Search found 17 matches
- Mon Mar 07, 2016 11:52 am
- Forum: *Haloalkanes
- Topic: Intro to Organic Chem (Self Test 2.2B)
- Replies: 1
- Views: 808
Re: Intro to Organic Chem (Self Test 2.2B)
As indicated in the name the F is attached to the second carbon atom in the parent chain. They count one methyl and ethyl group as part of the parent chain, hence why there is no dimethyl or diethyl. They start with 4-ethyl since the substituents must be alphabetized. Since they are treating the flu...
- Sun Feb 28, 2016 10:29 pm
- Forum: *Alkanes
- Topic: Quiz 3 Preparation
- Replies: 34
- Views: 11625
Re: Quiz 3 Preparation
Benzene has 6 hydrogens to go with the 6 carbons that give it its structure. A phenyl ring has 6 carbon atoms, but only 5 hydrogen atoms.
- Sun Feb 21, 2016 11:34 pm
- Forum: *Organic Reaction Mechanisms in General
- Topic: PseudoThermodynamics
- Replies: 2
- Views: 451
Re: PseudoThermodynamics
In Pseudod-thermodynamics, isn't delta G always positive and delta S always negative as well?
- Sun Feb 14, 2016 10:33 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Ways to Determine if a Cell Has Strong Voltage
- Replies: 1
- Views: 219
Ways to Determine if a Cell Has Strong Voltage
I believe in lecture Dr. Lavelle mentioned that there were two ways one could determine if a cell has strong voltage. I know he said one way was the inherent chemistry of the cell, but what was the other way that he mentioned in lecture? Or am I taking this completely out of context with what Dr. La...
- Sun Feb 14, 2016 10:12 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Calculating Cell Potential
- Replies: 3
- Views: 992
Re: Calculating Cell Potential
You must first determine which electrode is the cathode and which electrode is the anode. Since calculating cell potential involves subtracting the energy of the anode from the energy of the cathode, you can only flip the sign of the anode if the energy given is in negative voltage. That is why thos...
- Sun Feb 07, 2016 12:11 am
- Forum: Balancing Redox Reactions
- Topic: Homework Problem 14.5
- Replies: 1
- Views: 293
Homework Problem 14.5
For question 14.5a, O3 is given in aqueous form. However, in the solutions manual O3 is given as a gas. Why is this the case?
- Sun Jan 31, 2016 2:51 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Solutions Manual 9.67b
- Replies: 1
- Views: 233
Solutions Manual 9.67b
When I was doing the calculations for this problem, I noticed that when the change in entropy was calculated, it was rounded to -256.3 kJ/mol. However, when I was inputting the values I got for the change in entropy and the change in enthalpy into the Gibbs Free Energy Equation, I noticed that in th...
- Sat Jan 23, 2016 2:58 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Homework Problem 9.1
- Replies: 1
- Views: 331
Homework Problem 9.1
I was trying to solve this problem but did not know how to approach it. So I looked at the Solutions Manual, but I noticed that they had a negative sign in front of the qrev/T*time. Then, when they got the solution, the negative sign disappeared out of nowhere. Why is this the case for this problem?
- Sun Jan 17, 2016 9:38 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Error in Solutions Manual Calculation for 8.63c
- Replies: 1
- Views: 246
Error in Solutions Manual Calculation for 8.63c
There is an error in the calculations for the answer in the Solutions Manual for 8.63c. In the Solutions Manual, it gives -417.5 kJ/mol as the standard enthalpy of formation for K2S(aq) when in Appendix 2A it shows that the standard enthalpy of formation for K2S(aq) is -471.5 kJ/mol. Which is the ri...
- Sun Jan 10, 2016 8:20 pm
- Forum: Phase Changes & Related Calculations
- Topic: Question 8.9
- Replies: 3
- Views: 1743
Re: Question 8.9
We know to use these because we are given that the cylinder is filled with an ideal gas. This means that we must use gas constants that will convert our work from L.atm to Joules. The only gas constant that can cancel the L.atm out of the equation is 8.206*10^-2 L.atm.K^-1.mol^-1. However, this stil...
- Sun Nov 29, 2015 11:58 pm
- Forum: *Making Buffers & Calculating Buffer pH (Henderson-Hasselbalch Equation)
- Topic: Weak Acids
- Replies: 2
- Views: 422
Re: Weak Acids
This is a video on calculating the pH, pOH, and percentage deprotenation of weak acids and bases
- Fri Nov 27, 2015 11:25 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: HW Question 12.69 and 12.71
- Replies: 1
- Views: 452
HW Question 12.69 and 12.71
The constant Kw is used to determine Ka in 12.69a and Kb in 12.71. Why is this the case for these three problems but not for 12.69b? Does it have something to do with H2O being present in the acid itself in 12.69b [Al(H2O)6]3+?
- Sat Nov 21, 2015 11:59 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: how will equilibrium shift
- Replies: 3
- Views: 443
Re: how will equilibrium shift
Wouldn't it also depend on what particular volume is being increased? For example, if the H2O were a liquid in this case, wouldn't it have no effect on the equilibrium since liquids and solids are not taken into account when calculating equilibrium constant and concentrations?
- Fri Nov 13, 2015 8:04 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Naming the compounds
- Replies: 3
- Views: 540
Re: Naming the compounds
You would know that it is III by combining the charge you get with the charge of the ligands to see if it produces the charge of the complex.
- Fri Nov 13, 2015 8:02 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Naming the compounds
- Replies: 3
- Views: 540
Re: Naming the compounds
The Roman numeral III is the oxidation state of the coordination compound. This is obtained by combining the charge outside of the brackets and with the charges of the ligands.
- Fri Nov 06, 2015 11:49 pm
- Forum: Naming
- Topic: Anionic ligand?
- Replies: 1
- Views: 289
Re: Anionic ligand?
Based off the table in the course reader, an anionic ligand seems to have a negative charge. Any ligand that does not have a negative charge is a neutral ligand, like H2O and NH3.
- Sat Oct 03, 2015 11:34 pm
- Forum: SI Units, Unit Conversions
- Topic: Do we need to memorize unit conversions? [ENDORSED]
- Replies: 9
- Views: 2404
Re: Do we need to memorize unit conversions? [ENDORSED]
What other unit conversions must be memorized for the exams in Chem 14A?