Search found 30 matches
- Tue Mar 14, 2023 9:39 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #7
- Replies: 3
- Views: 134
Achieve 8-10 #7
hello! Can someone please help with these parts of problem 7? For the reaction 2A(g)+2B(g)+C(g)⟶3G(g)+4F(g) the initial rate data in the table was collected, where [A]0, [B]0, and [C]0 are the initial concentrations of A, B, and C, respectively. Experiment [A]0 (mmol⋅L−1) [B]0 (mmol⋅L−1) [C]0 (mmol⋅...
- Tue Mar 14, 2023 9:24 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #17
- Replies: 9
- Views: 268
Re: Achieve 8-10 #17
hiranya sundar 2D wrote:Let me know if you can see this!
Screenshot 2023-03-14 113102.png
I can! thank you so so much
- Mon Mar 13, 2023 9:33 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #20
- Replies: 3
- Views: 117
Achieve 8-10 #20
Can someone please explain how we're supposed to solve this problem? The presence of a catalyst provides a reaction pathway in which the activation energy of a reaction is reduced by 63.00 kJ⋅mol−1. Uncatalyzed: A⟶B Ea=133.00 kJ⋅mol−1 Catalyzed: A⟶B Ea=70.00 kJ⋅mol−1 Determine the factor by which th...
- Mon Mar 13, 2023 8:11 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #17
- Replies: 9
- Views: 268
Re: Achieve 8-10 #17
Since DELTA H is negative we assume this reaction is exothermic. If we look at a reaction diagram, the productions must have gone up by 53 kJ because that's the activation energy, and decrease by (53+24) to get the products value. 53 - (53+24) = -24 = DELTA H. To get the opposite reaction, we look ...
- Mon Mar 13, 2023 8:10 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #17
- Replies: 9
- Views: 268
Re: Achieve 8-10 #17
Thank you, this did help!
- Sun Mar 12, 2023 4:59 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #17
- Replies: 9
- Views: 268
Achieve 8-10 #17
Can someone please walk me through the steps of this problem? I don't really know where to start.
A certain reaction has an enthalpy of ΔH=−24 kJ and an activation energy of Ea=53 kJ. What is the activation energy of the reverse reaction?
Ea(reverse) = ? kJ
A certain reaction has an enthalpy of ΔH=−24 kJ and an activation energy of Ea=53 kJ. What is the activation energy of the reverse reaction?
Ea(reverse) = ? kJ
- Sun Mar 12, 2023 4:36 pm
- Forum: General Rate Laws
- Topic: Achieve 8-10 #5
- Replies: 5
- Views: 197
Achieve 8-10 #5
Hello! Can someone please walk me through this problem? I can't seem to get it right. The reaction A+B⟶C+Drate=k[A][B]2 has an initial rate of 0.0970 M/s. What will the initial rate be if [A] is halved and [B] is tripled? initial rate = ? M/s What will the initial rate be if [A] is tripled and [B] i...
- Fri Mar 10, 2023 11:12 pm
- Forum: General Rate Laws
- Topic: Achieve 8-10 #1
- Replies: 7
- Views: 224
Achieve 8-10 #1
I don't know where to start in solving this question. Can someone walk me through it or give tips?
The rate of the given reaction is 0.540 M/s.
A+3B⟶2C
What is the relative rate of change of each species in the reaction?
Δ[A]/Δt = ?
Δ[B]/Δt=?
Δ[C]/Δt=?
The rate of the given reaction is 0.540 M/s.
A+3B⟶2C
What is the relative rate of change of each species in the reaction?
Δ[A]/Δt = ?
Δ[B]/Δt=?
Δ[C]/Δt=?
- Wed Mar 08, 2023 10:57 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #19
- Replies: 4
- Views: 758
Re: Achieve 8-10 #19
Thank you so much! These explanations make a lot of sense, especially remembering the reactions learned in the LS 7 series relating to these
- Wed Mar 08, 2023 10:52 pm
- Forum: Balancing Redox Reactions
- Topic: Achieve 7/8 #8
- Replies: 8
- Views: 313
Re: Achieve 7/8 #8
Right, thank you so much! Didn't realize how much I had forgotten from high school chem
- Wed Mar 08, 2023 3:33 pm
- Forum: Balancing Redox Reactions
- Topic: Achieve 7/8 #8
- Replies: 8
- Views: 313
Re: Achieve 7/8 #8
Hi! When separating CuCl it becomes Cu+ and Cl-, so the reduction half reaction has Cl2 as reactant and 2Cl- (coefficient of 2 to make it balanced) as the product. Since the 2Cl- has a negative two charge, there should be two electrons on the reactants side. Hope this helps! This might be a stupid ...
- Wed Mar 08, 2023 3:30 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Achieve 7/8 #9
- Replies: 3
- Views: 144
Re: Achieve 7/8 #9
Thank you! That makes a lot of sense, I missed the part of it being spontaneous
- Wed Mar 08, 2023 2:05 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Achieve 8-10 #19
- Replies: 4
- Views: 758
Achieve 8-10 #19
Can someone please explain why activation energy is decreased when a catalyst is added? The feedback and solution on Achieve aren't very clear to me. How are the following aspects of a reaction affected by the addition of a catalyst? Increased, Decreased, or Not Affected? the answer bank: rate of th...
- Fri Mar 03, 2023 2:25 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Achieve 7/8 #9
- Replies: 3
- Views: 144
Achieve 7/8 #9
I think I remember that Professor Lavelle had said that for calculating standard cell potentials, we should put the larger, more positive E∘ in front so that the E∘cell always ends up positive. Why does the E∘cell have to be positive? I was specifically wondering about this for question 9 because th...
