Search found 28 matches
- Sat Mar 12, 2016 12:49 pm
- Forum: *Nucleophiles
- Topic: Final 2013
- Replies: 1
- Views: 477
Final 2013
For question 6a, why isn't it considered a trans/cis molecule since it has a double bond and the methyl group is on the opposite side of the ch2 so wouldn't it be E?
- Sat Mar 05, 2016 4:48 pm
- Forum: *Alkynes
- Topic: Alkene and Alkyne
- Replies: 2
- Views: 1556
Alkene and Alkyne
When naming organic molecules, why does the alkene get numbering priority before the alkyne?
Amines
For amines, in the course reader, it says that an R group connected to NH2 is a primary structure, so type would CH3CH2NH3(ethyl ammine) be? And just for clarification, is the ammine group always N connected to one or more C?
- Thu Feb 25, 2016 9:37 pm
- Forum: *Identifying Primary, Secondary, Tertiary, Quaternary Carbons, Hydrogens, Nitrogens
- Topic: Trans and Cis
- Replies: 2
- Views: 741
Trans and Cis
Can you determine trans and cis geometric isomers just by using the line structure, if so, how would you do that? or would you have to draw out the lewis structure?
- Sat Feb 20, 2016 1:36 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Difference between catalysts and intermediates
- Replies: 1
- Views: 564
Re: Difference between catalysts and intermediates
NO2 is an intermediate because by definition, an intermediate is a substance that is produced in one step and then used up in another step of the reaction mechanism. NO2 here matches this definition as it is produced in the first step and then used up in the second step. NO however is a catalyst bec...
- Sat Feb 13, 2016 3:30 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Phase Change and Enthalpy
- Replies: 1
- Views: 608
Re: Phase Change and Enthalpy
For the midterm, I did not add a phase change because the substance was not water and so you wouldn't be able to know the enthalpy of fusion since it was not given. It depends on how much temperature the change is say water going from -10 to 110 degrees Celsius, there are going to be phase changes f...
- Sun Feb 07, 2016 6:20 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: 2011 midterm Q6 B
- Replies: 1
- Views: 379
Re: 2011 midterm Q6 B
yes you multiply two to Rb because you have to balance the charges of the electrons from F2+2e--->2F, so that the electrons cancel out and you are left with a balanced equationl of F2+2Rb--->2F- + 2Rb+
- Sun Feb 07, 2016 6:10 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: logQ vs lnQ
- Replies: 1
- Views: 1984
Re: logQ vs lnQ
I have used both equations too and have received the same answers for both,which you should have but I don't you will be marked off if you used the logQ equation because essentially it should lead you to the answer unless on the midterm it says specifically to use the nernst equation in the ln form.
- Wed Feb 03, 2016 7:22 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.17 textbook problem
- Replies: 2
- Views: 710
Re: 14.17 textbook problem
I have a follow up question to this problem. So I noticed that in the solution's manual, there is no presence of Cl anywhere in the reaction. Is this because the Cl has completely dissociated due to the acidity of the reaction?
- Wed Feb 03, 2016 7:16 pm
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: Anode and Cathode
- Replies: 1
- Views: 646
Re: Anode and Cathode
it is important to determine the anode and cathode because when you are writing the galvanic cell, it is easiest to write the diagram flowing from anode to cathode as the book and the solution's manual does it, and theres not really a trick but when you write out the half reactions, the side with th...
- Wed Feb 03, 2016 7:11 pm
- Forum: Balancing Redox Reactions
- Topic: Standard reduction potentials
- Replies: 2
- Views: 589
Re: Standard reduction potentials
you don't multiply the value of the e cell because the E represents the cell's potential under standard conditions being at 25 C, 1 atm, and one mole and so even if you multiply and change the amount of moles, the value of the e cell would still wouldn't change and this isn't like hess's law where y...
- Wed Feb 03, 2016 7:03 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: homework 14.15
- Replies: 1
- Views: 419
homework 14.15
c. Cd(s)+2Ni(OH)3(s)--->Cd(OH)2(S)+2Ni(OH)2 I have a question with writing the galvanic cell diagram because I found the half reaction correctly just like the course reader but for the galvanic cell, the course reader had Koh(aq) on the anode side. I was wondering why Koh is needed and why is it the...
- Tue Jan 26, 2016 9:39 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Quiz 1 Prep
- Replies: 1
- Views: 2776
Quiz 1 Prep
For #6, What mass of propane, C3H8, must be burned to supply 2580 kJ of heat? The standard enthalpy of combustion of propane at 298K is -2220kJ/mol. I'm not sure how to approach this problem after writing out the combustion reaction.
- Tue Jan 26, 2016 8:47 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Determining Residual Entropy in Crystal Form
- Replies: 7
- Views: 2251
Re: Determining Residual Entropy in Crystal Form
I understand the calculations here, but just a general question to find the degeneracy. Do you just have to manually draw all the lewis structures for the molecule to find the degeneracy or is there another way?
- Tue Jan 12, 2016 10:52 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 8.31 heat released by Krypton gas
- Replies: 3
- Views: 1399
8.31 heat released by Krypton gas
Calculate the heat released by 5.025g of Kr at .4 atm as it cools from 97.6 degrees to 25 degrees at a)constant pressure, b)constant volume. Assume that krypton behaves as an ideal gas. For part a, why is the molar heat capacity 10.8J/mol*C and part b 12.5 J/mol*C? Does it have to do with ratio of s...
