CHEMISTRY COMMUNITY

rivera_1J

Professor Lavelle said that was a typo its actually suppose to be 13400J

rivera_1J

To calculate residual entropy you use the formula $S=k_{b}*ln(W)$ where W is the number of states a molecule can be in and still have the same amount of energy.

rivera_1J

An example of functional groups having priority over halogens is in the course reader page 104
ClCH2CH2CH(OH)CH3 here the alcohol functional group gets numbered as 2 and the chlorine is 4 because functional groups get priority in numbering over substituents and double/triple bonds

: example in course reader

rivera_1J

From what I've seen from Lavelle's problems it would be better to put the greek prefix instead of a number. Im not sure if its necessarily more proper but it is less confusing because it could also be seen that you are writing the placement of the double bond ex: 1,3-butadiene could also be written ...

rivera_1J

No we don't have to know functional groups for this quiz

rivera_1J

The quiz covers material up to page 99 of the course reader, so no functional groups will not in this quiz

rivera_1J

Dr Lavelle answered this question before. The molecule is tetrahedral because it is counting through electronic geometry. Electronic geometry counts for all regions of electron density which include lone pairs. Answer: It has a tetrahedral geometry if you count the lone pairs in the geometry, this i...

rivera_1J

They can be in any unit of time. In the textbook some problems had half lives in minutes and some in seconds, and in one problem in the workbook the half-life was in years

rivera_1J

The internal energy in step 2 is equal to -50J because it is returning back to its original internal energy. For step 1, we figured out the internal energy had increased by 50J, therefore in order for it to go back to its original internal energy deltaU must decrease by 50J which is why delta u=-50J

rivera_1J

So I know you can use the equation delta s= nRln(v2/v1) for both a reversible and an irreversible change in volume my question is can you use the equation delta s= Cln(T2/T1) for both a reversible and and irreversible change in temperature or just reversible, and why?

rivera_1J

An adiabatic process is one where there is no heat flowing in or out of a system, but temperature can still change. The first law of thermodynamics tells us in order for energy to be conserved, the change of internal energy of a system is dependent on heat and work (delta U=q+w). However since q=0 t...

rivera_1J

yes more complex molecules have higher entropy because they have more bonds, which means they have more possible ways of rotating. Because they can rearrange themselves in various positions they can take up more space.

rivera_1J

When calculating the enthalpy of a reaction using standard enthalpy of formation, should we assume an element is in their most stable form, or what should we do if the element that is given is not in their most stable form? How do you convert it into its most stable form?

rivera_1J

Quiz one will be covering chapters 8 and 9 thermodynamics and thermochemistry, and I believe we have to know up to Friday of this week

rivera_1J

Yes the fifth edition textbook chapters are behind by one, so chapter 8 in the sixth edition is chapter 7 in the fifth edition. As for the homework problems, they are almost always the same but sometimes the numbers are different and also the fifth edition doesn't have applied exercises like the six...

CHEMISTRY COMMUNITY

Search found 15 matches

Re: Final Exam 2015 #1B

Re: Winter 2011 Final Question

Re: Priority in Numbering

Re: # of double bonds in naming

Re: Alkynes for quiz 3?

Re: Quiz 3 Functional Groups

Re: Determining shape of molecule

Re: Time units

Re: Midterm 2012 Q5, Change in Volume

equation for irreversible change in temperature

Re: Adiabatic Systems

Re: Which has more entropy?

Elements in their most stable form

Re: Quiz 1 Chapters

Re: Fifth edition textbook problems