CHEMISTRY COMMUNITY

Layla Shapouri 2L

I spend a lot of time in the music building. So somewhere around there

Layla Shapouri 2L

Love love love sushi

Layla Shapouri 2L

It’s 25 questions, but we will already know 2 of them (respondus questions)

Layla Shapouri 2L

Oh my [censored] the nerd cluster gummies are so good

Layla Shapouri 2L

Not an artist,

But the song how to catch a thief. It’s by a bunch of people.

Layla Shapouri 2L

Also doing the practice problems in the textbook!

Layla Shapouri 2L

Do you guys have any tips on how to study for the final?

I dont want to find myself stuck studying so much and I feel like its so much material.

Layla Shapouri 2L

I asked the guy sitting next to me if he had any Sodium Hypobromite…
He said NaBrO

Layla Shapouri 2L

Hey, I answered this on another page but ill copy it here. Keep in mind its not the exact same question but it works the same way. Hi, So the first step would be to write out the oxidation and reduction half reactions. You can determine which is which by looking at the oxidation states of each eleme...

Layla Shapouri 2L

Yes, I believe it is written

Anode|aqueous materials|| aqueous materials|Cathode

There is a slight addition for phase changes, so for example the equation, Cu(s) + Cl2(g) -> Cu2+(aq) + 2Cl- (aq) with a platinum electrode for the cathode:

Cu(s)|Cu2+(aq)||Cl2(g)|Cl-(aq)|Pt(s)

Layla Shapouri 2L

Hi, So the first step would be to write out the oxidation and reduction half reactions. You can determine which is which by looking at the oxidation states of each element. So for example, it would look like Mn(+4)O2(-2) + Cu2+ -> Mn(+8)O4(-2)- + Cu+ So looking at that you can see that the MnO2 is b...

Layla Shapouri 2L

Hi, I think a good way to approach it is conceptually. So if you think about which side of the concentration cell would increase based on equilibrium rules we know it might help. For example, if you have a container that allows for the movement of molecules and the right side of the container has 20...

Layla Shapouri 2L

The equation for ∆G is ∆G= -nFE and ∆G°=-nFE°. these are derived from the concept of the potential difference equalling the -work/charge. (the work being negative because the battery is doing work thus). Then you find that the maximum work is equal to -nFE and we also know that maximum work is equal...

Layla Shapouri 2L

I like to hear chemistry puns,
periodically.

Layla Shapouri 2L

It’s similar to Delta H when O2, H2 etc. is zero. They are going from O2 (g) -> O2 (g).

Layla Shapouri 2L

It’s similar to Delta H when O2, H2 etc. is zero. They are going from O2 (g) -> O2 (g).

Layla Shapouri 2L

905802613 wrote:You can definitely download the textbook! Just click the right drop down menu by your name on the textbook page. From there you can choose to download the e-book. See screenshot below:

Thanks for posting the screenshot! I couldn’t seem to find it

Layla Shapouri 2L

For the first equation can be used when pressure is constant. The second, however is used when pressure is no longer constant and is changing by infinitesimally small increments.

Layla Shapouri 2L

I also think doing the textbook problems really help you understand the topics and also help guide you to see what problems on the midterm will be like.

Layla Shapouri 2L

Hi,

for that problem I believe it is asking for the delta S. This equation would not include temperature.

Layla Shapouri 2L

whats the sign of a bad chemistry joke?

no reaction :/

Layla Shapouri 2L

Yeah, to add on, you use the formula C = q/ delta T to find the q for compound b. Then you want to divide by the mass because it is asking for the heat of combustion per gram.

Layla Shapouri 2L

Hi, If I am understanding your question correctly, then you would have to think about whether or not heat is released or absorbed by the reaction. I don't know exactly what question you're asking about, but if heat is released by the reaction, then there is a negative absorption by the solution and ...

Layla Shapouri 2L

The table in 4E.2 show the enthalpy required to break the bond of the diatomic molecules. For examples, the enthalpy required to break H2(g) into 2H(g) (H-H) is 436 kJ/mol. The other molecules (CO, HF, etc) are diatomic molecules, not elements.

Layla Shapouri 2L

Yes, the standard state requires the everything to be at the standard pressure, temp etc.

Layla Shapouri 2L

Hey, just to add on to this answer, the standard enthalpy of formation of N2 would look like,

N2 (g) -> N2 (g). (because you want to have N2 g as your product, and the most stable form of it is also N2 (g). I think seeing it written out like this makes it easier to see how it would be zero.

Layla Shapouri 2L

Hi,

Just adding on to everyone, I would recommend using the quadratic formula. It only takes a minute or two longer and you don't have to worry about getting a percentage too high and redoing the problem.

Layla Shapouri 2L

Is knowing if an acid/base is strong or weak relevant to solving any specific problems in 14B or is it just extra information? It is helpful depending on the question. If the reaction involves a strong base or acid, then we know that the entire compound will dissociate into salt. However, when deal...

Layla Shapouri 2L

In the equation where it says that pKw = pH + pOH = 14 at 25(degrees c) what does the p mean in the pKw section? And just to clarify the Kw refers to the equilibrium constant when water is involved right? p in most situation is just another way to say -log. So, for example the pH, as we know is the...

Layla Shapouri 2L

Lose an electron?

Gotta keep an ion it.

(I think this one is funny)

Layla Shapouri 2L

I think as a general way to approach this, you should look to see if the question mentions concentrations or pressure. This would help specify what K you're using. (if concentration then Kc or pressure than Kp) These can be converted from one another using P=n/v RT with n/v being concentration and P...

Layla Shapouri 2L

If you alter the volume of the equations then the concentration will change. This is due to concentration being measured as moles over volume. Therefore changing volume directly changes the concentrations. If you increase the volume, then the concentration will decrease (the denominator increases) a...

Layla Shapouri 2L

Hi there, There can be a lot of arithmetic errors when doing the quadratic equation (Especially when it's so complex) so another way to approach it is to square root everything once you've set up the right formula. For example, when its at 53.3 = (2x)^2 / (.600-x)^2, you can square root both sides t...

Layla Shapouri 2L

Hi, like a lot of people have stated, K and Q are both ratios of products and reactants, however they occur at different states. If you think of a timeline with the farthest left point being the start of the reactions, and some point in the middle being the time where it reaches equilibrium, at that...

Layla Shapouri 2L

Hey, I was also under the impression of that activities implied the interactions between reactant and product. And like it was mentioned before, I assumed these existed within the net reactions that exist at equilibrium.

Layla Shapouri 2L

Hey, I like many others also struggle with a lot of anxiety. Very often when it comes to finals I have difficulty sleeping and am just general uncomfortable before. What helps me is to make sure to schedule time to cool down after the exam. There are definitely ways to be less stressed before like e...

CHEMISTRY COMMUNITY

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