Search found 15 matches
- Sat Mar 12, 2016 8:53 pm
- Forum: Phase Changes & Related Calculations
- Topic: Final Exam 2015 #1B
- Replies: 2
- Views: 333
Re: Final Exam 2015 #1B
Professor Lavelle said that was a typo its actually suppose to be 13400J
- Wed Mar 09, 2016 6:19 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Winter 2011 Final Question
- Replies: 2
- Views: 442
Re: Winter 2011 Final Question
To calculate residual entropy you use the formula
where W is the number of states a molecule can be in and still have the same amount of energy.
- Mon Mar 07, 2016 5:06 pm
- Forum: *Haloalkanes
- Topic: Priority in Numbering
- Replies: 3
- Views: 905
Re: Priority in Numbering
An example of functional groups having priority over halogens is in the course reader page 104
ClCH2CH2CH(OH)CH3 here the alcohol functional group gets numbered as 2 and the chlorine is 4 because functional groups get priority in numbering over substituents and double/triple bonds
ClCH2CH2CH(OH)CH3 here the alcohol functional group gets numbered as 2 and the chlorine is 4 because functional groups get priority in numbering over substituents and double/triple bonds
- Wed Mar 02, 2016 12:09 am
- Forum: *Alkenes
- Topic: # of double bonds in naming
- Replies: 2
- Views: 388
Re: # of double bonds in naming
From what I've seen from Lavelle's problems it would be better to put the greek prefix instead of a number. Im not sure if its necessarily more proper but it is less confusing because it could also be seen that you are writing the placement of the double bond ex: 1,3-butadiene could also be written ...
- Mon Feb 29, 2016 10:32 pm
- Forum: *Alkynes
- Topic: Alkynes for quiz 3?
- Replies: 3
- Views: 1034
Re: Alkynes for quiz 3?
No we don't have to know functional groups for this quiz
- Sun Feb 28, 2016 6:07 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 3 Functional Groups
- Replies: 1
- Views: 334
Re: Quiz 3 Functional Groups
The quiz covers material up to page 99 of the course reader, so no functional groups will not in this quiz
- Fri Feb 26, 2016 2:03 pm
- Forum: *Organic Reaction Mechanisms in General
- Topic: Determining shape of molecule
- Replies: 1
- Views: 332
Re: Determining shape of molecule
Dr Lavelle answered this question before. The molecule is tetrahedral because it is counting through electronic geometry. Electronic geometry counts for all regions of electron density which include lone pairs. Answer: It has a tetrahedral geometry if you count the lone pairs in the geometry, this i...
- Thu Feb 18, 2016 11:25 pm
- Forum: First Order Reactions
- Topic: Time units
- Replies: 1
- Views: 350
Re: Time units
They can be in any unit of time. In the textbook some problems had half lives in minutes and some in seconds, and in one problem in the workbook the half-life was in years
- Tue Feb 09, 2016 1:51 am
- Forum: Calculating Work of Expansion
- Topic: Midterm 2012 Q5, Change in Volume
- Replies: 3
- Views: 484
Re: Midterm 2012 Q5, Change in Volume
The internal energy in step 2 is equal to -50J because it is returning back to its original internal energy. For step 1, we figured out the internal energy had increased by 50J, therefore in order for it to go back to its original internal energy deltaU must decrease by 50J which is why delta u=-50J
- Tue Feb 02, 2016 2:47 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: equation for irreversible change in temperature
- Replies: 1
- Views: 330
equation for irreversible change in temperature
So I know you can use the equation delta s= nRln(v2/v1) for both a reversible and an irreversible change in volume my question is can you use the equation delta s= Cln(T2/T1) for both a reversible and and irreversible change in temperature or just reversible, and why?
- Mon Feb 01, 2016 2:34 am
- Forum: Calculating Work of Expansion
- Topic: Adiabatic Systems
- Replies: 2
- Views: 504
Re: Adiabatic Systems
An adiabatic process is one where there is no heat flowing in or out of a system, but temperature can still change. The first law of thermodynamics tells us in order for energy to be conserved, the change of internal energy of a system is dependent on heat and work (delta U=q+w). However since q=0 t...
- Sun Jan 31, 2016 9:53 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Which has more entropy?
- Replies: 4
- Views: 2352
Re: Which has more entropy?
yes more complex molecules have higher entropy because they have more bonds, which means they have more possible ways of rotating. Because they can rearrange themselves in various positions they can take up more space.
- Tue Jan 26, 2016 4:56 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Elements in their most stable form
- Replies: 2
- Views: 6866
Elements in their most stable form
When calculating the enthalpy of a reaction using standard enthalpy of formation, should we assume an element is in their most stable form, or what should we do if the element that is given is not in their most stable form? How do you convert it into its most stable form?
- Mon Jan 18, 2016 6:42 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Quiz 1 Chapters
- Replies: 3
- Views: 632
Re: Quiz 1 Chapters
Quiz one will be covering chapters 8 and 9 thermodynamics and thermochemistry, and I believe we have to know up to Friday of this week
- Tue Jan 12, 2016 10:16 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Fifth edition textbook problems
- Replies: 1
- Views: 1465
Re: Fifth edition textbook problems
Yes the fifth edition textbook chapters are behind by one, so chapter 8 in the sixth edition is chapter 7 in the fifth edition. As for the homework problems, they are almost always the same but sometimes the numbers are different and also the fifth edition doesn't have applied exercises like the six...