"Hi! Nice to meet you! What's your name?"
"I'm dead."
"Am I dead, too??"
"No! My name is DiEthyl Azo Dicarboxylate! DEAD for short."
Source: https://www.quora.com/What-are-some-good-jokes-about-organic-chemistry
Search found 10 matches
- Sun Mar 19, 2017 11:31 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3684680
- Sun Mar 12, 2017 11:48 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3684680
- Sun Mar 05, 2017 11:39 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3684680
- Sun Feb 26, 2017 11:49 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3684680
- Sun Feb 19, 2017 9:49 pm
- Forum: General Rate Laws
- Topic: rate of a reaction
- Replies: 2
- Views: 14346
Re: rate of a reaction
9. A scientist conducts an experiment to determine the rate of the following reaction: N2(g) + O2(g) → 2NO(g) If the initial concentration of N2 was 0.500 M and the concentration of N2 was 0.450 M after 0.100 s, what is the rate of the reaction? a. 0.500 M/s d. 10.0 M/s b. 1.00 M/s e. 0.250 M/s c. ...
- Sun Feb 12, 2017 10:47 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Enthalpy Question 8.31
- Replies: 1
- Views: 577
Re: Enthalpy Question 8.31
Calculate the heat released by 5.025 g of Kr(g) at 0.400 atm as it cools from 97.6°C to 25.0°C at (a) Constant pressure and (b) constant volume. Assume that krypton behaves as an ideal gas. We are given that P=0.400 atm and ΔT=72.6°C For part a, I know that heat(q) at constant pressure is equal to ...
- Sun Feb 05, 2017 10:35 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Anodes and Cathodes, and Standard Reduction Potential
- Replies: 1
- Views: 444
Re: Anodes and Cathodes, and Standard Reduction Potential
In class we have been writing anode on the left hand side and cathode on the right hand side of the cell diagram. Is there a particular reason for this? Also, on page 47, I know it states that standard reduction potential is an intensive property, so that would mean the value cannot be multiplied o...
- Sun Jan 29, 2017 11:43 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: HW #9.85
- Replies: 1
- Views: 495
Re: HW #9.85
Question 9.85 in the textbook says "Potassium nitrate dissolves readily in water, and its enthalpy of solution is +34.9 kJ* mol^{-1} ." Part C of the question then asks, "Is the entropy change of the system primarily a result of changes in the positional disorder or thermal disorder?...
- Sun Jan 22, 2017 10:29 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Enthalpy of H+ protons
- Replies: 2
- Views: 898
Re: Enthalpy of H+ protons
Why is the enthalpy of H+ protons 0? Could it be that whenever H + protons react with matter, they attach to pre-existing bonds? If so, then there shouldn't be any bonds breaking or forming, resulting in no change in energy (an enthalpy of 0). My reasoning for this is based on the fact that energy ...
- Sun Jan 15, 2017 8:24 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Standard Enthalpy of Formation
- Replies: 2
- Views: 639
Re: Standard Enthalpy of Formation
Why is it that diatomic molecules like oxygen gas and nitrogen gas have a standard enthalpy of formation of 0? Recall that standard enthalpy of formation is the heat required to make one mole of something from its components in their most stable state (paraphrased from course reader page 17). Oxyge...