Search found 11 matches
- Sat Mar 12, 2016 3:15 pm
- Forum: *Cyclohexanes (Chair, Boat, Geometric Isomers)
- Topic: Winter 2013 Q. 8C
- Replies: 1
- Views: 536
Re: Winter 2013 Q. 8C
In a Newman projection, the circle represents the carbon in the back. The carbon in the front is represented by the three lines that converge inside the circle. Whatever is connected to the carbons in the Newman projection is labeled at the ends of the lines. In 8C, we see that there are two Newman ...
- Mon Feb 29, 2016 9:20 am
- Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
- Topic: Introduction to Organic Chemistry Question 1.23
- Replies: 1
- Views: 475
Re: Introduction to Organic Chemistry Question 1.23
Since C5H10 is an alkene, it can have cis and trans structural isomers. The second one is trans-2-pentene while the third one is cis-2-pentene. "Cis" means that the two adjacent carbons to the double bond are on the same side. How I remember it is that they are "sis"ters so they ...
- Sat Feb 27, 2016 3:02 pm
- Forum: *Cycloalkanes
- Topic: Quiz 3 Preparation 1, Number 5
- Replies: 3
- Views: 865
Re: Quiz 3 Preparation 1, Number 5
the bromine and iodine both serve as alkyl halide functional groups so doesn't it still go by alphabetical order?
- Fri Feb 26, 2016 5:29 pm
- Forum: *Nucleophiles
- Topic: Nucleophilic strength
- Replies: 2
- Views: 860
Re: Nucleophilic strength
Nucleophilic strength is determined by four things: 1. Charge 2. Electronegativity 3. Solvent 4. Steric hinderance Charge: negatively charged particles are always stronger nucleophiles than their non-charged counterparts. ex: OH- > H2O Electronegativity: The more electronegative a particle is, the l...
- Sun Feb 14, 2016 3:22 pm
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: Catalyst and Activation Energy
- Replies: 1
- Views: 430
Re: Catalyst and Activation Energy
Catalysts lower activation energy by providing another pathway to complete the chemical reaction. Think of it as taking a shortcut. A catalysts combines with the reactants to form an unstable intermediate compound, which then becomes the product. In forming the product, the reactants break off from ...
- Sat Feb 06, 2016 5:00 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.11
- Replies: 1
- Views: 543
Re: 14.11
(b) C(gr)|H2(g)|H+(aq)||Cl-(aq)|Cl2(g)| Pt(s) You're asked to write the half-reactions. Cl-(aq)|Cl2(g)| Pt(s) the reduction half reaction is always written on the right side of the two lines || as denoted by the cell diagram in the book, Cl- -> Cl2 +2e is an oxidization reaction. It's a mistake in t...
- Mon Feb 01, 2016 3:01 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Usage of Platinum
- Replies: 1
- Views: 445
Re: Usage of Platinum
Platinum is on both sides of the reaction because neither side has a solid to serve as an electrode to move electrons through the circuit. Because there are no solids, an inert material such as platinum (or graphite) serves as a conduit to allow the electrons through the circuit. Whenever you see a ...
- Sun Jan 31, 2016 8:19 pm
- Forum: Balancing Redox Reactions
- Topic: Water in Half-Reactions
- Replies: 1
- Views: 465
Re: Water in Half-Reactions
You use H2O's when you need to balance out O's on one side.
Example:
O3 --> O2
to balance the O's, you add H2O's to the product side.
O3 --> O2 + H2O
Then to counteract the H's, you add H's to the reactant side.
H+O3 --> O2 + H2O
Then continue balancing
Example:
O3 --> O2
to balance the O's, you add H2O's to the product side.
O3 --> O2 + H2O
Then to counteract the H's, you add H's to the reactant side.
H+O3 --> O2 + H2O
Then continue balancing
- Wed Jan 20, 2016 7:57 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: HW 9.71
- Replies: 2
- Views: 610
HW 9.71
9.71 (a) Which substance would you expect to have the highest molar entropy in the liquid phase, benzene, methanol (CH3OH), or 1-propanol (CH3CH2CH2OH)? (b) Would your answer be different if these substances were in the gas phase? I don't understand why Benzene has higher molar entropy. Since it is ...
- Sun Jan 10, 2016 3:58 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: HW Question #8.111
- Replies: 1
- Views: 3045
Re: HW Question #8.111
A) You want to cancel out the SO2, so you want the coefficients of SO2 to be the same in both the reaction equations they give you. To do this, multiply the entire bottom equation by two. That way, both equations will have two SO2's and they can cancel out. 2H2S+3O2 -> 2SO2 + 2H2O 4H2S+2SO2 -> 6S +...
- Fri Nov 27, 2015 9:51 am
- Forum: Hybridization
- Topic: How to Determine the Hybridization of orbitals (2 min video)
- Replies: 1
- Views: 521
How to Determine the Hybridization of orbitals (2 min video)
I don't explain what hybridization is, or why it occurs, so make sure to pay attention in class! However, I have uploaded a very easily understood two-minute video that will help with the quizzes. Best of luck in chem!