Search found 31 matches
- Thu Mar 16, 2023 1:18 am
- Forum: General Rate Laws
- Topic: units for rate laws
- Replies: 9
- Views: 277
Re: units for rate laws
Usually, it will be in seconds unless stated otherwise.
- Thu Mar 16, 2023 1:16 am
- Forum: *Enzyme Kinetics
- Topic: Catalyst vs. Intermediate
- Replies: 11
- Views: 908
Re: Catalyst vs. Intermediate
First, a catalyst is something that is needed in order to get a reaction going, it is already formed initially. It usually lowers the activation energy and isn't used up in the reaction. An intermediate is formed as a product and then can be formed into a reactant.
- Thu Mar 16, 2023 1:12 am
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Half-Life
- Replies: 11
- Views: 330
Re: Half-Life
A Half-life is the time is takes for a reaction to decay in one half as to its original amount. Another way of remembering what a half-life is through exponential decay.
- Mon Mar 06, 2023 1:16 am
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Textbook Problem 6I.11
- Replies: 1
- Views: 376
Textbook Problem 6I.11
How do you calculate the molar solubility of silver bromide in 0.10 M KCN(aq)?
- Mon Mar 06, 2023 1:09 am
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: Textbook Problem 6L.9
- Replies: 1
- Views: 125
Textbook Problem 6L.9
How would I find the following?
(a) Write balanced half-reactions for the redox reaction of an acidified solution of potassium permanganate and iron(II) chloride. (b) Write the balanced equation for the cell reaction and devise a galvanic cell to study the reaction (write its cell diagram).
(a) Write balanced half-reactions for the redox reaction of an acidified solution of potassium permanganate and iron(II) chloride. (b) Write the balanced equation for the cell reaction and devise a galvanic cell to study the reaction (write its cell diagram).
- Mon Mar 06, 2023 1:09 am
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: 6L.6 Textbook Problem
- Replies: 1
- Views: 107
6L.6 Textbook Problem
How would I find the following for part C?
Write the half-reactions, the balanced equation for the cell reaction, and the cell diagram for each of the following skeletal equations:
Write the half-reactions, the balanced equation for the cell reaction, and the cell diagram for each of the following skeletal equations:
- Mon Feb 27, 2023 4:30 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Textbook Exercise 6L.1
- Replies: 1
- Views: 107
Textbook Exercise 6L.1
In part b, how would you calculate the standard reaction Gibbs free energy?
- Mon Feb 27, 2023 4:28 pm
- Forum: Balancing Redox Reactions
- Topic: Textbook Exercise 6k.1
- Replies: 1
- Views: 92
Textbook Exercise 6k.1
In exercise 6k.1, how would you write and balance the oxidation half-reaction that is shown?
- Mon Feb 27, 2023 3:53 pm
- Forum: Balancing Redox Reactions
- Topic: Oxidized v Reduced
- Replies: 79
- Views: 3746
Re: Oxidized v Reduced
From an equation, you can tell when it is oxidized when there is a loss of electrons and it is reduced when there is a gain of electrons.
- Sun Feb 19, 2023 11:33 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Achieve Hw #6
- Replies: 2
- Views: 139
Achieve Hw #6
Hi, can someone explain how to do this problem? A particular container holds 2.15 mol of neon gas. The volume of this container can be altered by sliding a piston in or out. The volume is changed from 8.80L to 4.40L while at the same time the temperature is changed from 334K to 218K. The molar heat ...
- Sun Feb 19, 2023 11:29 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Types of Systems
- Replies: 13
- Views: 992
Types of Systems
Hi, can someone explain the differences from open, closed, and isolated systems? What are ways of determining them?
- Sun Feb 19, 2023 11:26 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: ∆G and ∆G°
- Replies: 3
- Views: 121
∆G and ∆G°
Hi, can someone explain what the difference between ∆G and ∆G° is?
- Sun Feb 19, 2023 11:25 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Textbook problem 4H.9
- Replies: 1
- Views: 99
Textbook problem 4H.9
Can someone guide me through this textbook problem? 4H.9 Container A is filled with 1.0 mol of the atoms of an ideal monatomic gas. Container B has 1.0 mol of atoms bound together as diatomic molecules that are not vibrationally active. Container C has 1.0 mol of atoms bound together as diatomic mol...
- Sun Feb 19, 2023 11:23 pm
- Forum: Calculating Work of Expansion
- Topic: Sign of work
- Replies: 17
- Views: 417
Re: Sign of work
You can determine the sign of work from the following two things.
If there is work being done BY the system, the work is negative and if there is work being done ON the system, the work is positive.
