Search found 17 matches
- Thu Mar 10, 2016 10:05 pm
- Forum: *Aldehydes
- Topic: Double Bond/Aldehyde
- Replies: 1
- Views: 1377
Double Bond/Aldehyde
if there is a double bond in a structure that also has an aldehyde, does the double bond get priority? Does this mean that you would start numbering at the double bond and not the aldehyde?
- Sat Mar 05, 2016 11:37 am
- Forum: Phase Changes & Related Calculations
- Topic: 2006 Practice Final Question 1
- Replies: 1
- Views: 474
2006 Practice Final Question 1
In question 1 stating: During exercise, fats react with water to produce fatty acids. The fatty acids are then converted to water and carbon dioxide, a reaction that releases energy. The body uses this energy to perform activities. A typical fatty acid, lauric acid (CH3(CH2)10COOH), has the same amo...
- Mon Feb 29, 2016 8:33 pm
- Forum: *Alkanes
- Topic: Quiz 3 Prep # 7
- Replies: 1
- Views: 486
Quiz 3 Prep # 7
For number 7 on the last quiz prep, it asks for the product of the reaction of 2-butene with Cl2 and the answer that i got was CH3CH(Cl)CH(Cl)CH3. Im not sure if my answer is correct, however my reasoning is that the pi bond of the double bond between the second and third carbon went and broke up th...
- Sun Feb 28, 2016 6:43 pm
- Forum: *Organic Reaction Mechanisms in General
- Topic: Slow Step Determining Overall Rate
- Replies: 1
- Views: 529
Slow Step Determining Overall Rate
Im still a little confused on the concept of the slow step, i know that the slow step determines the overall rate for the reaction. So for example if the first step in a reaction involves breaking two bonds, is the fact that there were two bonds involved the reason why the overall rate is second ord...
- Sat Feb 20, 2016 9:51 pm
- Forum: *Nucleophiles
- Topic: Forming a Nucleophile Bond
- Replies: 1
- Views: 566
Forming a Nucleophile Bond
In lecture, when a nucleophile was added to the structure H-C-Cl-H, the C-Cl bond was broken in the process. Did this happen because carbon can only have 4 bonds or do you always have to break a bond when you form another bond with the nucleophile?
- Thu Feb 18, 2016 10:21 pm
- Forum: General Rate Laws
- Topic: Rate Constant K
- Replies: 2
- Views: 697
Rate Constant K
A lot of questions on practice quizzes ask us to find the rate constant k for the reaction that is given. Is there a general equation to find the rate constant k? If not, how would you calculate for the rate constant k?
- Sun Feb 14, 2016 9:08 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Rate Law
- Replies: 1
- Views: 597
Rate Law
In the course reader the equation: NO2 + CO --> NO + CO2 has a rate law of: k[NO2]^2
Why does the rate law have NO2 going to the power of 2 when NO2 doesn't have a coefficient of 2?
Why does the rate law have NO2 going to the power of 2 when NO2 doesn't have a coefficient of 2?
- Sun Feb 14, 2016 7:31 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Fast/Slow Step
- Replies: 2
- Views: 702
Fast/Slow Step
What does it mean when a reaction has a "fast step" and a "slow step"? Do these terms affect how you would complete a question, and if so how?
- Fri Feb 05, 2016 12:39 pm
- Forum: Balancing Redox Reactions
- Topic: Balancing Redox Reactions
- Replies: 3
- Views: 35171
Balancing Redox Reactions
When balancing redox reactions, when do you use H2O to balance it? How do you know to use H2O?
- Fri Jan 29, 2016 2:59 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Question Regarding K and Q
- Replies: 2
- Views: 606
Re: Question Regarding K and Q
The person above is correct, K is the ratio of products/reactants when the equation is currently at equilibrium. Q is used at any point of the reaction to figure out if you are at equilibrium or if you need to add more of something or reduce part of the reaction.
- Thu Jan 21, 2016 8:08 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Definition of degeneracy and relationship to entropy
- Replies: 6
- Views: 4426
Re: Definition of degeneracy and relationship to entropy
Degeneracy is the number of different ways that energy can exist, and degeneracy and entropy are directly related. This means that the higher that entropy is then there are potentially more ways for energy to be and so degeneracy is increased as well.
- Tue Jan 12, 2016 8:03 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpy
- Replies: 1
- Views: 470
Bond Enthalpy
When doing a question regarding bond enthalpy, would there ever be a time where the molecules were not in their gas state? How would one go about converting a molecule into its gas state?
- Thu Nov 19, 2015 6:57 pm
- Forum: Ideal Gases
- Topic: Reading the textbook
- Replies: 262
- Views: 156816
Re: Reading the textbook
I find it helpful to read the book when i don't completely understand a concept, because there are examples in the text as well. Maybe you should try just looking at the examples to see if you understand it and then if you don't reading the explanations around it instead of reading everything in the...
- Tue Nov 03, 2015 7:29 pm
- Forum: Quantum Numbers and The H-Atom
- Topic: Energy Released
- Replies: 1
- Views: 478
Energy Released
When your solving a problem that is determining the energy released from an electron moving from orbitals, does the equation change if an electron is moving from a 4d orbital to a 2p orbital rather than an electron moving from a 4d orbital to a 2s orbital?
- Fri Oct 30, 2015 2:42 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Determining Paramagnetism
- Replies: 2
- Views: 600
Re: Determining Paramagnetism
I think it would be easier to draw out the MO diagram so you don't miss anything, but i think the more problems you do then you'll be able to do it in your head faster or just write out the electron configuration like the person above said^^
- Thu Oct 15, 2015 7:48 pm
- Forum: Lewis Structures
- Topic: Drawing a Lewis Structure with a double/triple bond
- Replies: 4
- Views: 1362
Re: Drawing a Lewis Structure with a double/triple bond
You know to draw a double bond between the C and the O because Carbons always has to have 4 bonds around it, and since the only other elements are Hydrogen who can only have one bond, then the bond needs to be between Carbon and Oxygen.
- Sun Oct 11, 2015 7:33 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Formula Memorization
- Replies: 1
- Views: 738
Re: Formula Memorization
Yes, i believe we will be given most, if not all the equations we would need but if its not on the sheet then you would need to already know it