Search found 31 matches
- Sun Mar 13, 2016 9:12 pm
- Forum: *Alkenes
- Topic: Two different geometric isomers
- Replies: 1
- Views: 349
Re: Two different geometric isomers
Yes it is! If you have to double bonds within the carbon chain! You would need to identify cis and trans for both double bonds!
- Fri Mar 11, 2016 1:58 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Why is heat of vaporization not considered in this problem?
- Replies: 2
- Views: 321
Re: Why is heat of vaporization not considered in this probl
Yes! Since it is required to boil it is just the amount of heat needed to get to boiling point. Vaporization would occur at anything above 100 degrees celsius the difference comes from the wording, if it had said vaporize we would use the enthalpy of vaporization but since it says to boil we can omi...
- Sun Mar 06, 2016 4:22 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Determing salt bridge
- Replies: 4
- Views: 613
Re: Determing salt bridge
Yes you can use copper, that is a common one to use!
- Sun Feb 28, 2016 5:02 pm
- Forum: *Cycloalkanes
- Topic: naming cycloalkanes
- Replies: 1
- Views: 425
naming cycloalkanes
In our homework page 40 problem number 16, I am very confused as to how to name cycloalkanes. What gets priority when we are numbering? Also do we have to name the common names for the quiz or will the IUPAC names be sufficient?
- Sun Feb 21, 2016 3:00 pm
- Forum: *Nucleophiles
- Topic: Stability of nucleophiles
- Replies: 1
- Views: 322
Re: Stability of nucleophiles
Not necessarily, Br2 is the most stable form of Br as that is the one found in nature Br- is the ion and because of this it is unstable and acts as a nucleophile binding to electrophiles.
- Tue Feb 16, 2016 3:12 pm
- Forum: Second Order Reactions
- Topic: 2016 Winter Workbook pg. 36 #10
- Replies: 1
- Views: 379
Re: 2016 Winter Workbook pg. 36 #10
Because it is second order so if you use the equation 1/[a]=kt+1/[a0] you will see that 1-1/.5 is not the same as 1/.5-1/.25.
- Tue Feb 09, 2016 11:51 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: HW 8.67 b
- Replies: 1
- Views: 283
Re: HW 8.67 b
They state the standard enthalpy of sublimation for carbon is 717 kj/mol
- Tue Feb 09, 2016 11:49 pm
- Forum: Calculating Work of Expansion
- Topic: Change in moles
- Replies: 1
- Views: 384
Re: Change in moles
What they mean is there is one mole of each reactant meaning there are two moles of reactant gases and one mole of each product meaning two total moles of gas on the product side. Since the delta n is zero no work is done.
- Mon Feb 08, 2016 10:10 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Midterm 2012 2A
- Replies: 1
- Views: 228
Re: Midterm 2012 2A
Nope! It is correct! Hmm It could be that maybe you are subtracting? Make sure you add all the values together and you should get the correct answer!
- Mon Feb 08, 2016 6:58 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: How to know what units for pressure to use?
- Replies: 2
- Views: 404
Re: How to know what units for pressure to use?
We do not, we can use any unit for pressure I would use bar or atm but I do not think it matters since units for pressure cancel out anyways.
- Mon Feb 08, 2016 3:22 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Electrolysis
- Replies: 1
- Views: 385
Re: Electrolysis
Know the concept but also know that n=(I*t)/F
- Mon Feb 08, 2016 12:49 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Change in Free Energy is 0
- Replies: 1
- Views: 282
Re: Change in Free Energy is 0
By equilibrium we mean concentration equilibrium. So the concentration of reactants and products is the same making the equilibrium constant=1 and the Gibbs free energy to equal zero.
- Sun Feb 07, 2016 5:36 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Concentration Cells
- Replies: 1
- Views: 309
Re: Concentration Cells
Since the product is the one with the lower concentration the equation would be Cr3+(higher concentration)-->Cr3+ lower concentration. According to this equation the higher concentration is undergoing reduction and the lower concentration is undergoing oxidation. Oxidation occurs at the anode and re...
- Sun Feb 07, 2016 5:32 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: Max Potential
- Replies: 1
- Views: 323
Re: Max Potential
Max potential means the largest potential difference that the galvanic cell can have. The max potential will in turn do the most work and have the largest electromotive force.
- Sun Feb 07, 2016 5:31 pm
- Forum: Balancing Redox Reactions
- Topic: Dismissing parts of a compound
- Replies: 1
- Views: 277
Re: Dismissing parts of a compound
We the part of the compound that participates in the redox reaction for example in the case of KMno4- K+ is not being reduced or oxidized it remains as K+ through the entirety of the reaction. It is a spectator ion. Whatever is being oxidized or reduced is included in the redox reaction which is why...
