Search found 35 matches
- Thu Mar 16, 2017 6:45 pm
- Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
- Topic: Z-1-chloro-2-methyl-1-butene
- Replies: 2
- Views: 1468
Re: Z-1-chloro-2-methyl-1-butene
It is not methylene because methylene refers to a group in the middle of the carbon chain (-CH2-). The CH3 attached to one of the carbons in the double bond is a substituent by the rule that is discussed in this section, and is therefore called a methyl group. There is no "ethyl" in the na...
Re: 2.40
Before we think about lowering numbers, we should find the longest chain first. Because the structure's longest chain would include 4 carbons, we use "but".
- Sun Mar 05, 2017 2:30 pm
- Forum: *Alkanes
- Topic: Problem 1.16 in Organic Coursereader
- Replies: 1
- Views: 394
Re: Problem 1.16 in Organic Coursereader
"Iso" doesn't count as a prefix; it's part of the name. The prefixes that indicate number of a certain substituent (i.e. dimethyl, the "di") do not count in alphabetical naming, but prefixes that are part of a name (like isopropyl's "iso" or "neo") do.
- Thu Mar 02, 2017 11:02 am
- Forum: *Alkanes
- Topic: Naming Bonds
- Replies: 1
- Views: 366
Re: Naming Bonds
When we name a compound, there's no special designation for double or triple bonds. You just have to put the number carbon where the substituent is attached and name the substituent. Keep in mind though that you want to minimize the number of the carbon the substituent is attached to. For example, i...
- Thu Feb 23, 2017 9:05 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Rate Law and Intermediates
- Replies: 1
- Views: 556
Re: Rate Law and Intermediates
Rate laws don't have intermediates in them because intermediates are produced in one reaction and used up in (one of) the following reaction(s). And yes, you should solve for the intermediate to replace it if it shows up in the rate of formation for a product of the overall reaction.
- Mon Feb 13, 2017 8:09 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Homework #14.17
- Replies: 1
- Views: 478
Re: Homework #14.17
We've learned how to balance chemical reactions and write out chemical formulas, and know the reaction takes place in an acidified solution, so I think we should be expected to know how to balance the half-reactions. However, I think we'd have to be given the reduction potentials for each half react...
- Mon Feb 13, 2017 8:00 am
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: 2014 Midterm
- Replies: 5
- Views: 1127
Re: 2014 Midterm
We don't always necessarily want a positive cell potential: if we want a spontaneous reaction, we would need a positive cell potential, but that's not what we're looking for here. The first reaction is oxidized because we need to reverse that reaction to calculate Ka. The reaction that is associated...
- Mon Feb 13, 2017 7:54 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Why Pt(s) when we already have I2 (s)? HW 14.13
- Replies: 2
- Views: 620
Re: Why Pt(s) when we already have I2 (s)? HW 14.13
To be an electrode, it's not enough that something is solid; it also needs to conduct electricity, as electrons are transferred via electrode.
- Sun Feb 12, 2017 1:04 pm
- Forum: Balancing Redox Reactions
- Topic: balancing basic redox equations
- Replies: 1
- Views: 382
Re: balancing basic redox equations
To balance out the oxygen in a basic redox reaction, you'd add H2O, not OH-. To balance hydrogen, you'd add H2O and OH-. Which ever side needs hydrogen, add H2O to that side and add a corresponding amount of OH- on the other side. Notice that if you add H2O on one side and OH- on the other, you'll h...
- Sun Feb 12, 2017 1:00 pm
- Forum: Balancing Redox Reactions
- Topic: Midterm 2016 #6C
- Replies: 1
- Views: 1311
Re: Midterm 2016 #6C
H2O and H+ are used to balance out the numbers of oxygen and hydrogen atoms in the reaction. The first step of writing out the reduction half-reaction is to write down the reactant and product involved with what's being reduced. Balance any atoms that aren't hydrogen or oxygen first. {Cr_2O_7}^{2-}\...
- Sun Feb 12, 2017 10:02 am
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Midterm 2016 Question 8B [ENDORSED]
- Replies: 5
- Views: 954
Re: Midterm 2016 Question 8B [ENDORSED]
Cadmium ions are removed because they react with the sulfide ions that dissociate from sodium sulfide, and precipitate as CdS.
- Sun Feb 12, 2017 9:55 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Chapter 14, Problem 14.19
- Replies: 4
- Views: 1746
Re: Chapter 14, Problem 14.19
The solutions manual uses the positive reduction value for the anode, but notice that this positive reduction potential is being subtracted from the reduction potential of the cathode. We learned to reverse the sign of the reduction potential of the anode and then add the two half-reaction potential...