- Mon Jan 11, 2016 10:58 pm
- Forum: Phase Changes & Related Calculations
- Topic: Exothermic reaction
- Replies: 3
- Views: 583
Exothermic reaction
Why is it that when the temperature increases in an enthalpy problem, it is an exothermic reaction instead of endothermic?Wouldn't the increase from initial to final temperature make the system endothermic because heat is being absorbed by the system?
- Sat Jan 09, 2016 4:05 pm
- Forum: Phase Changes & Related Calculations
- Topic: Open, Closed, or Isolated Systems
- Replies: 6
- Views: 10607
Re: Open, Closed, or Isolated Systems
open system is when energy and matter of the system is exchanged with the surroundings. A closed system is when there is a fixed amount of matter in the system but still can exchange energy with its surrounding and an isolated system is when the system has no contact or exchange with its surrounding...
- Sat Dec 05, 2015 8:14 am
- Forum: Hybridization
- Topic: Final 2010 Q3A
- Replies: 1
- Views: 547
Re: Final 2010 Q3A
if you add up all the electrons from argon plus 4 from the 3d, you should have 22 electrons leaving you at Titanium. With a metal with a cation of 2+ that means that 2 electrons have previously been subtracted away from it leaving it with titanium with 2 less electrons. So to find the original state...
- Sat Nov 28, 2015 11:04 pm
- Forum: Ideal Gases
- Topic: Equilibruim
- Replies: 1
- Views: 756
Equilibruim
For homework question 11.67."The reaction 2HCL<->H2 + Cl2 has K=3.2 x 10^-34 at 298 K. The initial partial pressures are H2, 1 bar; HCl 2 bar and Cl2 at 3 bar at equilibrium there is 1 mol H2. What is the volume of the container?" Why is there a new initial state of pressure in this equati...
- Thu Nov 19, 2015 1:12 pm
- Forum: Naming
- Topic: Writing coordination compound formulas
- Replies: 2
- Views: 1293
Re: Writing coordination compound formulas
For pentaamminechloronickel (III) chloride, both of the formulas of [Ni(NH3)5Cl]Cl2 and [NiCl(NH3)5]Cl2 work and for the naming ligand, the letter a in ammine comes before the letter c in chloro so ammine gets named before chloro.
- Wed Nov 11, 2015 1:28 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Polydentate Using Lewis Structures
- Replies: 1
- Views: 569
Re: Polydentate Using Lewis Structures
I think its just helpful to know the Lewis structure because to figure out the binding of the ligand to the central atom, you need to know how many lone pairs and bond pairs it has to be available for binding. When a ligand is bidentate, it means that they have two donor atoms which allow them to bi...
- Fri Nov 06, 2015 10:32 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Octet Rule
- Replies: 3
- Views: 841
Re: Octet Rule
If it does not obey the octet rule, it can have more than 8 electrons on the central atom depending on the element because some transition metals can have up to 18 electrons because of the extra shells that can be filled in the d block so it just really depends on the atom itself.
- Wed Oct 28, 2015 10:58 pm
- Forum: Octet Exceptions
- Topic: Double bonds on group 17 atoms
- Replies: 2
- Views: 3134
Re: Double bonds on group 17 atoms
Yes, groups 17 atoms can form double and triple bonds, depending on the element it is bonding with. Iodine only needs one more valence electron to complete its octet, however, it has the ability to expand its octet so it is possible for Iodine to have more than a single bond. I believe all group 17 ...
- Wed Oct 28, 2015 10:52 pm
- Forum: Ionic & Covalent Bonds
- Topic: Covalent and Ionic Bonds
- Replies: 2
- Views: 755
Re: Covalent and Ionic Bonds
An ionic bond is usually between a metal and non-metal, where the negatively charged element with the higher ionization energy would attract the positively charged to form an octet in its valence electron. Covalent bonds are usually bonds between nonmetals in which the elements share valence electro...
- Wed Oct 28, 2015 6:17 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Bond angles of atoms with lone pair electrons
- Replies: 1
- Views: 760
Re: Bond angles of atoms with lone pair electrons
For bent, AX2E2, the bond angle is <109.5. The bond angles of seesaw would be less than 120 and 90 degrees, not 180 degrees and yes the lone pair does have a stronger repulsion than the bond pair, which is why the the angles are less than 120 and 90 degrees.
- Sat Oct 24, 2015 10:06 pm
- Forum: Ionic & Covalent Bonds
- Topic: Ground-State Electron Configurations of Ions 3.11
- Replies: 2
- Views: 2279
Re: Ground-State Electron Configurations of Ions 3.11
a) the electrons in the element Argon equals 18 and adding 6 more electrons from 3d^6 would make it 24 electrons, which would be chromium. However, the question is looking for a metal with 3+ ion which is means that 3 electrons were reduced from it already, so to find the element, you would add 3 mo...
- Thu Oct 15, 2015 11:18 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Fall 2014 Quiz 1 Preparation
- Replies: 3
- Views: 817
Re: Fall 2014 Quiz 1 Preparation
The answers in the workbook is telling you to use the Bohr equation which is En=-2.18*10^18 (z^2/n^2). The 2.18*10^18 is just a constant for the equation, the z is for the number of protons in the nucleus and n is the quantum level. Because the frequency was given, you can use it to find the change ...
- Thu Oct 08, 2015 9:54 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Rydberg's Equation
- Replies: 1
- Views: 453
Rydberg's Equation
The problem says, calculate the wavelength of light emitted when an electron in a hydrogen atom makes the transition from n=5 to n=3. How would you solve this equation? Using En= -hR/n^2 or v=R(1/n1 ^1) - (1/n2^2)?