure out unit cancellation by writing down all of the units in respect to the equation. We see that in deBroglie's equation, the numerator as the units (Joules)(Seconds) The denominator has the units (Kg)(m/s) It is important to know that Joule = [Kg(m^2)]/(s^2) So this sets...
- Sun Oct 10, 2021 4:04 pm
- Forum: *Black Body Radiation
- Topic: What is Black Body?
- Replies: 53
- Views: 2742
Re: What is Black Body?
Based on last week's lecture, Dr. Lavelle explained "blackbodies" as a material whether it be atoms or molecules that is able to absorb or emit "all" frequencies. It is a hypothetical because no matter is able to do this. Some materials are better at absorbing and emitting freque...
- Sun Oct 10, 2021 3:59 pm
- Forum: Properties of Electrons
- Topic: deBroglie equation
- Replies: 5
- Views: 254
Re: deBroglie equation
It depends on the givens/knowns The equations we have learned that include wavelength are 1. the classical mechanics description of light ( c=λv) 2. an altered version of E=hv in which you combine it with the first equation to create ( λ=(hc)/E) 3. deBroglie equation ( λ= h/(mv)) The equations can b...
- Sun Oct 10, 2021 3:46 pm
- Forum: Properties of Electrons
- Topic: What does this symbol mean?
- Replies: 18
- Views: 2679
Re: What does this symbol mean?
The symbol means "proportional to"
The symbol is known to the the Greek letter alpha. You use the symbol in between two variables/quantities. For example, if x and y had an alpha in between them, that that means x is directly proportional to y.
The symbol is known to the the Greek letter alpha. You use the symbol in between two variables/quantities. For example, if x and y had an alpha in between them, that that means x is directly proportional to y.
- Sun Oct 10, 2021 3:35 pm
- Forum: Properties of Light
- Topic: Speed of Light
- Replies: 16
- Views: 591
Re: Speed of Light
Yes that's correct. No matter the wavelength of the light, the speed it travels at in a vacuum is about 3.00 x 10^8. It is a constant.
- Sun Oct 10, 2021 3:23 pm
- Forum: Properties of Light
- Topic: Photoelectric Effect
- Replies: 19
- Views: 888
Re: Photoelectric Effect
The photoelectric effect is the phenomenon in which a metal surface releases an electron when it absorbs electromagnetic radiation in the form of light. Light with certain frequencies are shined onto this metal surface. If the frequency is high enough, then it an electron can be ejected. In the phot...
- Sat Oct 02, 2021 11:08 pm
- Forum: Balancing Chemical Reactions
- Topic: Moles changing on reactant and product side
- Replies: 10
- Views: 1617
Re: Moles changing on reactant and product side
When balancing equations, you need to look the the atoms in the chemical compounds. For example, if you have 6 carbons on the reactant side, you need to make sure that you also have 6 carbons on the product side. This goes for all of the elements seen in a chemical reaction. The reason you might be ...
- Sat Oct 02, 2021 11:00 pm
- Forum: Balancing Chemical Reactions
- Topic: If actual yield is greater than theoretical
- Replies: 66
- Views: 11236
Re: If actual yield is greater than theoretical
If the experiment is conducted using the correct amounts of the reactants, then the actual yield should less than the theoretical yield due to side reactions and some of the elements/compounds sticking to the sides of the container. If the actual yield is greater than the theoretical yield than this...