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Nitin Joseph

Will we be tested on substituent position in terms of ortho, meta and para positions in cycloalkenes, specifially benzene?

Nitin Joseph

If the lowest number of sig figs in the question is 1, but a value (like standard electrode potential) on the sheet with values has 2 sig figs, should the answer contain 1 sig fig or two?

Nitin Joseph

When A is kept constant and B is doubled (increased from 0.1 to 0.2), the rate is also doubled. Hence, the factor of increase of B is equal to the factor of increase of the rate. In other words, in both trial 1 and trial 3, Initial rate/[B]=50. When a reaction is first order, when a reactant is incr...

Nitin Joseph

This is because an Aldehyde functional group looks like this: CHO, where carbon is double bonded to oxygen, and single bonded to hydrogen. This carbon is also connected to another carbon atom, like this: C-C-C-CHO. So it's got all 4 valences filled (1 by carbon, 1 by hydrogen, 2 by oxygen), so it ha...

Nitin Joseph

Units for k work like this: M^{(1-n)}s^{-1} or (L\cdot mole^{-1})^{(1-n)}s^{-1} Where n is the order of the reaction. In your question, M^{-4} implies that (1-n)=-4. Hence n=5, or the reaction is fifth order. Similarly for (1-n)=-3, the reaction is 4th order. Hope this helps :)

Nitin Joseph

The question states: "the partial pressure for each of the reactants is equal to half that of the product."

Hence they've assumed that P(PCl3) and P(Cl2) are equal to x, and P(PCl5) is equal to 2x, since it is twice the value of that of the reactants.

Nitin Joseph

H2O -> O2 + H+ + e- (oxidation)

H2O + e- -> H2 + OH- (reduction)

Nitin Joseph

The values of the oxidation state and oxidation number of an element are commonly equal, but there is a slight difference between the terms. Oxidation state refers to the degree of oxidation of an element in a molecule, where the sum of all oxidation states of elements in that molecule or ion gives ...

Nitin Joseph

q=-w for an isothermal process. This is because \Delta U=-3/2k\Delta T For an isothermal process, ∆T=0, hence ∆U=0 We also know that ∆U= q+w Since ∆U=0, q+w=0 Hence q=-w for an isothermal process. We know ∆U= q+w For a system where the volume is constant, the gas is not doing any work of expansion, ...

Nitin Joseph

Open system: A glass of water
Closed system: A sealed soda bottle
Isolated system: A well made thermos

Note: No system (barring the universe itself - even this is debated) is truly isolated. The best thermos in the world will still leak some energy.

Nitin Joseph

Yes. Since gases have a tendency to expand (increase in volume) when heated, if you don't allow them to expand (by keeping the volume constant), the pressure will increase. For example, this is why balloons explode when exposed to a flame, because the volume of the balloon is kept constant, but the ...

Nitin Joseph

Coordination number and shape would not change between mono dentate and bidentate ligands (of the the same coordination number), but the number of ligands in the case of mono dentate ligands will be higher (4) than bidentate ligands (2)

Nitin Joseph

Another way to explain this is through hybridization. There are concepts known as Crystal Field Theory and Valence Bond Theory which we have not covered, but the basic explanation is this: Since the coordination number on the central metal atom is 6, this means it is surrounded by 6 coordinate bonds...

Nitin Joseph

The only commonly encountered coordination numbers for complex compounds are 4 and 6.
When coordination number is 4, the shape is tetrahedral
When coordination number is 6, the shape is octahedral.

Nitin Joseph

Here are the answers to those questions, hopefully it will help you understand the concept.
a) 4
b) 2
c) 6
d) 6

Nitin Joseph

Chlorine can never form a double covalent bond with any element, as it would then have 10 electrons in its orbits, and it cannot hold an expanded octet. Chlorine always forms a single bond. Now for the oxygens, one would be connected to the Sulfur with a double bond (FC = 0), and the other with a si...

Nitin Joseph

The electron config of Nickel would not be [Ar]3d^10 It's [Ar]3d^84s^2 Only one electron can be moved from the s orbital to the d orbital when fulfilling the half-filled subtle rule. This is why the electron config of Copper is [Ar]3d^{10}4s^1 and not [Ar]3d^94s^2 Similarly, the configuration of Van...

Nitin Joseph

T shaped molecules are always polar.
In both cases (octahedral and trigonal bipyramidal), the bond angles will be slightly less than 90 and 180 due to lone pair-bond pair repulsion.

Nitin Joseph

Ferrate is used when the complex is an anion, iron is used when the complex is a cation.

Nitin Joseph

Hydrogen reacts differently with metals, metalloids and non-metals. With metalloids and non-metals, Hydrogen is usually more electropositive (likes to donate electrons more) than the other element, leading to an oxidation state of +1, as is reflected in H_{2}Te However, with metals, Hydrogen is usua...

Nitin Joseph

A dark wedge indicates that that atom is closer to you (the observer) in terms of 3D structure. A dashed wedge is the opposite - it is further away from the observer than the central atom. Their placement is important as it indicates the 3D orientation of a molecule, without which we only have a rou...

CHEMISTRY COMMUNITY

Search found 21 matches

Ortho, meta, para

Sig Fig question

Re: Winter 2008 Final

Re: aldehyde must end

Re: Units for Second Order

Re: Midterm 2011 Q4

Re: Half equations

Re: Oxidation state

Re: Relating q, w, U, and H

Re: Examples of different thermodynamic systems

Re: Specific Heat Under Const. Press. vs. Const. Vol.

Re: Shape when dealing with polydentates

Re: Shapes

Re: Naming shape of compounds

Re: 17.37 Determine coordination number

Re: Determining which element to give a formal charge

Re: When to move electrons from the s orbital to d orbital

Re: T-Shaped Molecule and its Dipole Moments

Re: NAMING

Re: HW 3.25

Re: Wedges and Dashes