Search found 5 matches

by Nicole Ng IC
Sun Dec 14, 2014 10:42 am
Forum: Dipole Moments
Topic: Are all molecules with lone pairs polar?
Replies: 7
Views: 13008

Re: Are all molecules with lone pairs polar?

What about in terms of bond dipole moment? Would electrons be the more negative one, and hence the arrow pointing at them? Or are electrons not included in bond dipoles?
by Nicole Ng IC
Sat Dec 13, 2014 10:02 pm
Forum: *Titrations & Titration Calculations
Topic: Switching Ka and Kb
Replies: 2
Views: 667

Re: Switching Ka and Kb

Ka should be used because the substance that is affecting the pH is the conjugate acid (NH4+) that was produced by the neutralization reaction of NH3 and HCl. You can convert it from the given Kb because NH3 is the conjugate base of the acid in this reaction equation: NH4+ + H2O <--> NH3 + H3O+ henc...
by Nicole Ng IC
Sat Dec 13, 2014 9:54 pm
Forum: *Titrations & Titration Calculations
Topic: 12.39
Replies: 2
Views: 354

Re: 12.39

Since the moles are equal, and the concentrations are equal, then the volume has to be the same because:
n = c x v

Because the volume is the same, the volume is "doubled."

so it would be 0.2/2 "volume" = 0.1M.
by Nicole Ng IC
Sat Dec 13, 2014 9:45 pm
Forum: *Making Buffers & Calculating Buffer pH (Henderson-Hasselbalch Equation)
Topic: FINAL EXAM 2013 Q8
Replies: 2
Views: 472

Re: FINAL EXAM 2013 Q8

Or you can think of it as when the muscle works hard, oxygen concentration decreases while lactic acid is produced and hence will increase. Because oxygen levels decrease, the equilibrium will shift to make more oxygen, so HbO2- will decrease. When lactic acid increases, oxygen decrease, so HbO2- de...
by Nicole Ng IC
Sat Dec 13, 2014 9:41 pm
Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
Topic: Br 2+
Replies: 7
Views: 2551

Re: Br 2+

I had the same problem. When you remove the two electrons, one is from the pi*px and one from the pi*py, so those two orbitals would be unpaired. Hence the molecule would be paramagnetic. I don't think d orbitals are involved in any way. I might have been a typo because the answer key generalized th...

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