- Sat Feb 11, 2017 3:43 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Homework help 14.11 [ENDORSED]
- Replies: 5
- Views: 1235
Re: Homework help 14.11 [ENDORSED]
Though it doesn't explicitly reverse the reduction potential, the solutions manual does essentially the same thing. Instead of reversing the reduction potential and then adding the two half-reaction potentials to get the standard cell potential, it just subtracts the reduction potential of the anode...
- Sat Feb 11, 2017 3:33 pm
- Forum: Balancing Redox Reactions
- Topic: purpose of C(gr) at anode? [ENDORSED]
- Replies: 2
- Views: 632
Re: purpose of C(gr) at anode? [ENDORSED]
Though I'm not sure when you'd choose which as an electrode, graphite functions as an inert electrode much as platinum does.
- Sat Feb 11, 2017 3:30 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Nernst Equation Constant [ENDORSED]
- Replies: 1
- Views: 983
Re: Nernst Equation Constant [ENDORSED]
Keep in mind that these constants are a result of aggregating different constants used in the Nernst equation. Both values are calculated assuming the reaction takes place at 25 degrees Celsius (298 Kelvin), and using the value of the gas constant, 8.314 Joules over moles times Kelvin and Faraday's ...
- Mon Feb 06, 2017 9:23 pm
- Forum: Balancing Redox Reactions
- Topic: Homework 14.3.
- Replies: 2
- Views: 817
Re: Homework 14.3.
The first step should being figuring out what's oxidized and what's reduced. The straightforward way is to go through each reactant and its corresponding product and see how each element in it changes oxidation states, but since we know that transition metals commonly change oxidation states, I thin...
- Mon Feb 06, 2017 9:08 pm
- Forum: Balancing Redox Reactions
- Topic: Chapter 14 Question 1
- Replies: 2
- Views: 749
Re: Chapter 14 Question 1
I'm not sure how you're calculating the charge, but first, it's good to start with any transition metals if you see any because they typically change charge in redox equations. You can find the oxidation number of chromium (Cr) by looking at oxygen. Oxygen's common oxidation state is 2-. There's 7 o...
- Mon Feb 06, 2017 10:07 am
- Forum: Interesting Applications: Rechargeable Batteries (Cell Phones, Notebooks, Cars), Fuel Cells (Space Shuttle), Photovoltaic Cells (Solar Panels), Electrolysis, Rust
- Topic: Electrosis rechargeable battery
- Replies: 1
- Views: 605
Re: Electrosis rechargeable battery
Electrolysis is not technically a rechargeable battery because the reaction has to be able to go the opposite direction to be a battery. Electrolysis describes using an electric current to "push" a reaction in a direction opposite of the favorable direction, which is what happens each time...
- Wed Feb 01, 2017 8:44 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Self-Test 8.12B
- Replies: 1
- Views: 522
Re: Self-Test 8.12B
The only gas in the equation is the oxygen gas; for every 4 moles of aluminum that react, 3 moles of oxygen react, so for one mole of aluminum, 3/4 of a mole of oxygen will react. The sign on the moles is negative because you are using up 3/4 of a mole of oxygen (as opposed to gaining 3/4ths of a mo...
- Sat Jan 28, 2017 5:49 pm
- Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
- Topic: Ch 9 #1c Why does Entropy decrease when temperature increases?
- Replies: 1
- Views: 3624
Re: Ch 9 #1c Why does Entropy decrease when temperature increases?
As you said, mathematically, this makes sense; if you calculate the entropy change with some q value at 20 degrees Celsius and the same q value at 30 degrees Celsius, the entropy change of the 2nd calculation is smaller than that of the first. Rather than the temperature change though, I think it's ...
- Sun Jan 22, 2017 8:03 pm
- Forum: Phase Changes & Related Calculations
- Topic: Heat Released/Absorbed [ENDORSED]
- Replies: 2
- Views: 3406
Re: Heat Released/Absorbed [ENDORSED]
Hm, I think you have them mixed up? Heat released is negative and heat absorbed is positive. This all goes back to the concept of a system and the surroundings. The system is what we're focusing on while the surroundings are everything else. We think of change in energy from the perspective of the s...
- Wed Jan 18, 2017 7:55 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Chapter 8 Question #3 (The First Law)
- Replies: 2
- Views: 1104
Re: Chapter 8 Question #3 (The First Law)
First, I would write down what you're given in variables, ex. Pressure (P) =2.00atm. Then, relate the given with what you're looking for. In part a, you're looking for "work...done in the compression". Recall that work is force over a distance and pressure is force over an area. Page 22 in...
- Wed Jan 18, 2017 7:49 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Chapter 8 #5 [ENDORSED]
- Replies: 2
- Views: 724
Re: Chapter 8 #5 [ENDORSED]
Usually we subtract a final quantity from an initial quantity to calculate a change, but in this case, we should be thinking about what is affecting the system and how it is affecting it. Whether to add or subtract a quantity depends on its sign, which is determined by how the system is affected by ...
