## Search found 12 matches

Sun Jan 17, 2016 12:37 pm
Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
Topic: Heat Capacity of a Monoatomic Ideal Gas (9.13)
Replies: 7
Views: 1058

### Re: Heat Capacity of a Monoatomic Ideal Gas (9.13)

when applying these formulas, the R is always 8.314 correct?
Fri Jan 08, 2016 12:27 pm
Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
Topic: Heat Capacity
Replies: 2
Views: 381

### Heat Capacity

Is the specific heat capacity the same thing as the (heat capacity of a substance)/(the amount of grams of that substance)? Also, why were we given the definition of the heat capacity if we cannot even use it (since it is an extensive property)?
Fri Dec 04, 2015 6:37 pm
Forum: *Titrations & Titration Calculations
Topic: 2010 Final Q7 Henderson-Hasselbalch Equation
Replies: 4
Views: 678

### Re: 2010 Final Q7 Henderson-Hasselbalch Equation

If we do decide to use the Henderson-Hasselbalch equation, do we have to specifically write "assume x is negligible" in order to receive full credit?
Tue Nov 24, 2015 4:15 pm
Forum: Amphoteric Compounds
Topic: Amphoteric Compounds
Replies: 2
Views: 635

### Re: Amphoteric Compounds

Hi! I believe that the compound BaO is basic because typically metals form basic oxides. The compounds As2O3 and Bi2O3 are amphoteric oxides because the elements in and around the diagonal line of metalloids typically form amphoteric oxides.
Mon Nov 16, 2015 12:48 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Equilibrium Terminology
Replies: 1
Views: 317

### Equilibrium Terminology

Hi, what is the difference between equilibrium that is "shifted to the left" verses a reaction that is said to "lie to the left" in terms of the equilibrium constant K. I understand that is K is small, then the equilibrium favors the formation of reactants, but how is that knowle...
Fri Nov 13, 2015 9:12 am
Forum: Naming
Topic: Adding -ate at the end of names
Replies: 2
Views: 418

### Re: Adding -ate at the end of names

So just for clarification, if the complex is neutral, and the transition metal is iron, the correct terminology would be to use iron instead of ferrate.
Fri Nov 06, 2015 11:45 am
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Equilibrium constants
Replies: 4
Views: 644

### Equilibrium constants

Just a conceptual question, why are solids not included when calculating an equilibrium constant?
Thu Oct 29, 2015 10:18 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Lone Pair Repulsion in Bent Molecules
Replies: 5
Views: 1214

### Re: Lone Pair Repulsion in Bent Molecules

A continuation of the previous question, if a molecule has the formula AX2E3 will the 3 lone pairs cancel one another out and result in a nonpolar, linear molecule? Or will this molecule still be bent?
Thu Oct 22, 2015 7:30 pm
Forum: Determining Molecular Shape (VSEPR)
Topic: Dissociation Energies
Replies: 2
Views: 599

### Dissociation Energies

Hi, I was wondering why dissociation energies (the energy required to break a bond) are always positive?
Thu Oct 15, 2015 12:09 am
Forum: Properties of Light
Topic: How to increase the intensity of the photon
Replies: 6
Views: 1225

### Re: How to increase the intensity of the photon

After re-watching the lecture video on the photoelectric effect, the answer became somewhat more clear. The intensity of the light only affects the number of electrons ejected and the speed at which they are ejected only after certain threshold energy (determined by the frequency of the incoming lig...
Thu Oct 08, 2015 11:30 pm
Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
Topic: Rydberg Equation
Replies: 2
Views: 473

### Re: Rydberg Equation

I have the exact same question! However, I chose to solve the problem using the Rydberg formula from the textbook, which is Frequency= R{(1/n1^2)-(1/n2^2)} which allows you to solve for the frequency. Then, I just solved for wavelength using the formula wavelength= c/frequency. However, Professor La...
Thu Oct 01, 2015 4:34 pm
Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
Topic: Calculating the energy of a Photon
Replies: 1
Views: 461

### Calculating the energy of a Photon

In homework problem 1.33 part (c) why is it necessary to add the answer from part (b) (which is 1.66 x 10^-17J) to the kinetic energy of the electron in order to calculate the energy of the photon?