Search found 12 matches

by Jessica Quach 1K
Sat Mar 12, 2016 12:37 pm
Forum: *Alkanes and Substituted Alkanes (Staggered, Eclipsed, Gauche, Anti, Newman Projections)
Topic: Final Question
Replies: 2
Views: 387

Final Question

Are we expected to memorize the energies for the different conformations (for ex. gauche= .9kcal/mol) and also the c-c-c- angles cyclopropane, cyclobutane, and cyclohexane?
by Jessica Quach 1K
Sat Mar 12, 2016 12:29 pm
Forum: *Alkanes and Substituted Alkanes (Staggered, Eclipsed, Gauche, Anti, Newman Projections)
Topic: Ch3 in Newman projection
Replies: 1
Views: 332

Ch3 in Newman projection

When looking down a bond such as 2-3 bond for butane, does the CH3 in the front and back refer to carbon 1 and carbon 4?
by Jessica Quach 1K
Tue Mar 08, 2016 7:37 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7951
Views: 1213856

Re: Chemistry Jokes

What's the name of an non hydrogen atom orbital that has a talk show?
Ellen Degeneracy!
by Jessica Quach 1K
Thu Feb 25, 2016 1:16 pm
Forum: *Alkanes
Topic: Writing Out Condensed Structural Formulas
Replies: 1
Views: 204

Writing Out Condensed Structural Formulas

When writing condensed structural formulas, does it matter the order of the placement of the constituent or is it conventionally put at the end? For example in Self Test 1.1 A, the condensed version is written as (CH3)2CHCH2CH3
by Jessica Quach 1K
Mon Feb 15, 2016 2:29 pm
Forum: General Rate Laws
Topic: Using M instead of molL-
Replies: 1
Views: 376

Using M instead of molL-

In the textbook solutions, all answers are in molL-. Is it fine if we just use M?
by Jessica Quach 1K
Mon Feb 15, 2016 2:11 pm
Forum: General Rate Laws
Topic: Including k in rate laws
Replies: 4
Views: 587

Including k in rate laws

When asked to write down the rate law of a reaction, do we need to solve for k? Or are we just expected to write "k" for the rate law?
by Jessica Quach 1K
Tue Feb 09, 2016 8:30 pm
Forum: Concepts & Calculations Using First Law of Thermodynamics
Topic: W=0 when number of gas molecules constant
Replies: 1
Views: 305

W=0 when number of gas molecules constant

In Midterm 2015 Q2&3 Part A the answers state that w=0 because the product and reactant both have 2 moles gas molecules (V=0). So for any circumstances where P=0, would you just have to compare the number of moles of gas molecules on each side of the equation to know that volume is constant, ign...
by Jessica Quach 1K
Mon Feb 08, 2016 6:09 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Midterm 2011 Q5
Replies: 1
Views: 238

Midterm 2011 Q5

Why in Part A is the answer in JK-1mol-1 but the answer in Part b is in kJ (lacking the "mol-1"). I would understand why the mol-1 would be left out because both questions are asking specifically for one mol. So why is there still the "mol-1" for the answer in part A?
by Jessica Quach 1K
Mon Feb 08, 2016 3:46 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: 2011 Midterm Q1B
Replies: 1
Views: 270

2011 Midterm Q1B

Can someone explain conceptually why the the decrease in internal energy results in a decrease in temperature and pressure?
by Jessica Quach 1K
Tue Feb 02, 2016 9:05 pm
Forum: Balancing Redox Reactions
Topic: Balancing Basic Redox Reactions (HW 14.5 A)
Replies: 2
Views: 434

Balancing Basic Redox Reactions (HW 14.5 A)

For this problem, how do you know to split up the redox reactions into O3->02 and Br->BrO3, especially because in 14.3 D you put the reactant(Cl2) in both half reactions?
by Jessica Quach 1K
Sat Jan 30, 2016 9:21 pm
Forum: Balancing Redox Reactions
Topic: oxidation and reduction
Replies: 2
Views: 316

Re: oxidation and reduction

What is being oxidized (losing electrons) is the reducing agent. What is being reduced (gaining e-1) is the oxidizing agent.
by Jessica Quach 1K
Mon Jan 18, 2016 4:03 pm
Forum: Thermodynamic Systems (Open, Closed, Isolated)
Topic: Heat Release Quantities
Replies: 1
Views: 296

Re: Heat Release Quantities

Since enthalpy density is defined as enthalpy released per liter, the value would be positive since heat is being released in this case. If it were defined as enthalpy absorbed in the reaction per liter, the sign would be negative, as you calculated.

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