- Thu Jan 12, 2017 10:18 am
- Forum: Phase Changes & Related Calculations
- Topic: Bond Enthalpy and Enthalpy of Formation
- Replies: 4
- Views: 736
Re: Bond Enthalpy and Enthalpy of Formation
It's not so much that O2 is an exception as it is that the standard enthalpy of formation of an element in its most stable form is 0 (this definition is found on page 294 of the book). I think this makes more sense if you think about the "reaction" you'd need to form these elements. You co...
- Wed Nov 30, 2016 9:41 am
- Forum: Polyprotic Acids & Bases
- Topic: 12.81
- Replies: 1
- Views: 637
Re: 12.81
In this specific problem, the answer book probably says to ignore the second ionization because it is too small take into account. I don't think there's a specific cutoff of when to omit the second ionization, but I think if it doesn't contribute to changing the significant figures of the answer, it...
- Fri Nov 25, 2016 12:06 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Cl-
- Replies: 1
- Views: 414
Re: Cl-
The chloride ion (Cl-) doesn't affect pH because pH is a measure of how acidic (or basic) something is based on its hydronium ion concentration (H3O+). We aren't looking at charge, so the charge of the chloride ion wouldn't affect the pH of the solution, and if we're talking about hydrochloric acid ...
- Mon Nov 14, 2016 4:32 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Calculating K
- Replies: 4
- Views: 821
Re: Calculating K
Even if there's a solid in the reaction, you can still calculate the Q and K using just the concentrations of the reactants and or products in gas phase.
- Mon Nov 07, 2016 3:58 pm
- Forum: Hybridization
- Topic: Hybridization
- Replies: 2
- Views: 664
Re: Hybridization
Simply put, hybridized orbitals mesh together different unhybridized orbitals to better account for experimental observations. For example, the book gives the example of carbon: we know from experience with Lewis structures that carbon usually forms 4 bonds, but according to its electron configurati...
- Tue Nov 01, 2016 5:13 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Trigonal pyramidal vs. pyramidal
- Replies: 2
- Views: 8155
Re: Trigonal pyramidal vs. pyramidal
Also, just a note: trigonal pyramidal is shape based on that of tetrahedral. However, while tetrahedral has four bonds attached to the central atom, trigonal pyramidal has three bonds and one lone pair attached to the central atom. Due to lone pair repulsion, the bond angle of trigonal pyramidal is ...
- Tue Oct 25, 2016 6:47 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: chapter 3 #13B
- Replies: 2
- Views: 567
Re: chapter 3 #13B
Hi Ariana,
Electrons are removed from orbitals with the most energy first, so electrons from the 3p orbital will be removed before electrons from the 3s orbital.
Electrons are removed from orbitals with the most energy first, so electrons from the 3p orbital will be removed before electrons from the 3s orbital.
- Tue Oct 18, 2016 7:42 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Chapter 2 HW 55
- Replies: 1
- Views: 341
Re: Chapter 2 HW 55
In this part of the exercise, I believe they mean the 5th group within the transition metals, which would refer to what's actually the 7th group transition metals (manganese, technetium, etc.).
- Wed Oct 12, 2016 7:46 pm
- Forum: Trends in The Periodic Table
- Topic: Exceptions to the Periodic Trends
- Replies: 3
- Views: 6422
Re: Exceptions to the Periodic Trends
Hi Matt, I don't have an answer for all the specific examples you suggested, but in general, I believe irregularities in atomic radius are due to electron-electron repulsion and effective nuclear charge: electron-electron repulsion may cause electrons to spread out and effective nuclear charge affec...
- Wed Oct 05, 2016 8:23 am
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Atomic spectra
- Replies: 1
- Views: 353
Re: Atomic spectra
The high energy electron may already be releasing all of its energy - the smaller n is, the more energy it takes to move between the two energy levels (it'd take more energy to move from n =2 to n =1 than to go from n=4 to n=3). Therefore, if there were a high energy electron on one of the higher le...
- Thu Sep 29, 2016 9:17 am
- Forum: Einstein Equation
- Topic: Homework 1.69 [ENDORSED]
- Replies: 4
- Views: 1240
Re: Homework 1.69 [ENDORSED]
A general approach I typically use is writing down given information and thinking about what I know about the quantities given. The problem gives us the wavelengths of light and mentions a lithium photomultiplier is used; I singled out these tidbits of the problem because they deal directly with the...
- Wed Sep 28, 2016 12:09 pm
- Forum: Balancing Chemical Reactions
- Topic: Workbook Self Test pg. 11 #8
- Replies: 2
- Views: 705
Re: Workbook Self Test pg. 11 #8
It's not so much when the word "neutralize" is used, but if you're given the mass of only one reactant, I think it's safe to assume that the other reactant is present in excess. Therefore, it wouldn't affect the amount of product produced, so you can proceed with calculations using your gi...