## Search found 11 matches

Tue Mar 01, 2016 5:52 pm
Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
Topic: Drawing Constitutional and Geometric Isomers
Replies: 1
Views: 437

### Drawing Constitutional and Geometric Isomers

How can you determine whether or not you've drawn all the possible isomers for the molecule?
Sun Feb 28, 2016 4:05 pm
Forum: *Alkanes
Topic: Common Names
Replies: 4
Views: 704

### Common Names

Can someone explain to me when the different prefixes are used when writing the common name? I'm a bit confused on how to determine whether it's iso-, neo-, tert-, and sec-. Thank you!
Sat Feb 27, 2016 7:30 pm
Forum: *Alkanes
Replies: 2
Views: 468

I know that a single headed arrow means one electron is being transferred while a double headed arrow means two electrons. What are examples of when a single headed arrow is used? Is it a less common occurrence?
Sat Dec 05, 2015 10:24 am
Forum: Properties & Structures of Inorganic & Organic Acids
Topic: Strength of acids
Replies: 6
Views: 841

### Strength of acids

If we're given a set of Lewis structures, how do I determine the order of increasing acidity strength by looking at the structures?
Sat Nov 21, 2015 11:54 pm
Forum: Polyprotic Acids & Bases
Topic: Polyprotic Acids & Bases
Replies: 1
Views: 389

### Polyprotic Acids & Bases

How does one determine if an acid or base is polyprotic? Is there something in the molecular formula or structure that indicates that?
Fri Nov 13, 2015 11:05 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: 2014 Quiz 3 Prep #9
Replies: 1
Views: 226

### 2014 Quiz 3 Prep #9

For the following reaction at 523 K, with K=0.0736, the equilibrium concentrations are:
[PCl5]=0.110 M, [PCl3]=[Cl2]=0.0900 M. If suddenly 0.100 M PCl5(g), PCl3(g), Cl2(g) were added, what would happen?
Can someone explain why it is that more PCl5 is formed?
Thu Nov 05, 2015 3:27 pm
Forum: Naming
Topic: Naming Complex Ions with Charges
Replies: 1
Views: 607

### Naming Complex Ions with Charges

For naming complex ions, I understand that we have to add the suffix -ate to the transition metal if it has an overall negative charge. Is there a suffix we have to add for positive charges? Or will adding "ion" at the end indicate that it has a positive charge?
Fri Oct 30, 2015 3:39 pm
Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
Topic: MO Diagrams & Paramagnetism/Diamagnetism
Replies: 1
Views: 387

### MO Diagrams & Paramagnetism/Diamagnetism

When drawing M.O. diagrams, what determines whether or not it'll be symmetrical? I remember going over an example in class with CO but I don't remember why the 2s and 2p subshells for Oxygen are drawn lower. Also, is there a way to figure out whether an atom is paramagnetic or diamagnetic without dr...
Fri Oct 23, 2015 6:59 pm
Forum: Hybridization
Topic: Hybridization
Replies: 1
Views: 314

### Hybridization

After reviewing today's lecture, I am still a bit confused on hybridization. How would I figure out which sub-shells or orbitals are involved? Do I refer to the electron configuration of the element? Is there a "pattern" of some sort that you can imply from the periodic table?
Sun Oct 11, 2015 7:31 pm
Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
Topic: Hydrogen Atom / Quantum Level
Replies: 1
Views: 357

### Hydrogen Atom / Quantum Level

"An excited hydrogen atom emits light with the frequency of 1.14 x 10^14 Hz to reach the energy level for which n=4. In what principal quantum level did the electron begin?"

How do I go about solving this problem? I am kind of confused on which equation(s) to use.
Sun Oct 11, 2015 12:21 am
Forum: Empirical & Molecular Formulas
Topic: Quiz #1 Practice Question
Replies: 1
Views: 502

### Re: Quiz #1 Practice Question

You can convert from grams to moles by multiplying 7.45 g H2O * (1 mol H2O / Molar mass of H2O) and then convert that into molecules by multiplying it with Avogadro's number. Or you can just convert from grams to molecules by solving 7.45 g H2O * (Avogadro's number / Molar mass H2O) since 1 mol = 6....