If there is work being done BY the system, the work is negative and if there is work being done ON the system, the work is positive.
- Sun Feb 19, 2023 11:21 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Achieve Wk 5 #5
- Replies: 1
- Views: 93
Achieve Wk 5 #5
Hi, could someone help me solve this problem? The molar heat capacity for carbon monoxide at constant volume is CV, m=20.17 J/(K·mol). A 20.00L fixed-volume flask contains CO(g) at a pressure of 5.00 kPa and a temperature of 25.0 °C. Assuming that carbon monoxide acts as an ideal gas and that its he...
- Mon Feb 06, 2023 5:19 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: 4I.5
- Replies: 1
- Views: 319
4I.5
For textbook problem 4I.5, can someone guide me through solving it?
- Mon Feb 06, 2023 5:04 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: concept
- Replies: 9
- Views: 448
Re: concept
Yes it is possible, when heat is absorbed, Delta H will be positive and when entropy decreases, Delta S is negative.
- Mon Feb 06, 2023 5:04 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: concept
- Replies: 9
- Views: 448
Re: concept
Yes it is possible, when heat is absorbed, Delta H will be positive and when entropy decreases, Delta S is negative.
- Sun Feb 05, 2023 11:52 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Textbook problem 4G.5
- Replies: 2
- Views: 250
Textbook problem 4G.5
Hi, can someone guide me through solving textbook problem 4G.5?
- Sun Feb 05, 2023 11:48 pm
- Forum: Van't Hoff Equation
- Topic: ln vs log
- Replies: 93
- Views: 5558
Re: ln vs log
The difference between ln vs log is that ln = loge(x) while log = log10(x).
- Sun Feb 05, 2023 11:47 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Achieve HW #12
- Replies: 2
- Views: 222
Achieve HW #12
How would I find C in the following problem? At constant volume, the heat of combustion of a particular compound, compound A, is −3987.0 kJ/mol. When 1.545 g of compound A (molar mass =114.99 g/mol) is burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by ...
- Sun Jan 22, 2023 11:44 pm
- Forum: Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions
- Topic: Quadratic Formula
- Replies: 32
- Views: 1155
Re: Quadratic Formula
After you have completed the ICE table, you would use the quadratic formula to solve for x.
- Sun Jan 22, 2023 11:39 pm
- Forum: Bronsted Acids & Bases
- Topic: Acids and Bases
- Replies: 6
- Views: 393
Re: Acids and Bases
For a solution to be an alkaline, it has a pH greater than 7.
- Sun Jan 22, 2023 11:32 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Textbook Inquiry [ENDORSED]
- Replies: 29
- Views: 82483
Re: Textbook Inquiry [ENDORSED]
You are able to download the textbook and read it offline.
- Sun Jan 22, 2023 11:16 pm
- Forum: Lewis Acids & Bases
- Topic: pKa
- Replies: 31
- Views: 1589
Re: pKa
To answer your question, a large Ka will show a strong acid and a large pKa shows a weak acid. Bases would also be vise versa
- Sun Jan 15, 2023 11:07 pm
- Forum: Student Social/Study Group
- Topic: Final Jitters
- Replies: 457
- Views: 712454
Re: Final Jitters
Something that helps me when I get anxiety before a test is listening to music and taking deep breaths.
- Sun Jan 15, 2023 11:04 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Solids and Liquids
- Replies: 4
- Views: 170
Solids and Liquids
Why are solids and liquids not included in equilibrium constant?
- Sun Jan 15, 2023 11:03 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Solids and Liquids
- Replies: 4
- Views: 194
Solids and Liquids
Why are solids and liquids not included in equilibrium constant?
- Sun Jan 15, 2023 10:52 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Question 8 Part 2 Achieve Homework
- Replies: 3
- Views: 147
Question 8 Part 2 Achieve Homework
For question 8 part 2, How will the system respond to a temperature increase?
- Sun Jan 15, 2023 10:41 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Equilibrium constants
- Replies: 2
- Views: 95
Equilibrium constants
How do you identify when to write the equilibrium constant as Kc or Kp?
- Sun Jan 15, 2023 10:32 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Chemical Equilibrium
- Replies: 3
- Views: 126
Chemical Equilibrium
I was having difficulty understanding this question,
What can be said about Q and K immediately after an increase in temperature?
A)Q>K because Q increased.
B)Q>K because K decreased.
C)Q<K because K increased.
D) Q<K because Q decreased.
E) Q=K because neither changed.
What can be said about Q and K immediately after an increase in temperature?
A)Q>K because Q increased.
B)Q>K because K decreased.
C)Q<K because K increased.
D) Q<K because Q decreased.
E) Q=K because neither changed.