- Thu Mar 02, 2023 11:30 am
- Forum: Balancing Redox Reactions
- Topic: Achieve 7/8 #8
- Replies: 8
- Views: 313
Achieve 7/8 #8
Can someone explain why for the reduction half-reaction, the e- are on the left side and in front of Cl2? Separate this redox reaction into its balanced component half‑reactions. Use the symbol e− for an electron. Cl2+2Cu⟶2CuCl Oxidation half-reaction: 2Cu⟶2Cu++2e− reduction half-reaction: 2e−+Cl2⟶2...
- Thu Mar 02, 2023 11:21 am
- Forum: Balancing Redox Reactions
- Topic: Achieve 7/8 #5
- Replies: 3
- Views: 137
Achieve 7/8 #5
Can someone explain how to balance the following equation? I can't seem to get it right and I'm pretty sure it's from balancing oxygen wrong. Identify the oxidizing and reducing agents in the skeletal (unbalanced) reaction. Then, balance the reaction, including the phase (solid, liquid, etc.) of eac...
- Mon Feb 27, 2023 5:17 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Achieve 7/8 #7
- Replies: 4
- Views: 134
Re: Achieve 7/8 #7
And why is the cathode reaction different in the half-reaction versus the shorthand notation?
- Mon Feb 27, 2023 5:16 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Achieve 7/8 #7
- Replies: 4
- Views: 134
Achieve 7/8 #7
For question #7 on the week 7/8 Achieve homework, why is Cl− in the center of the shorthand notation?
- Mon Feb 27, 2023 4:37 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: finding bond enthalpies
- Replies: 4
- Views: 160
Re: finding bond enthalpies
The way to find bond enthalpy is you find how many bonds are associated with a given molecule. Usually you will be given the enthalpy numbers but you need to figure out how many bonds there are. For example if you were asked to find 2 H-H bond D’s you would multiply 2 to the given enthalpy. If you ...
- Mon Feb 27, 2023 4:35 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: finding bond enthalpies
- Replies: 4
- Views: 160
Re: finding bond enthalpies
Hi, I find it best to draw out all the molecular structures in the reaction to see which bonds remain on the product side. Then, you would be able to visually see which are broken on the reactants but formed on the products. I'm not sure there's a specific way to figure this out but I hope this hel...
- Sun Feb 26, 2023 8:52 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Sapling Week 5/6 #7
- Replies: 10
- Views: 1555
Re: Sapling Week 5/6 #7
I was able to find the molar enthalpy but I can't get the molar entropy correct. Are we supposed to divide the temperature in kelvins by the molar enthalpy in J's or kJ's? and the temperature is just the boiling point in kelvins right? To find molar entropy, divide molar enthalpy in joules by the b...
- Sun Feb 26, 2023 4:08 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Achieve HW 5/6 Q #7
- Replies: 3
- Views: 175
Achieve HW 5/6 Q #7
Three liquid samples of known masses are heated to their boiling points with the use of a heater rated at 550.0 W. Once the boiling points of each sample are reached, the samples are heated for an additional 3.09 min, which results in the vaporization of some of each sample. After 3.09 min, the samp...
- Sun Feb 26, 2023 3:07 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Sapling #8
- Replies: 13
- Views: 4104
Re: Sapling #8
Hello! To solve this problem, we need to know three steps that involve finding the standard molar entropy of vaporization: the entropy change heating water from 59.0 °C to 100 °C, the entropy of vaporization of water at 100.0 °C, and the entropy change cooling water from 100 °C to 59 °C. To solve t...
- Sun Feb 26, 2023 1:59 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Sapling Week 5/6 #7
- Replies: 10
- Views: 1555
Re: Sapling Week 5/6 #7
I was able to find the molar enthalpy but I can't get the molar entropy correct. Are we supposed to divide the temperature in kelvins by the molar enthalpy in J's or kJ's? and the temperature is just the boiling point in kelvins right?
- Thu Feb 23, 2023 6:13 pm
- Forum: Calculating Work of Expansion
- Topic: free expansion
- Replies: 6
- Views: 254
free expansion
Why is free expansion of a gas irreversible?
- Thu Feb 23, 2023 5:55 pm
- Forum: Calculating Work of Expansion
- Topic: isothermal process
- Replies: 2
- Views: 84
isothermal process
when calculating for an isothermal process and the problem does not specify if it is reversible or irreversible, is any equation accurate to use?
Out of: -nRTln(V2/V1)
-PexΔV
ΔS=nRln(V2/V1)
Out of: -nRTln(V2/V1)
-PexΔV
ΔS=nRln(V2/V1)
- Thu Feb 23, 2023 5:35 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: finding bond enthalpies
- Replies: 4
- Views: 160
finding bond enthalpies
How do we know which bonds are being broken and which bonds are being formed in an equation?
- Wed Feb 08, 2023 8:20 am
- Forum: Student Social/Study Group
- Topic: Fave food
- Replies: 266
- Views: 71303
Re: Fave food
pasta! especially my dad's aglio e olio.
- Wed Feb 08, 2023 8:16 am
- Forum: Administrative Questions and Class Announcements
- Topic: Advice from a Medical Student [ENDORSED]
- Replies: 297
- Views: 618597
Re: Advice from a Medical Student [ENDORSED]
Thank you so much for the advice! I always try to save my notes so it is good to know they will be helpful in the future
- Wed Feb 08, 2023 8:09 am
- Forum: Student Social/Study Group
- Topic: Fav Candy
- Replies: 40
- Views: 2810
Re: Fav Candy
mine would be anything chocolate or warheads !