- Sun Feb 07, 2016 5:29 pm
- Forum: Balancing Redox Reactions
- Topic: Determining Anode and Cathode from E values
- Replies: 1
- Views: 488
Re: Determining Anode and Cathode from E values
So since E(not) is equal to E(cathode)-E(anode) you can determine which one is the cathode or anode by calculating which combination of the two gives a positive value for E not. Hope this helped!
- Sun Feb 07, 2016 5:21 pm
- Forum: Phase Changes & Related Calculations
- Topic: SIG FIG CONFUSION ON PRACTICE MIDTERMS
- Replies: 1
- Views: 285
SIG FIG CONFUSION ON PRACTICE MIDTERMS
In many of the problems in the practice midterm sig figs are used every step of the calculation. I thought that for sig figs we round at the end according to the appropriate number of sig figs. If we do not round every step of the way the end answer is wrong. For example in the 2012 practice midterm...
- Thu Feb 04, 2016 9:51 am
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 14.93A
- Replies: 2
- Views: 422
Re: 14.93A
Okay thanks
- Thu Feb 04, 2016 9:51 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Clarification of Equilibrium
- Replies: 2
- Views: 306
Re: Clarification of Equilibrium
So since k is the equilibrium constant why isn't dG 0 when we have reached equilibrium concentrations?
- Tue Feb 02, 2016 11:18 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Clarification of Equilibrium
- Replies: 2
- Views: 306
Clarification of Equilibrium
I am having a hard time understanding the relationship between G, E, and k. I understand the k is the equilibrium constant and it can have any value. So why is it that when a reaction is at equilibrium G and E are both zero. According to the equation for k, logk=nE(not)/.0592 but technically since k...
- Tue Feb 02, 2016 11:13 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: 14.93A
- Replies: 2
- Views: 422
14.93A
For part a to this question it asks whether 1 M Cr(Cl)3 or .0010 M Cr(Cl)3 would undergo spontaneous reduction, how do we know which one would undergo spontaneous reduction?
- Mon Feb 01, 2016 9:34 pm
- Forum: Balancing Redox Reactions
- Topic: 14.5a
- Replies: 1
- Views: 323
14.5a
I am confused as to how to write the balanced half reaction for the reduction of O3 to O2.
- Sun Jan 31, 2016 1:13 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: The laws of thermodynamics
- Replies: 2
- Views: 564
Re: The laws of thermodynamics
Yes! The first law states that energy cannot be created or destroyed. The second law sates that the entropy of an isolated system not in thermal equilibrium will always increase. The third law states that the entropy of a system approaches a constant value as the temperature approaches absolute zero...
- Sun Jan 31, 2016 1:10 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Video Competition
- Replies: 66
- Views: 25287
Re: Video Competition
When is the video due by?
- Sat Jan 23, 2016 7:23 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Winter 2015 Quiz 1 question 3
- Replies: 1
- Views: 299
Winter 2015 Quiz 1 question 3
In this problem the system is isothermal which means that the temperature is constant so since q=ncdt this means that q=0 and dU=dw but is the answers it says that du+0 and q=-w. Why is that?
- Sat Jan 23, 2016 4:48 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Irreversible isothermal systems
- Replies: 1
- Views: 198
Irreversible isothermal systems
If a system is irreversible and isothermal how do we manipulate Pv=nrt to account for the constant pressure and the irreversibility of the system?
- Fri Jan 22, 2016 10:37 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Quiz 1 Preparation 2014
- Replies: 1
- Views: 263
Quiz 1 Preparation 2014
For number 11 I understand how the work was calculated but I do not understand why the number is positive. Since the system is expanding it is doing work on the surroundings so work should be negative but in the solutions it is positive. Can somebody please explain this?
- Sun Jan 17, 2016 5:02 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Microstates Clarification
- Replies: 1
- Views: 221
Re: Microstates Clarification
No it will not be the same as the degeneracy in the example they must be equal in energy to have that type of degeneracy.
- Sat Jan 09, 2016 6:35 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: 8.53
- Replies: 1
- Views: 246
8.53
For question 8.53 the temperature change occurs due to a reaction with 1.40 grams of carbon monoxide. How do we calculate the energy change for one mole of carbon monoxide?
- Sat Jan 09, 2016 3:35 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Standard Enthalpies of Formation
- Replies: 1
- Views: 225
Standard Enthalpies of Formation
When we are writing out our equation with elements in their standard form, should we just put the state of the standard form or the name of the actual standard form? For example, the standard form of C is graphite so when I am writing my equation should I write C(graphite) or C(s)?
- Sat Jan 09, 2016 3:30 pm
- Forum: Calculating Work of Expansion
- Topic: Identifying Positive Potential Energy
- Replies: 1
- Views: 367
Re: Identifying Positive Potential Energy
The work is being done by pushing the pump and internal energy is equal to heat plus work so if the work being done is positive the internal energy will also be positive! hope this helped!