CHEMISTRY COMMUNITY

Samuel_Vydro_1I

Yeah it could theoretically occur but it is just asking you to infer the most likely scenario

Samuel_Vydro_1I

All bonds affected by arrows are shows as dashed

Samuel_Vydro_1I

I don't know if we will have to go to this extent on the final

Samuel_Vydro_1I

OH- is a nucleaphile because it has three lone pairs that readily available to bond

Samuel_Vydro_1I

Nucleophile is simply a fancy way of saying -- molecule that has a lone pair to bond with a molecule that needs an electron. Electrophile is a fancy way of saying-- molecule that needs an electron. Cl to Cl- is something you can remember from 14a

Samuel_Vydro_1I

Well the more catalyst, the more reactant it can catalyze. A lot of enzyme use surface area, moree enzyme means more surface area

Samuel_Vydro_1I

Your confusion may strain from the fact that the deltaG is taken from reactant to maxima of a TS while Ea is first from reactant to TS1 in a two step and then from the intermediates to TS2. deltaG disregards the intermediates as a starting point of measurement

Samuel_Vydro_1I

Yes, as the questions on the Quizzes, the slow step governs the entirety of the reaction. When you see a reaction that is slow then fast, ONLY look at the slow step to determine rate law. Nice general rule

Samuel_Vydro_1I

Such as when given a question regarding a table of values (COncentrations, Rates, Etc.) and you are asked to find the order of each substance and the overall order. It is important to remember to add the overall exponents at the end to find overall rate. Each individual order only relates to the spe...

Samuel_Vydro_1I

Divide by Molarity for each order essentially

Samuel_Vydro_1I

NaCl has no effect because the Na and Cl are salts of a strong acid and strong base

Samuel_Vydro_1I

A higher pH corresponds to a higher amount of base as shown

Samuel_Vydro_1I

the sig figs for pH is the total like as in the 12 in 12.34. that is always unaffected. Starting with the decimal point, it is the number of sig figs in the value that was log'ed. so as log(2.73 ×10–5) = –4.564. The 2.73 is three sig figs for there must be three sig figs after the decimal point.

Samuel_Vydro_1I

The K equation deals with concentrations and as such aqueous solutions consist of dissolved solutes which can change in concentration unlike a solid group of atoms which cannot change in concentration

Samuel_Vydro_1I

Yes, the aspect of equilibrium can be disturbed or altered momentarily as noted in Le Chatelier's Principle:chemical principle that states that if a system in equilibrium is disturbed by changes in determining factors, such as temperature, pressure, and concentration of components, the system will t...

Samuel_Vydro_1I

Yes you need to know that hybridization only deals with regions of density as hybridized orbitals only encompass sigma bonds and lone pairs

Samuel_Vydro_1I

Yes remember that the double and triple bonds include pi bonds which aren't shown in the hybridized orbitals which only illustrate sigma bonds and lone pairs

Samuel_Vydro_1I

It's not the ability to draw the structures-- that's just a formality because we are operating in a 2-D sense. In reality the resonance means that each bond among the plausible options is the same length (as in the double bond is distributed throughout the options making the total molecule more stab...

Samuel_Vydro_1I

Therefore, the number in parentheses denotes what types of bonds the metals can make. For instance, Copper can be Cu(i) or Cu(ii). Cu(i) can give in one electron from a nonmetal as it is Cu1+ while Cu(ii) can give two electrons as it is Cu2+. Thus Cu(i) can form a bond like Cu2O while Cu(ii) can sim...

Samuel_Vydro_1I

Please explain how to do the question #10 on the first preparatory quiz. Alright so we are referring to "An excited hydrogen atom emits light with a frequency of 1.14x10^14 Hz to reach the energy level for which n = 4. In what principle quantum level did the electron begin?" If yes, then ...

Samuel_Vydro_1I

I had the same question, but reading this post definitely helped! Also during that same lecture on 9/28, when going through the worked example in our Course Readers I was confused on where the values for "h" and "c" came from. We were trying to calculate energy and wavelength of...

CHEMISTRY COMMUNITY

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Re: Question 4.30 in the organic chem book

Re: Transition Steps

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Re: Nucleophile vs Electrophile

Re: Catalyst that is used and produced

Re: Relationship between activation energy and pseudo delta g

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Re: Which Hybrid Orbital

Re: Resonance Structures-More Stable

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